Decomposing $k$th exterior powers $Lambda^kV(omega_1)$












3












$begingroup$


Let $Phi$ be a $G_2$ root system, $omega_1$ the fundamental weight corresponding to the shorter root and consider the unique irreducible highest weight module $V
= V(omega_1)$
of highest weight $omega_1$.



I am asked to decompose in terms of highest weights the exterior powers $Lambda^kV$ for all $k$.



Note $Lambda^kV = V^{otimes k}/N_n$, where:



$N_n = {v_1 otimes dots otimes v_k mid v_i in V ; forall i text{ and } v_i = v_j text{ for some }i text{ and } j}$.



Denote the coset of $u_1 otimes dots otimes u_k$ by $u_1 wedge dots wedge u_k$. It is known that if $V $ has basis $v_1, dots, v_n$, then $Lambda^kV$ has basis ${v_{i_1} wedge dots wedge v_{i_k} mid i_1 < dots < i_k in {1,dots, n} }$.



In our case, $V$ has dimension $n = 7$ and so, I think that it would be correct to say that $lambda^kV = 0, ; forall k geq 8$ since if we can't have eight of the seven basis vectors wedged together without a repeat, meaning it would land within $N_7$.



Further, I think this means that $Lambda^7V$ has dimension $1$ and is exactly $span{v_1wedge dots wedge v_7}$



Now, regarding the specifics of the question, I think this means that for $kgeq 8$ the $k$th exterior powers of $V$ have highest weight $0$ since it is the $0$-space?



For $k=7$ however, I am less certain of how to proceed. I suppose that we could without loss of generality suppose that $v_1$ is the highest weight vector of weight $omega_1$ in $V(omega_1)$, but then we have:



For $min mathbb C$ and $t in mathfrak{t}$ the Cartan Subalgebra,



$t cdot m(v_1wedge dots wedge v_7) = m((t cdot v_1)wedge dots wedge v_7 + dots + v_1 wedge dots wedge (tcdot v_7))$



It is not clear to me that this is a highest weight vector of any weight, because I am not sure how $t$ acts on any of the other basis vectors. Thus I am not sure how to proceed with this case.



Additionally, I am even less sure how to proceed with the cases of $k leq 6$. In these cases, the representation has dimension greater than 1, but aside from that I am struggling to make any helpful or worthwhile observations.



How might I be able to proceed and decompose these exterior powers?










share|cite|improve this question











$endgroup$

















    3












    $begingroup$


    Let $Phi$ be a $G_2$ root system, $omega_1$ the fundamental weight corresponding to the shorter root and consider the unique irreducible highest weight module $V
    = V(omega_1)$
    of highest weight $omega_1$.



    I am asked to decompose in terms of highest weights the exterior powers $Lambda^kV$ for all $k$.



    Note $Lambda^kV = V^{otimes k}/N_n$, where:



    $N_n = {v_1 otimes dots otimes v_k mid v_i in V ; forall i text{ and } v_i = v_j text{ for some }i text{ and } j}$.



    Denote the coset of $u_1 otimes dots otimes u_k$ by $u_1 wedge dots wedge u_k$. It is known that if $V $ has basis $v_1, dots, v_n$, then $Lambda^kV$ has basis ${v_{i_1} wedge dots wedge v_{i_k} mid i_1 < dots < i_k in {1,dots, n} }$.



    In our case, $V$ has dimension $n = 7$ and so, I think that it would be correct to say that $lambda^kV = 0, ; forall k geq 8$ since if we can't have eight of the seven basis vectors wedged together without a repeat, meaning it would land within $N_7$.



    Further, I think this means that $Lambda^7V$ has dimension $1$ and is exactly $span{v_1wedge dots wedge v_7}$



    Now, regarding the specifics of the question, I think this means that for $kgeq 8$ the $k$th exterior powers of $V$ have highest weight $0$ since it is the $0$-space?



    For $k=7$ however, I am less certain of how to proceed. I suppose that we could without loss of generality suppose that $v_1$ is the highest weight vector of weight $omega_1$ in $V(omega_1)$, but then we have:



    For $min mathbb C$ and $t in mathfrak{t}$ the Cartan Subalgebra,



    $t cdot m(v_1wedge dots wedge v_7) = m((t cdot v_1)wedge dots wedge v_7 + dots + v_1 wedge dots wedge (tcdot v_7))$



    It is not clear to me that this is a highest weight vector of any weight, because I am not sure how $t$ acts on any of the other basis vectors. Thus I am not sure how to proceed with this case.



    Additionally, I am even less sure how to proceed with the cases of $k leq 6$. In these cases, the representation has dimension greater than 1, but aside from that I am struggling to make any helpful or worthwhile observations.



