JQuery - get the min and max date of an associative array

1

I have this associative array:

[{"start_date":"2018-11-20", "end_date":"2019-01-20", name:"NO Name"},

 {"start_date":"2018-10-10", "end_date":"2019-02-14", name:"Name No"},

 {"start_date":"2019-02-15", "end_date":"2019-03-01", name:"No Name No"}]

The value I wanted to get is the minimun start date which is 2018-10-10 and the maximum end date which is 2019-03-01. How can I get that?

What Ive Tried:

data = '[{"start_date":"2018-11-20", "end_date":"2019-01-20", name:"NO Name"},{"start_date":"2018-10-10", "end_date":"2019-02-14", name:"Name No"},{"start_date":"2019-02-15", "end_date":"2019-03-01", name:"No Name No"}]';



var end_date = new Date();

var start_date = new Date();





for (var i=0; i<data.length; i++) {

    if (data[i].end_date > end_date) {

        end_date = data[i].end_date

    }



    if (data[i].start_date > start_date) {

        start_date = data[i].start_date;

    }

}



console.log(end_date);

console.log(start_date);

javascript jquery arrays json

share|improve this question

edited Nov 20 '18 at 1:54

sad saddest

asked Nov 20 '18 at 1:47

sad saddestsad saddest

338

add a comment | 

1

I have this associative array:

[{"start_date":"2018-11-20", "end_date":"2019-01-20", name:"NO Name"},

 {"start_date":"2018-10-10", "end_date":"2019-02-14", name:"Name No"},

 {"start_date":"2019-02-15", "end_date":"2019-03-01", name:"No Name No"}]

The value I wanted to get is the minimun start date which is 2018-10-10 and the maximum end date which is 2019-03-01. How can I get that?

What Ive Tried:

data = '[{"start_date":"2018-11-20", "end_date":"2019-01-20", name:"NO Name"},{"start_date":"2018-10-10", "end_date":"2019-02-14", name:"Name No"},{"start_date":"2019-02-15", "end_date":"2019-03-01", name:"No Name No"}]';



var end_date = new Date();

var start_date = new Date();





for (var i=0; i<data.length; i++) {

    if (data[i].end_date > end_date) {

        end_date = data[i].end_date

    }



    if (data[i].start_date > start_date) {

        start_date = data[i].start_date;

    }

}



console.log(end_date);

console.log(start_date);

javascript jquery arrays json

share|improve this question

edited Nov 20 '18 at 1:54

sad saddest

asked Nov 20 '18 at 1:47

sad saddestsad saddest

338

add a comment | 

1

1

1

I have this associative array:

[{"start_date":"2018-11-20", "end_date":"2019-01-20", name:"NO Name"},

 {"start_date":"2018-10-10", "end_date":"2019-02-14", name:"Name No"},

 {"start_date":"2019-02-15", "end_date":"2019-03-01", name:"No Name No"}]

The value I wanted to get is the minimun start date which is 2018-10-10 and the maximum end date which is 2019-03-01. How can I get that?

What Ive Tried:

data = '[{"start_date":"2018-11-20", "end_date":"2019-01-20", name:"NO Name"},{"start_date":"2018-10-10", "end_date":"2019-02-14", name:"Name No"},{"start_date":"2019-02-15", "end_date":"2019-03-01", name:"No Name No"}]';



var end_date = new Date();

var start_date = new Date();





for (var i=0; i<data.length; i++) {

    if (data[i].end_date > end_date) {

        end_date = data[i].end_date

    }



    if (data[i].start_date > start_date) {

        start_date = data[i].start_date;

    }

}



console.log(end_date);

console.log(start_date);

javascript jquery arrays json

share|improve this question

edited Nov 20 '18 at 1:54

sad saddest

asked Nov 20 '18 at 1:47

sad saddestsad saddest

338

I have this associative array:

[{"start_date":"2018-11-20", "end_date":"2019-01-20", name:"NO Name"},

 {"start_date":"2018-10-10", "end_date":"2019-02-14", name:"Name No"},

 {"start_date":"2019-02-15", "end_date":"2019-03-01", name:"No Name No"}]

The value I wanted to get is the minimun start date which is 2018-10-10 and the maximum end date which is 2019-03-01. How can I get that?

