Determine the period for the function y=10cot(10π/11x−7π/11) [closed]

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Determine the period for the function

$y=10cot(frac{10π}{11x}−frac{7π}{11})$

algebra-precalculus periodic-functions

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edited Jan 19 at 1:10

Martin Sleziak

44.7k10119272

asked Jan 18 at 3:28

Anas ChammamAnas Chammam

191

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closed as off-topic by Simply Beautiful Art, Math1000, Martin Sleziak, Shailesh, A. Pongrácz Jan 19 at 7:49

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Simply Beautiful Art, Math1000, Martin Sleziak, Shailesh, A. Pongrácz

If this question can be reworded to fit the rules in the help center, please edit the question.

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  Welcome to MSE! It helps if you can explain what you have tried in the question itself so that you can avoid that whole "Here's my homework, do it for me" vibe, because that's not really what this website is for. I know your intentions probably aren't that, but just for future reference, make sure to include whatever work you have tried, or what in particular you don't understand
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  – Aniruddh Venkatesan
  Jan 18 at 3:34
  

  
  
  
  


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  Dear Downvoters, kindly desist. Give the OP a chance to edit their question.
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  – Rhys Hughes
  Jan 18 at 3:36
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  try graphing with desmos or some other graphing calculator. What do you notice?
  $endgroup$
  – Aniruddh Venkatesan
  Jan 18 at 3:39
  

  
  
  
  

add a comment | 

1

$begingroup$

Determine the period for the function

$y=10cot(frac{10π}{11x}−frac{7π}{11})$

algebra-precalculus periodic-functions

share|cite|improve this question

edited Jan 19 at 1:10

Martin Sleziak

44.7k10119272

asked Jan 18 at 3:28

Anas ChammamAnas Chammam

191

$endgroup$

closed as off-topic by Simply Beautiful Art, Math1000, Martin Sleziak, Shailesh, A. Pongrácz Jan 19 at 7:49

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Simply Beautiful Art, Math1000, Martin Sleziak, Shailesh, A. Pongrácz

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  Welcome to MSE! It helps if you can explain what you have tried in the question itself so that you can avoid that whole "Here's my homework, do it for me" vibe, because that's not really what this website is for. I know your intentions probably aren't that, but just for future reference, make sure to include whatever work you have tried, or what in particular you don't understand
  $endgroup$
  – Aniruddh Venkatesan
  Jan 18 at 3:34
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  Dear Downvoters, kindly desist. Give the OP a chance to edit their question.
  $endgroup$
  – Rhys Hughes
  Jan 18 at 3:36
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  try graphing with desmos or some other graphing calculator. What do you notice?
  $endgroup$
  – Aniruddh Venkatesan
  Jan 18 at 3:39
  

  
  
  
  

add a comment | 

1

1

1

0

$begingroup$

Determine the period for the function

$y=10cot(frac{10π}{11x}−frac{7π}{11})$

algebra-precalculus periodic-functions

share|cite|improve this question

edited Jan 19 at 1:10

Martin Sleziak

44.7k10119272

asked Jan 18 at 3:28

Anas ChammamAnas Chammam

191

$endgroup$

Determine the period for the function

$y=10cot(frac{10π}{11x}−frac{7π}{11})$

algebra-precalculus periodic-functions

algebra-precalculus periodic-functions

share|cite|improve this question

edited Jan 19 at 1:10

Martin Sleziak

44.7k10119272

asked Jan 18 at 3:28

Anas ChammamAnas Chammam

191

share|cite|improve this question

edited Jan 19 at 1:10

Martin Sleziak

44.7k10119272

asked Jan 18 at 3:28

Anas ChammamAnas Chammam

191

share|cite|improve this question

share|cite|improve this question

edited Jan 19 at 1:10

Martin Sleziak

44.7k10119272

edited Jan 19 at 1:10

Martin Sleziak

44.7k10119272

edited Jan 19 at 1:10

Martin Sleziak

44.7k10119272

44.7k10119272

asked Jan 18 at 3:28

Anas ChammamAnas Chammam

191

asked Jan 18 at 3:28

Anas ChammamAnas Chammam

191

asked Jan 18 at 3:28

Anas ChammamAnas Chammam

191

191

closed as off-topic by Simply Beautiful Art, Math1000, Martin Sleziak, Shailesh, A. Pongrácz Jan 19 at 7:49

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Simply Beautiful Art, Math1000, Martin Sleziak, Shailesh, A. Pongrácz

If this question can be reworded to fit the rules in the help center, please edit the question.

closed as off-topic by Simply Beautiful Art, Math1000, Martin Sleziak, Shailesh, A. Pongrácz Jan 19 at 7:49

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Simply Beautiful Art, Math1000, Martin Sleziak, Shailesh, A. Pongrácz

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  Welcome to MSE! It helps if you can explain what you have tried in the question itself so that you can avoid that whole "Here's my homework, do it for me" vibe, because that's not really what this website is for. I know your intentions probably aren't that, but just for future reference, make sure to include whatever work you have tried, or what in particular you don't understand
  $endgroup$
  – Aniruddh Venkatesan
  Jan 18 at 3:34
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  Dear Downvoters, kindly desist. Give the OP a chance to edit their question.
  $endgroup$
  – Rhys Hughes
  Jan 18 at 3:36
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  try graphing with desmos or some other graphing calculator. What do you notice?
  $endgroup$
  – Aniruddh Venkatesan
  Jan 18 at 3:39
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  Welcome to MSE! It helps if you can explain what you have tried in the question itself so that you can avoid that whole "Here's my homework, do it for me" vibe, because that's not really what this website is for. I know your intentions probably aren't that, but just for future reference, make sure to include whatever work you have tried, or what in particular you don't understand
  $endgroup$
  – Aniruddh Venkatesan
  Jan 18 at 3:34
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  Dear Downvoters, kindly desist. Give the OP a chance to edit their question.
  $endgroup$
  – Rhys Hughes
  Jan 18 at 3:36
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  try graphing with desmos or some other graphing calculator. What do you notice?
  $endgroup$
  – Aniruddh Venkatesan
  Jan 18 at 3:39
  

