What was midnight yesterday as an epoch time?

I'm trying to get my head around the datetime module. I know the time now as an epoch and the time an event last happened (as an epoch time). What I need to do is figure out whether that event happened between midnight and midnight of yesterday.

t = time.time() # is now

t2 = 1234567890 # some arbitrary time from my log

24 hours ago is t - 86400, but how can I round that up and down to midnight. I'm having real trouble finding a way to get timestamps in and out of datetime or then manipulating a datetime to set the time.

edited Aug 5 '14 at 7:00

Martijn Pieters♦

717k13925052319

asked Oct 25 '13 at 16:13

t0mmyt

1831312

1

Sounds like you may have to convert it to regular time somewhere in there, since dividers like days/midnight/etc are not a part of epoch times.

– Gray
Oct 25 '13 at 16:15

add a comment |

t = time.time() # is now

t2 = 1234567890 # some arbitrary time from my log

edited Aug 5 '14 at 7:00

Martijn Pieters♦

717k13925052319

asked Oct 25 '13 at 16:13

t0mmyt

1831312

1

Sounds like you may have to convert it to regular time somewhere in there, since dividers like days/midnight/etc are not a part of epoch times.

– Gray
Oct 25 '13 at 16:15

add a comment |

t = time.time() # is now

t2 = 1234567890 # some arbitrary time from my log

edited Aug 5 '14 at 7:00

Martijn Pieters♦

717k13925052319

asked Oct 25 '13 at 16:13

t0mmyt

1831312

t = time.time() # is now

t2 = 1234567890 # some arbitrary time from my log

python datetime

edited Aug 5 '14 at 7:00

Martijn Pieters♦

717k13925052319

asked Oct 25 '13 at 16:13

t0mmyt

1831312

edited Aug 5 '14 at 7:00

Martijn Pieters♦

717k13925052319

asked Oct 25 '13 at 16:13

t0mmyt

1831312

edited Aug 5 '14 at 7:00

Martijn Pieters♦

717k13925052319

edited Aug 5 '14 at 7:00

Martijn Pieters♦

717k13925052319

edited Aug 5 '14 at 7:00

Martijn Pieters♦

717k13925052319

asked Oct 25 '13 at 16:13

t0mmyt

1831312

asked Oct 25 '13 at 16:13

t0mmyt

1831312

asked Oct 25 '13 at 16:13

t0mmyt

1831312

1

Sounds like you may have to convert it to regular time somewhere in there, since dividers like days/midnight/etc are not a part of epoch times.

– Gray
Oct 25 '13 at 16:15

add a comment |

1

Sounds like you may have to convert it to regular time somewhere in there, since dividers like days/midnight/etc are not a part of epoch times.

– Gray
Oct 25 '13 at 16:15

Sounds like you may have to convert it to regular time somewhere in there, since dividers like days/midnight/etc are not a part of epoch times.

– Gray
Oct 25 '13 at 16:15

add a comment |

5 Answers
5

active

oldest

votes

In the Middle of the Night

Generating the last midnight is easy:

from datetime import datetime, time



midnight = datetime.combine(datetime.today(), time.min)

That combines today's date (you can use date() or a datetime() instance, your pick), together with time.min to form a datetime object at midnight.

Yesterday

With a timedelta() you can calculate the previous midnight:

from datetime import timedelta



yesterday_midnight = midnight - timedelta(days=1)

That Was Yesterday

Now test if your timestamp is in between these two points:

timestamp = datetime.fromtimestamp(some_timestamp_from_your_log)

if yesterday_midnight <= timestamp < midnight:

    # this happened between 00:00:00 and 23:59:59 yesterday

All Together Now

Combined into one function:

from datetime import datetime, time, timedelta



def is_yesterday(timestamp):

    midnight = datetime.combine(datetime.today(), time.min)

    yesterday_midnight = midnight - timedelta(days=1)

    return yesterday_midnight <= timestamp < midnight:



if is_yesterday(datetime.fromtimestamp(some_timestamp_from_your_log)):

    # ...

edited Mar 29 '18 at 17:48

answered Oct 25 '13 at 16:21

Martijn Pieters♦

717k13925052319

How can you tell when midnight is without specifying the timezone?

– sdanzig
Oct 25 '13 at 16:28

@sdanzig: By default, the datetime module is not timezone aware. It can return local or UTC times, as provided by the OS. This code uses local time.