    How might I be able to proceed and decompose these exterior powers?










    share|cite|improve this question











    $endgroup$















      3












      3








      3


      1



      $begingroup$


      Let $Phi$ be a $G_2$ root system, $omega_1$ the fundamental weight corresponding to the shorter root and consider the unique irreducible highest weight module $V
      = V(omega_1)$
      of highest weight $omega_1$.



      I am asked to decompose in terms of highest weights the exterior powers $Lambda^kV$ for all $k$.



      Note $Lambda^kV = V^{otimes k}/N_n$, where:



      $N_n = {v_1 otimes dots otimes v_k mid v_i in V ; forall i text{ and } v_i = v_j text{ for some }i text{ and } j}$.



      Denote the coset of $u_1 otimes dots otimes u_k$ by $u_1 wedge dots wedge u_k$. It is known that if $V $ has basis $v_1, dots, v_n$, then $Lambda^kV$ has basis ${v_{i_1} wedge dots wedge v_{i_k} mid i_1 < dots < i_k in {1,dots, n} }$.



      In our case, $V$ has dimension $n = 7$ and so, I think that it would be correct to say that $lambda^kV = 0, ; forall k geq 8$ since if we can't have eight of the seven basis vectors wedged together without a repeat, meaning it would land within $N_7$.



      Further, I think this means that $Lambda^7V$ has dimension $1$ and is exactly $span{v_1wedge dots wedge v_7}$



      Now, regarding the specifics of the question, I think this means that for $kgeq 8$ the $k$th exterior powers of $V$ have highest weight $0$ since it is the $0$-space?



      For $k=7$ however, I am less certain of how to proceed. I suppose that we could without loss of generality suppose that $v_1$ is the highest weight vector of weight $omega_1$ in $V(omega_1)$, but then we have:



      For $min mathbb C$ and $t in mathfrak{t}$ the Cartan Subalgebra,



      $t cdot m(v_1wedge dots wedge v_7) = m((t cdot v_1)wedge dots wedge v_7 + dots + v_1 wedge dots wedge (tcdot v_7))$



      It is not clear to me that this is a highest weight vector of any weight, because I am not sure how $t$ acts on any of the other basis vectors. Thus I am not sure how to proceed with this case.



      Additionally, I am even less sure how to proceed with the cases of $k leq 6$. In these cases, the representation has dimension greater than 1, but aside from that I am struggling to make any helpful or worthwhile observations.



      How might I be able to proceed and decompose these exterior powers?










      share|cite|improve this question











      $endgroup$




      Let $Phi$ be a $G_2$ root system, $omega_1$ the fundamental weight corresponding to the shorter root and consider the unique irreducible highest weight module $V
      = V(omega_1)$
      of highest weight $omega_1$.



      I am asked to decompose in terms of highest weights the exterior powers $Lambda^kV$ for all $k$.



      Note $Lambda^kV = V^{otimes k}/N_n$, where:



      $N_n = {v_1 otimes dots otimes v_k mid v_i in V ; forall i text{ and } v_i = v_j text{ for some }i text{ and } j}$.



      Denote the coset of $u_1 otimes dots otimes u_k$ by $u_1 wedge dots wedge u_k$. It is known that if $V $ has basis $v_1, dots, v_n$, then $Lambda^kV$ has basis ${v_{i_1} wedge dots wedge v_{i_k} mid i_1 < dots < i_k in {1,dots, n} }$.



      In our case, $V$ has dimension $n = 7$ and so, I think that it would be correct to say that $lambda^kV = 0, ; forall k geq 8$ since if we can't have eight of the seven basis vectors wedged together without a repeat, meaning it would land within $N_7$.



      Further, I think this means that $Lambda^7V$ has dimension $1$ and is exactly $span{v_1wedge dots wedge v_7}$



      Now, regarding the specifics of the question, I think this means that for $kgeq 8$ the $k$th exterior powers of $V$ have highest weight $0$ since it is the $0$-space?



      For $k=7$ however, I am less certain of how to proceed. I suppose that we could without loss of generality suppose that $v_1$ is the highest weight vector of weight $omega_1$ in $V(omega_1)$, but then we have:



      For $min mathbb C$ and $t in mathfrak{t}$ the Cartan Subalgebra,



      $t cdot m(v_1wedge dots wedge v_7) = m((t cdot v_1)wedge dots wedge v_7 + dots + v_1 wedge dots wedge (tcdot v_7))$



      It is not clear to me that this is a highest weight vector of any weight, because I am not sure how $t$ acts on any of the other basis vectors. Thus I am not sure how to proceed with this case.



      Additionally, I am even less sure how to proceed with the cases of $k leq 6$. In these cases, the representation has dimension greater than 1, but aside from that I am struggling to make any helpful or worthwhile observations.



      How might I be able to proceed and decompose these exterior powers?







      representation-theory lie-algebras exterior-algebra root-systems






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      share|cite|improve this question













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      edited Jan 10 at 0:14







      user366818

















      asked Jan 9 at 21:48









      user366818user366818

      949410




      949410






















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