How to find the number of squares between a range of numbers that are also divisible by $ 12 $?












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I know to find all numbers divisible by $ 12 $ between a range of numbers is something like:



$$ frac{x}{12} - frac{y}{12} + 1, quad text{where} x>y .$$
And to find the number of squares would be:



$$left lfloor{sqrt{y}} rightrfloor- left lceil {sqrt{x}} right rceil + 1$$



Is there some way to calculate the number of numbers that has both qualities?










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    Welcome to MSE! Can you provide some context? See: math.meta.stackexchange.com/questions/9959/…
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    – user549397
    Jan 23 at 2:34


















0












$begingroup$


I know to find all numbers divisible by $ 12 $ between a range of numbers is something like:



$$ frac{x}{12} - frac{y}{12} + 1, quad text{where} x>y .$$
And to find the number of squares would be:



$$left lfloor{sqrt{y}} rightrfloor- left lceil {sqrt{x}} right rceil + 1$$



Is there some way to calculate the number of numbers that has both qualities?










share|cite|improve this question











$endgroup$












  • $begingroup$
    Welcome to MSE! Can you provide some context? See: math.meta.stackexchange.com/questions/9959/…
    $endgroup$
    – user549397
    Jan 23 at 2:34
















0












0








0





$begingroup$


I know to find all numbers divisible by $ 12 $ between a range of numbers is something like:



$$ frac{x}{12} - frac{y}{12} + 1, quad text{where} x>y .$$
And to find the number of squares would be:



$$left lfloor{sqrt{y}} rightrfloor- left lceil {sqrt{x}} right rceil + 1$$



Is there some way to calculate the number of numbers that has both qualities?










share|cite|improve this question











$endgroup$




I know to find all numbers divisible by $ 12 $ between a range of numbers is something like:



$$ frac{x}{12} - frac{y}{12} + 1, quad text{where} x>y .$$
And to find the number of squares would be:



$$left lfloor{sqrt{y}} rightrfloor- left lceil {sqrt{x}} right rceil + 1$$



Is there some way to calculate the number of numbers that has both qualities?







algebra-precalculus






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edited Jan 23 at 5:42









J. W. Tanner

3,1061320




3,1061320










asked Jan 23 at 2:12









Kevin LeKevin Le

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  • $begingroup$
    Welcome to MSE! Can you provide some context? See: math.meta.stackexchange.com/questions/9959/…
    $endgroup$
    – user549397
    Jan 23 at 2:34




















  • $begingroup$
    Welcome to MSE! Can you provide some context? See: math.meta.stackexchange.com/questions/9959/…
    $endgroup$
    – user549397
    Jan 23 at 2:34


















$begingroup$
Welcome to MSE! Can you provide some context? See: math.meta.stackexchange.com/questions/9959/…
$endgroup$
– user549397
Jan 23 at 2:34






$begingroup$
Welcome to MSE! Can you provide some context? See: math.meta.stackexchange.com/questions/9959/…
$endgroup$
– user549397
Jan 23 at 2:34












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To be a square divisible by $12$ a number needs to be divisible by $36$ because you need an even number of factors of $3$. The square root then needs to be divisible by $6$. So find the number of numbers divisible by $6$ between $lceil sqrt x rceil$ and $lfloor sqrt yrfloor$ inclusive






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    $begingroup$

    To be a square divisible by $12$ a number needs to be divisible by $36$ because you need an even number of factors of $3$. The square root then needs to be divisible by $6$. So find the number of numbers divisible by $6$ between $lceil sqrt x rceil$ and $lfloor sqrt yrfloor$ inclusive






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      To be a square divisible by $12$ a number needs to be divisible by $36$ because you need an even number of factors of $3$. The square root then needs to be divisible by $6$. So find the number of numbers divisible by $6$ between $lceil sqrt x rceil$ and $lfloor sqrt yrfloor$ inclusive






      share|cite|improve this answer









      $endgroup$
















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        0





        $begingroup$

        To be a square divisible by $12$ a number needs to be divisible by $36$ because you need an even number of factors of $3$. The square root then needs to be divisible by $6$. So find the number of numbers divisible by $6$ between $lceil sqrt x rceil$ and $lfloor sqrt yrfloor$ inclusive






        share|cite|improve this answer









        $endgroup$



        To be a square divisible by $12$ a number needs to be divisible by $36$ because you need an even number of factors of $3$. The square root then needs to be divisible by $6$. So find the number of numbers divisible by $6$ between $lceil sqrt x rceil$ and $lfloor sqrt yrfloor$ inclusive







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Jan 23 at 2:20









        Ross MillikanRoss Millikan

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        299k24200374






























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