trouble in java, splitting strings

-2

I want to scan a sentence that the user types, but I want to scan the words separately and then perform the actions depending on the words the user has put.

}else if(choice.equals("load")){

  System.out.println("Enter the name of the file:");

  String name = input.next();

  loadFile(name);

what I want is the user to type "load file.txt" directly

edited Nov 20 '18 at 2:09

Cœur

17.6k9104145

asked Dec 18 '12 at 22:15

Angelo Mico

194

4

What problems are you having?

– Hovercraft Full Of Eels
Dec 18 '12 at 22:15

Show us some input and expected output. You can split string by String.split("\s+") for whitespaces

– Smit
Dec 18 '12 at 22:16

this is one case of my code, so for each one of them i need the user to type the full sentence of what he wants and with one scan the program will execute.

– Angelo Mico
Dec 18 '12 at 22:16

I basically answered that question in my comment under your other question.

– jlordo
Dec 18 '12 at 22:17

@smit the input should be "load file.txt" and the program will execute that file without the need for the user to firstly type if he wants to load and then asked again what file he wants to load

– Angelo Mico
Dec 18 '12 at 22:18

|
show 6 more comments

-2

I want to scan a sentence that the user types, but I want to scan the words separately and then perform the actions depending on the words the user has put.

}else if(choice.equals("load")){

  System.out.println("Enter the name of the file:");

  String name = input.next();

  loadFile(name);

what I want is the user to type "load file.txt" directly

edited Nov 20 '18 at 2:09

Cœur

17.6k9104145

asked Dec 18 '12 at 22:15

Angelo Mico

194

4

What problems are you having?

– Hovercraft Full Of Eels
Dec 18 '12 at 22:15

Show us some input and expected output. You can split string by String.split("\s+") for whitespaces

– Smit
Dec 18 '12 at 22:16

this is one case of my code, so for each one of them i need the user to type the full sentence of what he wants and with one scan the program will execute.

– Angelo Mico
Dec 18 '12 at 22:16

I basically answered that question in my comment under your other question.

– jlordo
Dec 18 '12 at 22:17

@smit the input should be "load file.txt" and the program will execute that file without the need for the user to firstly type if he wants to load and then asked again what file he wants to load

– Angelo Mico
Dec 18 '12 at 22:18

|
show 6 more comments

-2

I want to scan a sentence that the user types, but I want to scan the words separately and then perform the actions depending on the words the user has put.

}else if(choice.equals("load")){

  System.out.println("Enter the name of the file:");

  String name = input.next();

  loadFile(name);

what I want is the user to type "load file.txt" directly

edited Nov 20 '18 at 2:09

Cœur

17.6k9104145

asked Dec 18 '12 at 22:15

Angelo Mico

194

I want to scan a sentence that the user types, but I want to scan the words separately and then perform the actions depending on the words the user has put.

}else if(choice.equals("load")){

  System.out.println("Enter the name of the file:");

  String name = input.next();

  loadFile(name);

what I want is the user to type "load file.txt" directly

java string split

edited Nov 20 '18 at 2:09

Cœur

17.6k9104145

asked Dec 18 '12 at 22:15

Angelo Mico

194

edited Nov 20 '18 at 2:09

Cœur

17.6k9104145

asked Dec 18 '12 at 22:15

Angelo Mico

194

edited Nov 20 '18 at 2:09

Cœur

17.6k9104145

edited Nov 20 '18 at 2:09

Cœur

17.6k9104145

edited Nov 20 '18 at 2:09

Cœur

17.6k9104145

asked Dec 18 '12 at 22:15

Angelo Mico

194

asked Dec 18 '12 at 22:15

Angelo Mico

194

asked Dec 18 '12 at 22:15

Angelo Mico

194

4

What problems are you having?

– Hovercraft Full Of Eels
Dec 18 '12 at 22:15

Show us some input and expected output. You can split string by String.split("\s+") for whitespaces

– Smit
Dec 18 '12 at 22:16

this is one case of my code, so for each one of them i need the user to type the full sentence of what he wants and with one scan the program will execute.

