Proof that the binary entropy is concave












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Defining the binary entropy function as $H_{bin}(x) = - xlog(x) - (1-x)log(1-x)$, how do I show that it is concave? I can see the intuition but not the proof.



Namely, I need to prove that $H_{bin}(px_1 + (1-p)x_2) geq pH_{bin}(x_1) + (1-p)H_{bin}(x_2)$.



Following the comment posted, I take the second derivative of $H_{bin}$ with respect to $p$ and obtain $frac{partial^2 H}{partial p^2} = -(x_1 - x_2)^2 frac{1-2a}{a(1-a)}$, where $a = px_1 + (1-p)x_2$. How do I see that $frac{1-2a}{a(1-a)}$ is positive?










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  • This is best done using Calculus. Show that the second derivative is negative on this interval.
    – Hans Engler
    Nov 20 '18 at 17:06










  • @HansEngler, thanks. I think I'm close but I don't quite see the solution yet.
    – user1936752
    Nov 20 '18 at 18:31
















0














Defining the binary entropy function as $H_{bin}(x) = - xlog(x) - (1-x)log(1-x)$, how do I show that it is concave? I can see the intuition but not the proof.



Namely, I need to prove that $H_{bin}(px_1 + (1-p)x_2) geq pH_{bin}(x_1) + (1-p)H_{bin}(x_2)$.



Following the comment posted, I take the second derivative of $H_{bin}$ with respect to $p$ and obtain $frac{partial^2 H}{partial p^2} = -(x_1 - x_2)^2 frac{1-2a}{a(1-a)}$, where $a = px_1 + (1-p)x_2$. How do I see that $frac{1-2a}{a(1-a)}$ is positive?










share|cite|improve this question
























  • This is best done using Calculus. Show that the second derivative is negative on this interval.
    – Hans Engler
    Nov 20 '18 at 17:06










  • @HansEngler, thanks. I think I'm close but I don't quite see the solution yet.
    – user1936752
    Nov 20 '18 at 18:31














0












0








0







Defining the binary entropy function as $H_{bin}(x) = - xlog(x) - (1-x)log(1-x)$, how do I show that it is concave? I can see the intuition but not the proof.



Namely, I need to prove that $H_{bin}(px_1 + (1-p)x_2) geq pH_{bin}(x_1) + (1-p)H_{bin}(x_2)$.



Following the comment posted, I take the second derivative of $H_{bin}$ with respect to $p$ and obtain $frac{partial^2 H}{partial p^2} = -(x_1 - x_2)^2 frac{1-2a}{a(1-a)}$, where $a = px_1 + (1-p)x_2$. How do I see that $frac{1-2a}{a(1-a)}$ is positive?










share|cite|improve this question















Defining the binary entropy function as $H_{bin}(x) = - xlog(x) - (1-x)log(1-x)$, how do I show that it is concave? I can see the intuition but not the proof.



Namely, I need to prove that $H_{bin}(px_1 + (1-p)x_2) geq pH_{bin}(x_1) + (1-p)H_{bin}(x_2)$.



Following the comment posted, I take the second derivative of $H_{bin}$ with respect to $p$ and obtain $frac{partial^2 H}{partial p^2} = -(x_1 - x_2)^2 frac{1-2a}{a(1-a)}$, where $a = px_1 + (1-p)x_2$. How do I see that $frac{1-2a}{a(1-a)}$ is positive?







entropy






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 20 '18 at 18:18

























asked Nov 20 '18 at 16:58









user1936752

5181513




5181513












  • This is best done using Calculus. Show that the second derivative is negative on this interval.
    – Hans Engler
    Nov 20 '18 at 17:06










  • @HansEngler, thanks. I think I'm close but I don't quite see the solution yet.
    – user1936752
    Nov 20 '18 at 18:31


















  • This is best done using Calculus. Show that the second derivative is negative on this interval.
    – Hans Engler
    Nov 20 '18 at 17:06










  • @HansEngler, thanks. I think I'm close but I don't quite see the solution yet.
    – user1936752
    Nov 20 '18 at 18:31
















This is best done using Calculus. Show that the second derivative is negative on this interval.
– Hans Engler
Nov 20 '18 at 17:06




This is best done using Calculus. Show that the second derivative is negative on this interval.
– Hans Engler
Nov 20 '18 at 17:06












@HansEngler, thanks. I think I'm close but I don't quite see the solution yet.
– user1936752
Nov 20 '18 at 18:31




@HansEngler, thanks. I think I'm close but I don't quite see the solution yet.
– user1936752
Nov 20 '18 at 18:31










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