Map an array of arrays

Is there a method in lodash to map over an array of arrays

I would like to do something like this so that it keeps the structure of the array.

def double(x) { return x*2 }



_([[1,2],[3,4]]).somemethod(double) == [[2,4],[6,8]]

edited Feb 25 '17 at 12:02

user663031

asked Feb 10 '16 at 20:58

bwbrowning

2,42742431

add a comment |

Is there a method in lodash to map over an array of arrays

I would like to do something like this so that it keeps the structure of the array.

def double(x) { return x*2 }



_([[1,2],[3,4]]).somemethod(double) == [[2,4],[6,8]]

edited Feb 25 '17 at 12:02

user663031

asked Feb 10 '16 at 20:58

bwbrowning

2,42742431

add a comment |

Is there a method in lodash to map over an array of arrays

I would like to do something like this so that it keeps the structure of the array.

def double(x) { return x*2 }



_([[1,2],[3,4]]).somemethod(double) == [[2,4],[6,8]]

edited Feb 25 '17 at 12:02

user663031

asked Feb 10 '16 at 20:58

bwbrowning

2,42742431

Is there a method in lodash to map over an array of arrays

I would like to do something like this so that it keeps the structure of the array.

def double(x) { return x*2 }



_([[1,2],[3,4]]).somemethod(double) == [[2,4],[6,8]]

javascript underscore.js lodash

edited Feb 25 '17 at 12:02

user663031

asked Feb 10 '16 at 20:58

bwbrowning

2,42742431

edited Feb 25 '17 at 12:02

user663031

asked Feb 10 '16 at 20:58

bwbrowning

2,42742431

edited Feb 25 '17 at 12:02

user663031

edited Feb 25 '17 at 12:02

user663031

edited Feb 25 '17 at 12:02

user663031

asked Feb 10 '16 at 20:58

bwbrowning

2,42742431

asked Feb 10 '16 at 20:58

bwbrowning

2,42742431

asked Feb 10 '16 at 20:58

bwbrowning

2,42742431

add a comment |

3 Answers
3

active

oldest

votes

You can make your code much cleaner with ES2015 arrow functions:

var array = [[1, 2], [3, 4]];

var double = x => x * 2;

var doubledArray = _.map( array, subarray => _.map( subarray, double ));

Using vanilla JS:

var array = [[1, 2], [3, 4]];

var double = x => x * 2;

var doubledArray = array.map( subarray => subarray.map( double ));

answered Feb 10 '16 at 21:09

TbWill4321

7,14411720

3

Assuming the target environment supports them and/or they transpile it with something like Babel.

– Mike Cluck
Feb 10 '16 at 21:17

2

arrow functions have nothing to do with his question.

– andygoestohollywood
Feb 23 '17 at 9:42

add a comment |

Just _.map it twice:

var array = [[1, 2], [3, 4]];

var doubledArray = _.map(array, function (nested) {

    return _.map(nested, function (element) {

        return element * 2;

    });

});

Or without lodash:

var doubledArray = array.map(function (nested) {

    return nested.map(function (element) {

        return element * 2;

    });

});

Furthermore, consider using es6 arrow functions:

var doubledArray = array.map(nested => nested.map(element => element * 2));

edited Feb 11 '16 at 6:28

answered Feb 10 '16 at 21:04

Radosław Miernik

2,43632231

add a comment |

It can be a kind of entangle:

var Coef = Array.apply(null, Array(3)).map(function(){return

Array.apply(null, Array(4)).map(function(){return 0})})

Nevertheless, it can be useful if you want to initialize an array in Gas

edited Nov 21 '18 at 2:49

Unheilig

12k165386

answered Nov 21 '18 at 2:28

manguel1980

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

You can make your code much cleaner with ES2015 arrow functions:

var array = [[1, 2], [3, 4]];

var double = x => x * 2;

var doubledArray = _.map( array, subarray => _.map( subarray, double ));

Using vanilla JS:

var array = [[1, 2], [3, 4]];

var double = x => x * 2;

var doubledArray = array.map( subarray => subarray.map( double ));

answered Feb 10 '16 at 21:09

TbWill4321

7,14411720

3

Assuming the target environment supports them and/or they transpile it with something like Babel.

– Mike Cluck
Feb 10 '16 at 21:17

2

arrow functions have nothing to do with his question.

– andygoestohollywood
Feb 23 '17 at 9:42

add a comment |

You can make your code much cleaner with ES2015 arrow functions:

var array = [[1, 2], [3, 4]];

var double = x => x * 2;

var doubledArray = _.map( array, subarray => _.map( subarray, double ));

Using vanilla JS:

var array = [[1, 2], [3, 4]];

var double = x => x * 2;

var doubledArray = array.map( subarray => subarray.map( double ));

answered Feb 10 '16 at 21:09

TbWill4321

7,14411720

3

Assuming the target environment supports them and/or they transpile it with something like Babel.

– Mike Cluck
Feb 10 '16 at 21:17

2

arrow functions have nothing to do with his question.

– andygoestohollywood
Feb 23 '17 at 9:42

add a comment |

You can make your code much cleaner with ES2015 arrow functions:

var array = [[1, 2], [3, 4]];

var double = x => x * 2;

var doubledArray = _.map( array, subarray => _.map( subarray, double ));

Using vanilla JS:

var array = [[1, 2], [3, 4]];

var double = x => x * 2;

var doubledArray = array.map( subarray => subarray.map( double ));

answered Feb 10 '16 at 21:09

TbWill4321

7,14411720

You can make your code much cleaner with ES2015 arrow functions:

var array = [[1, 2], [3, 4]];

var double = x => x * 2;

var doubledArray = _.map( array, subarray => _.map( subarray, double ));

Using vanilla JS:

var array = [[1, 2], [3, 4]];

var double = x => x * 2;

var doubledArray = array.map( subarray => subarray.map( double ));

answered Feb 10 '16 at 21:09

TbWill4321

7,14411720

answered Feb 10 '16 at 21:09

TbWill4321

7,14411720

answered Feb 10 '16 at 21:09

TbWill4321

7,14411720

answered Feb 10 '16 at 21:09

TbWill4321

7,14411720

3

Assuming the target environment supports them and/or they transpile it with something like Babel.