– Angelo Mico
Dec 18 '12 at 22:16

I basically answered that question in my comment under your other question.

– jlordo
Dec 18 '12 at 22:17

@smit the input should be "load file.txt" and the program will execute that file without the need for the user to firstly type if he wants to load and then asked again what file he wants to load

– Angelo Mico
Dec 18 '12 at 22:18

|
show 6 more comments

4

What problems are you having?

– Hovercraft Full Of Eels
Dec 18 '12 at 22:15

Show us some input and expected output. You can split string by String.split("\s+") for whitespaces

– Smit
Dec 18 '12 at 22:16

this is one case of my code, so for each one of them i need the user to type the full sentence of what he wants and with one scan the program will execute.

– Angelo Mico
Dec 18 '12 at 22:16

I basically answered that question in my comment under your other question.

– jlordo
Dec 18 '12 at 22:17

@smit the input should be "load file.txt" and the program will execute that file without the need for the user to firstly type if he wants to load and then asked again what file he wants to load

– Angelo Mico
Dec 18 '12 at 22:18

What problems are you having?

– Hovercraft Full Of Eels
Dec 18 '12 at 22:15

Show us some input and expected output. You can split string by String.split("\s+") for whitespaces

– Smit
Dec 18 '12 at 22:16

this is one case of my code, so for each one of them i need the user to type the full sentence of what he wants and with one scan the program will execute.

– Angelo Mico
Dec 18 '12 at 22:16

I basically answered that question in my comment under your other question.

– jlordo
Dec 18 '12 at 22:17

@smit the input should be "load file.txt" and the program will execute that file without the need for the user to firstly type if he wants to load and then asked again what file he wants to load

– Angelo Mico
Dec 18 '12 at 22:18

|
show 6 more comments

2 Answers
2

active

oldest

votes

I try to write a small code for you may be this can help you a little bit

    public class Tester2 {



    /**

     * @param args

     */

    public static void main(String args) {



        boolean state = true;

        while(state) {



            System.out.println("Please enter your text");

            Scanner scan = new Scanner(System.in);

            String input = scan.nextLine();

            if(input.contains("load")) {

                String fileName = getFileName(input);

                if(fileName != "" || fileName!= null) {

                    load(fileName);

                }

            }else{



            }



        }



    }



    private static String getFileName(String input) {

        String values = input.split("\s+");

        String fileName = "";

        for(String s : values) {

            if(s.indexOf(".") > 0) {

                fileName = s;

                break;

            }

        }

        return fileName;

    }



}

edited Dec 18 '12 at 23:12

answered Dec 18 '12 at 22:30

Festus Tamakloe

9,68484559

Whenever you have questions, feel free to ask

– Festus Tamakloe
Dec 18 '12 at 22:32

,yup i think its kind of what i want i just dont get this : for(String s : values) { if(s.indexOf(".") > 0) { fileName = s; break; why did you do this?

– Angelo Mico
Dec 18 '12 at 22:49

for(String s : values) ==> iteration/loop over the values if(s.indexOf(".") > 0) ==> here we want to which word has an extension in another which word contains(".") if we get one we passe it to fileName then we do not need anymore to continue (break). If your satisfy with my answer just vote up and accept it

– Festus Tamakloe
Dec 18 '12 at 22:50

ok,one more thing,I need to have some other options other than "load" like "inspect" an other class etc.. should I continue with this way? put an "else" and carry on with the next option?and do i need to do the thing i asked above again for each of the options i have?

– Angelo Mico
Dec 18 '12 at 23:05

You can do it in the same. but use else if(conditions){} try write a litte method where you can some some codes to avoid the repetition

– Festus Tamakloe
Dec 18 '12 at 23:10

|
show 2 more comments

It's too long for a comment, and I don't really understand what your last comment means. Here's some sample code. Try it with inputs like

load filename.txt

load foo bar baz

save foo

whatever ...

