Mixing
Creating random colour in Java?
53
I want to draw random coloured points on a JPanel in a Java application. Is there any method to create random colours?
java colors random
edited Jan 19 '15 at 17:59
Boann
36.9k1290121
asked Nov 22 '10 at 14:22
Elton.fdElton.fd
71031123
add a comment |
53
I want to draw random coloured points on a JPanel in a Java application. Is there any method to create random colours?
java colors random
edited Jan 19 '15 at 17:59
Boann
36.9k1290121
asked Nov 22 '10 at 14:22
Elton.fdElton.fd
71031123
add a comment |
53
53
53
24
I want to draw random coloured points on a JPanel in a Java application. Is there any method to create random colours?
java colors random
edited Jan 19 '15 at 17:59
Boann
36.9k1290121
asked Nov 22 '10 at 14:22
Elton.fdElton.fd
71031123
I want to draw random coloured points on a JPanel in a Java application. Is there any method to create random colours?
java colors random
java colors random
edited Jan 19 '15 at 17:59
Boann
36.9k1290121
asked Nov 22 '10 at 14:22
Elton.fdElton.fd
71031123
edited Jan 19 '15 at 17:59
Boann
36.9k1290121
asked Nov 22 '10 at 14:22
Elton.fdElton.fd
71031123
edited Jan 19 '15 at 17:59
Boann
36.9k1290121
edited Jan 19 '15 at 17:59
Boann
36.9k1290121
edited Jan 19 '15 at 17:59
Boann
36.9k1290121
36.9k1290121
asked Nov 22 '10 at 14:22
Elton.fdElton.fd
71031123
asked Nov 22 '10 at 14:22
Elton.fdElton.fd
71031123
asked Nov 22 '10 at 14:22
Elton.fdElton.fd
71031123
71031123
add a comment |
add a comment |
14 Answers
14
active
oldest
votes
99
Use the random library:
import java.util.Random;
Then create a random generator:
Random rand = new Random();
As colours are separated into red green and blue, you can create a new random colour by creating random primary colours:
// Java 'Color' class takes 3 floats, from 0 to 1.
float r = rand.nextFloat();
float g = rand.nextFloat();
float b = rand.nextFloat();
Then to finally create the colour, pass the primary colours into the constructor:
Color randomColor = new Color(r, g, b);
You can also create different random effects using this method, such as creating random colours with more emphasis on certain colours ... pass in less green and blue to produce a "pinker" random colour.
// Will produce a random colour with more red in it (usually "pink-ish")
float r = rand.nextFloat();
float g = rand.nextFloat() / 2f;
float b = rand.nextFloat() / 2f;
Or to ensure that only "light" colours are generated, you can generate colours that are always > 0.5 of each colour element:
// Will produce only bright / light colours:
float r = rand.nextFloat() / 2f + 0.5;
float g = rand.nextFloat() / 2f + 0.5;
float b = rand.nextFloat() / 2f + 0.5;
There are various other colour functions that can be used with the Color class, such as making the colour brighter:
randomColor.brighter();
An overview of the Color class can be read here: http://download.oracle.com/javase/6/docs/api/java/awt/Color.html
edited Jul 24 '15 at 18:10
Panda TG Attwood
593824
answered Nov 22 '10 at 14:28
GregGreg
15.1k106693
2
your code for will only produce bright/light colors will not work. next float does not accept float nor double as an argument and adding .5 makes color go out of range.
– Xitcod13
Jun 6 '14 at 14:08
Do these colors look good? Do you have a picture?
– Thomas Ahle
Jun 27 '14 at 13:52
@ThomasAhle It will produce any and every possible colour. I can't draw that in a picture. :)
– Greg
Jun 27 '14 at 15:04
1
As suggested above, doesn't exist anymore a nextFloat constructor that accepts a parameter.
– giaffa86
May 8 '15 at 7:24
If you want a more "purple" tone of colors what would be the code changes?
– kabuto178
Jul 2 '16 at 14:06
|
show 1 more comment
32
A one-liner for random RGB values:
new Color((int)(Math.random() * 0x1000000))
answered Nov 17 '13 at 14:46
BoannBoann
36.9k1290121
add a comment |
28
If you want pleasing, pastel colors, it is best to use the HLS system.
final float hue = random.nextFloat();
// Saturation between 0.1 and 0.3
final float saturation = (random.nextInt(2000) + 1000) / 10000f;
final float luminance = 0.9f;
final Color color = Color.getHSBColor(hue, saturation, luminance);
answered Nov 22 '10 at 15:45
Sualeh FatehiSualeh Fatehi
3,75011625
1
Do you have a sample with some of the colors this generates?
– Thomas Ahle
Jun 27 '14 at 13:53
add a comment |
17
Copy paste this for bright pastel rainbow colors
int R = (int)(Math.random()*256);
int G = (int)(Math.random()*256);
int B= (int)(Math.random()*256);
Color color = new Color(R, G, B); //random color, but can be bright or dull
//to get rainbow, pastel colors
Random random = new Random();
final float hue = random.nextFloat();
final float saturation = 0.9f;//1.0 for brilliant, 0.0 for dull
final float luminance = 1.0f; //1.0 for brighter, 0.0 for black
color = Color.getHSBColor(hue, saturation, luminance);
answered Jan 5 '12 at 7:54
KomplotKomplot
44647
Works great, thanks Komplot!
– Sahil Muthoo
Jan 27 '12 at 12:04
@Komplot: Very nice...
– Mani
Jun 16 '14 at 11:26
I prefer this way (HSB) of picking a random color. Using the RGB system can create very weird combinations. As a side note, the hue value is internally multiplied by 360 to produce the hue angle in the HSB color model (Javadoc).
– patrickGranite
Apr 22 '16 at 14:33
add a comment |
9
If you don't want it to look horrible I'd suggest defining a list of colours in an array and then using a random number generator to pick one.
If you want a truly random colour you can just generate 3 random numbers from 0 to 255 and then use the Color(int,int,int) constructor to create a new Color instance.
Random randomGenerator = new Random();
int red = randomGenerator.nextInt(256);
int green = randomGenerator.nextInt(256);
int blue = randomGenerator.nextInt(256);
Color randomColour = new Color(red,green,blue);
edited Dec 22 '14 at 4:12
Boann
36.9k1290121
answered Nov 22 '10 at 14:26
Rob Stevenson-LeggettRob Stevenson-Leggett
21.8k1779134
1
And this way you can easily avoid points that are the same colour as the background.
– sje397
Nov 22 '10 at 14:29
add a comment |
5
I know it's a bit late for this answer, but I've not seen anyone else put this.
Like Greg said, you want to use the Random class
Random rand = new Random();
but the difference I'm going to say is simple do this:
Color color = new Color(rand.nextInt(0xFFFFFF));
And it's as simple as that! no need to generate lots of different floats.
answered Feb 11 '14 at 11:31
Shaun WildShaun Wild
63921130
Ahh. That's why I must have just skipped over it. The extra colour won't make a difference however :P
– Shaun Wild
Feb 11 '14 at 12:34
add a comment |
4
import android.graphics.Color;
import java.util.Random;
public class ColorDiagram {
// Member variables (properties about the object)
public String mColors = {
"#39add1", // light blue
"#3079ab", // dark blue
"#c25975", // mauve
"#e15258", // red
"#f9845b", // orange
"#838cc7", // lavender
"#7d669e", // purple
"#53bbb4", // aqua
"#51b46d", // green
"#e0ab18", // mustard
"#637a91", // dark gray
"#f092b0", // pink
"#b7c0c7" // light gray
};
// Method (abilities: things the object can do)
public int getColor() {
String color = "";
// Randomly select a fact
Random randomGenerator = new Random(); // Construct a new Random number generator
int randomNumber = randomGenerator.nextInt(mColors.length);
color = mColors[randomNumber];
int colorAsInt = Color.parseColor(color);
return colorAsInt;
}
}
answered Dec 28 '15 at 16:45
Durul DalkanatDurul Dalkanat
4,81622732
Thanks, I know how to do this...but I didn't feel like it and you saved me some time!
– ryanp102694
Dec 12 '18 at 4:05
add a comment |
2
I have used this simple and clever way for creating random color in Java,
Random random = new Random();
System.out.println(String.format("#%06x", random.nextInt(256*256*256)));
Where #%06x gives you zero-padded hex (always 6 characters long).
answered Jan 12 '18 at 13:31
Deepak KumbharDeepak Kumbhar
131210
add a comment |
1
You can instantiate a color with three floats (r, g, b), each between 0.0 and 1.0: http://download.oracle.com/javase/6/docs/api/java/awt/Color.html#Color(float,%20float,%20float).
