DjangoRestFramework - URI with multiple items (cross between a list view and a detail view)












2















django 2.1, python 3.6.



I have a list of items that could contain duplicates. When I pass it to the model and use the in filter, it removes the duplicates . Is there anyway to return a query set with each item in the list instead of each item in the deduped list



card_list = [1,1,2,3]    

qs = Card.objects.filter(id__in=card_list)


qs.count() yields 3
I is there a better command to use that 'in' or a way to join it back to the origial list so I can return with a 4 item queryset?



Thanks






python-3.x django-2.1







share|improve this question



























    2















    django 2.1, python 3.6.



    I have a list of items that could contain duplicates. When I pass it to the model and use the in filter, it removes the duplicates . Is there anyway to return a query set with each item in the list instead of each item in the deduped list



    card_list = [1,1,2,3]    
    
qs = Card.objects.filter(id__in=card_list)


    qs.count() yields 3
    I is there a better command to use that 'in' or a way to join it back to the origial list so I can return with a 4 item queryset?



    Thanks






    python-3.x django-2.1







    share|improve this question

























      2












      2








      2








      django 2.1, python 3.6.



      I have a list of items that could contain duplicates. When I pass it to the model and use the in filter, it removes the duplicates . Is there anyway to return a query set with each item in the list instead of each item in the deduped list



      card_list = [1,1,2,3]    
      
qs = Card.objects.filter(id__in=card_list)


      qs.count() yields 3
      I is there a better command to use that 'in' or a way to join it back to the origial list so I can return with a 4 item queryset?



      Thanks






      python-3.x django-2.1







      share|improve this question














      django 2.1, python 3.6.



      I have a list of items that could contain duplicates. When I pass it to the model and use the in filter, it removes the duplicates . Is there anyway to return a query set with each item in the list instead of each item in the deduped list



      card_list = [1,1,2,3]    
      
qs = Card.objects.filter(id__in=card_list)


      qs.count() yields 3
      I is there a better command to use that 'in' or a way to join it back to the origial list so I can return with a 4 item queryset?



      Thanks






      python-3.x django-2.1




      python-3.x django-2.1






      share|improve this question













      share|improve this question











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      asked Jan 1 at 17:14









      Micah PearceMicah Pearce

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