How to get id from hyperlink onclick using jquery?

-3

I have hyperlink containing `class="candidate_type". I want click on a button
and show the id of the anchor with the id of candidate_type.

<script>

    $(document).ready(function(){

        $("#continue").click(function(){

            candidate_type = $(".candidate_type").attr('id');

            alert(candidate_type);

        });

    });

</script>



<a class="candidate_type" id="Employer">I`m Employer</a>

<a class="candidate_type" id="Consultant">I`m Consultant</a>



<a href="javascript:void(0)" id="continue" class="btn-new">Continue</a>

Thank You

edited Nov 21 '18 at 5:27

Madison Courto

428312

asked Nov 21 '18 at 5:02

Bruce

235

1

Please provide current output and expected output.

– Jignesh M. Khatri
Nov 21 '18 at 5:05

it only shows Employer when I click on continue while I select employer or consultant @JigneshM.Khatri

– Bruce
Nov 21 '18 at 5:07

What exactly do you mean by "select"? How are you selecting anything?

– Phil
Nov 21 '18 at 5:08

add a comment |

-3

I have hyperlink containing `class="candidate_type". I want click on a button
and show the id of the anchor with the id of candidate_type.

<script>

    $(document).ready(function(){

        $("#continue").click(function(){

            candidate_type = $(".candidate_type").attr('id');

            alert(candidate_type);

        });

    });

</script>



<a class="candidate_type" id="Employer">I`m Employer</a>

<a class="candidate_type" id="Consultant">I`m Consultant</a>



<a href="javascript:void(0)" id="continue" class="btn-new">Continue</a>

Thank You

edited Nov 21 '18 at 5:27

Madison Courto

428312

asked Nov 21 '18 at 5:02

Bruce

235

1

Please provide current output and expected output.

– Jignesh M. Khatri
Nov 21 '18 at 5:05

it only shows Employer when I click on continue while I select employer or consultant @JigneshM.Khatri

– Bruce
Nov 21 '18 at 5:07

What exactly do you mean by "select"? How are you selecting anything?

– Phil
Nov 21 '18 at 5:08

add a comment |

-3

I have hyperlink containing `class="candidate_type". I want click on a button
and show the id of the anchor with the id of candidate_type.

<script>

    $(document).ready(function(){

        $("#continue").click(function(){

            candidate_type = $(".candidate_type").attr('id');

            alert(candidate_type);

        });

    });

</script>



<a class="candidate_type" id="Employer">I`m Employer</a>

<a class="candidate_type" id="Consultant">I`m Consultant</a>



<a href="javascript:void(0)" id="continue" class="btn-new">Continue</a>

Thank You

edited Nov 21 '18 at 5:27

Madison Courto

428312

asked Nov 21 '18 at 5:02

Bruce

235

I have hyperlink containing `class="candidate_type". I want click on a button
and show the id of the anchor with the id of candidate_type.

<script>

    $(document).ready(function(){

        $("#continue").click(function(){

            candidate_type = $(".candidate_type").attr('id');

            alert(candidate_type);

        });

    });

</script>



<a class="candidate_type" id="Employer">I`m Employer</a>

<a class="candidate_type" id="Consultant">I`m Consultant</a>



<a href="javascript:void(0)" id="continue" class="btn-new">Continue</a>

Thank You

javascript jquery

edited Nov 21 '18 at 5:27

Madison Courto

428312

asked Nov 21 '18 at 5:02

Bruce

235

edited Nov 21 '18 at 5:27

Madison Courto

428312

asked Nov 21 '18 at 5:02

Bruce

235

edited Nov 21 '18 at 5:27

Madison Courto

428312

edited Nov 21 '18 at 5:27

Madison Courto

428312

edited Nov 21 '18 at 5:27

Madison Courto

428312

asked Nov 21 '18 at 5:02

Bruce

235

asked Nov 21 '18 at 5:02

Bruce

235

asked Nov 21 '18 at 5:02

Bruce

235

1

Please provide current output and expected output.

– Jignesh M. Khatri
Nov 21 '18 at 5:05

it only shows Employer when I click on continue while I select employer or consultant @JigneshM.Khatri

– Bruce
Nov 21 '18 at 5:07

What exactly do you mean by "select"? How are you selecting anything?

– Phil
Nov 21 '18 at 5:08

add a comment |

1

Please provide current output and expected output.

– Jignesh M. Khatri
Nov 21 '18 at 5:05

it only shows Employer when I click on continue while I select employer or consultant @JigneshM.Khatri

– Bruce
Nov 21 '18 at 5:07

What exactly do you mean by "select"? How are you selecting anything?

– Phil
Nov 21 '18 at 5:08

Please provide current output and expected output.

– Jignesh M. Khatri
Nov 21 '18 at 5:05

it only shows Employer when I click on continue while I select employer or consultant @JigneshM.Khatri

– Bruce
Nov 21 '18 at 5:07

What exactly do you mean by "select"? How are you selecting anything?