System.out.println("What would you like to do");

Scanner scanner = new Scanner(System.in);

String line = scanner.nextLine();

String input = line.split("\s+");

if (input[0].equals("load")) {

    for (int i = 1; i < input.length; i++) {

        System.out.println("Token #" + i + " after load: " + input[i]);

    }

} else {

    System.out.println("You did not enter load, I ignore your input");

}

If you have a question about the behavior or anything else: feel free to leave a comment.

answered Dec 18 '12 at 23:07

jlordo

31.1k54371

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

I try to write a small code for you may be this can help you a little bit

    public class Tester2 {



    /**

     * @param args

     */

    public static void main(String args) {



        boolean state = true;

        while(state) {



            System.out.println("Please enter your text");

            Scanner scan = new Scanner(System.in);

            String input = scan.nextLine();

            if(input.contains("load")) {

                String fileName = getFileName(input);

                if(fileName != "" || fileName!= null) {

                    load(fileName);

                }

            }else{



            }



        }



    }



    private static String getFileName(String input) {

        String values = input.split("\s+");

        String fileName = "";

        for(String s : values) {

            if(s.indexOf(".") > 0) {

                fileName = s;

                break;

            }

        }

        return fileName;

    }



}

edited Dec 18 '12 at 23:12

answered Dec 18 '12 at 22:30

Festus Tamakloe

9,68484559

Whenever you have questions, feel free to ask

– Festus Tamakloe
Dec 18 '12 at 22:32

,yup i think its kind of what i want i just dont get this : for(String s : values) { if(s.indexOf(".") > 0) { fileName = s; break; why did you do this?

– Angelo Mico
Dec 18 '12 at 22:49

for(String s : values) ==> iteration/loop over the values if(s.indexOf(".") > 0) ==> here we want to which word has an extension in another which word contains(".") if we get one we passe it to fileName then we do not need anymore to continue (break). If your satisfy with my answer just vote up and accept it

– Festus Tamakloe
Dec 18 '12 at 22:50

ok,one more thing,I need to have some other options other than "load" like "inspect" an other class etc.. should I continue with this way? put an "else" and carry on with the next option?and do i need to do the thing i asked above again for each of the options i have?

– Angelo Mico
Dec 18 '12 at 23:05

You can do it in the same. but use else if(conditions){} try write a litte method where you can some some codes to avoid the repetition

– Festus Tamakloe
Dec 18 '12 at 23:10

|
show 2 more comments

I try to write a small code for you may be this can help you a little bit

    public class Tester2 {



    /**

     * @param args

     */

    public static void main(String args) {



        boolean state = true;

        while(state) {



            System.out.println("Please enter your text");

            Scanner scan = new Scanner(System.in);

            String input = scan.nextLine();

            if(input.contains("load")) {

                String fileName = getFileName(input);

                if(fileName != "" || fileName!= null) {

                    load(fileName);

                }

            }else{



            }



        }



    }



    private static String getFileName(String input) {

        String values = input.split("\s+");

        String fileName = "";

        for(String s : values) {

            if(s.indexOf(".") > 0) {

                fileName = s;

                break;

            }

        }

        return fileName;

    }



}

edited Dec 18 '12 at 23:12

answered Dec 18 '12 at 22:30

Festus Tamakloe

9,68484559

Whenever you have questions, feel free to ask

– Festus Tamakloe
Dec 18 '12 at 22:32

,yup i think its kind of what i want i just dont get this : for(String s : values) { if(s.indexOf(".") > 0) { fileName = s; break; why did you do this?

– Angelo Mico
Dec 18 '12 at 22:49

for(String s : values) ==> iteration/loop over the values if(s.indexOf(".") > 0) ==> here we want to which word has an extension in another which word contains(".") if we get one we passe it to fileName then we do not need anymore to continue (break). If your satisfy with my answer just vote up and accept it

– Festus Tamakloe
Dec 18 '12 at 22:50

ok,one more thing,I need to have some other options other than "load" like "inspect" an other class etc.. should I continue with this way? put an "else" and carry on with the next option?and do i need to do the thing i asked above again for each of the options i have?

