Get 3d point(x,y,depth) coordinates from the image camera to another image camera












1















I have two images of two stereo already calibrated and rectified. I made the stitching to build a panoramic image based on the two images, so I have the homography matrix, and I can also find the matrices R and T based on H. I use the function perspectivetransform to find the correspondence of a point 2d of the image 1 in the panoramic image.



Problem:



My stereos are positioned on top-view , if I look for the correspondence of a point of non-planar point (for example point of detection which corresponds to a head of person), I can not find its correspondence in the stitched image?



I have also the 3d points (x, y, depth) in the real coordinate that corresponds to my detection points, when I multiply this point by either the homography matrix or by R | T, I do not find the point of destination in picture 2 (I know his coordinates in 3d too).
did you have any solutions?










share|improve this question



























    1















    I have two images of two stereo already calibrated and rectified. I made the stitching to build a panoramic image based on the two images, so I have the homography matrix, and I can also find the matrices R and T based on H. I use the function perspectivetransform to find the correspondence of a point 2d of the image 1 in the panoramic image.



    Problem:



    My stereos are positioned on top-view , if I look for the correspondence of a point of non-planar point (for example point of detection which corresponds to a head of person), I can not find its correspondence in the stitched image?



    I have also the 3d points (x, y, depth) in the real coordinate that corresponds to my detection points, when I multiply this point by either the homography matrix or by R | T, I do not find the point of destination in picture 2 (I know his coordinates in 3d too).
    did you have any solutions?










    share|improve this question

























      1












      1








      1








      I have two images of two stereo already calibrated and rectified. I made the stitching to build a panoramic image based on the two images, so I have the homography matrix, and I can also find the matrices R and T based on H. I use the function perspectivetransform to find the correspondence of a point 2d of the image 1 in the panoramic image.



      Problem:



      My stereos are positioned on top-view , if I look for the correspondence of a point of non-planar point (for example point of detection which corresponds to a head of person), I can not find its correspondence in the stitched image?



      I have also the 3d points (x, y, depth) in the real coordinate that corresponds to my detection points, when I multiply this point by either the homography matrix or by R | T, I do not find the point of destination in picture 2 (I know his coordinates in 3d too).
      did you have any solutions?










      share|improve this question














      I have two images of two stereo already calibrated and rectified. I made the stitching to build a panoramic image based on the two images, so I have the homography matrix, and I can also find the matrices R and T based on H. I use the function perspectivetransform to find the correspondence of a point 2d of the image 1 in the panoramic image.



      Problem:



      My stereos are positioned on top-view , if I look for the correspondence of a point of non-planar point (for example point of detection which corresponds to a head of person), I can not find its correspondence in the stitched image?



      I have also the 3d points (x, y, depth) in the real coordinate that corresponds to my detection points, when I multiply this point by either the homography matrix or by R | T, I do not find the point of destination in picture 2 (I know his coordinates in 3d too).
      did you have any solutions?







      c++ opencv homography






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 20 '18 at 14:36









      user2502117user2502117

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