Using Java's Random class you can easily instantiate a new random color as such:
Random r = new Random();
Color randomColor = new Color(r.nextFloat(), r.nextFloat(), r.nextFloat());
I can't guarantee they'll all be pretty, but they'll be random =)
answered Nov 22 '10 at 14:27
Jason NicholsJason Nichols
9,91642950
add a comment |
1
Sure. Just generate a color using random RGB values. Like:
public Color randomColor()
{
Random random=new Random(); // Probably really put this somewhere where it gets executed only once
int red=random.nextInt(256);
int green=random.nextInt(256);
int blue=random.nextInt(256);
return new Color(red, green, blue);
}
You might want to vary up the generation of the random numbers if you don't like the colors it comes up with. I'd guess these will tend to be fairly dark.
answered Nov 22 '10 at 14:30
JayJay
22.3k74787
1
It's great. but, what can i do for creating lighter color?
– Elton.fd
Nov 22 '10 at 14:44
you can use the Color.brighter() method to make any generated color look like.
– Andrew
Nov 22 '10 at 14:48
1
Sandra, to influence the brightness, make sure the random values are never very dark. 0 is darkest and 255 is brightest, so just do a random.nextInt(128) + 128 for example to never get any colers darker than half brightness.
– Stijn de Witt
Nov 22 '10 at 14:49
yes, It works nice, thanks :)
– Elton.fd
Nov 22 '10 at 15:03
@Stijn: Ditto. I might add that if you want more uniform brightness, you might make the 2nd value depend on the 1st and the 3rd depending on the first two. Like say red=nextInt(255); green=nextInt(255-red); etc. You could play with this sort of thing endlessly until you get the results you want.
– Jay
Nov 23 '10 at 17:22
|
show 2 more comments
1
You seem to want light random colors. Not sure what you mean exactly with light. But if you want random 'rainbow colors', try this
Random r = new Random();
Color c = Color.getHSBColor(r.nextFloat(),//random hue, color
1.0,//full saturation, 1.0 for 'colorful' colors, 0.0 for grey
1.0 //1.0 for bright, 0.0 for black
);
Search for HSB color model for more information.
answered Nov 22 '10 at 15:37
IshtarIshtar
10.3k11830
add a comment |
0
package com.adil.util;
/**
* The Class RandomColor.
*
* @author Adil OUIDAD
* @URL : http://kizana.fr
*/
public class RandomColor {
/**
* Gets the random color.
*
* @return the random color
*/
public static String getRandomColor() {
String letters = {"0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"};
String color = "#";
for (int i = 0; i < 6; i++ ) {
color += letters[(int) Math.round(Math.random() * 15)];
}
return color;
}
}
edited Nov 17 '13 at 14:38
Hitham S. AlQadheeb
11.9k33262
answered Jun 8 '13 at 20:54
user1942990user1942990
6416
add a comment |
0
Here is a method for getting a random color:
private static Random sRandom;
public static synchronized int randomColor() {
if (sRandom == null) {
sRandom = new Random();
}
return 0xff000000 + 256 * 256 * sRandom.nextInt(256) + 256 * sRandom.nextInt(256)
+ sRandom.nextInt(256);
}
Benefits:
- Get the integer representation which can be used with
java.awt.Colororandroid.graphics.Color
- Keep a static reference to
Random.
answered Jan 19 '15 at 8:54
Jared RummlerJared Rummler
29.4k1396119
add a comment |
-1
It would be helpful.
Random randomGenerator = new Random();
int red = randomGenerator.nextInt(255);
int green = randomGenerator.nextInt(255);
int blue = randomGenerator.nextInt(255);
Color randomColour = new Color(red,green,blue);
edited Dec 3 '14 at 6:12
Evan Knowles
5,69112359
answered Dec 3 '14 at 5:27
K.MaheshK.Mahesh
11
All you did was copy-paste the other answer.
– Boann
Dec 3 '14 at 13:46
I tried this..It is working..that's whay I prefer this..
– K.Mahesh
Dec 4 '14 at 5:10
Oh I see. That's not what we do on Stack Overflow. The thing to do is earn 15 rep on the site (by posting new useful questions and answers), so you can vote up the answers you find useful.
– Boann
Dec 4 '14 at 13:01
Okay..Next time I'll focus on that.
– K.Mahesh
Dec 5 '14 at 5:45
add a comment |
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14 Answers
14
active
oldest
votes
14 Answers
14
active
oldest
votes
active
oldest
votes
active
oldest
votes
99
Use the random library:
import java.util.Random;
Then create a random generator:
Random rand = new Random();
As colours are separated into red green and blue, you can create a new random colour by creating random primary colours:
// Java 'Color' class takes 3 floats, from 0 to 1.
float r = rand.nextFloat();
float g = rand.nextFloat();
float b = rand.nextFloat();
Then to finally create the colour, pass the primary colours into the constructor:
Color randomColor = new Color(r, g, b);
You can also create different random effects using this method, such as creating random colours with more emphasis on certain colours ... pass in less green and blue to produce a "pinker" random colour.
// Will produce a random colour with more red in it (usually "pink-ish")
float r = rand.nextFloat();
float g = rand.nextFloat() / 2f;
float b = rand.nextFloat() / 2f;
Or to ensure that only "light" colours are generated, you can generate colours that are always > 0.5 of each colour element:
// Will produce only bright / light colours:
float r = rand.nextFloat() / 2f + 0.5;
float g = rand.nextFloat() / 2f + 0.5;
float b = rand.nextFloat() / 2f + 0.5;
There are various other colour functions that can be used with the Color class, such as making the colour brighter:
randomColor.brighter();
An overview of the Color class can be read here: http://download.oracle.com/javase/6/docs/api/java/awt/Color.html
edited Jul 24 '15 at 18:10
Panda TG Attwood
593824
answered Nov 22 '10 at 14:28
GregGreg
15.1k106693
2
your code for will only produce bright/light colors will not work. next float does not accept float nor double as an argument and adding .5 makes color go out of range.
– Xitcod13
Jun 6 '14 at 14:08
Do these colors look good? Do you have a picture?
– Thomas Ahle
Jun 27 '14 at 13:52
@ThomasAhle It will produce any and every possible colour. I can't draw that in a picture. :)
– Greg
Jun 27 '14 at 15:04
1
As suggested above, doesn't exist anymore a nextFloat constructor that accepts a parameter.
– giaffa86
May 8 '15 at 7:24
If you want a more "purple" tone of colors what would be the code changes?
– kabuto178
Jul 2 '16 at 14:06
|
show 1 more comment
99
Use the random library:
import java.util.Random;
Then create a random generator:
Random rand = new Random();
As colours are separated into red green and blue, you can create a new random colour by creating random primary colours:
// Java 'Color' class takes 3 floats, from 0 to 1.
float r = rand.nextFloat();
float g = rand.nextFloat();
float b = rand.nextFloat();
Then to finally create the colour, pass the primary colours into the constructor:
Color randomColor = new Color(r, g, b);
You can also create different random effects using this method, such as creating random colours with more emphasis on certain colours ... pass in less green and blue to produce a "pinker" random colour.
// Will produce a random colour with more red in it (usually "pink-ish")
float r = rand.nextFloat();
float g = rand.nextFloat() / 2f;
float b = rand.nextFloat() / 2f;
Or to ensure that only "light" colours are generated, you can generate colours that are always > 0.5 of each colour element:
// Will produce only bright / light colours:
float r = rand.nextFloat() / 2f + 0.5;
float g = rand.nextFloat() / 2f + 0.5;
float b = rand.nextFloat() / 2f + 0.5;
There are various other colour functions that can be used with the Color class, such as making the colour brighter:
randomColor.brighter();
An overview of the Color class can be read here: http://download.oracle.com/javase/6/docs/api/java/awt/Color.html
edited Jul 24 '15 at 18:10
Panda TG Attwood
593824
answered Nov 22 '10 at 14:28
GregGreg
15.1k106693
2
your code for will only produce bright/light colors will not work. next float does not accept float nor double as an argument and adding .5 makes color go out of range.
– Xitcod13
Jun 6 '14 at 14:08
Do these colors look good? Do you have a picture?
– Thomas Ahle
Jun 27 '14 at 13:52
@ThomasAhle It will produce any and every possible colour. I can't draw that in a picture. :)
– Greg
Jun 27 '14 at 15:04
1
As suggested above, doesn't exist anymore a nextFloat constructor that accepts a parameter.
