Mixing
The domain of your function doesn't match that of the correct answer
$begingroup$
After working through this problem, webwork gives me "The domain of your function doesn't match that of the correct answer". Usually this happens if you have a log function that needs absolute value bars or are missing a +C, but that doesn't apply here so I'm wondering if I'm missing something obvious in the question?
$$intfrac{sec^2(8t)tan^2(8t)}{sqrt{16-tan^2(8t)}}dt
$$
image
integration
edited Jan 17 at 23:44
coreyman317
774420
asked Jan 17 at 23:36
JrowJrow
72
$endgroup$
add a comment |
$begingroup$
After working through this problem, webwork gives me "The domain of your function doesn't match that of the correct answer". Usually this happens if you have a log function that needs absolute value bars or are missing a +C, but that doesn't apply here so I'm wondering if I'm missing something obvious in the question?
$$intfrac{sec^2(8t)tan^2(8t)}{sqrt{16-tan^2(8t)}}dt
$$
image
integration
edited Jan 17 at 23:44
coreyman317
774420
asked Jan 17 at 23:36
JrowJrow
72
$endgroup$
add a comment |
$begingroup$
After working through this problem, webwork gives me "The domain of your function doesn't match that of the correct answer". Usually this happens if you have a log function that needs absolute value bars or are missing a +C, but that doesn't apply here so I'm wondering if I'm missing something obvious in the question?
$$intfrac{sec^2(8t)tan^2(8t)}{sqrt{16-tan^2(8t)}}dt
$$
image
integration
edited Jan 17 at 23:44
coreyman317
774420
asked Jan 17 at 23:36
JrowJrow
72
$endgroup$
After working through this problem, webwork gives me "The domain of your function doesn't match that of the correct answer". Usually this happens if you have a log function that needs absolute value bars or are missing a +C, but that doesn't apply here so I'm wondering if I'm missing something obvious in the question?
$$intfrac{sec^2(8t)tan^2(8t)}{sqrt{16-tan^2(8t)}}dt
$$
image
integration
integration
edited Jan 17 at 23:44
coreyman317
774420
asked Jan 17 at 23:36
JrowJrow
72
edited Jan 17 at 23:44
coreyman317
774420
asked Jan 17 at 23:36
JrowJrow
72
edited Jan 17 at 23:44
coreyman317
774420
edited Jan 17 at 23:44
coreyman317
774420
edited Jan 17 at 23:44
coreyman317
774420
774420
asked Jan 17 at 23:36
JrowJrow
72
asked Jan 17 at 23:36
JrowJrow
72
asked Jan 17 at 23:36
JrowJrow
72
72
add a comment |
add a comment |
1 Answer
1
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$begingroup$
I think your problem is that inside the $tan$ you have $8t/4$ and the $4$ should be on the outside of the parens. (Otherwise you'd write $tan 2t$, eh?_)
answered Jan 17 at 23:40
B. GoddardB. Goddard
19.1k21441
$endgroup$
$begingroup$
Perfect! That's totally correct, thanks!
$endgroup$
– Jrow
Jan 17 at 23:47
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
I think your problem is that inside the $tan$ you have $8t/4$ and the $4$ should be on the outside of the parens. (Otherwise you'd write $tan 2t$, eh?_)
answered Jan 17 at 23:40
B. GoddardB. Goddard
19.1k21441
$endgroup$
$begingroup$
Perfect! That's totally correct, thanks!
$endgroup$
– Jrow
Jan 17 at 23:47
add a comment |
$begingroup$
I think your problem is that inside the $tan$ you have $8t/4$ and the $4$ should be on the outside of the parens. (Otherwise you'd write $tan 2t$, eh?_)
answered Jan 17 at 23:40
B. GoddardB. Goddard
19.1k21441
$endgroup$
$begingroup$
Perfect! That's totally correct, thanks!
$endgroup$
– Jrow
Jan 17 at 23:47
add a comment |
$begingroup$
I think your problem is that inside the $tan$ you have $8t/4$ and the $4$ should be on the outside of the parens. (Otherwise you'd write $tan 2t$, eh?_)
answered Jan 17 at 23:40
B. GoddardB. Goddard
19.1k21441
$endgroup$
I think your problem is that inside the $tan$ you have $8t/4$ and the $4$ should be on the outside of the parens. (Otherwise you'd write $tan 2t$, eh?_)
answered Jan 17 at 23:40
B. GoddardB. Goddard
19.1k21441
answered Jan 17 at 23:40
B. GoddardB. Goddard
19.1k21441
answered Jan 17 at 23:40
B. GoddardB. Goddard
19.1k21441
answered Jan 17 at 23:40
B. GoddardB. Goddard
19.1k21441
19.1k21441
$begingroup$
Perfect! That's totally correct, thanks!
$endgroup$
– Jrow
Jan 17 at 23:47
add a comment |
$begingroup$
Perfect! That's totally correct, thanks!
$endgroup$
– Jrow
Jan 17 at 23:47
$begingroup$
Perfect! That's totally correct, thanks!
$endgroup$
– Jrow
Jan 17 at 23:47
$begingroup$
Perfect! That's totally correct, thanks!
$endgroup$
– Jrow
Jan 17 at 23:47
add a comment |
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