Ordered Sequence to Set Definition
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From Why ordered sequences can be reduced to sets?
$$ (x,y):={{x},{x,y}}$$
What's the more general equation to convert ordered sequences to sets?
What about $(x, y, z, ...)$?
sequences-and-series elementary-set-theory
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add a comment |
$begingroup$
From Why ordered sequences can be reduced to sets?
$$ (x,y):={{x},{x,y}}$$
What's the more general equation to convert ordered sequences to sets?
What about $(x, y, z, ...)$?
sequences-and-series elementary-set-theory
$endgroup$
add a comment |
$begingroup$
From Why ordered sequences can be reduced to sets?
$$ (x,y):={{x},{x,y}}$$
What's the more general equation to convert ordered sequences to sets?
What about $(x, y, z, ...)$?
sequences-and-series elementary-set-theory
$endgroup$
From Why ordered sequences can be reduced to sets?
$$ (x,y):={{x},{x,y}}$$
What's the more general equation to convert ordered sequences to sets?
What about $(x, y, z, ...)$?
sequences-and-series elementary-set-theory
sequences-and-series elementary-set-theory
edited Jan 10 at 5:06
Andrés E. Caicedo
65.3k8158247
65.3k8158247
asked Jan 9 at 23:24
A_for_ AbacusA_for_ Abacus
955925
955925
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1 Answer
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Two options: either define $(x_1,x_2,ldots,x_n)$ inductively as $(x_1,(x_2,ldots,x_n))$, or define it as ${{x_1},{x_1,x_2},ldots,{x_1,ldots,x_n}}$, and define $(x_1,x_2,x_3,ldots)$, therefore, to be ${{x_1},{x_1,x_2},ldots,{x_1,ldots,x_n},ldots}$.
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ah, makes much more sense when I see the big picture.
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– A_for_ Abacus
Jan 9 at 23:36
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1 Answer
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1 Answer
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$begingroup$
Two options: either define $(x_1,x_2,ldots,x_n)$ inductively as $(x_1,(x_2,ldots,x_n))$, or define it as ${{x_1},{x_1,x_2},ldots,{x_1,ldots,x_n}}$, and define $(x_1,x_2,x_3,ldots)$, therefore, to be ${{x_1},{x_1,x_2},ldots,{x_1,ldots,x_n},ldots}$.
$endgroup$
$begingroup$
ah, makes much more sense when I see the big picture.
$endgroup$
– A_for_ Abacus
Jan 9 at 23:36
add a comment |
$begingroup$
Two options: either define $(x_1,x_2,ldots,x_n)$ inductively as $(x_1,(x_2,ldots,x_n))$, or define it as ${{x_1},{x_1,x_2},ldots,{x_1,ldots,x_n}}$, and define $(x_1,x_2,x_3,ldots)$, therefore, to be ${{x_1},{x_1,x_2},ldots,{x_1,ldots,x_n},ldots}$.
$endgroup$
$begingroup$
ah, makes much more sense when I see the big picture.
$endgroup$
– A_for_ Abacus
Jan 9 at 23:36
add a comment |
$begingroup$
Two options: either define $(x_1,x_2,ldots,x_n)$ inductively as $(x_1,(x_2,ldots,x_n))$, or define it as ${{x_1},{x_1,x_2},ldots,{x_1,ldots,x_n}}$, and define $(x_1,x_2,x_3,ldots)$, therefore, to be ${{x_1},{x_1,x_2},ldots,{x_1,ldots,x_n},ldots}$.
$endgroup$
Two options: either define $(x_1,x_2,ldots,x_n)$ inductively as $(x_1,(x_2,ldots,x_n))$, or define it as ${{x_1},{x_1,x_2},ldots,{x_1,ldots,x_n}}$, and define $(x_1,x_2,x_3,ldots)$, therefore, to be ${{x_1},{x_1,x_2},ldots,{x_1,ldots,x_n},ldots}$.
answered Jan 9 at 23:27
user3482749user3482749
4,256919
4,256919
$begingroup$
ah, makes much more sense when I see the big picture.
$endgroup$
– A_for_ Abacus
Jan 9 at 23:36
add a comment |
$begingroup$
ah, makes much more sense when I see the big picture.
$endgroup$
– A_for_ Abacus
Jan 9 at 23:36
$begingroup$
ah, makes much more sense when I see the big picture.
$endgroup$
– A_for_ Abacus
Jan 9 at 23:36
$begingroup$
ah, makes much more sense when I see the big picture.
$endgroup$
– A_for_ Abacus
Jan 9 at 23:36
add a comment |
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