– Phil
Nov 21 '18 at 5:08

add a comment |

1 Answer
1

active

oldest

votes

You have more than one candidate_type elements, to get id of all elements you can iterate over it using .each as shown below

    $(document).ready(function(){

        $("#continue").click(function(){

            $(".candidate_type").each(function(){

              var candidate_type = $(this).attr('id');

              alert(candidate_type);

            });

        });

    });

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<a class="candidate_type" id="Employer">I`m Employer</a>

<a class="candidate_type" id="Consultant">I`m Consultant</a>



<a href="javascript:void(0)" id="continue" class="btn-new">Continue</a>

answered Nov 21 '18 at 5:05

Bhushan Kawadkar

23.5k42149

add a comment |

Your Answer

StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});

}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53405542%2fhow-to-get-id-from-hyperlink-onclick-using-jquery%23new-answer', 'question_page');
}
);

Post as a guest

Name

Required, but never shown

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

You have more than one candidate_type elements, to get id of all elements you can iterate over it using .each as shown below

    $(document).ready(function(){

        $("#continue").click(function(){

            $(".candidate_type").each(function(){

              var candidate_type = $(this).attr('id');

              alert(candidate_type);

            });

        });

    });

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<a class="candidate_type" id="Employer">I`m Employer</a>

<a class="candidate_type" id="Consultant">I`m Consultant</a>



<a href="javascript:void(0)" id="continue" class="btn-new">Continue</a>

answered Nov 21 '18 at 5:05

Bhushan Kawadkar

23.5k42149

add a comment |

You have more than one candidate_type elements, to get id of all elements you can iterate over it using .each as shown below

    $(document).ready(function(){

        $("#continue").click(function(){

            $(".candidate_type").each(function(){

              var candidate_type = $(this).attr('id');

              alert(candidate_type);

            });

        });

    });

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<a class="candidate_type" id="Employer">I`m Employer</a>

<a class="candidate_type" id="Consultant">I`m Consultant</a>



<a href="javascript:void(0)" id="continue" class="btn-new">Continue</a>

answered Nov 21 '18 at 5:05

Bhushan Kawadkar

23.5k42149

add a comment |

You have more than one candidate_type elements, to get id of all elements you can iterate over it using .each as shown below

    $(document).ready(function(){

        $("#continue").click(function(){

            $(".candidate_type").each(function(){

              var candidate_type = $(this).attr('id');

              alert(candidate_type);

            });

        });

    });

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<a class="candidate_type" id="Employer">I`m Employer</a>

<a class="candidate_type" id="Consultant">I`m Consultant</a>



<a href="javascript:void(0)" id="continue" class="btn-new">Continue</a>

answered Nov 21 '18 at 5:05

Bhushan Kawadkar

23.5k42149

You have more than one candidate_type elements, to get id of all elements you can iterate over it using .each as shown below

    $(document).ready(function(){

        $("#continue").click(function(){

            $(".candidate_type").each(function(){

              var candidate_type = $(this).attr('id');

              alert(candidate_type);

            });

        });

    });

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<a class="candidate_type" id="Employer">I`m Employer</a>

<a class="candidate_type" id="Consultant">I`m Consultant</a>



<a href="javascript:void(0)" id="continue" class="btn-new">Continue</a>

    $(document).ready(function(){

        $("#continue").click(function(){

            $(".candidate_type").each(function(){

              var candidate_type = $(this).attr('id');

              alert(candidate_type);

            });

        });

    });

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<a class="candidate_type" id="Employer">I`m Employer</a>

<a class="candidate_type" id="Consultant">I`m Consultant</a>



<a href="javascript:void(0)" id="continue" class="btn-new">Continue</a>

    $(document).ready(function(){

        $("#continue").click(function(){

            $(".candidate_type").each(function(){

              var candidate_type = $(this).attr('id');

              alert(candidate_type);

            });

        });

    });

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<a class="candidate_type" id="Employer">I`m Employer</a>

<a class="candidate_type" id="Consultant">I`m Consultant</a>



<a href="javascript:void(0)" id="continue" class="btn-new">Continue</a>

answered Nov 21 '18 at 5:05

Bhushan Kawadkar

23.5k42149

answered Nov 21 '18 at 5:05

Bhushan Kawadkar

23.5k42149

answered Nov 21 '18 at 5:05

Bhushan Kawadkar

23.5k42149

answered Nov 21 '18 at 5:05

Bhushan Kawadkar

23.5k42149

add a comment |

draft saved

draft discarded

Thanks for contributing an answer to Stack Overflow!

Please be sure to answer the question. Provide details and share your research!

But avoid …

Asking for help, clarification, or responding to other answers.

Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Name

Required, but never shown

Name

Required, but never shown

This page is only for reference, If you need detailed information, please check here

Search This Blog

Ufyukyu