Write a differential equation representing the rate of change of grams of chocolate/ minute











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I have one cup of hot milk and I stir in melted chocolate that is 24g/cup at a rate of 1cup/min. So that my cup does not overflow, I pour the mixed drink out at the same rate.



I was given the answer of dy/dx = 24 - 24y.
I would like an explanation.










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    Geesh, who are those nobodies x and y?
    – William Elliot
    Nov 18 at 2:08















up vote
-1
down vote

favorite












I have one cup of hot milk and I stir in melted chocolate that is 24g/cup at a rate of 1cup/min. So that my cup does not overflow, I pour the mixed drink out at the same rate.



I was given the answer of dy/dx = 24 - 24y.
I would like an explanation.










share|cite|improve this question




















  • 1




    Geesh, who are those nobodies x and y?
    – William Elliot
    Nov 18 at 2:08













up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











I have one cup of hot milk and I stir in melted chocolate that is 24g/cup at a rate of 1cup/min. So that my cup does not overflow, I pour the mixed drink out at the same rate.



I was given the answer of dy/dx = 24 - 24y.
I would like an explanation.










share|cite|improve this question















I have one cup of hot milk and I stir in melted chocolate that is 24g/cup at a rate of 1cup/min. So that my cup does not overflow, I pour the mixed drink out at the same rate.



I was given the answer of dy/dx = 24 - 24y.
I would like an explanation.







calculus differential-equations






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited yesterday

























asked Nov 17 at 23:50









PlayerUnknown_12

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  • 1




    Geesh, who are those nobodies x and y?
    – William Elliot
    Nov 18 at 2:08














  • 1




    Geesh, who are those nobodies x and y?
    – William Elliot
    Nov 18 at 2:08








1




1




Geesh, who are those nobodies x and y?
– William Elliot
Nov 18 at 2:08




Geesh, who are those nobodies x and y?
– William Elliot
Nov 18 at 2:08















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