Conformal group of closed ball












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I read recently the follow affirmation on book "The Smith Conjectura" written by John W. Morgan and Hyman Bass : Every conformal transformation of unit sphere $S^2$ is has an unique conformal extention to closed unit ball , and this conformal extention is an isometry of hiperbolic space $H^{n + 1}$ as ball model ". My question is if this affirmation is true in dimention $n geq 2$. Of more way exact, I want of know if the relation between conformal transformation group is true. I read some texts, o Liouville Theorem, but not find nothings about the closed case.










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  • 1




    $begingroup$
    This is a direct corollary of Liouville's theorem: Every conformal automorphism of $S^n$ is Moebius and Moebius transformations are exactly the restrictions of isometries of the hyperbolic space $H^{n+1}$ in the unit ball model. One way to see this is that each Moebius transformation is a composition of inversions and each inversion acting on $S^n$ extends uniquely to an inversion acting on $S^{n+1}$.
    $endgroup$
    – Moishe Cohen
    Jan 11 at 0:14
















0












$begingroup$


I read recently the follow affirmation on book "The Smith Conjectura" written by John W. Morgan and Hyman Bass : Every conformal transformation of unit sphere $S^2$ is has an unique conformal extention to closed unit ball , and this conformal extention is an isometry of hiperbolic space $H^{n + 1}$ as ball model ". My question is if this affirmation is true in dimention $n geq 2$. Of more way exact, I want of know if the relation between conformal transformation group is true. I read some texts, o Liouville Theorem, but not find nothings about the closed case.










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    This is a direct corollary of Liouville's theorem: Every conformal automorphism of $S^n$ is Moebius and Moebius transformations are exactly the restrictions of isometries of the hyperbolic space $H^{n+1}$ in the unit ball model. One way to see this is that each Moebius transformation is a composition of inversions and each inversion acting on $S^n$ extends uniquely to an inversion acting on $S^{n+1}$.
    $endgroup$
    – Moishe Cohen
    Jan 11 at 0:14














0












0








0





$begingroup$


I read recently the follow affirmation on book "The Smith Conjectura" written by John W. Morgan and Hyman Bass : Every conformal transformation of unit sphere $S^2$ is has an unique conformal extention to closed unit ball , and this conformal extention is an isometry of hiperbolic space $H^{n + 1}$ as ball model ". My question is if this affirmation is true in dimention $n geq 2$. Of more way exact, I want of know if the relation between conformal transformation group is true. I read some texts, o Liouville Theorem, but not find nothings about the closed case.










share|cite|improve this question









$endgroup$




I read recently the follow affirmation on book "The Smith Conjectura" written by John W. Morgan and Hyman Bass : Every conformal transformation of unit sphere $S^2$ is has an unique conformal extention to closed unit ball , and this conformal extention is an isometry of hiperbolic space $H^{n + 1}$ as ball model ". My question is if this affirmation is true in dimention $n geq 2$. Of more way exact, I want of know if the relation between conformal transformation group is true. I read some texts, o Liouville Theorem, but not find nothings about the closed case.







riemannian-geometry






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asked Jan 10 at 17:56









A.D.A.D.

375110




375110








  • 1




    $begingroup$
    This is a direct corollary of Liouville's theorem: Every conformal automorphism of $S^n$ is Moebius and Moebius transformations are exactly the restrictions of isometries of the hyperbolic space $H^{n+1}$ in the unit ball model. One way to see this is that each Moebius transformation is a composition of inversions and each inversion acting on $S^n$ extends uniquely to an inversion acting on $S^{n+1}$.
    $endgroup$
    – Moishe Cohen
    Jan 11 at 0:14














  • 1




    $begingroup$
    This is a direct corollary of Liouville's theorem: Every conformal automorphism of $S^n$ is Moebius and Moebius transformations are exactly the restrictions of isometries of the hyperbolic space $H^{n+1}$ in the unit ball model. One way to see this is that each Moebius transformation is a composition of inversions and each inversion acting on $S^n$ extends uniquely to an inversion acting on $S^{n+1}$.
    $endgroup$
    – Moishe Cohen
    Jan 11 at 0:14








1




1




$begingroup$
This is a direct corollary of Liouville's theorem: Every conformal automorphism of $S^n$ is Moebius and Moebius transformations are exactly the restrictions of isometries of the hyperbolic space $H^{n+1}$ in the unit ball model. One way to see this is that each Moebius transformation is a composition of inversions and each inversion acting on $S^n$ extends uniquely to an inversion acting on $S^{n+1}$.
$endgroup$
– Moishe Cohen
Jan 11 at 0:14




$begingroup$
This is a direct corollary of Liouville's theorem: Every conformal automorphism of $S^n$ is Moebius and Moebius transformations are exactly the restrictions of isometries of the hyperbolic space $H^{n+1}$ in the unit ball model. One way to see this is that each Moebius transformation is a composition of inversions and each inversion acting on $S^n$ extends uniquely to an inversion acting on $S^{n+1}$.
$endgroup$
– Moishe Cohen
Jan 11 at 0:14










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