– Martijn Pieters♦
Oct 25 '13 at 16:29

1

In this case it's not an issue as everything runs in UTC.

– t0mmyt
Oct 25 '13 at 16:30

1

If everything runs UTC, then not only is it fine, but there's a smart developer behind it. Just to be aware though, the concept of "yesterday" will only apply to what England considers yesterday. If you wanted to do something based on the timing at the site where the logs were written, for instance, you'd have to specify the timezone accordingly.

– sdanzig
Oct 25 '13 at 16:34

add a comment |

Given such a timestamp, you can use divmod to compute the number of days since the epoch (which you don't care about), and how many seconds are leftover (which you do):

days_since, remaining_seconds = divmod(t, 24*3600)  # Divide by number of seconds in one day

Then, you subtract the leftover seconds from your original timestamp, which produces midnight
of the current day.

t -= remaining_seconds

Rounding up is as simple as shifting your target timestamp forward exactly one day before rounding down.

tomorrow_t = t + 24 * 3600

days_since, remaining_seconds = divmod(tomorrow_t, 24*3600)

t = tomorrow_t - remaining_seconds

answered Oct 25 '13 at 16:36

chepner

255k34243337

I thought about that approach, I was actually just going to mod 86400, but then I remembered leap seconds.

– t0mmyt
Oct 25 '13 at 16:45

1

These timestamps are not affected by leap seconds. When a leap second occurs, the UNIX epoch timestamp simply repeats, so you are guaranteed to have 86400 seconds per day. Repeating a timestamp is just another arbitrary label for the leap second, like 23:59:60 is an arbitrary label for the leap second between 23:59:59 and 00:00:00 (or whenever leap seconds get applied).

– chepner
Oct 25 '13 at 17:02

add a comment |

In my estimation, many date and time manipulations are easier to do, and to understand, using the arrow library. This is one of them.

Create an arbitrary date and time.

>>> import arrow

>>> arbitrary = arrow.get(2017,8,16,11,5)

Calculate midnight_yesterday: first, midnight of arbitrary as its 'day' floor; then shift this back by one day. Display the result.

>>> midnight_yesterday = arbitrary.floor('day').shift(days=-1)

>>> midnight_yesterday 

<Arrow [2017-08-15T00:00:00+00:00]>

Use timestamp for the desired overall result, for Python 3.3+.

>>> midnight_yesterday.datetime.timestamp()

1502755200.0

Or use this expression for Python 2.7. (Credit: https://stackoverflow.com/a/11743262/131187 for the latter two expressions.)

>>> (midnight_yesterday-arrow.get(1970,1,1)).total_seconds()

1502755200.0

answered Aug 29 '17 at 16:29

Bill Bell

15.7k42642

add a comment |

You can use this code:

import time



seconds_of_day = 24 * 60 * 60  # 86400

last_midnight = (round(time.time()) // seconds_of_day) * seconds_of_day

yesterday_last_midnight = last_midnight - seconds_of_day

answered Jan 1 at 10:10

Mastisa

1,0962922

add a comment |

Midnight at the start of today is:

midnight = (int(time.time() // 86400)) * 86400

so yesterday's midnight is:

midnight = (int(time.time() // 86400)) * 86400 - 86400

edited Jan 2 at 5:50

Mastisa

1,0962922

answered Dec 30 '18 at 17:36

ggemmill

You must use // instead of %

– Mastisa
Jan 1 at 10:10

Mastisa - many thanks for the correction; I was about to make it myself.

– ggemmill
Jan 1 at 16:34

add a comment |

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5 Answers
5

active

oldest

votes

5 Answers
5

active

oldest

votes

In the Middle of the Night

Generating the last midnight is easy:

from datetime import datetime, time



midnight = datetime.combine(datetime.today(), time.min)

That combines today's date (you can use date() or a datetime() instance, your pick), together with time.min to form a datetime object at midnight.