– giaffa86
May 8 '15 at 7:24
If you want a more "purple" tone of colors what would be the code changes?
– kabuto178
Jul 2 '16 at 14:06
|
show 1 more comment
99
99
99
Use the random library:
import java.util.Random;
Then create a random generator:
Random rand = new Random();
As colours are separated into red green and blue, you can create a new random colour by creating random primary colours:
// Java 'Color' class takes 3 floats, from 0 to 1.
float r = rand.nextFloat();
float g = rand.nextFloat();
float b = rand.nextFloat();
Then to finally create the colour, pass the primary colours into the constructor:
Color randomColor = new Color(r, g, b);
You can also create different random effects using this method, such as creating random colours with more emphasis on certain colours ... pass in less green and blue to produce a "pinker" random colour.
// Will produce a random colour with more red in it (usually "pink-ish")
float r = rand.nextFloat();
float g = rand.nextFloat() / 2f;
float b = rand.nextFloat() / 2f;
Or to ensure that only "light" colours are generated, you can generate colours that are always > 0.5 of each colour element:
// Will produce only bright / light colours:
float r = rand.nextFloat() / 2f + 0.5;
float g = rand.nextFloat() / 2f + 0.5;
float b = rand.nextFloat() / 2f + 0.5;
There are various other colour functions that can be used with the Color class, such as making the colour brighter:
randomColor.brighter();
An overview of the Color class can be read here: http://download.oracle.com/javase/6/docs/api/java/awt/Color.html
edited Jul 24 '15 at 18:10
Panda TG Attwood
593824
answered Nov 22 '10 at 14:28
GregGreg
15.1k106693
Use the random library:
import java.util.Random;
Then create a random generator:
Random rand = new Random();
As colours are separated into red green and blue, you can create a new random colour by creating random primary colours:
// Java 'Color' class takes 3 floats, from 0 to 1.
float r = rand.nextFloat();
float g = rand.nextFloat();
float b = rand.nextFloat();
Then to finally create the colour, pass the primary colours into the constructor:
Color randomColor = new Color(r, g, b);
You can also create different random effects using this method, such as creating random colours with more emphasis on certain colours ... pass in less green and blue to produce a "pinker" random colour.
// Will produce a random colour with more red in it (usually "pink-ish")
float r = rand.nextFloat();
float g = rand.nextFloat() / 2f;
float b = rand.nextFloat() / 2f;
Or to ensure that only "light" colours are generated, you can generate colours that are always > 0.5 of each colour element:
// Will produce only bright / light colours:
float r = rand.nextFloat() / 2f + 0.5;
float g = rand.nextFloat() / 2f + 0.5;
float b = rand.nextFloat() / 2f + 0.5;
There are various other colour functions that can be used with the Color class, such as making the colour brighter:
randomColor.brighter();
An overview of the Color class can be read here: http://download.oracle.com/javase/6/docs/api/java/awt/Color.html
edited Jul 24 '15 at 18:10
Panda TG Attwood
593824
answered Nov 22 '10 at 14:28
GregGreg
15.1k106693
edited Jul 24 '15 at 18:10
Panda TG Attwood
593824
edited Jul 24 '15 at 18:10
Panda TG Attwood
593824
edited Jul 24 '15 at 18:10
Panda TG Attwood
593824
593824
answered Nov 22 '10 at 14:28
GregGreg
15.1k106693
answered Nov 22 '10 at 14:28
GregGreg
15.1k106693
answered Nov 22 '10 at 14:28
GregGreg
15.1k106693
15.1k106693
2
your code for will only produce bright/light colors will not work. next float does not accept float nor double as an argument and adding .5 makes color go out of range.
– Xitcod13
Jun 6 '14 at 14:08
Do these colors look good? Do you have a picture?
– Thomas Ahle
Jun 27 '14 at 13:52
@ThomasAhle It will produce any and every possible colour. I can't draw that in a picture. :)
– Greg
Jun 27 '14 at 15:04
1
As suggested above, doesn't exist anymore a nextFloat constructor that accepts a parameter.
– giaffa86
May 8 '15 at 7:24
If you want a more "purple" tone of colors what would be the code changes?
– kabuto178
Jul 2 '16 at 14:06
|
show 1 more comment
2
your code for will only produce bright/light colors will not work. next float does not accept float nor double as an argument and adding .5 makes color go out of range.
– Xitcod13
Jun 6 '14 at 14:08
Do these colors look good? Do you have a picture?
– Thomas Ahle
Jun 27 '14 at 13:52
@ThomasAhle It will produce any and every possible colour. I can't draw that in a picture. :)
– Greg
Jun 27 '14 at 15:04
1
As suggested above, doesn't exist anymore a nextFloat constructor that accepts a parameter.
– giaffa86
May 8 '15 at 7:24
If you want a more "purple" tone of colors what would be the code changes?
– kabuto178
Jul 2 '16 at 14:06
2
2
your code for will only produce bright/light colors will not work. next float does not accept float nor double as an argument and adding .5 makes color go out of range.
– Xitcod13
Jun 6 '14 at 14:08
your code for will only produce bright/light colors will not work. next float does not accept float nor double as an argument and adding .5 makes color go out of range.
– Xitcod13
Jun 6 '14 at 14:08
Do these colors look good? Do you have a picture?
– Thomas Ahle
Jun 27 '14 at 13:52
Do these colors look good? Do you have a picture?
– Thomas Ahle
Jun 27 '14 at 13:52
@ThomasAhle It will produce any and every possible colour. I can't draw that in a picture. :)
– Greg
Jun 27 '14 at 15:04
@ThomasAhle It will produce any and every possible colour. I can't draw that in a picture. :)
– Greg
Jun 27 '14 at 15:04
1
1
As suggested above, doesn't exist anymore a nextFloat constructor that accepts a parameter.
– giaffa86
May 8 '15 at 7:24
As suggested above, doesn't exist anymore a nextFloat constructor that accepts a parameter.
– giaffa86
May 8 '15 at 7:24
If you want a more "purple" tone of colors what would be the code changes?
– kabuto178
Jul 2 '16 at 14:06
If you want a more "purple" tone of colors what would be the code changes?
– kabuto178
Jul 2 '16 at 14:06
|
show 1 more comment
32
A one-liner for random RGB values:
new Color((int)(Math.random() * 0x1000000))
answered Nov 17 '13 at 14:46
BoannBoann
36.9k1290121
add a comment |
32
A one-liner for random RGB values:
new Color((int)(Math.random() * 0x1000000))
answered Nov 17 '13 at 14:46
BoannBoann
36.9k1290121
add a comment |
32
32
32
A one-liner for random RGB values:
new Color((int)(Math.random() * 0x1000000))
answered Nov 17 '13 at 14:46
BoannBoann
36.9k1290121
A one-liner for random RGB values:
new Color((int)(Math.random() * 0x1000000))
answered Nov 17 '13 at 14:46
BoannBoann
36.9k1290121
answered Nov 17 '13 at 14:46
BoannBoann
36.9k1290121
answered Nov 17 '13 at 14:46
BoannBoann
36.9k1290121
answered Nov 17 '13 at 14:46
BoannBoann
36.9k1290121
36.9k1290121
add a comment |
add a comment |
28
If you want pleasing, pastel colors, it is best to use the HLS system.
final float hue = random.nextFloat();
// Saturation between 0.1 and 0.3
final float saturation = (random.nextInt(2000) + 1000) / 10000f;
final float luminance = 0.9f;
final Color color = Color.getHSBColor(hue, saturation, luminance);
answered Nov 22 '10 at 15:45
Sualeh FatehiSualeh Fatehi
3,75011625
1
Do you have a sample with some of the colors this generates?
– Thomas Ahle
Jun 27 '14 at 13:53
add a comment |
28
If you want pleasing, pastel colors, it is best to use the HLS system.
final float hue = random.nextFloat();
// Saturation between 0.1 and 0.3
final float saturation = (random.nextInt(2000) + 1000) / 10000f;
final float luminance = 0.9f;
final Color color = Color.getHSBColor(hue, saturation, luminance);
answered Nov 22 '10 at 15:45
Sualeh FatehiSualeh Fatehi
3,75011625
1
Do you have a sample with some of the colors this generates?