What Ive Tried:

data = '[{"start_date":"2018-11-20", "end_date":"2019-01-20", name:"NO Name"},{"start_date":"2018-10-10", "end_date":"2019-02-14", name:"Name No"},{"start_date":"2019-02-15", "end_date":"2019-03-01", name:"No Name No"}]';



var end_date = new Date();

var start_date = new Date();





for (var i=0; i<data.length; i++) {

    if (data[i].end_date > end_date) {

        end_date = data[i].end_date

    }



    if (data[i].start_date > start_date) {

        start_date = data[i].start_date;

    }

}



console.log(end_date);

console.log(start_date);

javascript jquery arrays json

javascript jquery arrays json

share|improve this question

edited Nov 20 '18 at 1:54

sad saddest

asked Nov 20 '18 at 1:47

sad saddestsad saddest

338

share|improve this question

edited Nov 20 '18 at 1:54

sad saddest

asked Nov 20 '18 at 1:47

sad saddestsad saddest

338

share|improve this question

share|improve this question

edited Nov 20 '18 at 1:54

sad saddest

edited Nov 20 '18 at 1:54

sad saddest

edited Nov 20 '18 at 1:54

sad saddest

asked Nov 20 '18 at 1:47

sad saddestsad saddest

338

asked Nov 20 '18 at 1:47

sad saddestsad saddest

338

asked Nov 20 '18 at 1:47

sad saddestsad saddest

338

338

add a comment | 

add a comment | 

1 Answer
1

active

oldest

votes

2

You can just sort by start_date via String.localeCompare and then get the fist and last element of the resulting array:

const data = [{ "start_date": "2018-11-20", "end_date": "2019-01-20", name: "NO Name" }, { "start_date": "2018-10-10", "end_date": "2019-02-14", name: "Name No" }, { "start_date": "2019-02-15", "end_date": "2019-03-01", name: "No Name No" } ]



const result = data.sort((a,b) => a.start_date.localeCompare(b.start_date))

console.log(result[0], result[result.length-1])

// Just the dates

console.log(result[0].start_date, result[result.length-1].start_date)

share|improve this answer

edited Nov 20 '18 at 1:59

answered Nov 20 '18 at 1:52

AkrionAkrion

9,42711224

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can I get only the dates?
  
  – sad saddest
  Nov 20 '18 at 1:59
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Sure: console.log(result[0].start_date, result[result.length-1].start_date)
  
  – Akrion
  Nov 20 '18 at 2:00
  

  
  
  
  

add a comment | 

Your Answer

StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});

Thanks for contributing an answer to Stack Overflow!

• Please be sure to answer the question. Provide details and share your research!

But avoid …

• Asking for help, clarification, or responding to other answers.


• Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53385098%2fjquery-get-the-min-and-max-date-of-an-associative-array%23new-answer', 'question_page');
}
);

Post as a guest

Name

Email

Required, but never shown

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

active

oldest

votes

active

oldest

votes

2

You can just sort by start_date via String.localeCompare and then get the fist and last element of the resulting array:

const data = [{ "start_date": "2018-11-20", "end_date": "2019-01-20", name: "NO Name" }, { "start_date": "2018-10-10", "end_date": "2019-02-14", name: "Name No" }, { "start_date": "2019-02-15", "end_date": "2019-03-01", name: "No Name No" } ]



const result = data.sort((a,b) => a.start_date.localeCompare(b.start_date))

console.log(result[0], result[result.length-1])

// Just the dates

console.log(result[0].start_date, result[result.length-1].start_date)

share|improve this answer

edited Nov 20 '18 at 1:59

answered Nov 20 '18 at 1:52

AkrionAkrion

9,42711224

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can I get only the dates?
  
  – sad saddest
  Nov 20 '18 at 1:59
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Sure: console.log(result[0].start_date, result[result.length-1].start_date)
  
  – Akrion
  Nov 20 '18 at 2:00
  

  
  
  
  

add a comment | 

2

You can just sort by start_date via String.localeCompare and then get the fist and last element of the resulting array:

const data = [{ "start_date": "2018-11-20", "end_date": "2019-01-20", name: "NO Name" }, { "start_date": "2018-10-10", "end_date": "2019-02-14", name: "Name No" }, { "start_date": "2019-02-15", "end_date": "2019-03-01", name: "No Name No" } ]



const result = data.sort((a,b) => a.start_date.localeCompare(b.start_date))

console.log(result[0], result[result.length-1])

// Just the dates

console.log(result[0].start_date, result[result.length-1].start_date)

share|improve this answer

edited Nov 20 '18 at 1:59

answered Nov 20 '18 at 1:52

AkrionAkrion

9,42711224

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can I get only the dates?
  