Yesterday

With a timedelta() you can calculate the previous midnight:

from datetime import timedelta



yesterday_midnight = midnight - timedelta(days=1)

That Was Yesterday

Now test if your timestamp is in between these two points:

timestamp = datetime.fromtimestamp(some_timestamp_from_your_log)

if yesterday_midnight <= timestamp < midnight:

    # this happened between 00:00:00 and 23:59:59 yesterday

All Together Now

Combined into one function:

from datetime import datetime, time, timedelta



def is_yesterday(timestamp):

    midnight = datetime.combine(datetime.today(), time.min)

    yesterday_midnight = midnight - timedelta(days=1)

    return yesterday_midnight <= timestamp < midnight:



if is_yesterday(datetime.fromtimestamp(some_timestamp_from_your_log)):

    # ...

edited Mar 29 '18 at 17:48

answered Oct 25 '13 at 16:21

Martijn Pieters♦

717k13925052319

How can you tell when midnight is without specifying the timezone?

– sdanzig
Oct 25 '13 at 16:28

@sdanzig: By default, the datetime module is not timezone aware. It can return local or UTC times, as provided by the OS. This code uses local time.

– Martijn Pieters♦
Oct 25 '13 at 16:29

1

In this case it's not an issue as everything runs in UTC.

– t0mmyt
Oct 25 '13 at 16:30

1

If everything runs UTC, then not only is it fine, but there's a smart developer behind it. Just to be aware though, the concept of "yesterday" will only apply to what England considers yesterday. If you wanted to do something based on the timing at the site where the logs were written, for instance, you'd have to specify the timezone accordingly.

– sdanzig
Oct 25 '13 at 16:34

add a comment |

In the Middle of the Night

Generating the last midnight is easy:

from datetime import datetime, time



midnight = datetime.combine(datetime.today(), time.min)

That combines today's date (you can use date() or a datetime() instance, your pick), together with time.min to form a datetime object at midnight.

Yesterday

With a timedelta() you can calculate the previous midnight:

from datetime import timedelta



yesterday_midnight = midnight - timedelta(days=1)

That Was Yesterday

Now test if your timestamp is in between these two points:

timestamp = datetime.fromtimestamp(some_timestamp_from_your_log)

if yesterday_midnight <= timestamp < midnight:

    # this happened between 00:00:00 and 23:59:59 yesterday

All Together Now

Combined into one function:

from datetime import datetime, time, timedelta



def is_yesterday(timestamp):

    midnight = datetime.combine(datetime.today(), time.min)

    yesterday_midnight = midnight - timedelta(days=1)

    return yesterday_midnight <= timestamp < midnight:



if is_yesterday(datetime.fromtimestamp(some_timestamp_from_your_log)):

    # ...

edited Mar 29 '18 at 17:48

answered Oct 25 '13 at 16:21

Martijn Pieters♦

717k13925052319

How can you tell when midnight is without specifying the timezone?

– sdanzig
Oct 25 '13 at 16:28

@sdanzig: By default, the datetime module is not timezone aware. It can return local or UTC times, as provided by the OS. This code uses local time.

– Martijn Pieters♦
Oct 25 '13 at 16:29

1

In this case it's not an issue as everything runs in UTC.

– t0mmyt
Oct 25 '13 at 16:30

1

If everything runs UTC, then not only is it fine, but there's a smart developer behind it. Just to be aware though, the concept of "yesterday" will only apply to what England considers yesterday. If you wanted to do something based on the timing at the site where the logs were written, for instance, you'd have to specify the timezone accordingly.

– sdanzig
Oct 25 '13 at 16:34

add a comment |

In the Middle of the Night

Generating the last midnight is easy:

from datetime import datetime, time



midnight = datetime.combine(datetime.today(), time.min)

That combines today's date (you can use date() or a datetime() instance, your pick), together with time.min to form a datetime object at midnight.

Yesterday

With a timedelta() you can calculate the previous midnight:

from datetime import timedelta



yesterday_midnight = midnight - timedelta(days=1)

That Was Yesterday

Now test if your timestamp is in between these two points:

timestamp = datetime.fromtimestamp(some_timestamp_from_your_log)

if yesterday_midnight <= timestamp < midnight:

    # this happened between 00:00:00 and 23:59:59 yesterday

All Together Now

Combined into one function:

from datetime import datetime, time, timedelta



def is_yesterday(timestamp):

    midnight = datetime.combine(datetime.today(), time.min)

    yesterday_midnight = midnight - timedelta(days=1)

    return yesterday_midnight <= timestamp < midnight:



if is_yesterday(datetime.fromtimestamp(some_timestamp_from_your_log)):

    # ...

edited Mar 29 '18 at 17:48

answered Oct 25 '13 at 16:21

Martijn Pieters♦

717k13925052319

In the Middle of the Night

Generating the last midnight is easy:

from datetime import datetime, time



midnight = datetime.combine(datetime.today(), time.min)

That combines today's date (you can use date() or a datetime() instance, your pick), together with time.min to form a datetime object at midnight.