– Thomas Ahle
Jun 27 '14 at 13:53
add a comment |
28
28
28
If you want pleasing, pastel colors, it is best to use the HLS system.
final float hue = random.nextFloat();
// Saturation between 0.1 and 0.3
final float saturation = (random.nextInt(2000) + 1000) / 10000f;
final float luminance = 0.9f;
final Color color = Color.getHSBColor(hue, saturation, luminance);
answered Nov 22 '10 at 15:45
Sualeh FatehiSualeh Fatehi
3,75011625
If you want pleasing, pastel colors, it is best to use the HLS system.
final float hue = random.nextFloat();
// Saturation between 0.1 and 0.3
final float saturation = (random.nextInt(2000) + 1000) / 10000f;
final float luminance = 0.9f;
final Color color = Color.getHSBColor(hue, saturation, luminance);
answered Nov 22 '10 at 15:45
Sualeh FatehiSualeh Fatehi
3,75011625
answered Nov 22 '10 at 15:45
Sualeh FatehiSualeh Fatehi
3,75011625
answered Nov 22 '10 at 15:45
Sualeh FatehiSualeh Fatehi
3,75011625
answered Nov 22 '10 at 15:45
Sualeh FatehiSualeh Fatehi
3,75011625
3,75011625
1
Do you have a sample with some of the colors this generates?
– Thomas Ahle
Jun 27 '14 at 13:53
add a comment |
1
Do you have a sample with some of the colors this generates?
– Thomas Ahle
Jun 27 '14 at 13:53
1
1
Do you have a sample with some of the colors this generates?
– Thomas Ahle
Jun 27 '14 at 13:53
Do you have a sample with some of the colors this generates?
– Thomas Ahle
Jun 27 '14 at 13:53
add a comment |
17
Copy paste this for bright pastel rainbow colors
int R = (int)(Math.random()*256);
int G = (int)(Math.random()*256);
int B= (int)(Math.random()*256);
Color color = new Color(R, G, B); //random color, but can be bright or dull
//to get rainbow, pastel colors
Random random = new Random();
final float hue = random.nextFloat();
final float saturation = 0.9f;//1.0 for brilliant, 0.0 for dull
final float luminance = 1.0f; //1.0 for brighter, 0.0 for black
color = Color.getHSBColor(hue, saturation, luminance);
answered Jan 5 '12 at 7:54
KomplotKomplot
44647
Works great, thanks Komplot!
– Sahil Muthoo
Jan 27 '12 at 12:04
@Komplot: Very nice...
– Mani
Jun 16 '14 at 11:26
I prefer this way (HSB) of picking a random color. Using the RGB system can create very weird combinations. As a side note, the hue value is internally multiplied by 360 to produce the hue angle in the HSB color model (Javadoc).
– patrickGranite
Apr 22 '16 at 14:33
add a comment |
17
Copy paste this for bright pastel rainbow colors
int R = (int)(Math.random()*256);
int G = (int)(Math.random()*256);
int B= (int)(Math.random()*256);
Color color = new Color(R, G, B); //random color, but can be bright or dull
//to get rainbow, pastel colors
Random random = new Random();
final float hue = random.nextFloat();
final float saturation = 0.9f;//1.0 for brilliant, 0.0 for dull
final float luminance = 1.0f; //1.0 for brighter, 0.0 for black
color = Color.getHSBColor(hue, saturation, luminance);
answered Jan 5 '12 at 7:54
KomplotKomplot
44647
Works great, thanks Komplot!
– Sahil Muthoo
Jan 27 '12 at 12:04
@Komplot: Very nice...
– Mani
Jun 16 '14 at 11:26
I prefer this way (HSB) of picking a random color. Using the RGB system can create very weird combinations. As a side note, the hue value is internally multiplied by 360 to produce the hue angle in the HSB color model (Javadoc).
– patrickGranite
Apr 22 '16 at 14:33
add a comment |
17
17
17
Copy paste this for bright pastel rainbow colors
int R = (int)(Math.random()*256);
int G = (int)(Math.random()*256);
int B= (int)(Math.random()*256);
Color color = new Color(R, G, B); //random color, but can be bright or dull
//to get rainbow, pastel colors
Random random = new Random();
final float hue = random.nextFloat();
final float saturation = 0.9f;//1.0 for brilliant, 0.0 for dull
final float luminance = 1.0f; //1.0 for brighter, 0.0 for black
color = Color.getHSBColor(hue, saturation, luminance);
answered Jan 5 '12 at 7:54
KomplotKomplot
44647
Copy paste this for bright pastel rainbow colors
int R = (int)(Math.random()*256);
int G = (int)(Math.random()*256);
int B= (int)(Math.random()*256);
Color color = new Color(R, G, B); //random color, but can be bright or dull
//to get rainbow, pastel colors
Random random = new Random();
final float hue = random.nextFloat();
final float saturation = 0.9f;//1.0 for brilliant, 0.0 for dull
final float luminance = 1.0f; //1.0 for brighter, 0.0 for black
color = Color.getHSBColor(hue, saturation, luminance);
answered Jan 5 '12 at 7:54
KomplotKomplot
44647
answered Jan 5 '12 at 7:54
KomplotKomplot
44647
answered Jan 5 '12 at 7:54
KomplotKomplot
44647
answered Jan 5 '12 at 7:54
KomplotKomplot
44647
44647
Works great, thanks Komplot!
– Sahil Muthoo
Jan 27 '12 at 12:04
@Komplot: Very nice...
– Mani
Jun 16 '14 at 11:26
I prefer this way (HSB) of picking a random color. Using the RGB system can create very weird combinations. As a side note, the hue value is internally multiplied by 360 to produce the hue angle in the HSB color model (Javadoc).
– patrickGranite
Apr 22 '16 at 14:33
add a comment |
Works great, thanks Komplot!
– Sahil Muthoo
Jan 27 '12 at 12:04
@Komplot: Very nice...
– Mani
Jun 16 '14 at 11:26
I prefer this way (HSB) of picking a random color. Using the RGB system can create very weird combinations. As a side note, the hue value is internally multiplied by 360 to produce the hue angle in the HSB color model (Javadoc).
– patrickGranite
Apr 22 '16 at 14:33
Works great, thanks Komplot!
– Sahil Muthoo
Jan 27 '12 at 12:04
Works great, thanks Komplot!
– Sahil Muthoo
Jan 27 '12 at 12:04
@Komplot: Very nice...
– Mani
Jun 16 '14 at 11:26
@Komplot: Very nice...
– Mani
Jun 16 '14 at 11:26
I prefer this way (HSB) of picking a random color. Using the RGB system can create very weird combinations. As a side note, the hue value is internally multiplied by 360 to produce the hue angle in the HSB color model (Javadoc).
– patrickGranite
Apr 22 '16 at 14:33
I prefer this way (HSB) of picking a random color. Using the RGB system can create very weird combinations. As a side note, the hue value is internally multiplied by 360 to produce the hue angle in the HSB color model (Javadoc).
– patrickGranite
Apr 22 '16 at 14:33
add a comment |
9
If you don't want it to look horrible I'd suggest defining a list of colours in an array and then using a random number generator to pick one.
If you want a truly random colour you can just generate 3 random numbers from 0 to 255 and then use the Color(int,int,int) constructor to create a new Color instance.
Random randomGenerator = new Random();
int red = randomGenerator.nextInt(256);
int green = randomGenerator.nextInt(256);
int blue = randomGenerator.nextInt(256);
Color randomColour = new Color(red,green,blue);
edited Dec 22 '14 at 4:12
Boann
36.9k1290121
answered Nov 22 '10 at 14:26
Rob Stevenson-LeggettRob Stevenson-Leggett
21.8k1779134
1
And this way you can easily avoid points that are the same colour as the background.
– sje397
Nov 22 '10 at 14:29
add a comment |
9
If you don't want it to look horrible I'd suggest defining a list of colours in an array and then using a random number generator to pick one.
If you want a truly random colour you can just generate 3 random numbers from 0 to 255 and then use the Color(int,int,int) constructor to create a new Color instance.
Random randomGenerator = new Random();
int red = randomGenerator.nextInt(256);
int green = randomGenerator.nextInt(256);
int blue = randomGenerator.nextInt(256);
Color randomColour = new Color(red,green,blue);
edited Dec 22 '14 at 4:12
Boann
36.9k1290121
answered Nov 22 '10 at 14:26
Rob Stevenson-LeggettRob Stevenson-Leggett
21.8k1779134
1
And this way you can easily avoid points that are the same colour as the background.
– sje397
Nov 22 '10 at 14:29
add a comment |
9
9
9
If you don't want it to look horrible I'd suggest defining a list of colours in an array and then using a random number generator to pick one.
If you want a truly random colour you can just generate 3 random numbers from 0 to 255 and then use the Color(int,int,int) constructor to create a new Color instance.