– Angelo Mico
Dec 18 '12 at 23:05

You can do it in the same. but use else if(conditions){} try write a litte method where you can some some codes to avoid the repetition

– Festus Tamakloe
Dec 18 '12 at 23:10

|
show 2 more comments

I try to write a small code for you may be this can help you a little bit

    public class Tester2 {



    /**

     * @param args

     */

    public static void main(String args) {



        boolean state = true;

        while(state) {



            System.out.println("Please enter your text");

            Scanner scan = new Scanner(System.in);

            String input = scan.nextLine();

            if(input.contains("load")) {

                String fileName = getFileName(input);

                if(fileName != "" || fileName!= null) {

                    load(fileName);

                }

            }else{



            }



        }



    }



    private static String getFileName(String input) {

        String values = input.split("\s+");

        String fileName = "";

        for(String s : values) {

            if(s.indexOf(".") > 0) {

                fileName = s;

                break;

            }

        }

        return fileName;

    }



}

edited Dec 18 '12 at 23:12

answered Dec 18 '12 at 22:30

Festus Tamakloe

9,68484559

I try to write a small code for you may be this can help you a little bit

    public class Tester2 {



    /**

     * @param args

     */

    public static void main(String args) {



        boolean state = true;

        while(state) {



            System.out.println("Please enter your text");

            Scanner scan = new Scanner(System.in);

            String input = scan.nextLine();

            if(input.contains("load")) {

                String fileName = getFileName(input);

                if(fileName != "" || fileName!= null) {

                    load(fileName);

                }

            }else{



            }



        }



    }



    private static String getFileName(String input) {

        String values = input.split("\s+");

        String fileName = "";

        for(String s : values) {

            if(s.indexOf(".") > 0) {

                fileName = s;

                break;

            }

        }

        return fileName;

    }



}

edited Dec 18 '12 at 23:12

answered Dec 18 '12 at 22:30

Festus Tamakloe

9,68484559

edited Dec 18 '12 at 23:12

answered Dec 18 '12 at 22:30

Festus Tamakloe

9,68484559

answered Dec 18 '12 at 22:30

Festus Tamakloe

9,68484559

answered Dec 18 '12 at 22:30

Festus Tamakloe

9,68484559

Whenever you have questions, feel free to ask

– Festus Tamakloe
Dec 18 '12 at 22:32

,yup i think its kind of what i want i just dont get this : for(String s : values) { if(s.indexOf(".") > 0) { fileName = s; break; why did you do this?

– Angelo Mico
Dec 18 '12 at 22:49

for(String s : values) ==> iteration/loop over the values if(s.indexOf(".") > 0) ==> here we want to which word has an extension in another which word contains(".") if we get one we passe it to fileName then we do not need anymore to continue (break). If your satisfy with my answer just vote up and accept it

– Festus Tamakloe
Dec 18 '12 at 22:50

ok,one more thing,I need to have some other options other than "load" like "inspect" an other class etc.. should I continue with this way? put an "else" and carry on with the next option?and do i need to do the thing i asked above again for each of the options i have?

– Angelo Mico
Dec 18 '12 at 23:05

You can do it in the same. but use else if(conditions){} try write a litte method where you can some some codes to avoid the repetition

– Festus Tamakloe
Dec 18 '12 at 23:10

|
show 2 more comments

Whenever you have questions, feel free to ask

– Festus Tamakloe
Dec 18 '12 at 22:32

,yup i think its kind of what i want i just dont get this : for(String s : values) { if(s.indexOf(".") > 0) { fileName = s; break; why did you do this?

– Angelo Mico
Dec 18 '12 at 22:49

for(String s : values) ==> iteration/loop over the values if(s.indexOf(".") > 0) ==> here we want to which word has an extension in another which word contains(".") if we get one we passe it to fileName then we do not need anymore to continue (break). If your satisfy with my answer just vote up and accept it

– Festus Tamakloe
Dec 18 '12 at 22:50

ok,one more thing,I need to have some other options other than "load" like "inspect" an other class etc.. should I continue with this way? put an "else" and carry on with the next option?and do i need to do the thing i asked above again for each of the options i have?

