How to declare a variable range to a spreadsheet in google scripts












0















I can't set a variable to return the number to the last row under the K column in google sheets. The code fails on the last line - .setValues(exampleText) where I have already defined exampleText as a variable.



I have used different methods of setting variables including setting a variable for a column.



I get the following error: "Cannot find method getRange(number,number)."



The following code works solved by @TheMaster



var ss = SpreadsheetApp.getActiveSpreadsheet()

var column = 11

var lastRow = ss.getLastRow();

range = ss.getActiveSheet().getRange(lastRow,column);
range.setValue(exampletext)









share|improve this question




















  • 1





    getRange(row,column) type syntax only accepts numbers NOT strings.

    – TheMaster
    Dec 31 '18 at 12:43











  • You need to review the method signatures. These appear in the autocomplete popup (while writing code in the editor) and have more detail explained on the reference documentation website (use the Help menu).

    – tehhowch
    Dec 31 '18 at 12:55











  • I have edited my code to include column = 11 and replaced k with column but still doesn't work. I don't understand why? @TheMaster I have already checked documentation before posting but don't know how to proceed.

    – Jonathan Harker
    Dec 31 '18 at 12:59








  • 3





    Only getRange(string) is available on Spreadsheet(ss). So, you can use ss.getRange('Sheet1!A1:B4'). getRange(number,number) is only available on sheet. ss.getActiveSheet().getRange(1,4)

    – TheMaster
    Dec 31 '18 at 13:42








  • 1





    Thanks @TheMaster I'm new at interacting here - I'll keep these points in mind for next time - have a great day.

    – Jonathan Harker
    Jan 1 at 13:06
















0















I can't set a variable to return the number to the last row under the K column in google sheets. The code fails on the last line - .setValues(exampleText) where I have already defined exampleText as a variable.



I have used different methods of setting variables including setting a variable for a column.



I get the following error: "Cannot find method getRange(number,number)."



The following code works solved by @TheMaster



var ss = SpreadsheetApp.getActiveSpreadsheet()

var column = 11

var lastRow = ss.getLastRow();

range = ss.getActiveSheet().getRange(lastRow,column);
range.setValue(exampletext)









share|improve this question




















  • 1





    getRange(row,column) type syntax only accepts numbers NOT strings.

    – TheMaster
    Dec 31 '18 at 12:43











  • You need to review the method signatures. These appear in the autocomplete popup (while writing code in the editor) and have more detail explained on the reference documentation website (use the Help menu).

    – tehhowch
    Dec 31 '18 at 12:55











  • I have edited my code to include column = 11 and replaced k with column but still doesn't work. I don't understand why? @TheMaster I have already checked documentation before posting but don't know how to proceed.

    – Jonathan Harker
    Dec 31 '18 at 12:59








  • 3





    Only getRange(string) is available on Spreadsheet(ss). So, you can use ss.getRange('Sheet1!A1:B4'). getRange(number,number) is only available on sheet. ss.getActiveSheet().getRange(1,4)

    – TheMaster
    Dec 31 '18 at 13:42








  • 1





    Thanks @TheMaster I'm new at interacting here - I'll keep these points in mind for next time - have a great day.

    – Jonathan Harker
    Jan 1 at 13:06














0












0








0


0






I can't set a variable to return the number to the last row under the K column in google sheets. The code fails on the last line - .setValues(exampleText) where I have already defined exampleText as a variable.



I have used different methods of setting variables including setting a variable for a column.



I get the following error: "Cannot find method getRange(number,number)."



The following code works solved by @TheMaster



var ss = SpreadsheetApp.getActiveSpreadsheet()

var column = 11

var lastRow = ss.getLastRow();

range = ss.getActiveSheet().getRange(lastRow,column);
range.setValue(exampletext)









share|improve this question
















I can't set a variable to return the number to the last row under the K column in google sheets. The code fails on the last line - .setValues(exampleText) where I have already defined exampleText as a variable.



I have used different methods of setting variables including setting a variable for a column.



I get the following error: "Cannot find method getRange(number,number)."



The following code works solved by @TheMaster



var ss = SpreadsheetApp.getActiveSpreadsheet()

var column = 11

var lastRow = ss.getLastRow();

range = ss.getActiveSheet().getRange(lastRow,column);
range.setValue(exampletext)






google-apps-script






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 31 '18 at 13:51







Jonathan Harker

















asked Dec 31 '18 at 12:16









Jonathan HarkerJonathan Harker

76




76








  • 1





    getRange(row,column) type syntax only accepts numbers NOT strings.

    – TheMaster
    Dec 31 '18 at 12:43











  • You need to review the method signatures. These appear in the autocomplete popup (while writing code in the editor) and have more detail explained on the reference documentation website (use the Help menu).

    – tehhowch
    Dec 31 '18 at 12:55











  • I have edited my code to include column = 11 and replaced k with column but still doesn't work. I don't understand why? @TheMaster I have already checked documentation before posting but don't know how to proceed.

    – Jonathan Harker
    Dec 31 '18 at 12:59








  • 3





    Only getRange(string) is available on Spreadsheet(ss). So, you can use ss.getRange('Sheet1!A1:B4'). getRange(number,number) is only available on sheet. ss.getActiveSheet().getRange(1,4)

    – TheMaster
    Dec 31 '18 at 13:42








  • 1





    Thanks @TheMaster I'm new at interacting here - I'll keep these points in mind for next time - have a great day.