Random randomGenerator = new Random();
int red = randomGenerator.nextInt(256);
int green = randomGenerator.nextInt(256);
int blue = randomGenerator.nextInt(256);
Color randomColour = new Color(red,green,blue);
edited Dec 22 '14 at 4:12
Boann
36.9k1290121
answered Nov 22 '10 at 14:26
Rob Stevenson-LeggettRob Stevenson-Leggett
21.8k1779134
If you don't want it to look horrible I'd suggest defining a list of colours in an array and then using a random number generator to pick one.
If you want a truly random colour you can just generate 3 random numbers from 0 to 255 and then use the Color(int,int,int) constructor to create a new Color instance.
Random randomGenerator = new Random();
int red = randomGenerator.nextInt(256);
int green = randomGenerator.nextInt(256);
int blue = randomGenerator.nextInt(256);
Color randomColour = new Color(red,green,blue);
edited Dec 22 '14 at 4:12
Boann
36.9k1290121
answered Nov 22 '10 at 14:26
Rob Stevenson-LeggettRob Stevenson-Leggett
21.8k1779134
edited Dec 22 '14 at 4:12
Boann
36.9k1290121
edited Dec 22 '14 at 4:12
Boann
36.9k1290121
edited Dec 22 '14 at 4:12
Boann
36.9k1290121
36.9k1290121
answered Nov 22 '10 at 14:26
Rob Stevenson-LeggettRob Stevenson-Leggett
21.8k1779134
answered Nov 22 '10 at 14:26
Rob Stevenson-LeggettRob Stevenson-Leggett
21.8k1779134
answered Nov 22 '10 at 14:26
Rob Stevenson-LeggettRob Stevenson-Leggett
21.8k1779134
21.8k1779134
1
And this way you can easily avoid points that are the same colour as the background.
– sje397
Nov 22 '10 at 14:29
add a comment |
1
And this way you can easily avoid points that are the same colour as the background.
– sje397
Nov 22 '10 at 14:29
1
1
And this way you can easily avoid points that are the same colour as the background.
– sje397
Nov 22 '10 at 14:29
And this way you can easily avoid points that are the same colour as the background.
– sje397
Nov 22 '10 at 14:29
add a comment |
5
I know it's a bit late for this answer, but I've not seen anyone else put this.
Like Greg said, you want to use the Random class
Random rand = new Random();
but the difference I'm going to say is simple do this:
Color color = new Color(rand.nextInt(0xFFFFFF));
And it's as simple as that! no need to generate lots of different floats.
answered Feb 11 '14 at 11:31
Shaun WildShaun Wild
63921130
Ahh. That's why I must have just skipped over it. The extra colour won't make a difference however :P
– Shaun Wild
Feb 11 '14 at 12:34
add a comment |
5
I know it's a bit late for this answer, but I've not seen anyone else put this.
Like Greg said, you want to use the Random class
Random rand = new Random();
but the difference I'm going to say is simple do this:
Color color = new Color(rand.nextInt(0xFFFFFF));
And it's as simple as that! no need to generate lots of different floats.
answered Feb 11 '14 at 11:31
Shaun WildShaun Wild
63921130
Ahh. That's why I must have just skipped over it. The extra colour won't make a difference however :P
– Shaun Wild
Feb 11 '14 at 12:34
add a comment |
5
5
5
I know it's a bit late for this answer, but I've not seen anyone else put this.
Like Greg said, you want to use the Random class
Random rand = new Random();
but the difference I'm going to say is simple do this:
Color color = new Color(rand.nextInt(0xFFFFFF));
And it's as simple as that! no need to generate lots of different floats.
answered Feb 11 '14 at 11:31
Shaun WildShaun Wild
63921130
I know it's a bit late for this answer, but I've not seen anyone else put this.
Like Greg said, you want to use the Random class
Random rand = new Random();
but the difference I'm going to say is simple do this:
Color color = new Color(rand.nextInt(0xFFFFFF));
And it's as simple as that! no need to generate lots of different floats.
answered Feb 11 '14 at 11:31
Shaun WildShaun Wild
63921130
answered Feb 11 '14 at 11:31
Shaun WildShaun Wild
63921130
answered Feb 11 '14 at 11:31
Shaun WildShaun Wild
63921130
answered Feb 11 '14 at 11:31
Shaun WildShaun Wild
63921130
63921130
Ahh. That's why I must have just skipped over it. The extra colour won't make a difference however :P
– Shaun Wild
Feb 11 '14 at 12:34
add a comment |
Ahh. That's why I must have just skipped over it. The extra colour won't make a difference however :P
– Shaun Wild
Feb 11 '14 at 12:34
Ahh. That's why I must have just skipped over it. The extra colour won't make a difference however :P
– Shaun Wild
Feb 11 '14 at 12:34
Ahh. That's why I must have just skipped over it. The extra colour won't make a difference however :P
– Shaun Wild
Feb 11 '14 at 12:34
add a comment |
4
import android.graphics.Color;
import java.util.Random;
public class ColorDiagram {
// Member variables (properties about the object)
public String mColors = {
"#39add1", // light blue
"#3079ab", // dark blue
"#c25975", // mauve
"#e15258", // red
"#f9845b", // orange
"#838cc7", // lavender
"#7d669e", // purple
"#53bbb4", // aqua
"#51b46d", // green
"#e0ab18", // mustard
"#637a91", // dark gray
"#f092b0", // pink
"#b7c0c7" // light gray
};
// Method (abilities: things the object can do)
public int getColor() {
String color = "";
// Randomly select a fact
Random randomGenerator = new Random(); // Construct a new Random number generator
int randomNumber = randomGenerator.nextInt(mColors.length);
color = mColors[randomNumber];
int colorAsInt = Color.parseColor(color);
return colorAsInt;
}
}
answered Dec 28 '15 at 16:45
Durul DalkanatDurul Dalkanat
4,81622732
Thanks, I know how to do this...but I didn't feel like it and you saved me some time!
– ryanp102694
Dec 12 '18 at 4:05
add a comment |
4
import android.graphics.Color;
import java.util.Random;
public class ColorDiagram {
// Member variables (properties about the object)
public String mColors = {
"#39add1", // light blue
"#3079ab", // dark blue
"#c25975", // mauve
"#e15258", // red
"#f9845b", // orange
"#838cc7", // lavender
"#7d669e", // purple
"#53bbb4", // aqua
"#51b46d", // green
"#e0ab18", // mustard
"#637a91", // dark gray
"#f092b0", // pink
"#b7c0c7" // light gray
};
// Method (abilities: things the object can do)
public int getColor() {
String color = "";
// Randomly select a fact
Random randomGenerator = new Random(); // Construct a new Random number generator
int randomNumber = randomGenerator.nextInt(mColors.length);
color = mColors[randomNumber];
int colorAsInt = Color.parseColor(color);
return colorAsInt;
}
}
answered Dec 28 '15 at 16:45
Durul DalkanatDurul Dalkanat
4,81622732
Thanks, I know how to do this...but I didn't feel like it and you saved me some time!
– ryanp102694
Dec 12 '18 at 4:05
add a comment |
4
4
4
import android.graphics.Color;
import java.util.Random;
public class ColorDiagram {
// Member variables (properties about the object)
public String mColors = {
"#39add1", // light blue
"#3079ab", // dark blue
"#c25975", // mauve
"#e15258", // red
"#f9845b", // orange
"#838cc7", // lavender
"#7d669e", // purple
"#53bbb4", // aqua
"#51b46d", // green
"#e0ab18", // mustard
"#637a91", // dark gray
"#f092b0", // pink
"#b7c0c7" // light gray
};
// Method (abilities: things the object can do)
public int getColor() {
String color = "";
// Randomly select a fact
Random randomGenerator = new Random(); // Construct a new Random number generator
int randomNumber = randomGenerator.nextInt(mColors.length);
color = mColors[randomNumber];
int colorAsInt = Color.parseColor(color);
return colorAsInt;
}
}
answered Dec 28 '15 at 16:45
Durul DalkanatDurul Dalkanat
4,81622732
import android.graphics.Color;
import java.util.Random;
public class ColorDiagram {
// Member variables (properties about the object)
public String mColors = {
"#39add1", // light blue
"#3079ab", // dark blue
"#c25975", // mauve
"#e15258", // red
"#f9845b", // orange
"#838cc7", // lavender
"#7d669e", // purple
"#53bbb4", // aqua
"#51b46d", // green
"#e0ab18", // mustard
"#637a91", // dark gray
"#f092b0", // pink
"#b7c0c7" // light gray
};
// Method (abilities: things the object can do)
public int getColor() {
String color = "";
// Randomly select a fact
Random randomGenerator = new Random(); // Construct a new Random number generator
int randomNumber = randomGenerator.nextInt(mColors.length);
color = mColors[randomNumber];
int colorAsInt = Color.parseColor(color);
return colorAsInt;
}
}
answered Dec 28 '15 at 16:45
Durul DalkanatDurul Dalkanat
4,81622732
answered Dec 28 '15 at 16:45
Durul DalkanatDurul Dalkanat
4,81622732
answered Dec 28 '15 at 16:45
Durul DalkanatDurul Dalkanat
4,81622732
answered Dec 28 '15 at 16:45
Durul DalkanatDurul Dalkanat
4,81622732
4,81622732
Thanks, I know how to do this...but I didn't feel like it and you saved me some time!