Yesterday

With a timedelta() you can calculate the previous midnight:

from datetime import timedelta



yesterday_midnight = midnight - timedelta(days=1)

That Was Yesterday

Now test if your timestamp is in between these two points:

timestamp = datetime.fromtimestamp(some_timestamp_from_your_log)

if yesterday_midnight <= timestamp < midnight:

    # this happened between 00:00:00 and 23:59:59 yesterday

All Together Now

Combined into one function:

from datetime import datetime, time, timedelta



def is_yesterday(timestamp):

    midnight = datetime.combine(datetime.today(), time.min)

    yesterday_midnight = midnight - timedelta(days=1)

    return yesterday_midnight <= timestamp < midnight:



if is_yesterday(datetime.fromtimestamp(some_timestamp_from_your_log)):

    # ...

edited Mar 29 '18 at 17:48

answered Oct 25 '13 at 16:21

Martijn Pieters♦

717k13925052319

edited Mar 29 '18 at 17:48

answered Oct 25 '13 at 16:21

Martijn Pieters♦

717k13925052319

answered Oct 25 '13 at 16:21

Martijn Pieters♦

717k13925052319

answered Oct 25 '13 at 16:21

Martijn Pieters♦

717k13925052319

How can you tell when midnight is without specifying the timezone?

– sdanzig
Oct 25 '13 at 16:28

@sdanzig: By default, the datetime module is not timezone aware. It can return local or UTC times, as provided by the OS. This code uses local time.

– Martijn Pieters♦
Oct 25 '13 at 16:29

1

In this case it's not an issue as everything runs in UTC.

– t0mmyt
Oct 25 '13 at 16:30

1

If everything runs UTC, then not only is it fine, but there's a smart developer behind it. Just to be aware though, the concept of "yesterday" will only apply to what England considers yesterday. If you wanted to do something based on the timing at the site where the logs were written, for instance, you'd have to specify the timezone accordingly.

– sdanzig
Oct 25 '13 at 16:34

add a comment |

How can you tell when midnight is without specifying the timezone?

– sdanzig
Oct 25 '13 at 16:28

@sdanzig: By default, the datetime module is not timezone aware. It can return local or UTC times, as provided by the OS. This code uses local time.

– Martijn Pieters♦
Oct 25 '13 at 16:29

1

In this case it's not an issue as everything runs in UTC.

– t0mmyt
Oct 25 '13 at 16:30

1

If everything runs UTC, then not only is it fine, but there's a smart developer behind it. Just to be aware though, the concept of "yesterday" will only apply to what England considers yesterday. If you wanted to do something based on the timing at the site where the logs were written, for instance, you'd have to specify the timezone accordingly.

– sdanzig
Oct 25 '13 at 16:34

How can you tell when midnight is without specifying the timezone?

– sdanzig
Oct 25 '13 at 16:28

@sdanzig: By default, the datetime module is not timezone aware. It can return local or UTC times, as provided by the OS. This code uses local time.

– Martijn Pieters♦
Oct 25 '13 at 16:29

In this case it's not an issue as everything runs in UTC.

– t0mmyt
Oct 25 '13 at 16:30

If everything runs UTC, then not only is it fine, but there's a smart developer behind it. Just to be aware though, the concept of "yesterday" will only apply to what England considers yesterday. If you wanted to do something based on the timing at the site where the logs were written, for instance, you'd have to specify the timezone accordingly.

– sdanzig
Oct 25 '13 at 16:34

add a comment |

Given such a timestamp, you can use divmod to compute the number of days since the epoch (which you don't care about), and how many seconds are leftover (which you do):

days_since, remaining_seconds = divmod(t, 24*3600)  # Divide by number of seconds in one day

Then, you subtract the leftover seconds from your original timestamp, which produces midnight
of the current day.

t -= remaining_seconds

Rounding up is as simple as shifting your target timestamp forward exactly one day before rounding down.

tomorrow_t = t + 24 * 3600

days_since, remaining_seconds = divmod(tomorrow_t, 24*3600)

t = tomorrow_t - remaining_seconds

answered Oct 25 '13 at 16:36

chepner

255k34243337

I thought about that approach, I was actually just going to mod 86400, but then I remembered leap seconds.