    – Jonathan Harker
    Jan 1 at 13:06














  • 1





    getRange(row,column) type syntax only accepts numbers NOT strings.

    – TheMaster
    Dec 31 '18 at 12:43











  • You need to review the method signatures. These appear in the autocomplete popup (while writing code in the editor) and have more detail explained on the reference documentation website (use the Help menu).

    – tehhowch
    Dec 31 '18 at 12:55











  • I have edited my code to include column = 11 and replaced k with column but still doesn't work. I don't understand why? @TheMaster I have already checked documentation before posting but don't know how to proceed.

    – Jonathan Harker
    Dec 31 '18 at 12:59








  • 3





    Only getRange(string) is available on Spreadsheet(ss). So, you can use ss.getRange('Sheet1!A1:B4'). getRange(number,number) is only available on sheet. ss.getActiveSheet().getRange(1,4)

    – TheMaster
    Dec 31 '18 at 13:42








  • 1





    Thanks @TheMaster I'm new at interacting here - I'll keep these points in mind for next time - have a great day.

    – Jonathan Harker
    Jan 1 at 13:06








1




1





getRange(row,column) type syntax only accepts numbers NOT strings.

– TheMaster
Dec 31 '18 at 12:43





getRange(row,column) type syntax only accepts numbers NOT strings.

– TheMaster
Dec 31 '18 at 12:43













You need to review the method signatures. These appear in the autocomplete popup (while writing code in the editor) and have more detail explained on the reference documentation website (use the Help menu).

– tehhowch
Dec 31 '18 at 12:55





You need to review the method signatures. These appear in the autocomplete popup (while writing code in the editor) and have more detail explained on the reference documentation website (use the Help menu).

– tehhowch
Dec 31 '18 at 12:55













I have edited my code to include column = 11 and replaced k with column but still doesn't work. I don't understand why? @TheMaster I have already checked documentation before posting but don't know how to proceed.

– Jonathan Harker
Dec 31 '18 at 12:59







I have edited my code to include column = 11 and replaced k with column but still doesn't work. I don't understand why? @TheMaster I have already checked documentation before posting but don't know how to proceed.

– Jonathan Harker
Dec 31 '18 at 12:59






3




3





Only getRange(string) is available on Spreadsheet(ss). So, you can use ss.getRange('Sheet1!A1:B4'). getRange(number,number) is only available on sheet. ss.getActiveSheet().getRange(1,4)

– TheMaster
Dec 31 '18 at 13:42







Only getRange(string) is available on Spreadsheet(ss). So, you can use ss.getRange('Sheet1!A1:B4'). getRange(number,number) is only available on sheet. ss.getActiveSheet().getRange(1,4)

– TheMaster
Dec 31 '18 at 13:42






1




1





Thanks @TheMaster I'm new at interacting here - I'll keep these points in mind for next time - have a great day.

– Jonathan Harker
Jan 1 at 13:06





Thanks @TheMaster I'm new at interacting here - I'll keep these points in mind for next time - have a great day.

– Jonathan Harker
Jan 1 at 13:06












1 Answer
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getRange is a method that's available both on Spreadsheet class and Sheet class.



However, only getRange(string) is available on Spreadsheet(ss). So, you can use ss.getRange('Sheet1!A1:B4').



And getRange(number,number) is only available on sheet. So, You can use ss.getActiveSheet().getRange(1,4). Sheet class also accepts other variations of this method, but Spreadsheet class doesn't, which only accepts string as the only parameter.






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    getRange is a method that's available both on Spreadsheet class and Sheet class.



    However, only getRange(string) is available on Spreadsheet(ss). So, you can use ss.getRange('Sheet1!A1:B4').



    And getRange(number,number) is only available on sheet. So, You can use ss.getActiveSheet().getRange(1,4). Sheet class also accepts other variations of this method, but Spreadsheet class doesn't, which only accepts string as the only parameter.






    share|improve this answer






























      2














      getRange is a method that's available both on Spreadsheet class and Sheet class.



      However, only getRange(string) is available on Spreadsheet(ss). So, you can use ss.getRange('Sheet1!A1:B4').



      And getRange(number,number) is only available on sheet. So, You can use ss.getActiveSheet().getRange(1,4). Sheet class also accepts other variations of this method, but Spreadsheet class doesn't, which only accepts string as the only parameter.






      share|improve this answer




























        2












        2








        2







        getRange is a method that's available both on Spreadsheet class and Sheet class.



        However, only getRange(string) is available on Spreadsheet(ss). So, you can use ss.getRange('Sheet1!A1:B4').



        And getRange(number,number) is only available on sheet. So, You can use ss.getActiveSheet().getRange(1,4). Sheet class also accepts other variations of this method, but Spreadsheet class doesn't, which only accepts string as the only parameter.






        share|improve this answer















        getRange is a method that's available both on Spreadsheet class and Sheet class.



        However, only getRange(string) is available on Spreadsheet(ss). So, you can use ss.getRange('Sheet1!A1:B4').



        And getRange(number,number) is only available on sheet. So, You can use ss.getActiveSheet().getRange(1,4). Sheet class also accepts other variations of this method, but Spreadsheet class doesn't, which only accepts string as the only parameter.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Jan 1 at 9:23

























        answered Jan 1 at 9:17









        TheMasterTheMaster

        10.4k3836




        10.4k3836
































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