– Mike Cluck
Feb 10 '16 at 21:17

2

arrow functions have nothing to do with his question.

– andygoestohollywood
Feb 23 '17 at 9:42

add a comment |

3

Assuming the target environment supports them and/or they transpile it with something like Babel.

– Mike Cluck
Feb 10 '16 at 21:17

2

arrow functions have nothing to do with his question.

– andygoestohollywood
Feb 23 '17 at 9:42

Assuming the target environment supports them and/or they transpile it with something like Babel.

– Mike Cluck
Feb 10 '16 at 21:17

arrow functions have nothing to do with his question.

– andygoestohollywood
Feb 23 '17 at 9:42

add a comment |

Just _.map it twice:

var array = [[1, 2], [3, 4]];

var doubledArray = _.map(array, function (nested) {

    return _.map(nested, function (element) {

        return element * 2;

    });

});

Or without lodash:

var doubledArray = array.map(function (nested) {

    return nested.map(function (element) {

        return element * 2;

    });

});

Furthermore, consider using es6 arrow functions:

var doubledArray = array.map(nested => nested.map(element => element * 2));

edited Feb 11 '16 at 6:28

answered Feb 10 '16 at 21:04

Radosław Miernik

2,43632231

add a comment |

Just _.map it twice:

var array = [[1, 2], [3, 4]];

var doubledArray = _.map(array, function (nested) {

    return _.map(nested, function (element) {

        return element * 2;

    });

});

Or without lodash:

var doubledArray = array.map(function (nested) {

    return nested.map(function (element) {

        return element * 2;

    });

});

Furthermore, consider using es6 arrow functions:

var doubledArray = array.map(nested => nested.map(element => element * 2));

edited Feb 11 '16 at 6:28

answered Feb 10 '16 at 21:04

Radosław Miernik

2,43632231

add a comment |

Just _.map it twice:

var array = [[1, 2], [3, 4]];

var doubledArray = _.map(array, function (nested) {

    return _.map(nested, function (element) {

        return element * 2;

    });

});

Or without lodash:

var doubledArray = array.map(function (nested) {

    return nested.map(function (element) {

        return element * 2;

    });

});

Furthermore, consider using es6 arrow functions:

var doubledArray = array.map(nested => nested.map(element => element * 2));

edited Feb 11 '16 at 6:28

answered Feb 10 '16 at 21:04

Radosław Miernik

2,43632231

Just _.map it twice:

var array = [[1, 2], [3, 4]];

var doubledArray = _.map(array, function (nested) {

    return _.map(nested, function (element) {

        return element * 2;

    });

});

Or without lodash:

var doubledArray = array.map(function (nested) {

    return nested.map(function (element) {

        return element * 2;

    });

});

Furthermore, consider using es6 arrow functions:

var doubledArray = array.map(nested => nested.map(element => element * 2));

edited Feb 11 '16 at 6:28

answered Feb 10 '16 at 21:04

Radosław Miernik

2,43632231

edited Feb 11 '16 at 6:28

answered Feb 10 '16 at 21:04

Radosław Miernik

2,43632231

answered Feb 10 '16 at 21:04

Radosław Miernik

2,43632231

answered Feb 10 '16 at 21:04

Radosław Miernik

2,43632231

add a comment |

It can be a kind of entangle:

var Coef = Array.apply(null, Array(3)).map(function(){return

Array.apply(null, Array(4)).map(function(){return 0})})

Nevertheless, it can be useful if you want to initialize an array in Gas

edited Nov 21 '18 at 2:49

Unheilig

12k165386

answered Nov 21 '18 at 2:28

manguel1980

add a comment |

It can be a kind of entangle:

var Coef = Array.apply(null, Array(3)).map(function(){return

Array.apply(null, Array(4)).map(function(){return 0})})

Nevertheless, it can be useful if you want to initialize an array in Gas

edited Nov 21 '18 at 2:49

Unheilig

12k165386

answered Nov 21 '18 at 2:28

manguel1980

add a comment |

It can be a kind of entangle:

var Coef = Array.apply(null, Array(3)).map(function(){return

Array.apply(null, Array(4)).map(function(){return 0})})

Nevertheless, it can be useful if you want to initialize an array in Gas

edited Nov 21 '18 at 2:49

Unheilig

12k165386

answered Nov 21 '18 at 2:28

manguel1980

It can be a kind of entangle:

var Coef = Array.apply(null, Array(3)).map(function(){return

Array.apply(null, Array(4)).map(function(){return 0})})

Nevertheless, it can be useful if you want to initialize an array in Gas

edited Nov 21 '18 at 2:49

Unheilig

12k165386

answered Nov 21 '18 at 2:28

manguel1980

edited Nov 21 '18 at 2:49

Unheilig

12k165386

edited Nov 21 '18 at 2:49

Unheilig

12k165386

edited Nov 21 '18 at 2:49

Unheilig

12k165386

answered Nov 21 '18 at 2:28

manguel1980

answered Nov 21 '18 at 2:28

manguel1980

answered Nov 21 '18 at 2:28

manguel1980

add a comment |

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