– t0mmyt
Oct 25 '13 at 16:45

1

These timestamps are not affected by leap seconds. When a leap second occurs, the UNIX epoch timestamp simply repeats, so you are guaranteed to have 86400 seconds per day. Repeating a timestamp is just another arbitrary label for the leap second, like 23:59:60 is an arbitrary label for the leap second between 23:59:59 and 00:00:00 (or whenever leap seconds get applied).

– chepner
Oct 25 '13 at 17:02

add a comment |

Given such a timestamp, you can use divmod to compute the number of days since the epoch (which you don't care about), and how many seconds are leftover (which you do):

days_since, remaining_seconds = divmod(t, 24*3600)  # Divide by number of seconds in one day

Then, you subtract the leftover seconds from your original timestamp, which produces midnight
of the current day.

t -= remaining_seconds

Rounding up is as simple as shifting your target timestamp forward exactly one day before rounding down.

tomorrow_t = t + 24 * 3600

days_since, remaining_seconds = divmod(tomorrow_t, 24*3600)

t = tomorrow_t - remaining_seconds

answered Oct 25 '13 at 16:36

chepner

255k34243337

I thought about that approach, I was actually just going to mod 86400, but then I remembered leap seconds.

– t0mmyt
Oct 25 '13 at 16:45

1

These timestamps are not affected by leap seconds. When a leap second occurs, the UNIX epoch timestamp simply repeats, so you are guaranteed to have 86400 seconds per day. Repeating a timestamp is just another arbitrary label for the leap second, like 23:59:60 is an arbitrary label for the leap second between 23:59:59 and 00:00:00 (or whenever leap seconds get applied).

– chepner
Oct 25 '13 at 17:02

add a comment |

Given such a timestamp, you can use divmod to compute the number of days since the epoch (which you don't care about), and how many seconds are leftover (which you do):

days_since, remaining_seconds = divmod(t, 24*3600)  # Divide by number of seconds in one day

Then, you subtract the leftover seconds from your original timestamp, which produces midnight
of the current day.

t -= remaining_seconds

Rounding up is as simple as shifting your target timestamp forward exactly one day before rounding down.

tomorrow_t = t + 24 * 3600

days_since, remaining_seconds = divmod(tomorrow_t, 24*3600)

t = tomorrow_t - remaining_seconds

answered Oct 25 '13 at 16:36

chepner

255k34243337

Given such a timestamp, you can use divmod to compute the number of days since the epoch (which you don't care about), and how many seconds are leftover (which you do):

days_since, remaining_seconds = divmod(t, 24*3600)  # Divide by number of seconds in one day

Then, you subtract the leftover seconds from your original timestamp, which produces midnight
of the current day.

t -= remaining_seconds

Rounding up is as simple as shifting your target timestamp forward exactly one day before rounding down.

tomorrow_t = t + 24 * 3600

days_since, remaining_seconds = divmod(tomorrow_t, 24*3600)

t = tomorrow_t - remaining_seconds

answered Oct 25 '13 at 16:36

chepner

255k34243337

answered Oct 25 '13 at 16:36

chepner

255k34243337

answered Oct 25 '13 at 16:36

chepner

255k34243337

answered Oct 25 '13 at 16:36

chepner

255k34243337

I thought about that approach, I was actually just going to mod 86400, but then I remembered leap seconds.

– t0mmyt
Oct 25 '13 at 16:45

1

These timestamps are not affected by leap seconds. When a leap second occurs, the UNIX epoch timestamp simply repeats, so you are guaranteed to have 86400 seconds per day. Repeating a timestamp is just another arbitrary label for the leap second, like 23:59:60 is an arbitrary label for the leap second between 23:59:59 and 00:00:00 (or whenever leap seconds get applied).

– chepner
Oct 25 '13 at 17:02

add a comment |

I thought about that approach, I was actually just going to mod 86400, but then I remembered leap seconds.

– t0mmyt
Oct 25 '13 at 16:45

1

These timestamps are not affected by leap seconds. When a leap second occurs, the UNIX epoch timestamp simply repeats, so you are guaranteed to have 86400 seconds per day. Repeating a timestamp is just another arbitrary label for the leap second, like 23:59:60 is an arbitrary label for the leap second between 23:59:59 and 00:00:00 (or whenever leap seconds get applied).