  
  
  
  

2

2

$begingroup$
Welcome to MSE! It helps if you can explain what you have tried in the question itself so that you can avoid that whole "Here's my homework, do it for me" vibe, because that's not really what this website is for. I know your intentions probably aren't that, but just for future reference, make sure to include whatever work you have tried, or what in particular you don't understand
$endgroup$
– Aniruddh Venkatesan
Jan 18 at 3:34

$begingroup$
Welcome to MSE! It helps if you can explain what you have tried in the question itself so that you can avoid that whole "Here's my homework, do it for me" vibe, because that's not really what this website is for. I know your intentions probably aren't that, but just for future reference, make sure to include whatever work you have tried, or what in particular you don't understand
$endgroup$
– Aniruddh Venkatesan
Jan 18 at 3:34

1

1

$begingroup$
Dear Downvoters, kindly desist. Give the OP a chance to edit their question.
$endgroup$
– Rhys Hughes
Jan 18 at 3:36

$begingroup$
Dear Downvoters, kindly desist. Give the OP a chance to edit their question.
$endgroup$
– Rhys Hughes
Jan 18 at 3:36

$begingroup$
try graphing with desmos or some other graphing calculator. What do you notice?
$endgroup$
– Aniruddh Venkatesan
Jan 18 at 3:39

$begingroup$
try graphing with desmos or some other graphing calculator. What do you notice?
$endgroup$
– Aniruddh Venkatesan
Jan 18 at 3:39

add a comment | 

1 Answer
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We know the period of $cot$ is $pi$. So:
$cot(-7pi/11) = cot(pi-7pi/11)$

The LFH corresponds to $x=0$, and in the RHS $x$ can be pinned down by solving:
$10pi/11x-7pi/11=pi-7pi/11 Rightarrow x=11/10$

The period is $11/10-0= 11/10$.

Note: I read the term inside $cot$ to be $10pi x/11$. If was meant to be $10pi /(11x)$ the answer will be different, and the period will not me constant.

share|cite|improve this answer

answered Jan 18 at 3:42

Francisco AndrésFrancisco Andrés

556

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add a comment | 

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

active

oldest

votes

active

oldest

votes

1

$begingroup$

We know the period of $cot$ is $pi$. So:
$cot(-7pi/11) = cot(pi-7pi/11)$

The LFH corresponds to $x=0$, and in the RHS $x$ can be pinned down by solving:
$10pi/11x-7pi/11=pi-7pi/11 Rightarrow x=11/10$

The period is $11/10-0= 11/10$.

Note: I read the term inside $cot$ to be $10pi x/11$. If was meant to be $10pi /(11x)$ the answer will be different, and the period will not me constant.

share|cite|improve this answer

answered Jan 18 at 3:42

Francisco AndrésFrancisco Andrés

556

$endgroup$

add a comment | 

1

$begingroup$

We know the period of $cot$ is $pi$. So:
$cot(-7pi/11) = cot(pi-7pi/11)$

The LFH corresponds to $x=0$, and in the RHS $x$ can be pinned down by solving:
$10pi/11x-7pi/11=pi-7pi/11 Rightarrow x=11/10$

The period is $11/10-0= 11/10$.

Note: I read the term inside $cot$ to be $10pi x/11$. If was meant to be $10pi /(11x)$ the answer will be different, and the period will not me constant.

share|cite|improve this answer

answered Jan 18 at 3:42

Francisco AndrésFrancisco Andrés

556

$endgroup$

add a comment | 

1

1

1

$begingroup$

We know the period of $cot$ is $pi$. So:
$cot(-7pi/11) = cot(pi-7pi/11)$

The LFH corresponds to $x=0$, and in the RHS $x$ can be pinned down by solving:
$10pi/11x-7pi/11=pi-7pi/11 Rightarrow x=11/10$

The period is $11/10-0= 11/10$.

Note: I read the term inside $cot$ to be $10pi x/11$. If was meant to be $10pi /(11x)$ the answer will be different, and the period will not me constant.

share|cite|improve this answer

answered Jan 18 at 3:42

Francisco AndrésFrancisco Andrés

556

$endgroup$

We know the period of $cot$ is $pi$. So:
$cot(-7pi/11) = cot(pi-7pi/11)$

The LFH corresponds to $x=0$, and in the RHS $x$ can be pinned down by solving:
$10pi/11x-7pi/11=pi-7pi/11 Rightarrow x=11/10$

The period is $11/10-0= 11/10$.

Note: I read the term inside $cot$ to be $10pi x/11$. If was meant to be $10pi /(11x)$ the answer will be different, and the period will not me constant.

share|cite|improve this answer

answered Jan 18 at 3:42

Francisco AndrésFrancisco Andrés

556

share|cite|improve this answer

share|cite|improve this answer

answered Jan 18 at 3:42

Francisco AndrésFrancisco Andrés

556

answered Jan 18 at 3:42

Francisco AndrésFrancisco Andrés

556

answered Jan 18 at 3:42

Francisco AndrésFrancisco Andrés

556

556

add a comment | 

add a comment | 

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