Roots of equation involving both polynomials and trigonometric functions












1












$begingroup$


I have to determine for which values of $x$ that the velocity vector is orthogonal to the acceleration vector, the position is given by:



$(3 cos(t), - sin(3t), 2t^3 - t^2)$,



I then use that $u cdot v = 0$ if $u$ and $v$ is orthogonal. The dot product of the acceleration and velocity gives the following equation (if I have done the differentiation correctly):



$9sinleft(tright)cosleft(tright)-27cosleft(3tright)sinleft(3tright)+4tleft(18t^2-9t+1right) = 0$.



$t = 0$ (or position $x = (3,0,0)$) is clearly a root but i can't find the other two. Is there a general way of computing roots of this sort of function analytically?










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$endgroup$








  • 1




    $begingroup$
    Except in very special cases, equations involving both trig functions and polynomials cannot be solved explicitly in the sense you probably intend. Are you SURE this is not a calculator exercise, where you solve by the use of a graphing calculator?
    $endgroup$
    – Dave L. Renfro
    Jan 21 at 14:15










  • $begingroup$
    @DaveL.Renfro I had a small typo in the equation, it is corrected now. But yes, this was given to students as a question in multivariate calculus on a test.
    $endgroup$
    – Loggoman
    Jan 21 at 14:19






  • 1




    $begingroup$
    @Blue You are correct, thanks.
    $endgroup$
    – Loggoman
    Jan 21 at 14:33










  • $begingroup$
    But yes, this was given to students as a question in multivariate calculus on a test. --- Were calculators allowed to be used on the test?
    $endgroup$
    – Dave L. Renfro
    Jan 21 at 14:46










  • $begingroup$
    @DaveL.Renfro No, only pencil and eraser.
    $endgroup$
    – Loggoman
    Jan 21 at 14:50
















1












$begingroup$


I have to determine for which values of $x$ that the velocity vector is orthogonal to the acceleration vector, the position is given by:



$(3 cos(t), - sin(3t), 2t^3 - t^2)$,



I then use that $u cdot v = 0$ if $u$ and $v$ is orthogonal. The dot product of the acceleration and velocity gives the following equation (if I have done the differentiation correctly):



$9sinleft(tright)cosleft(tright)-27cosleft(3tright)sinleft(3tright)+4tleft(18t^2-9t+1right) = 0$.



$t = 0$ (or position $x = (3,0,0)$) is clearly a root but i can't find the other two. Is there a general way of computing roots of this sort of function analytically?










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    Except in very special cases, equations involving both trig functions and polynomials cannot be solved explicitly in the sense you probably intend. Are you SURE this is not a calculator exercise, where you solve by the use of a graphing calculator?
    $endgroup$
    – Dave L. Renfro
    Jan 21 at 14:15










  • $begingroup$
    @DaveL.Renfro I had a small typo in the equation, it is corrected now. But yes, this was given to students as a question in multivariate calculus on a test.
    $endgroup$
    – Loggoman
    Jan 21 at 14:19






  • 1




    $begingroup$
    @Blue You are correct, thanks.
    $endgroup$
    – Loggoman
    Jan 21 at 14:33










  • $begingroup$
    But yes, this was given to students as a question in multivariate calculus on a test. --- Were calculators allowed to be used on the test?
    $endgroup$
    – Dave L. Renfro
    Jan 21 at 14:46










  • $begingroup$
    @DaveL.Renfro No, only pencil and eraser.
    $endgroup$
    – Loggoman
    Jan 21 at 14:50














1












1








1





$begingroup$


I have to determine for which values of $x$ that the velocity vector is orthogonal to the acceleration vector, the position is given by:



$(3 cos(t), - sin(3t), 2t^3 - t^2)$,



I then use that $u cdot v = 0$ if $u$ and $v$ is orthogonal. The dot product of the acceleration and velocity gives the following equation (if I have done the differentiation correctly):



$9sinleft(tright)cosleft(tright)-27cosleft(3tright)sinleft(3tright)+4tleft(18t^2-9t+1right) = 0$.



$t = 0$ (or position $x = (3,0,0)$) is clearly a root but i can't find the other two. Is there a general way of computing roots of this sort of function analytically?










share|cite|improve this question











$endgroup$




I have to determine for which values of $x$ that the velocity vector is orthogonal to the acceleration vector, the position is given by:



$(3 cos(t), - sin(3t), 2t^3 - t^2)$,



I then use that $u cdot v = 0$ if $u$ and $v$ is orthogonal. The dot product of the acceleration and velocity gives the following equation (if I have done the differentiation correctly):



$9sinleft(tright)cosleft(tright)-27cosleft(3tright)sinleft(3tright)+4tleft(18t^2-9t+1right) = 0$.