– ryanp102694
Dec 12 '18 at 4:05
add a comment |
Thanks, I know how to do this...but I didn't feel like it and you saved me some time!
– ryanp102694
Dec 12 '18 at 4:05
Thanks, I know how to do this...but I didn't feel like it and you saved me some time!
– ryanp102694
Dec 12 '18 at 4:05
Thanks, I know how to do this...but I didn't feel like it and you saved me some time!
– ryanp102694
Dec 12 '18 at 4:05
add a comment |
2
I have used this simple and clever way for creating random color in Java,
Random random = new Random();
System.out.println(String.format("#%06x", random.nextInt(256*256*256)));
Where #%06x gives you zero-padded hex (always 6 characters long).
answered Jan 12 '18 at 13:31
Deepak KumbharDeepak Kumbhar
131210
add a comment |
2
I have used this simple and clever way for creating random color in Java,
Random random = new Random();
System.out.println(String.format("#%06x", random.nextInt(256*256*256)));
Where #%06x gives you zero-padded hex (always 6 characters long).
answered Jan 12 '18 at 13:31
Deepak KumbharDeepak Kumbhar
131210
add a comment |
2
2
2
I have used this simple and clever way for creating random color in Java,
Random random = new Random();
System.out.println(String.format("#%06x", random.nextInt(256*256*256)));
Where #%06x gives you zero-padded hex (always 6 characters long).
answered Jan 12 '18 at 13:31
Deepak KumbharDeepak Kumbhar
131210
I have used this simple and clever way for creating random color in Java,
Random random = new Random();
System.out.println(String.format("#%06x", random.nextInt(256*256*256)));
Where #%06x gives you zero-padded hex (always 6 characters long).
answered Jan 12 '18 at 13:31
Deepak KumbharDeepak Kumbhar
131210
answered Jan 12 '18 at 13:31
Deepak KumbharDeepak Kumbhar
131210
answered Jan 12 '18 at 13:31
Deepak KumbharDeepak Kumbhar
131210
answered Jan 12 '18 at 13:31
Deepak KumbharDeepak Kumbhar
131210
131210
add a comment |
add a comment |
1
You can instantiate a color with three floats (r, g, b), each between 0.0 and 1.0: http://download.oracle.com/javase/6/docs/api/java/awt/Color.html#Color(float,%20float,%20float).
Using Java's Random class you can easily instantiate a new random color as such:
Random r = new Random();
Color randomColor = new Color(r.nextFloat(), r.nextFloat(), r.nextFloat());
I can't guarantee they'll all be pretty, but they'll be random =)
answered Nov 22 '10 at 14:27
Jason NicholsJason Nichols
9,91642950
add a comment |
1
You can instantiate a color with three floats (r, g, b), each between 0.0 and 1.0: http://download.oracle.com/javase/6/docs/api/java/awt/Color.html#Color(float,%20float,%20float).
Using Java's Random class you can easily instantiate a new random color as such:
Random r = new Random();
Color randomColor = new Color(r.nextFloat(), r.nextFloat(), r.nextFloat());
I can't guarantee they'll all be pretty, but they'll be random =)
answered Nov 22 '10 at 14:27
Jason NicholsJason Nichols
9,91642950
add a comment |
1
1
1
You can instantiate a color with three floats (r, g, b), each between 0.0 and 1.0: http://download.oracle.com/javase/6/docs/api/java/awt/Color.html#Color(float,%20float,%20float).
Using Java's Random class you can easily instantiate a new random color as such:
Random r = new Random();
Color randomColor = new Color(r.nextFloat(), r.nextFloat(), r.nextFloat());
I can't guarantee they'll all be pretty, but they'll be random =)
answered Nov 22 '10 at 14:27
Jason NicholsJason Nichols
9,91642950
You can instantiate a color with three floats (r, g, b), each between 0.0 and 1.0: http://download.oracle.com/javase/6/docs/api/java/awt/Color.html#Color(float,%20float,%20float).
Using Java's Random class you can easily instantiate a new random color as such:
Random r = new Random();
Color randomColor = new Color(r.nextFloat(), r.nextFloat(), r.nextFloat());
I can't guarantee they'll all be pretty, but they'll be random =)
answered Nov 22 '10 at 14:27
Jason NicholsJason Nichols
9,91642950
answered Nov 22 '10 at 14:27
Jason NicholsJason Nichols
9,91642950
answered Nov 22 '10 at 14:27
Jason NicholsJason Nichols
9,91642950
answered Nov 22 '10 at 14:27
Jason NicholsJason Nichols
9,91642950
9,91642950
add a comment |
add a comment |
1
Sure. Just generate a color using random RGB values. Like:
public Color randomColor()
{
Random random=new Random(); // Probably really put this somewhere where it gets executed only once
int red=random.nextInt(256);
int green=random.nextInt(256);
int blue=random.nextInt(256);
return new Color(red, green, blue);
}
You might want to vary up the generation of the random numbers if you don't like the colors it comes up with. I'd guess these will tend to be fairly dark.
answered Nov 22 '10 at 14:30
JayJay
22.3k74787
1
It's great. but, what can i do for creating lighter color?
– Elton.fd
Nov 22 '10 at 14:44
you can use the Color.brighter() method to make any generated color look like.
– Andrew
Nov 22 '10 at 14:48
1
Sandra, to influence the brightness, make sure the random values are never very dark. 0 is darkest and 255 is brightest, so just do a random.nextInt(128) + 128 for example to never get any colers darker than half brightness.
– Stijn de Witt
Nov 22 '10 at 14:49
yes, It works nice, thanks :)
– Elton.fd
Nov 22 '10 at 15:03
@Stijn: Ditto. I might add that if you want more uniform brightness, you might make the 2nd value depend on the 1st and the 3rd depending on the first two. Like say red=nextInt(255); green=nextInt(255-red); etc. You could play with this sort of thing endlessly until you get the results you want.
– Jay
Nov 23 '10 at 17:22
|
show 2 more comments
1
Sure. Just generate a color using random RGB values. Like:
public Color randomColor()
{
Random random=new Random(); // Probably really put this somewhere where it gets executed only once
int red=random.nextInt(256);
int green=random.nextInt(256);
int blue=random.nextInt(256);
return new Color(red, green, blue);
}
You might want to vary up the generation of the random numbers if you don't like the colors it comes up with. I'd guess these will tend to be fairly dark.
answered Nov 22 '10 at 14:30
JayJay
22.3k74787
1
It's great. but, what can i do for creating lighter color?
– Elton.fd
Nov 22 '10 at 14:44
you can use the Color.brighter() method to make any generated color look like.
– Andrew
Nov 22 '10 at 14:48
1
Sandra, to influence the brightness, make sure the random values are never very dark. 0 is darkest and 255 is brightest, so just do a random.nextInt(128) + 128 for example to never get any colers darker than half brightness.
– Stijn de Witt
Nov 22 '10 at 14:49
yes, It works nice, thanks :)
– Elton.fd
Nov 22 '10 at 15:03
@Stijn: Ditto. I might add that if you want more uniform brightness, you might make the 2nd value depend on the 1st and the 3rd depending on the first two. Like say red=nextInt(255); green=nextInt(255-red); etc. You could play with this sort of thing endlessly until you get the results you want.