  – sad saddest
  Nov 20 '18 at 1:59
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Sure: console.log(result[0].start_date, result[result.length-1].start_date)
  
  – Akrion
  Nov 20 '18 at 2:00
  

  
  
  
  

add a comment | 

2

2

2

You can just sort by start_date via String.localeCompare and then get the fist and last element of the resulting array:

const data = [{ "start_date": "2018-11-20", "end_date": "2019-01-20", name: "NO Name" }, { "start_date": "2018-10-10", "end_date": "2019-02-14", name: "Name No" }, { "start_date": "2019-02-15", "end_date": "2019-03-01", name: "No Name No" } ]



const result = data.sort((a,b) => a.start_date.localeCompare(b.start_date))

console.log(result[0], result[result.length-1])

// Just the dates

console.log(result[0].start_date, result[result.length-1].start_date)

share|improve this answer

edited Nov 20 '18 at 1:59

answered Nov 20 '18 at 1:52

AkrionAkrion

9,42711224

You can just sort by start_date via String.localeCompare and then get the fist and last element of the resulting array:

const data = [{ "start_date": "2018-11-20", "end_date": "2019-01-20", name: "NO Name" }, { "start_date": "2018-10-10", "end_date": "2019-02-14", name: "Name No" }, { "start_date": "2019-02-15", "end_date": "2019-03-01", name: "No Name No" } ]



const result = data.sort((a,b) => a.start_date.localeCompare(b.start_date))

console.log(result[0], result[result.length-1])

// Just the dates

console.log(result[0].start_date, result[result.length-1].start_date)

const data = [{ "start_date": "2018-11-20", "end_date": "2019-01-20", name: "NO Name" }, { "start_date": "2018-10-10", "end_date": "2019-02-14", name: "Name No" }, { "start_date": "2019-02-15", "end_date": "2019-03-01", name: "No Name No" } ]



const result = data.sort((a,b) => a.start_date.localeCompare(b.start_date))

console.log(result[0], result[result.length-1])

// Just the dates

console.log(result[0].start_date, result[result.length-1].start_date)

const data = [{ "start_date": "2018-11-20", "end_date": "2019-01-20", name: "NO Name" }, { "start_date": "2018-10-10", "end_date": "2019-02-14", name: "Name No" }, { "start_date": "2019-02-15", "end_date": "2019-03-01", name: "No Name No" } ]



const result = data.sort((a,b) => a.start_date.localeCompare(b.start_date))

console.log(result[0], result[result.length-1])

// Just the dates

console.log(result[0].start_date, result[result.length-1].start_date)

share|improve this answer

edited Nov 20 '18 at 1:59

answered Nov 20 '18 at 1:52

AkrionAkrion

9,42711224

share|improve this answer

share|improve this answer

edited Nov 20 '18 at 1:59

edited Nov 20 '18 at 1:59

edited Nov 20 '18 at 1:59

answered Nov 20 '18 at 1:52

AkrionAkrion

9,42711224

answered Nov 20 '18 at 1:52

AkrionAkrion

9,42711224

answered Nov 20 '18 at 1:52

AkrionAkrion

9,42711224

9,42711224

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can I get only the dates?
  
  – sad saddest
  Nov 20 '18 at 1:59
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Sure: console.log(result[0].start_date, result[result.length-1].start_date)
  
  – Akrion
  Nov 20 '18 at 2:00
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can I get only the dates?
  
  – sad saddest
  Nov 20 '18 at 1:59
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Sure: console.log(result[0].start_date, result[result.length-1].start_date)
  
  – Akrion
  Nov 20 '18 at 2:00
  

  
  
  
  

Can I get only the dates?

– sad saddest
Nov 20 '18 at 1:59

Can I get only the dates?

– sad saddest
Nov 20 '18 at 1:59

Sure: console.log(result[0].start_date, result[result.length-1].start_date)

– Akrion
Nov 20 '18 at 2:00

Sure: console.log(result[0].start_date, result[result.length-1].start_date)

– Akrion
Nov 20 '18 at 2:00

add a comment | 

Thanks for contributing an answer to Stack Overflow!

• Please be sure to answer the question. Provide details and share your research!

But avoid …

• Asking for help, clarification, or responding to other answers.


• Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Thanks for contributing an answer to Stack Overflow!

• Please be sure to answer the question. Provide details and share your research!

But avoid …

• Asking for help, clarification, or responding to other answers.


• Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53385098%2fjquery-get-the-min-and-max-date-of-an-associative-array%23new-answer', 'question_page');
}
);

Post as a guest

Name

Email

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

Name

Name

Email

Required, but never shown

Email

Required, but never shown

Email

Required, but never shown

Email

Required, but never shown

Name

Name

Email

Required, but never shown

Email

Required, but never shown

Email

Required, but never shown

Email

Required, but never shown

This page is only for reference, If you need detailed information, please check here