– Angelo Mico
Dec 18 '12 at 23:05

You can do it in the same. but use else if(conditions){} try write a litte method where you can some some codes to avoid the repetition

– Festus Tamakloe
Dec 18 '12 at 23:10

Whenever you have questions, feel free to ask

– Festus Tamakloe
Dec 18 '12 at 22:32

,yup i think its kind of what i want i just dont get this : for(String s : values) { if(s.indexOf(".") > 0) { fileName = s; break; why did you do this?

– Angelo Mico
Dec 18 '12 at 22:49

for(String s : values) ==> iteration/loop over the values if(s.indexOf(".") > 0) ==> here we want to which word has an extension in another which word contains(".") if we get one we passe it to fileName then we do not need anymore to continue (break). If your satisfy with my answer just vote up and accept it

– Festus Tamakloe
Dec 18 '12 at 22:50

ok,one more thing,I need to have some other options other than "load" like "inspect" an other class etc.. should I continue with this way? put an "else" and carry on with the next option?and do i need to do the thing i asked above again for each of the options i have?

– Angelo Mico
Dec 18 '12 at 23:05

You can do it in the same. but use else if(conditions){} try write a litte method where you can some some codes to avoid the repetition

– Festus Tamakloe
Dec 18 '12 at 23:10

|
show 2 more comments

It's too long for a comment, and I don't really understand what your last comment means. Here's some sample code. Try it with inputs like

load filename.txt

load foo bar baz

save foo

whatever ...

System.out.println("What would you like to do");

Scanner scanner = new Scanner(System.in);

String line = scanner.nextLine();

String input = line.split("\s+");

if (input[0].equals("load")) {

    for (int i = 1; i < input.length; i++) {

        System.out.println("Token #" + i + " after load: " + input[i]);

    }

} else {

    System.out.println("You did not enter load, I ignore your input");

}

If you have a question about the behavior or anything else: feel free to leave a comment.

answered Dec 18 '12 at 23:07

jlordo

31.1k54371

add a comment |

It's too long for a comment, and I don't really understand what your last comment means. Here's some sample code. Try it with inputs like

load filename.txt

load foo bar baz

save foo

whatever ...

System.out.println("What would you like to do");

Scanner scanner = new Scanner(System.in);

String line = scanner.nextLine();

String input = line.split("\s+");

if (input[0].equals("load")) {

    for (int i = 1; i < input.length; i++) {

        System.out.println("Token #" + i + " after load: " + input[i]);

    }

} else {

    System.out.println("You did not enter load, I ignore your input");

}

If you have a question about the behavior or anything else: feel free to leave a comment.

answered Dec 18 '12 at 23:07

jlordo

31.1k54371

add a comment |

It's too long for a comment, and I don't really understand what your last comment means. Here's some sample code. Try it with inputs like

load filename.txt

load foo bar baz

save foo

whatever ...

System.out.println("What would you like to do");

Scanner scanner = new Scanner(System.in);

String line = scanner.nextLine();

String input = line.split("\s+");

if (input[0].equals("load")) {

    for (int i = 1; i < input.length; i++) {

        System.out.println("Token #" + i + " after load: " + input[i]);

    }

} else {

    System.out.println("You did not enter load, I ignore your input");

}

If you have a question about the behavior or anything else: feel free to leave a comment.

answered Dec 18 '12 at 23:07

jlordo

31.1k54371

It's too long for a comment, and I don't really understand what your last comment means. Here's some sample code. Try it with inputs like

load filename.txt

load foo bar baz

save foo

whatever ...

System.out.println("What would you like to do");

Scanner scanner = new Scanner(System.in);

String line = scanner.nextLine();

String input = line.split("\s+");

if (input[0].equals("load")) {

    for (int i = 1; i < input.length; i++) {

        System.out.println("Token #" + i + " after load: " + input[i]);

    }

} else {

    System.out.println("You did not enter load, I ignore your input");

}

If you have a question about the behavior or anything else: feel free to leave a comment.

answered Dec 18 '12 at 23:07

jlordo

31.1k54371

answered Dec 18 '12 at 23:07

jlordo

31.1k54371

answered Dec 18 '12 at 23:07

jlordo

31.1k54371

answered Dec 18 '12 at 23:07

jlordo

31.1k54371

add a comment |

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