Mixing
Search files into a directory / compatible Unix / Windows
i'm a beginner in Python, and try to use the os module to find and aggregate all files in a given folder, given a key word such as "example".
Based on what I found so far, here is my code :
def import_files_list(path, key_word):
files =
for i in os.listdir(path):
if os.path.isfile(os.path.join(path,i)) and key_word in i:
file_plus_path = path+i
pprint(file_plus_path)
files.append(file_plus_path)
return files
actual_dir = os.path.dirname(os.path.realpath(__file__))
wanted_dir = os.path.split(actual_dir)[0]
files_list = import_files_list(wanted_dir, 'example')
pprint(files_list)
The thing is that, instead of getting for instance :
'C:\Users\User\folder\example1.csv'
I'm getting :
'C:\Users\User\folderexample1.csv'
So this is not correct.
I don't want to hardcode anything such as "" to solve the problem, and I'm pretty sure I could also simplify the above code.
Could you help me and tell me here I am wrong ?
python
asked Nov 19 '18 at 14:14
SidGabriel
736
add a comment |
i'm a beginner in Python, and try to use the os module to find and aggregate all files in a given folder, given a key word such as "example".
Based on what I found so far, here is my code :
def import_files_list(path, key_word):
files =
for i in os.listdir(path):
if os.path.isfile(os.path.join(path,i)) and key_word in i:
file_plus_path = path+i
pprint(file_plus_path)
files.append(file_plus_path)
return files
actual_dir = os.path.dirname(os.path.realpath(__file__))
wanted_dir = os.path.split(actual_dir)[0]
files_list = import_files_list(wanted_dir, 'example')
pprint(files_list)
The thing is that, instead of getting for instance :
'C:\Users\User\folder\example1.csv'
I'm getting :
'C:\Users\User\folderexample1.csv'
So this is not correct.
I don't want to hardcode anything such as "" to solve the problem, and I'm pretty sure I could also simplify the above code.
Could you help me and tell me here I am wrong ?
python
asked Nov 19 '18 at 14:14
SidGabriel
736
add a comment |
i'm a beginner in Python, and try to use the os module to find and aggregate all files in a given folder, given a key word such as "example".
Based on what I found so far, here is my code :
def import_files_list(path, key_word):
files =
for i in os.listdir(path):
if os.path.isfile(os.path.join(path,i)) and key_word in i:
file_plus_path = path+i
pprint(file_plus_path)
files.append(file_plus_path)
return files
actual_dir = os.path.dirname(os.path.realpath(__file__))
wanted_dir = os.path.split(actual_dir)[0]
files_list = import_files_list(wanted_dir, 'example')
pprint(files_list)
The thing is that, instead of getting for instance :
'C:\Users\User\folder\example1.csv'
I'm getting :
'C:\Users\User\folderexample1.csv'
So this is not correct.
I don't want to hardcode anything such as "" to solve the problem, and I'm pretty sure I could also simplify the above code.
Could you help me and tell me here I am wrong ?
python
asked Nov 19 '18 at 14:14
SidGabriel
736
i'm a beginner in Python, and try to use the os module to find and aggregate all files in a given folder, given a key word such as "example".
Based on what I found so far, here is my code :
def import_files_list(path, key_word):
files =
for i in os.listdir(path):
if os.path.isfile(os.path.join(path,i)) and key_word in i:
file_plus_path = path+i
pprint(file_plus_path)
files.append(file_plus_path)
return files
actual_dir = os.path.dirname(os.path.realpath(__file__))
wanted_dir = os.path.split(actual_dir)[0]
files_list = import_files_list(wanted_dir, 'example')
pprint(files_list)
The thing is that, instead of getting for instance :
'C:\Users\User\folder\example1.csv'
I'm getting :
'C:\Users\User\folderexample1.csv'
So this is not correct.
I don't want to hardcode anything such as "" to solve the problem, and I'm pretty sure I could also simplify the above code.
Could you help me and tell me here I am wrong ?
python
python
asked Nov 19 '18 at 14:14
SidGabriel
736
asked Nov 19 '18 at 14:14
SidGabriel
736
asked Nov 19 '18 at 14:14
SidGabriel
736
asked Nov 19 '18 at 14:14
SidGabriel
736
asked Nov 19 '18 at 14:14
SidGabriel
736
736
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Your problem is this line:
file_plus_path = path+i
Here you append one string to another, but without any delimiter between them. On the previous line you did it correctly: os.path.join(path,i).
So here's a way to correct that:
file_plus_path = os.path.join(path,i)
if os.path.isfile(file_plus_path) and key_word in i:
pprint(file_plus_path)
files.append(file_plus_path)
answered Nov 19 '18 at 14:20
dsh
10.2k32141
You're right ! It solved my mistake :) Thank you !
– SidGabriel
Nov 19 '18 at 14:27
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your problem is this line:
file_plus_path = path+i
Here you append one string to another, but without any delimiter between them. On the previous line you did it correctly: os.path.join(path,i).
So here's a way to correct that:
file_plus_path = os.path.join(path,i)
if os.path.isfile(file_plus_path) and key_word in i:
pprint(file_plus_path)
files.append(file_plus_path)
answered Nov 19 '18 at 14:20
dsh
10.2k32141
You're right ! It solved my mistake :) Thank you !
– SidGabriel
Nov 19 '18 at 14:27
add a comment |
Your problem is this line:
file_plus_path = path+i
Here you append one string to another, but without any delimiter between them. On the previous line you did it correctly: os.path.join(path,i).
So here's a way to correct that:
file_plus_path = os.path.join(path,i)
if os.path.isfile(file_plus_path) and key_word in i:
pprint(file_plus_path)
files.append(file_plus_path)
answered Nov 19 '18 at 14:20
dsh
10.2k32141
You're right ! It solved my mistake :) Thank you !
– SidGabriel
Nov 19 '18 at 14:27
add a comment |
Your problem is this line:
file_plus_path = path+i
Here you append one string to another, but without any delimiter between them. On the previous line you did it correctly: os.path.join(path,i).
So here's a way to correct that:
file_plus_path = os.path.join(path,i)
if os.path.isfile(file_plus_path) and key_word in i:
pprint(file_plus_path)
files.append(file_plus_path)
answered Nov 19 '18 at 14:20
dsh
10.2k32141
Your problem is this line:
file_plus_path = path+i
Here you append one string to another, but without any delimiter between them. On the previous line you did it correctly: os.path.join(path,i).
So here's a way to correct that:
file_plus_path = os.path.join(path,i)
if os.path.isfile(file_plus_path) and key_word in i:
pprint(file_plus_path)
files.append(file_plus_path)
answered Nov 19 '18 at 14:20
dsh
10.2k32141
answered Nov 19 '18 at 14:20
dsh
10.2k32141
answered Nov 19 '18 at 14:20
dsh
10.2k32141
answered Nov 19 '18 at 14:20
dsh
10.2k32141
10.2k32141
You're right ! It solved my mistake :) Thank you !
– SidGabriel
Nov 19 '18 at 14:27
add a comment |
You're right ! It solved my mistake :) Thank you !
– SidGabriel
Nov 19 '18 at 14:27
You're right ! It solved my mistake :) Thank you !
– SidGabriel
Nov 19 '18 at 14:27
You're right ! It solved my mistake :) Thank you !
– SidGabriel
Nov 19 '18 at 14:27
add a comment |
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