– Jay
Nov 23 '10 at 17:22
|
show 2 more comments
1
1
1
Sure. Just generate a color using random RGB values. Like:
public Color randomColor()
{
Random random=new Random(); // Probably really put this somewhere where it gets executed only once
int red=random.nextInt(256);
int green=random.nextInt(256);
int blue=random.nextInt(256);
return new Color(red, green, blue);
}
You might want to vary up the generation of the random numbers if you don't like the colors it comes up with. I'd guess these will tend to be fairly dark.
answered Nov 22 '10 at 14:30
JayJay
22.3k74787
Sure. Just generate a color using random RGB values. Like:
public Color randomColor()
{
Random random=new Random(); // Probably really put this somewhere where it gets executed only once
int red=random.nextInt(256);
int green=random.nextInt(256);
int blue=random.nextInt(256);
return new Color(red, green, blue);
}
You might want to vary up the generation of the random numbers if you don't like the colors it comes up with. I'd guess these will tend to be fairly dark.
answered Nov 22 '10 at 14:30
JayJay
22.3k74787
answered Nov 22 '10 at 14:30
JayJay
22.3k74787
answered Nov 22 '10 at 14:30
JayJay
22.3k74787
answered Nov 22 '10 at 14:30
JayJay
22.3k74787
22.3k74787
1
It's great. but, what can i do for creating lighter color?
– Elton.fd
Nov 22 '10 at 14:44
you can use the Color.brighter() method to make any generated color look like.
– Andrew
Nov 22 '10 at 14:48
1
Sandra, to influence the brightness, make sure the random values are never very dark. 0 is darkest and 255 is brightest, so just do a random.nextInt(128) + 128 for example to never get any colers darker than half brightness.
– Stijn de Witt
Nov 22 '10 at 14:49
yes, It works nice, thanks :)
– Elton.fd
Nov 22 '10 at 15:03
@Stijn: Ditto. I might add that if you want more uniform brightness, you might make the 2nd value depend on the 1st and the 3rd depending on the first two. Like say red=nextInt(255); green=nextInt(255-red); etc. You could play with this sort of thing endlessly until you get the results you want.
– Jay
Nov 23 '10 at 17:22
|
show 2 more comments
1
It's great. but, what can i do for creating lighter color?
– Elton.fd
Nov 22 '10 at 14:44
you can use the Color.brighter() method to make any generated color look like.
– Andrew
Nov 22 '10 at 14:48
1
Sandra, to influence the brightness, make sure the random values are never very dark. 0 is darkest and 255 is brightest, so just do a random.nextInt(128) + 128 for example to never get any colers darker than half brightness.
– Stijn de Witt
Nov 22 '10 at 14:49
yes, It works nice, thanks :)
– Elton.fd
Nov 22 '10 at 15:03
@Stijn: Ditto. I might add that if you want more uniform brightness, you might make the 2nd value depend on the 1st and the 3rd depending on the first two. Like say red=nextInt(255); green=nextInt(255-red); etc. You could play with this sort of thing endlessly until you get the results you want.
– Jay
Nov 23 '10 at 17:22
1
1
It's great. but, what can i do for creating lighter color?
– Elton.fd
Nov 22 '10 at 14:44
It's great. but, what can i do for creating lighter color?
– Elton.fd
Nov 22 '10 at 14:44
you can use the Color.brighter() method to make any generated color look like.
– Andrew
Nov 22 '10 at 14:48
you can use the Color.brighter() method to make any generated color look like.
– Andrew
Nov 22 '10 at 14:48
1
1
Sandra, to influence the brightness, make sure the random values are never very dark. 0 is darkest and 255 is brightest, so just do a random.nextInt(128) + 128 for example to never get any colers darker than half brightness.
– Stijn de Witt
Nov 22 '10 at 14:49
Sandra, to influence the brightness, make sure the random values are never very dark. 0 is darkest and 255 is brightest, so just do a random.nextInt(128) + 128 for example to never get any colers darker than half brightness.
– Stijn de Witt
Nov 22 '10 at 14:49
yes, It works nice, thanks :)
– Elton.fd
Nov 22 '10 at 15:03
yes, It works nice, thanks :)
– Elton.fd
Nov 22 '10 at 15:03
@Stijn: Ditto. I might add that if you want more uniform brightness, you might make the 2nd value depend on the 1st and the 3rd depending on the first two. Like say red=nextInt(255); green=nextInt(255-red); etc. You could play with this sort of thing endlessly until you get the results you want.
– Jay
Nov 23 '10 at 17:22
@Stijn: Ditto. I might add that if you want more uniform brightness, you might make the 2nd value depend on the 1st and the 3rd depending on the first two. Like say red=nextInt(255); green=nextInt(255-red); etc. You could play with this sort of thing endlessly until you get the results you want.
– Jay
Nov 23 '10 at 17:22
|
show 2 more comments
1
You seem to want light random colors. Not sure what you mean exactly with light. But if you want random 'rainbow colors', try this
Random r = new Random();
Color c = Color.getHSBColor(r.nextFloat(),//random hue, color
1.0,//full saturation, 1.0 for 'colorful' colors, 0.0 for grey
1.0 //1.0 for bright, 0.0 for black
);
Search for HSB color model for more information.
answered Nov 22 '10 at 15:37
IshtarIshtar
10.3k11830
add a comment |
1
You seem to want light random colors. Not sure what you mean exactly with light. But if you want random 'rainbow colors', try this
Random r = new Random();
Color c = Color.getHSBColor(r.nextFloat(),//random hue, color
1.0,//full saturation, 1.0 for 'colorful' colors, 0.0 for grey
1.0 //1.0 for bright, 0.0 for black
);
Search for HSB color model for more information.
answered Nov 22 '10 at 15:37
IshtarIshtar
10.3k11830
add a comment |
1
1
1
You seem to want light random colors. Not sure what you mean exactly with light. But if you want random 'rainbow colors', try this
Random r = new Random();
Color c = Color.getHSBColor(r.nextFloat(),//random hue, color
1.0,//full saturation, 1.0 for 'colorful' colors, 0.0 for grey
1.0 //1.0 for bright, 0.0 for black
);
Search for HSB color model for more information.
answered Nov 22 '10 at 15:37
IshtarIshtar
10.3k11830
You seem to want light random colors. Not sure what you mean exactly with light. But if you want random 'rainbow colors', try this
Random r = new Random();
Color c = Color.getHSBColor(r.nextFloat(),//random hue, color
1.0,//full saturation, 1.0 for 'colorful' colors, 0.0 for grey
1.0 //1.0 for bright, 0.0 for black
);
Search for HSB color model for more information.
answered Nov 22 '10 at 15:37
IshtarIshtar
10.3k11830
answered Nov 22 '10 at 15:37
IshtarIshtar
10.3k11830
answered Nov 22 '10 at 15:37
IshtarIshtar
10.3k11830
answered Nov 22 '10 at 15:37
IshtarIshtar
10.3k11830
10.3k11830
add a comment |
add a comment |
0
package com.adil.util;
/**
* The Class RandomColor.
*
* @author Adil OUIDAD
* @URL : http://kizana.fr
*/
public class RandomColor {
/**
* Gets the random color.
*
* @return the random color
*/
public static String getRandomColor() {
String letters = {"0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"};
String color = "#";
for (int i = 0; i < 6; i++ ) {
color += letters[(int) Math.round(Math.random() * 15)];
}
return color;
}
}
edited Nov 17 '13 at 14:38
Hitham S. AlQadheeb
11.9k33262
answered Jun 8 '13 at 20:54
user1942990user1942990
6416
add a comment |
0
package com.adil.util;
/**
* The Class RandomColor.
*
* @author Adil OUIDAD
* @URL : http://kizana.fr
*/
public class RandomColor {
/**
* Gets the random color.
*
* @return the random color
*/
public static String getRandomColor() {
String letters = {"0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"};
String color = "#";
for (int i = 0; i < 6; i++ ) {
color += letters[(int) Math.round(Math.random() * 15)];
}
return color;
}
}
edited Nov 17 '13 at 14:38
Hitham S. AlQadheeb
11.9k33262
answered Jun 8 '13 at 20:54
user1942990user1942990
6416
add a comment |
0
0
0
package com.adil.util;
/**
* The Class RandomColor.
*
* @author Adil OUIDAD
* @URL : http://kizana.fr
*/
public class RandomColor {
/**
* Gets the random color.
*
* @return the random color
*/
public static String getRandomColor() {
String letters = {"0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"};
String color = "#";
for (int i = 0; i < 6; i++ ) {
color += letters[(int) Math.round(Math.random() * 15)];
}
return color;
}
}
edited Nov 17 '13 at 14:38
Hitham S. AlQadheeb
11.9k33262
answered Jun 8 '13 at 20:54
user1942990user1942990
6416
package com.adil.util;
/**
* The Class RandomColor.
*
* @author Adil OUIDAD
* @URL : http://kizana.fr
*/
public class RandomColor {
/**
* Gets the random color.