– chepner
Oct 25 '13 at 17:02

I thought about that approach, I was actually just going to mod 86400, but then I remembered leap seconds.

– t0mmyt
Oct 25 '13 at 16:45

These timestamps are not affected by leap seconds. When a leap second occurs, the UNIX epoch timestamp simply repeats, so you are guaranteed to have 86400 seconds per day. Repeating a timestamp is just another arbitrary label for the leap second, like 23:59:60 is an arbitrary label for the leap second between 23:59:59 and 00:00:00 (or whenever leap seconds get applied).

– chepner
Oct 25 '13 at 17:02

add a comment |

In my estimation, many date and time manipulations are easier to do, and to understand, using the arrow library. This is one of them.

Create an arbitrary date and time.

>>> import arrow

>>> arbitrary = arrow.get(2017,8,16,11,5)

Calculate midnight_yesterday: first, midnight of arbitrary as its 'day' floor; then shift this back by one day. Display the result.

>>> midnight_yesterday = arbitrary.floor('day').shift(days=-1)

>>> midnight_yesterday 

<Arrow [2017-08-15T00:00:00+00:00]>

Use timestamp for the desired overall result, for Python 3.3+.

>>> midnight_yesterday.datetime.timestamp()

1502755200.0

Or use this expression for Python 2.7. (Credit: https://stackoverflow.com/a/11743262/131187 for the latter two expressions.)

>>> (midnight_yesterday-arrow.get(1970,1,1)).total_seconds()

1502755200.0

answered Aug 29 '17 at 16:29

Bill Bell

15.7k42642

add a comment |

In my estimation, many date and time manipulations are easier to do, and to understand, using the arrow library. This is one of them.

Create an arbitrary date and time.

>>> import arrow

>>> arbitrary = arrow.get(2017,8,16,11,5)

Calculate midnight_yesterday: first, midnight of arbitrary as its 'day' floor; then shift this back by one day. Display the result.

>>> midnight_yesterday = arbitrary.floor('day').shift(days=-1)

>>> midnight_yesterday 

<Arrow [2017-08-15T00:00:00+00:00]>

Use timestamp for the desired overall result, for Python 3.3+.

>>> midnight_yesterday.datetime.timestamp()

1502755200.0

Or use this expression for Python 2.7. (Credit: https://stackoverflow.com/a/11743262/131187 for the latter two expressions.)

>>> (midnight_yesterday-arrow.get(1970,1,1)).total_seconds()

1502755200.0

answered Aug 29 '17 at 16:29

Bill Bell

15.7k42642

add a comment |

In my estimation, many date and time manipulations are easier to do, and to understand, using the arrow library. This is one of them.

Create an arbitrary date and time.

>>> import arrow

>>> arbitrary = arrow.get(2017,8,16,11,5)

Calculate midnight_yesterday: first, midnight of arbitrary as its 'day' floor; then shift this back by one day. Display the result.

>>> midnight_yesterday = arbitrary.floor('day').shift(days=-1)

>>> midnight_yesterday 

<Arrow [2017-08-15T00:00:00+00:00]>

Use timestamp for the desired overall result, for Python 3.3+.

>>> midnight_yesterday.datetime.timestamp()

1502755200.0

Or use this expression for Python 2.7. (Credit: https://stackoverflow.com/a/11743262/131187 for the latter two expressions.)

>>> (midnight_yesterday-arrow.get(1970,1,1)).total_seconds()

1502755200.0

answered Aug 29 '17 at 16:29

Bill Bell

15.7k42642

In my estimation, many date and time manipulations are easier to do, and to understand, using the arrow library. This is one of them.

Create an arbitrary date and time.

>>> import arrow

>>> arbitrary = arrow.get(2017,8,16,11,5)

Calculate midnight_yesterday: first, midnight of arbitrary as its 'day' floor; then shift this back by one day. Display the result.

>>> midnight_yesterday = arbitrary.floor('day').shift(days=-1)

>>> midnight_yesterday 

<Arrow [2017-08-15T00:00:00+00:00]>

Use timestamp for the desired overall result, for Python 3.3+.

>>> midnight_yesterday.datetime.timestamp()

1502755200.0

Or use this expression for Python 2.7. (Credit: https://stackoverflow.com/a/11743262/131187 for the latter two expressions.)

