Mixing
Check which number is bigger within a function call - vb.net
Say I'm using this piece of code
With TextBox
.Size = New Windows.Size(InsideRadius)
End With
I want to choose within the function call which size to use dependent on which is the biggest, If Inside Radius is the biggest then choose that, but if a number such as say 20 is bigger then pick that, all within the call.
So something like this
With TextBox
.Size = New Windows.Size(If (InsideRadius >= 20) Then InsideRadius Else 20 End If)
End With
but I'm unsure how to do this within vb.net, I'm sure it is possible but after some searching I think I'm not typing in the correct question to get what I am looking for. Hope you understand, thanks
vb.net
asked Nov 19 '18 at 14:26
fodger_rederer
1
add a comment |
Say I'm using this piece of code
With TextBox
.Size = New Windows.Size(InsideRadius)
End With
I want to choose within the function call which size to use dependent on which is the biggest, If Inside Radius is the biggest then choose that, but if a number such as say 20 is bigger then pick that, all within the call.
So something like this
With TextBox
.Size = New Windows.Size(If (InsideRadius >= 20) Then InsideRadius Else 20 End If)
End With
but I'm unsure how to do this within vb.net, I'm sure it is possible but after some searching I think I'm not typing in the correct question to get what I am looking for. Hope you understand, thanks
vb.net
asked Nov 19 '18 at 14:26
fodger_rederer
1
Is InsideRadius a Size? It should be. Are you wanting width or height? docs.microsoft.com/en-us/dotnet/api/…
– dbasnett
Nov 19 '18 at 15:35
Is this vba? vb.net and vba are not the same.
– Mary
Nov 19 '18 at 19:57
add a comment |
Say I'm using this piece of code
With TextBox
.Size = New Windows.Size(InsideRadius)
End With
I want to choose within the function call which size to use dependent on which is the biggest, If Inside Radius is the biggest then choose that, but if a number such as say 20 is bigger then pick that, all within the call.
So something like this
With TextBox
.Size = New Windows.Size(If (InsideRadius >= 20) Then InsideRadius Else 20 End If)
End With
but I'm unsure how to do this within vb.net, I'm sure it is possible but after some searching I think I'm not typing in the correct question to get what I am looking for. Hope you understand, thanks
vb.net
asked Nov 19 '18 at 14:26
fodger_rederer
1
Say I'm using this piece of code
With TextBox
.Size = New Windows.Size(InsideRadius)
End With
I want to choose within the function call which size to use dependent on which is the biggest, If Inside Radius is the biggest then choose that, but if a number such as say 20 is bigger then pick that, all within the call.
So something like this
With TextBox
.Size = New Windows.Size(If (InsideRadius >= 20) Then InsideRadius Else 20 End If)
End With
but I'm unsure how to do this within vb.net, I'm sure it is possible but after some searching I think I'm not typing in the correct question to get what I am looking for. Hope you understand, thanks
vb.net
vb.net
asked Nov 19 '18 at 14:26
fodger_rederer
1
asked Nov 19 '18 at 14:26
fodger_rederer
1
asked Nov 19 '18 at 14:26
fodger_rederer
1
asked Nov 19 '18 at 14:26
fodger_rederer
1
asked Nov 19 '18 at 14:26
fodger_rederer
1
1
Is InsideRadius a Size? It should be. Are you wanting width or height? docs.microsoft.com/en-us/dotnet/api/…
– dbasnett
Nov 19 '18 at 15:35
Is this vba? vb.net and vba are not the same.
– Mary
Nov 19 '18 at 19:57
add a comment |
Is InsideRadius a Size? It should be. Are you wanting width or height? docs.microsoft.com/en-us/dotnet/api/…
– dbasnett
Nov 19 '18 at 15:35
Is this vba? vb.net and vba are not the same.
– Mary
Nov 19 '18 at 19:57
Is InsideRadius a Size? It should be. Are you wanting width or height? docs.microsoft.com/en-us/dotnet/api/…
– dbasnett
Nov 19 '18 at 15:35
Is InsideRadius a Size? It should be. Are you wanting width or height? docs.microsoft.com/en-us/dotnet/api/…
– dbasnett
Nov 19 '18 at 15:35
Is this vba? vb.net and vba are not the same.
– Mary
Nov 19 '18 at 19:57
Is this vba? vb.net and vba are not the same.
– Mary
Nov 19 '18 at 19:57
add a comment |
2 Answers
2
active
oldest
votes
It is possible, it looks like a function that is called if:
If(Statement, True, False)
https://docs.microsoft.com/en-us/dotnet/visual-basic/language-reference/operators/if-operator
answered Nov 19 '18 at 14:32
DaanV
3466
add a comment |
Math.Max()
Math.Max(InsideRadius, 20)
This will return whichever is the larger number.
TextBox.Size = New Windows.Size(Math.Max(InsideRadius, 20)
answered Nov 20 '18 at 13:08
Gravitate
1,2031225
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
It is possible, it looks like a function that is called if:
If(Statement, True, False)
https://docs.microsoft.com/en-us/dotnet/visual-basic/language-reference/operators/if-operator
answered Nov 19 '18 at 14:32
DaanV
3466
add a comment |
It is possible, it looks like a function that is called if:
If(Statement, True, False)
https://docs.microsoft.com/en-us/dotnet/visual-basic/language-reference/operators/if-operator
answered Nov 19 '18 at 14:32
DaanV
3466
add a comment |
It is possible, it looks like a function that is called if:
If(Statement, True, False)
https://docs.microsoft.com/en-us/dotnet/visual-basic/language-reference/operators/if-operator
answered Nov 19 '18 at 14:32
DaanV
3466
It is possible, it looks like a function that is called if:
If(Statement, True, False)
https://docs.microsoft.com/en-us/dotnet/visual-basic/language-reference/operators/if-operator
answered Nov 19 '18 at 14:32
DaanV
3466
answered Nov 19 '18 at 14:32
DaanV
3466
answered Nov 19 '18 at 14:32
DaanV
3466
answered Nov 19 '18 at 14:32
DaanV
3466
3466
add a comment |
add a comment |
Math.Max()
Math.Max(InsideRadius, 20)
This will return whichever is the larger number.
TextBox.Size = New Windows.Size(Math.Max(InsideRadius, 20)
answered Nov 20 '18 at 13:08
Gravitate
1,2031225
add a comment |
Math.Max()
Math.Max(InsideRadius, 20)
This will return whichever is the larger number.
TextBox.Size = New Windows.Size(Math.Max(InsideRadius, 20)
answered Nov 20 '18 at 13:08
Gravitate
1,2031225
add a comment |
Math.Max()
Math.Max(InsideRadius, 20)
This will return whichever is the larger number.
TextBox.Size = New Windows.Size(Math.Max(InsideRadius, 20)
answered Nov 20 '18 at 13:08
Gravitate
1,2031225
Math.Max()
Math.Max(InsideRadius, 20)
This will return whichever is the larger number.
TextBox.Size = New Windows.Size(Math.Max(InsideRadius, 20)
answered Nov 20 '18 at 13:08
Gravitate
1,2031225
answered Nov 20 '18 at 13:08
Gravitate
1,2031225
answered Nov 20 '18 at 13:08
Gravitate
1,2031225
answered Nov 20 '18 at 13:08
Gravitate
1,2031225
1,2031225
add a comment |
add a comment |
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Is InsideRadius a Size? It should be. Are you wanting width or height? docs.microsoft.com/en-us/dotnet/api/…
– dbasnett
Nov 19 '18 at 15:35
Is this vba? vb.net and vba are not the same.
– Mary
Nov 19 '18 at 19:57