Function receiving and modifying a list without returning it [closed]

-3

There is a question around here with a similar title, however it refers to something different.

Example:

lst = [1,2,3,4,2]

def drop_duplicates(lst):

    # Write the rest of the code for question 3a below here.

    lst.pop(0)

print lst





>>> [1, 2, 3, 4, 2]

As you can see my issue is that it is not being modified. I've been told that is possible to accomplish this without adding a return statement or using Global. Would love to have some insight into this.

Thanks!

python python-2.7 function

share|improve this question

asked Nov 19 '18 at 17:22

Moriel Mankevich

1

closed as off-topic by timgeb, jpp, Austin, chepner, pushkin Nov 19 '18 at 17:42

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – timgeb, jpp, Austin, chepner, pushkin

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  You never called your function.
  – timgeb
  Nov 19 '18 at 17:23
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Suppose I replaced the def statement with drop_duplicates = operater.methodcaller('pop', 0). Would you still be surprised that lst remained unmodified, given that the definition doesn't mention lst at all.
  – chepner
  Nov 19 '18 at 17:35
  
  
  

  
  
  
  

add a comment | 

-3

There is a question around here with a similar title, however it refers to something different.

Example:

lst = [1,2,3,4,2]

def drop_duplicates(lst):

    # Write the rest of the code for question 3a below here.

    lst.pop(0)

print lst





>>> [1, 2, 3, 4, 2]

As you can see my issue is that it is not being modified. I've been told that is possible to accomplish this without adding a return statement or using Global. Would love to have some insight into this.

Thanks!

python python-2.7 function

share|improve this question

asked Nov 19 '18 at 17:22

Moriel Mankevich

1

closed as off-topic by timgeb, jpp, Austin, chepner, pushkin Nov 19 '18 at 17:42

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – timgeb, jpp, Austin, chepner, pushkin

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  You never called your function.
  – timgeb
  Nov 19 '18 at 17:23
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Suppose I replaced the def statement with drop_duplicates = operater.methodcaller('pop', 0). Would you still be surprised that lst remained unmodified, given that the definition doesn't mention lst at all.
  – chepner
  Nov 19 '18 at 17:35
  
  
  

  
  
  
  

add a comment | 

-3

-3

-3

There is a question around here with a similar title, however it refers to something different.

Example:

lst = [1,2,3,4,2]

def drop_duplicates(lst):

    # Write the rest of the code for question 3a below here.

    lst.pop(0)

print lst





>>> [1, 2, 3, 4, 2]

As you can see my issue is that it is not being modified. I've been told that is possible to accomplish this without adding a return statement or using Global. Would love to have some insight into this.

Thanks!

python python-2.7 function

share|improve this question

asked Nov 19 '18 at 17:22

Moriel Mankevich

1

There is a question around here with a similar title, however it refers to something different.

Example:

lst = [1,2,3,4,2]

def drop_duplicates(lst):

    # Write the rest of the code for question 3a below here.

    lst.pop(0)

print lst





>>> [1, 2, 3, 4, 2]

As you can see my issue is that it is not being modified. I've been told that is possible to accomplish this without adding a return statement or using Global. Would love to have some insight into this.

Thanks!

python python-2.7 function

python python-2.7 function

share|improve this question

asked Nov 19 '18 at 17:22

Moriel Mankevich

1

share|improve this question

asked Nov 19 '18 at 17:22

Moriel Mankevich

1

share|improve this question

share|improve this question

asked Nov 19 '18 at 17:22

Moriel Mankevich

1

asked Nov 19 '18 at 17:22

Moriel Mankevich

1

asked Nov 19 '18 at 17:22

Moriel Mankevich

1

1

closed as off-topic by timgeb, jpp, Austin, chepner, pushkin Nov 19 '18 at 17:42

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – timgeb, jpp, Austin, chepner, pushkin

If this question can be reworded to fit the rules in the help center, please edit the question.

closed as off-topic by timgeb, jpp, Austin, chepner, pushkin Nov 19 '18 at 17:42

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – timgeb, jpp, Austin, chepner, pushkin

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  You never called your function.
  – timgeb
  Nov 19 '18 at 17:23
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Suppose I replaced the def statement with drop_duplicates = operater.methodcaller('pop', 0). Would you still be surprised that lst remained unmodified, given that the definition doesn't mention lst at all.
  – chepner
  Nov 19 '18 at 17:35
  
  
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  You never called your function.
  – timgeb
  Nov 19 '18 at 17:23
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Suppose I replaced the def statement with drop_duplicates = operater.methodcaller('pop', 0). Would you still be surprised that lst remained unmodified, given that the definition doesn't mention lst at all.
  – chepner
  Nov 19 '18 at 17:35
  
  
  

  
  
  
  

3

3

You never called your function.
– timgeb
Nov 19 '18 at 17:23

You never called your function.
– timgeb
Nov 19 '18 at 17:23

Suppose I replaced the def statement with drop_duplicates = operater.methodcaller('pop', 0). Would you still be surprised that lst remained unmodified, given that the definition doesn't mention lst at all.
– chepner
Nov 19 '18 at 17:35

Suppose I replaced the def statement with drop_duplicates = operater.methodcaller('pop', 0). Would you still be surprised that lst remained unmodified, given that the definition doesn't mention lst at all.
– chepner
Nov 19 '18 at 17:35

add a comment | 

1 Answer
1

active

oldest

votes

1

You need to call your function

lst = [1,2,3,4,2]

def drop_duplicates(lst):

# Write the rest of the code for question 3a below here.

   lst.pop(0)

drop_duplicates(lst)

print lst

[2, 3, 4, 2]

share|improve this answer

answered Nov 19 '18 at 17:26

Garvita Tiwari

453211

add a comment | 

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

active

oldest

votes

active

oldest

votes

1

You need to call your function

lst = [1,2,3,4,2]

def drop_duplicates(lst):

# Write the rest of the code for question 3a below here.

   lst.pop(0)

drop_duplicates(lst)

print lst

[2, 3, 4, 2]

share|improve this answer

answered Nov 19 '18 at 17:26

Garvita Tiwari

453211

add a comment | 

1

You need to call your function

lst = [1,2,3,4,2]

def drop_duplicates(lst):

# Write the rest of the code for question 3a below here.

   lst.pop(0)

drop_duplicates(lst)

print lst

[2, 3, 4, 2]

share|improve this answer

answered Nov 19 '18 at 17:26

Garvita Tiwari

453211

add a comment | 

1

1

1

You need to call your function

lst = [1,2,3,4,2]

def drop_duplicates(lst):

# Write the rest of the code for question 3a below here.

   lst.pop(0)

drop_duplicates(lst)

print lst

[2, 3, 4, 2]

share|improve this answer

answered Nov 19 '18 at 17:26

Garvita Tiwari

453211

You need to call your function

lst = [1,2,3,4,2]

def drop_duplicates(lst):

# Write the rest of the code for question 3a below here.

   lst.pop(0)

drop_duplicates(lst)

print lst

[2, 3, 4, 2]

share|improve this answer

answered Nov 19 '18 at 17:26

Garvita Tiwari

453211

share|improve this answer

share|improve this answer

answered Nov 19 '18 at 17:26

Garvita Tiwari

453211

answered Nov 19 '18 at 17:26

Garvita Tiwari

453211

answered Nov 19 '18 at 17:26

Garvita Tiwari

453211

453211

add a comment | 

add a comment | 

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