Mixing
$57$ companies. $10$ displayed at random. Probability of being displayed?
0
- In my industry our clients are presented with $10$ companies from a possible $57$ to select and send work to. They only choose $1$.
What is the probability that a company is displayed in the $10$ shown to the client?
My attempt: $dfrac{10}{57}$
- Another group of companies are in a separate pot and $2$ are displayed from a possible $10$. What is the probability that a company is displayed in the $2$ shown to the client?
Apologies if this appears basic or I have failed to include any relevant information - I have no idea where to begin!
probability
edited Nov 21 '18 at 15:32
N. F. Taussig
43.6k93355
asked Nov 21 '18 at 12:24
Dan W
1
add a comment |
0
- In my industry our clients are presented with $10$ companies from a possible $57$ to select and send work to. They only choose $1$.
What is the probability that a company is displayed in the $10$ shown to the client?
My attempt: $dfrac{10}{57}$
- Another group of companies are in a separate pot and $2$ are displayed from a possible $10$. What is the probability that a company is displayed in the $2$ shown to the client?
Apologies if this appears basic or I have failed to include any relevant information - I have no idea where to begin!
probability
edited Nov 21 '18 at 15:32
N. F. Taussig
43.6k93355
asked Nov 21 '18 at 12:24
Dan W
1
Well, what definition of "probability" are you using? The standard is that ir there are n possible outcomes, all equally likely, then the probability the outcome is one of a subset containing m of those outcomes is m/n.
– user247327
Nov 21 '18 at 12:30
Yes I would be using standard definition. So the answer would be 10/57 = 0.1754 ?
– Dan W
Nov 21 '18 at 12:36
Your answer to the first question is correct. You can use the same method to solve the second question.
– N. F. Taussig
Nov 21 '18 at 15:34
add a comment |
0
0
0
- In my industry our clients are presented with $10$ companies from a possible $57$ to select and send work to. They only choose $1$.
What is the probability that a company is displayed in the $10$ shown to the client?
My attempt: $dfrac{10}{57}$
- Another group of companies are in a separate pot and $2$ are displayed from a possible $10$. What is the probability that a company is displayed in the $2$ shown to the client?
Apologies if this appears basic or I have failed to include any relevant information - I have no idea where to begin!
probability
edited Nov 21 '18 at 15:32
N. F. Taussig
43.6k93355
asked Nov 21 '18 at 12:24
Dan W
1
- In my industry our clients are presented with $10$ companies from a possible $57$ to select and send work to. They only choose $1$.
What is the probability that a company is displayed in the $10$ shown to the client?
My attempt: $dfrac{10}{57}$
- Another group of companies are in a separate pot and $2$ are displayed from a possible $10$. What is the probability that a company is displayed in the $2$ shown to the client?
Apologies if this appears basic or I have failed to include any relevant information - I have no idea where to begin!
probability
probability
edited Nov 21 '18 at 15:32
N. F. Taussig
43.6k93355
asked Nov 21 '18 at 12:24
Dan W
1
edited Nov 21 '18 at 15:32
N. F. Taussig
43.6k93355
asked Nov 21 '18 at 12:24
Dan W
1
edited Nov 21 '18 at 15:32
N. F. Taussig
43.6k93355
edited Nov 21 '18 at 15:32
N. F. Taussig
43.6k93355
edited Nov 21 '18 at 15:32
N. F. Taussig
43.6k93355
43.6k93355
asked Nov 21 '18 at 12:24
Dan W
1
asked Nov 21 '18 at 12:24
Dan W
1
asked Nov 21 '18 at 12:24
Dan W
1
1
Well, what definition of "probability" are you using? The standard is that ir there are n possible outcomes, all equally likely, then the probability the outcome is one of a subset containing m of those outcomes is m/n.
– user247327
Nov 21 '18 at 12:30
Yes I would be using standard definition. So the answer would be 10/57 = 0.1754 ?
– Dan W
Nov 21 '18 at 12:36
Your answer to the first question is correct. You can use the same method to solve the second question.
– N. F. Taussig
Nov 21 '18 at 15:34
add a comment |
Well, what definition of "probability" are you using? The standard is that ir there are n possible outcomes, all equally likely, then the probability the outcome is one of a subset containing m of those outcomes is m/n.
– user247327
Nov 21 '18 at 12:30
Yes I would be using standard definition. So the answer would be 10/57 = 0.1754 ?
– Dan W
Nov 21 '18 at 12:36
Your answer to the first question is correct. You can use the same method to solve the second question.
– N. F. Taussig
Nov 21 '18 at 15:34
Well, what definition of "probability" are you using? The standard is that ir there are n possible outcomes, all equally likely, then the probability the outcome is one of a subset containing m of those outcomes is m/n.
– user247327
Nov 21 '18 at 12:30
Well, what definition of "probability" are you using? The standard is that ir there are n possible outcomes, all equally likely, then the probability the outcome is one of a subset containing m of those outcomes is m/n.
– user247327
Nov 21 '18 at 12:30
Yes I would be using standard definition. So the answer would be 10/57 = 0.1754 ?
– Dan W
Nov 21 '18 at 12:36
Yes I would be using standard definition. So the answer would be 10/57 = 0.1754 ?
– Dan W
Nov 21 '18 at 12:36
Your answer to the first question is correct. You can use the same method to solve the second question.
– N. F. Taussig
Nov 21 '18 at 15:34
Your answer to the first question is correct. You can use the same method to solve the second question.
– N. F. Taussig
Nov 21 '18 at 15:34
add a comment |
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Well, what definition of "probability" are you using? The standard is that ir there are n possible outcomes, all equally likely, then the probability the outcome is one of a subset containing m of those outcomes is m/n.
– user247327
Nov 21 '18 at 12:30
Yes I would be using standard definition. So the answer would be 10/57 = 0.1754 ?
– Dan W
Nov 21 '18 at 12:36
Your answer to the first question is correct. You can use the same method to solve the second question.
– N. F. Taussig
Nov 21 '18 at 15:34