Mixing
Access Object property using key name within map
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I have below array of object
const reports = [{id:3, name:'three', description:'three d', other: 'other 3'}, {id:2, name:'two', description:'two d', other: 'other 2'}];
and I want to filter out only 2 property of each object and below is my desired output
[{id:3, name:'three'}, {id:2, name:'two'}];
so tried this way
const reportList = reports.map((report) => {id,name} );
console.log(reportList);
throw error
ReferenceError: id is not defined
even I can achieve this by using this approach
this.reportList = reports.map((report) => ({
id: report.id,
name: report.name,
description: report.description
}));
but here I need to write extra code, I want to use object accessor using key, can I achieve anyway?
object ecmascript-6
asked Jan 3 at 8:44
diEchodiEcho
38.2k27130202
add a comment |
I have below array of object
const reports = [{id:3, name:'three', description:'three d', other: 'other 3'}, {id:2, name:'two', description:'two d', other: 'other 2'}];
and I want to filter out only 2 property of each object and below is my desired output
[{id:3, name:'three'}, {id:2, name:'two'}];
so tried this way
const reportList = reports.map((report) => {id,name} );
console.log(reportList);
throw error
ReferenceError: id is not defined
even I can achieve this by using this approach
this.reportList = reports.map((report) => ({
id: report.id,
name: report.name,
description: report.description
}));
but here I need to write extra code, I want to use object accessor using key, can I achieve anyway?
object ecmascript-6
asked Jan 3 at 8:44
diEchodiEcho
38.2k27130202
add a comment |
I have below array of object
const reports = [{id:3, name:'three', description:'three d', other: 'other 3'}, {id:2, name:'two', description:'two d', other: 'other 2'}];
and I want to filter out only 2 property of each object and below is my desired output
[{id:3, name:'three'}, {id:2, name:'two'}];
so tried this way
const reportList = reports.map((report) => {id,name} );
console.log(reportList);
throw error
ReferenceError: id is not defined
even I can achieve this by using this approach
this.reportList = reports.map((report) => ({
id: report.id,
name: report.name,
description: report.description
}));
but here I need to write extra code, I want to use object accessor using key, can I achieve anyway?
object ecmascript-6
asked Jan 3 at 8:44
diEchodiEcho
38.2k27130202
I have below array of object
const reports = [{id:3, name:'three', description:'three d', other: 'other 3'}, {id:2, name:'two', description:'two d', other: 'other 2'}];
and I want to filter out only 2 property of each object and below is my desired output
[{id:3, name:'three'}, {id:2, name:'two'}];
so tried this way
const reportList = reports.map((report) => {id,name} );
console.log(reportList);
throw error
ReferenceError: id is not defined
even I can achieve this by using this approach
this.reportList = reports.map((report) => ({
id: report.id,
name: report.name,
description: report.description
}));
but here I need to write extra code, I want to use object accessor using key, can I achieve anyway?
object ecmascript-6
object ecmascript-6
asked Jan 3 at 8:44
diEchodiEcho
38.2k27130202
asked Jan 3 at 8:44
diEchodiEcho
38.2k27130202
asked Jan 3 at 8:44
diEchodiEcho
38.2k27130202
asked Jan 3 at 8:44
diEchodiEcho
38.2k27130202
asked Jan 3 at 8:44
diEchodiEcho
38.2k27130202
38.2k27130202
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You just need to wrap your map arguments like this return object in ()
const reports = [{
id: 3,
name: 'three',
description: 'three d',
other: 'other 3'
}, {
id: 2,
name: 'two',
description: 'two d',
other: 'other 2'
}];
const reportList = reports.map(({id, name}) => ({
id,
name
}));
console.log(reportList);answered Jan 3 at 9:17
Bhargav PatelBhargav Patel
262
Thanks. got it now.
– diEcho
Jan 3 at 9:22
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You just need to wrap your map arguments like this return object in ()
const reports = [{
id: 3,
name: 'three',
description: 'three d',
other: 'other 3'
}, {
id: 2,
name: 'two',
description: 'two d',
other: 'other 2'
}];
const reportList = reports.map(({id, name}) => ({
id,
name
}));
console.log(reportList);answered Jan 3 at 9:17
Bhargav PatelBhargav Patel
262
Thanks. got it now.
– diEcho
Jan 3 at 9:22
add a comment |
You just need to wrap your map arguments like this return object in ()
const reports = [{
id: 3,
name: 'three',
description: 'three d',
other: 'other 3'
}, {
id: 2,
name: 'two',
description: 'two d',
other: 'other 2'
}];
const reportList = reports.map(({id, name}) => ({
id,
name
}));
console.log(reportList);answered Jan 3 at 9:17
Bhargav PatelBhargav Patel
262
Thanks. got it now.
– diEcho
Jan 3 at 9:22
add a comment |
You just need to wrap your map arguments like this return object in ()
const reports = [{
id: 3,
name: 'three',
description: 'three d',
other: 'other 3'
}, {
id: 2,
name: 'two',
description: 'two d',
other: 'other 2'
}];
const reportList = reports.map(({id, name}) => ({
id,
name
}));
console.log(reportList);answered Jan 3 at 9:17
Bhargav PatelBhargav Patel
262
You just need to wrap your map arguments like this return object in ()
const reports = [{
id: 3,
name: 'three',
description: 'three d',
other: 'other 3'
}, {
id: 2,
name: 'two',
description: 'two d',
other: 'other 2'
}];
const reportList = reports.map(({id, name}) => ({
id,
name
}));
console.log(reportList);const reports = [{
id: 3,
name: 'three',
description: 'three d',
other: 'other 3'
}, {
id: 2,
name: 'two',
description: 'two d',
other: 'other 2'
}];
const reportList = reports.map(({id, name}) => ({
id,
name
}));
console.log(reportList);const reports = [{
id: 3,
name: 'three',
description: 'three d',
other: 'other 3'
}, {
id: 2,
name: 'two',
description: 'two d',
other: 'other 2'
}];
const reportList = reports.map(({id, name}) => ({
id,
name
}));
console.log(reportList);answered Jan 3 at 9:17
Bhargav PatelBhargav Patel
262
answered Jan 3 at 9:17
Bhargav PatelBhargav Patel
262
answered Jan 3 at 9:17
Bhargav PatelBhargav Patel
262
answered Jan 3 at 9:17
Bhargav PatelBhargav Patel
262
262
Thanks. got it now.
– diEcho
Jan 3 at 9:22
add a comment |
Thanks. got it now.
– diEcho
Jan 3 at 9:22
Thanks. got it now.
– diEcho
Jan 3 at 9:22
Thanks. got it now.
– diEcho
Jan 3 at 9:22
add a comment |
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