*
* @return the random color
*/
public static String getRandomColor() {
String letters = {"0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"};
String color = "#";
for (int i = 0; i < 6; i++ ) {
color += letters[(int) Math.round(Math.random() * 15)];
}
return color;
}
}
edited Nov 17 '13 at 14:38
Hitham S. AlQadheeb
11.9k33262
answered Jun 8 '13 at 20:54
user1942990user1942990
6416
edited Nov 17 '13 at 14:38
Hitham S. AlQadheeb
11.9k33262
edited Nov 17 '13 at 14:38
Hitham S. AlQadheeb
11.9k33262
edited Nov 17 '13 at 14:38
Hitham S. AlQadheeb
11.9k33262
11.9k33262
answered Jun 8 '13 at 20:54
user1942990user1942990
6416
answered Jun 8 '13 at 20:54
user1942990user1942990
6416
answered Jun 8 '13 at 20:54
user1942990user1942990
6416
6416
add a comment |
add a comment |
0
Here is a method for getting a random color:
private static Random sRandom;
public static synchronized int randomColor() {
if (sRandom == null) {
sRandom = new Random();
}
return 0xff000000 + 256 * 256 * sRandom.nextInt(256) + 256 * sRandom.nextInt(256)
+ sRandom.nextInt(256);
}
Benefits:
- Get the integer representation which can be used with
java.awt.Colororandroid.graphics.Color
- Keep a static reference to
Random.
answered Jan 19 '15 at 8:54
Jared RummlerJared Rummler
29.4k1396119
add a comment |
0
Here is a method for getting a random color:
private static Random sRandom;
public static synchronized int randomColor() {
if (sRandom == null) {
sRandom = new Random();
}
return 0xff000000 + 256 * 256 * sRandom.nextInt(256) + 256 * sRandom.nextInt(256)
+ sRandom.nextInt(256);
}
Benefits:
- Get the integer representation which can be used with
java.awt.Colororandroid.graphics.Color
- Keep a static reference to
Random.
answered Jan 19 '15 at 8:54
Jared RummlerJared Rummler
29.4k1396119
add a comment |
0
0
0
Here is a method for getting a random color:
private static Random sRandom;
public static synchronized int randomColor() {
if (sRandom == null) {
sRandom = new Random();
}
return 0xff000000 + 256 * 256 * sRandom.nextInt(256) + 256 * sRandom.nextInt(256)
+ sRandom.nextInt(256);
}
Benefits:
- Get the integer representation which can be used with
java.awt.Colororandroid.graphics.Color
- Keep a static reference to
Random.
answered Jan 19 '15 at 8:54
Jared RummlerJared Rummler
29.4k1396119
Here is a method for getting a random color:
private static Random sRandom;
public static synchronized int randomColor() {
if (sRandom == null) {
sRandom = new Random();
}
return 0xff000000 + 256 * 256 * sRandom.nextInt(256) + 256 * sRandom.nextInt(256)
+ sRandom.nextInt(256);
}
Benefits:
- Get the integer representation which can be used with
java.awt.Colororandroid.graphics.Color
- Keep a static reference to
Random.
answered Jan 19 '15 at 8:54
Jared RummlerJared Rummler
29.4k1396119
edited Apr 29 '16 at 22:55
answered Jan 19 '15 at 8:54
Jared RummlerJared Rummler
29.4k1396119
answered Jan 19 '15 at 8:54
Jared RummlerJared Rummler
29.4k1396119
answered Jan 19 '15 at 8:54
Jared RummlerJared Rummler
29.4k1396119
29.4k1396119
add a comment |
add a comment |
-1
It would be helpful.
Random randomGenerator = new Random();
int red = randomGenerator.nextInt(255);
int green = randomGenerator.nextInt(255);
int blue = randomGenerator.nextInt(255);
Color randomColour = new Color(red,green,blue);
edited Dec 3 '14 at 6:12
Evan Knowles
5,69112359
answered Dec 3 '14 at 5:27
K.MaheshK.Mahesh
11
All you did was copy-paste the other answer.
– Boann
Dec 3 '14 at 13:46
I tried this..It is working..that's whay I prefer this..
– K.Mahesh
Dec 4 '14 at 5:10
Oh I see. That's not what we do on Stack Overflow. The thing to do is earn 15 rep on the site (by posting new useful questions and answers), so you can vote up the answers you find useful.
– Boann
Dec 4 '14 at 13:01
Okay..Next time I'll focus on that.
– K.Mahesh
Dec 5 '14 at 5:45
add a comment |
-1
It would be helpful.
Random randomGenerator = new Random();
int red = randomGenerator.nextInt(255);
int green = randomGenerator.nextInt(255);
int blue = randomGenerator.nextInt(255);
Color randomColour = new Color(red,green,blue);
edited Dec 3 '14 at 6:12
Evan Knowles
5,69112359
answered Dec 3 '14 at 5:27
K.MaheshK.Mahesh
11
All you did was copy-paste the other answer.
– Boann
Dec 3 '14 at 13:46
I tried this..It is working..that's whay I prefer this..
– K.Mahesh
Dec 4 '14 at 5:10
Oh I see. That's not what we do on Stack Overflow. The thing to do is earn 15 rep on the site (by posting new useful questions and answers), so you can vote up the answers you find useful.
– Boann
Dec 4 '14 at 13:01
Okay..Next time I'll focus on that.
– K.Mahesh
Dec 5 '14 at 5:45
add a comment |
-1
-1
-1
It would be helpful.
Random randomGenerator = new Random();
int red = randomGenerator.nextInt(255);
int green = randomGenerator.nextInt(255);
int blue = randomGenerator.nextInt(255);
Color randomColour = new Color(red,green,blue);
edited Dec 3 '14 at 6:12
Evan Knowles
5,69112359
answered Dec 3 '14 at 5:27
K.MaheshK.Mahesh
11
It would be helpful.
Random randomGenerator = new Random();
int red = randomGenerator.nextInt(255);
int green = randomGenerator.nextInt(255);
int blue = randomGenerator.nextInt(255);
Color randomColour = new Color(red,green,blue);
edited Dec 3 '14 at 6:12
Evan Knowles
5,69112359
answered Dec 3 '14 at 5:27
K.MaheshK.Mahesh
11
edited Dec 3 '14 at 6:12
Evan Knowles
5,69112359
edited Dec 3 '14 at 6:12
Evan Knowles
5,69112359
edited Dec 3 '14 at 6:12
Evan Knowles
5,69112359
5,69112359
answered Dec 3 '14 at 5:27
K.MaheshK.Mahesh
11
answered Dec 3 '14 at 5:27
K.MaheshK.Mahesh
11
answered Dec 3 '14 at 5:27
K.MaheshK.Mahesh
11
11
All you did was copy-paste the other answer.
– Boann
Dec 3 '14 at 13:46
I tried this..It is working..that's whay I prefer this..
– K.Mahesh
Dec 4 '14 at 5:10
Oh I see. That's not what we do on Stack Overflow. The thing to do is earn 15 rep on the site (by posting new useful questions and answers), so you can vote up the answers you find useful.
– Boann
Dec 4 '14 at 13:01
Okay..Next time I'll focus on that.
– K.Mahesh
Dec 5 '14 at 5:45
add a comment |
All you did was copy-paste the other answer.
– Boann
Dec 3 '14 at 13:46
I tried this..It is working..that's whay I prefer this..
– K.Mahesh
Dec 4 '14 at 5:10
Oh I see. That's not what we do on Stack Overflow. The thing to do is earn 15 rep on the site (by posting new useful questions and answers), so you can vote up the answers you find useful.
– Boann
Dec 4 '14 at 13:01
Okay..Next time I'll focus on that.
– K.Mahesh
Dec 5 '14 at 5:45
All you did was copy-paste the other answer.
– Boann
Dec 3 '14 at 13:46
All you did was copy-paste the other answer.
– Boann
Dec 3 '14 at 13:46
I tried this..It is working..that's whay I prefer this..
– K.Mahesh
Dec 4 '14 at 5:10
I tried this..It is working..that's whay I prefer this..
– K.Mahesh
Dec 4 '14 at 5:10
Oh I see. That's not what we do on Stack Overflow. The thing to do is earn 15 rep on the site (by posting new useful questions and answers), so you can vote up the answers you find useful.
– Boann
Dec 4 '14 at 13:01
Oh I see. That's not what we do on Stack Overflow. The thing to do is earn 15 rep on the site (by posting new useful questions and answers), so you can vote up the answers you find useful.
– Boann
Dec 4 '14 at 13:01
Okay..Next time I'll focus on that.
– K.Mahesh
Dec 5 '14 at 5:45
Okay..Next time I'll focus on that.
– K.Mahesh
Dec 5 '14 at 5:45
add a comment |
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