$t = 0$ (or position $x = (3,0,0)$) is clearly a root but i can't find the other two. Is there a general way of computing roots of this sort of function analytically?







real-analysis trigonometry roots






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 21 at 14:52









Andreas

8,2431137




8,2431137










asked Jan 21 at 14:06









LoggomanLoggoman

63




63








  • 1




    $begingroup$
    Except in very special cases, equations involving both trig functions and polynomials cannot be solved explicitly in the sense you probably intend. Are you SURE this is not a calculator exercise, where you solve by the use of a graphing calculator?
    $endgroup$
    – Dave L. Renfro
    Jan 21 at 14:15










  • $begingroup$
    @DaveL.Renfro I had a small typo in the equation, it is corrected now. But yes, this was given to students as a question in multivariate calculus on a test.
    $endgroup$
    – Loggoman
    Jan 21 at 14:19






  • 1




    $begingroup$
    @Blue You are correct, thanks.
    $endgroup$
    – Loggoman
    Jan 21 at 14:33










  • $begingroup$
    But yes, this was given to students as a question in multivariate calculus on a test. --- Were calculators allowed to be used on the test?
    $endgroup$
    – Dave L. Renfro
    Jan 21 at 14:46










  • $begingroup$
    @DaveL.Renfro No, only pencil and eraser.
    $endgroup$
    – Loggoman
    Jan 21 at 14:50














  • 1




    $begingroup$
    Except in very special cases, equations involving both trig functions and polynomials cannot be solved explicitly in the sense you probably intend. Are you SURE this is not a calculator exercise, where you solve by the use of a graphing calculator?
    $endgroup$
    – Dave L. Renfro
    Jan 21 at 14:15










  • $begingroup$
    @DaveL.Renfro I had a small typo in the equation, it is corrected now. But yes, this was given to students as a question in multivariate calculus on a test.
    $endgroup$
    – Loggoman
    Jan 21 at 14:19






  • 1




    $begingroup$
    @Blue You are correct, thanks.
    $endgroup$
    – Loggoman
    Jan 21 at 14:33










  • $begingroup$
    But yes, this was given to students as a question in multivariate calculus on a test. --- Were calculators allowed to be used on the test?
    $endgroup$
    – Dave L. Renfro
    Jan 21 at 14:46










  • $begingroup$
    @DaveL.Renfro No, only pencil and eraser.
    $endgroup$
    – Loggoman
    Jan 21 at 14:50








1




1




$begingroup$
Except in very special cases, equations involving both trig functions and polynomials cannot be solved explicitly in the sense you probably intend. Are you SURE this is not a calculator exercise, where you solve by the use of a graphing calculator?
$endgroup$
– Dave L. Renfro
Jan 21 at 14:15




$begingroup$
Except in very special cases, equations involving both trig functions and polynomials cannot be solved explicitly in the sense you probably intend. Are you SURE this is not a calculator exercise, where you solve by the use of a graphing calculator?
$endgroup$
– Dave L. Renfro
Jan 21 at 14:15












$begingroup$
@DaveL.Renfro I had a small typo in the equation, it is corrected now. But yes, this was given to students as a question in multivariate calculus on a test.
$endgroup$
– Loggoman
Jan 21 at 14:19




$begingroup$
@DaveL.Renfro I had a small typo in the equation, it is corrected now. But yes, this was given to students as a question in multivariate calculus on a test.
$endgroup$
– Loggoman
Jan 21 at 14:19




1




1




$begingroup$
@Blue You are correct, thanks.
$endgroup$
– Loggoman
Jan 21 at 14:33




$begingroup$
@Blue You are correct, thanks.
$endgroup$
– Loggoman
Jan 21 at 14:33












$begingroup$
But yes, this was given to students as a question in multivariate calculus on a test. --- Were calculators allowed to be used on the test?
$endgroup$
– Dave L. Renfro
Jan 21 at 14:46




$begingroup$
But yes, this was given to students as a question in multivariate calculus on a test. --- Were calculators allowed to be used on the test?
$endgroup$
– Dave L. Renfro
Jan 21 at 14:46












$begingroup$
@DaveL.Renfro No, only pencil and eraser.
$endgroup$
– Loggoman
Jan 21 at 14:50




$begingroup$
@DaveL.Renfro No, only pencil and eraser.
$endgroup$
– Loggoman
Jan 21 at 14:50










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