proposition with quantifier 5
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I was asked to give an example of a proposition with a quantifier which is true if the quantifier ranges over the integers, but false if it ranges over the rational numbers.
My attempt:
$(forall n in mathbb{Z}, n^2geq n)$
Is this what the question is looking for?
calculus proof-verification proof-explanation
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add a comment |
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I was asked to give an example of a proposition with a quantifier which is true if the quantifier ranges over the integers, but false if it ranges over the rational numbers.
My attempt:
$(forall n in mathbb{Z}, n^2geq n)$
Is this what the question is looking for?
calculus proof-verification proof-explanation
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Your example is perfect. Plus one.
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– Lubin
Jan 9 at 21:39
add a comment |
$begingroup$
I was asked to give an example of a proposition with a quantifier which is true if the quantifier ranges over the integers, but false if it ranges over the rational numbers.
My attempt:
$(forall n in mathbb{Z}, n^2geq n)$
Is this what the question is looking for?
calculus proof-verification proof-explanation
$endgroup$
I was asked to give an example of a proposition with a quantifier which is true if the quantifier ranges over the integers, but false if it ranges over the rational numbers.
My attempt:
$(forall n in mathbb{Z}, n^2geq n)$
Is this what the question is looking for?
calculus proof-verification proof-explanation
calculus proof-verification proof-explanation
asked Jan 9 at 20:39
ForextraderForextrader
677
677
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Your example is perfect. Plus one.
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– Lubin
Jan 9 at 21:39
add a comment |
$begingroup$
Your example is perfect. Plus one.
$endgroup$
– Lubin
Jan 9 at 21:39
$begingroup$
Your example is perfect. Plus one.
$endgroup$
– Lubin
Jan 9 at 21:39
$begingroup$
Your example is perfect. Plus one.
$endgroup$
– Lubin
Jan 9 at 21:39
add a comment |
1 Answer
1
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Here is an example,
$$(forall (n,p)in Bbb N^2);; pnotin (n,n+1)$$
this is not true in $Bbb Q$ since it is dense.
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$begingroup$
Thank you, so mine is not correct?
$endgroup$
– Forextrader
Jan 9 at 20:46
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@Forextrader Yours is correct.
$endgroup$
– hamam_Abdallah
Jan 9 at 20:47
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Here is an example,
$$(forall (n,p)in Bbb N^2);; pnotin (n,n+1)$$
this is not true in $Bbb Q$ since it is dense.
$endgroup$
$begingroup$
Thank you, so mine is not correct?
$endgroup$
– Forextrader
Jan 9 at 20:46
$begingroup$
@Forextrader Yours is correct.
$endgroup$
– hamam_Abdallah
Jan 9 at 20:47
add a comment |
$begingroup$
Here is an example,
$$(forall (n,p)in Bbb N^2);; pnotin (n,n+1)$$
this is not true in $Bbb Q$ since it is dense.
$endgroup$
$begingroup$
Thank you, so mine is not correct?
$endgroup$
– Forextrader
Jan 9 at 20:46
$begingroup$
@Forextrader Yours is correct.
$endgroup$
– hamam_Abdallah
Jan 9 at 20:47
add a comment |
$begingroup$
Here is an example,
$$(forall (n,p)in Bbb N^2);; pnotin (n,n+1)$$
this is not true in $Bbb Q$ since it is dense.
$endgroup$
Here is an example,
$$(forall (n,p)in Bbb N^2);; pnotin (n,n+1)$$
this is not true in $Bbb Q$ since it is dense.
edited Jan 9 at 20:46
answered Jan 9 at 20:45


hamam_Abdallahhamam_Abdallah
38k21634
38k21634
$begingroup$
Thank you, so mine is not correct?
$endgroup$
– Forextrader
Jan 9 at 20:46
$begingroup$
@Forextrader Yours is correct.
$endgroup$
– hamam_Abdallah
Jan 9 at 20:47
add a comment |
$begingroup$
Thank you, so mine is not correct?
$endgroup$
– Forextrader
Jan 9 at 20:46
$begingroup$
@Forextrader Yours is correct.
$endgroup$
– hamam_Abdallah
Jan 9 at 20:47
$begingroup$
Thank you, so mine is not correct?
$endgroup$
– Forextrader
Jan 9 at 20:46
$begingroup$
Thank you, so mine is not correct?
$endgroup$
– Forextrader
Jan 9 at 20:46
$begingroup$
@Forextrader Yours is correct.
$endgroup$
– hamam_Abdallah
Jan 9 at 20:47
$begingroup$
@Forextrader Yours is correct.
$endgroup$
– hamam_Abdallah
Jan 9 at 20:47
add a comment |
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$begingroup$
Your example is perfect. Plus one.
$endgroup$
– Lubin
Jan 9 at 21:39