>>> (midnight_yesterday-arrow.get(1970,1,1)).total_seconds()

1502755200.0

answered Aug 29 '17 at 16:29

Bill Bell

15.7k42642

answered Aug 29 '17 at 16:29

Bill Bell

15.7k42642

answered Aug 29 '17 at 16:29

Bill Bell

15.7k42642

answered Aug 29 '17 at 16:29

Bill Bell

15.7k42642

add a comment |

You can use this code:

import time



seconds_of_day = 24 * 60 * 60  # 86400

last_midnight = (round(time.time()) // seconds_of_day) * seconds_of_day

yesterday_last_midnight = last_midnight - seconds_of_day

answered Jan 1 at 10:10

Mastisa

1,0962922

add a comment |

You can use this code:

import time



seconds_of_day = 24 * 60 * 60  # 86400

last_midnight = (round(time.time()) // seconds_of_day) * seconds_of_day

yesterday_last_midnight = last_midnight - seconds_of_day

answered Jan 1 at 10:10

Mastisa

1,0962922

add a comment |

You can use this code:

import time



seconds_of_day = 24 * 60 * 60  # 86400

last_midnight = (round(time.time()) // seconds_of_day) * seconds_of_day

yesterday_last_midnight = last_midnight - seconds_of_day

answered Jan 1 at 10:10

Mastisa

1,0962922

You can use this code:

import time



seconds_of_day = 24 * 60 * 60  # 86400

last_midnight = (round(time.time()) // seconds_of_day) * seconds_of_day

yesterday_last_midnight = last_midnight - seconds_of_day

answered Jan 1 at 10:10

Mastisa

1,0962922

answered Jan 1 at 10:10

Mastisa

1,0962922

answered Jan 1 at 10:10

Mastisa

1,0962922

answered Jan 1 at 10:10

Mastisa

1,0962922

add a comment |

Midnight at the start of today is:

midnight = (int(time.time() // 86400)) * 86400

so yesterday's midnight is:

midnight = (int(time.time() // 86400)) * 86400 - 86400

edited Jan 2 at 5:50

Mastisa

1,0962922

answered Dec 30 '18 at 17:36

ggemmill

You must use // instead of %

– Mastisa
Jan 1 at 10:10

Mastisa - many thanks for the correction; I was about to make it myself.

– ggemmill
Jan 1 at 16:34

add a comment |

Midnight at the start of today is:

midnight = (int(time.time() // 86400)) * 86400

so yesterday's midnight is:

midnight = (int(time.time() // 86400)) * 86400 - 86400

edited Jan 2 at 5:50

Mastisa

1,0962922

answered Dec 30 '18 at 17:36

ggemmill

You must use // instead of %

– Mastisa
Jan 1 at 10:10

Mastisa - many thanks for the correction; I was about to make it myself.

– ggemmill
Jan 1 at 16:34

add a comment |

Midnight at the start of today is:

midnight = (int(time.time() // 86400)) * 86400

so yesterday's midnight is:

midnight = (int(time.time() // 86400)) * 86400 - 86400

edited Jan 2 at 5:50

Mastisa

1,0962922

answered Dec 30 '18 at 17:36

ggemmill

Midnight at the start of today is:

midnight = (int(time.time() // 86400)) * 86400

so yesterday's midnight is:

midnight = (int(time.time() // 86400)) * 86400 - 86400

edited Jan 2 at 5:50

Mastisa

1,0962922

answered Dec 30 '18 at 17:36

ggemmill

edited Jan 2 at 5:50

Mastisa

1,0962922

edited Jan 2 at 5:50

Mastisa

1,0962922

edited Jan 2 at 5:50

Mastisa

1,0962922

answered Dec 30 '18 at 17:36

ggemmill

answered Dec 30 '18 at 17:36

ggemmill

answered Dec 30 '18 at 17:36

ggemmill

You must use // instead of %

– Mastisa
Jan 1 at 10:10

Mastisa - many thanks for the correction; I was about to make it myself.

– ggemmill
Jan 1 at 16:34

add a comment |

You must use // instead of %

– Mastisa
Jan 1 at 10:10

Mastisa - many thanks for the correction; I was about to make it myself.

– ggemmill
Jan 1 at 16:34

You must use // instead of %

– Mastisa
Jan 1 at 10:10

Mastisa - many thanks for the correction; I was about to make it myself.

– ggemmill
Jan 1 at 16:34

add a comment |

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