How to get name of an enumeration in MATLAB

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I define an enumerated type in MATLAB

classdef(Enumeration) Color < Simulink.IntEnumType

  enumeration

    RED(0),

    GREEN(1),

    BLUE(2),

  end

end

I can assign it:

>> x = Color.RED    

x = 

    RED

I can display it like this:

>> disp(x)

    RED

or like this

>> x.display()

x =

    RED

How can I get access to that name ("RED") as a string?

In other words I'm lookin for something like:

s = x.toString()

s = tostring(x)

both of which do not work.

edited Aug 27 '13 at 20:37

Amro

116k19210393

asked Feb 22 '10 at 17:33

Philipp

2,10972853

add a comment |

I define an enumerated type in MATLAB

classdef(Enumeration) Color < Simulink.IntEnumType

  enumeration

    RED(0),

    GREEN(1),

    BLUE(2),

  end

end

I can assign it:

>> x = Color.RED    

x = 

    RED

I can display it like this:

>> disp(x)

    RED

or like this

>> x.display()

x =

    RED

How can I get access to that name ("RED") as a string?

In other words I'm lookin for something like:

s = x.toString()

s = tostring(x)

both of which do not work.

edited Aug 27 '13 at 20:37

Amro

116k19210393

asked Feb 22 '10 at 17:33

Philipp

2,10972853

add a comment |

I define an enumerated type in MATLAB

classdef(Enumeration) Color < Simulink.IntEnumType

  enumeration

    RED(0),

    GREEN(1),

    BLUE(2),

  end

end

I can assign it:

>> x = Color.RED    

x = 

    RED

I can display it like this:

>> disp(x)

    RED

or like this

>> x.display()

x =

    RED

How can I get access to that name ("RED") as a string?

In other words I'm lookin for something like:

s = x.toString()

s = tostring(x)

both of which do not work.

edited Aug 27 '13 at 20:37

Amro

116k19210393

asked Feb 22 '10 at 17:33

Philipp

2,10972853

I define an enumerated type in MATLAB

classdef(Enumeration) Color < Simulink.IntEnumType

  enumeration

    RED(0),

    GREEN(1),

    BLUE(2),

  end

end

I can assign it:

>> x = Color.RED    

x = 

    RED

I can display it like this:

>> disp(x)

    RED

or like this

>> x.display()

x =

    RED

How can I get access to that name ("RED") as a string?

In other words I'm lookin for something like:

s = x.toString()

s = tostring(x)

both of which do not work.

matlab oop enums

edited Aug 27 '13 at 20:37

Amro

116k19210393

asked Feb 22 '10 at 17:33

Philipp

2,10972853

edited Aug 27 '13 at 20:37

Amro

116k19210393

asked Feb 22 '10 at 17:33

Philipp

2,10972853

edited Aug 27 '13 at 20:37

Amro

116k19210393

edited Aug 27 '13 at 20:37

Amro

116k19210393

edited Aug 27 '13 at 20:37

Amro

116k19210393

asked Feb 22 '10 at 17:33

Philipp

2,10972853

asked Feb 22 '10 at 17:33

Philipp

2,10972853

asked Feb 22 '10 at 17:33

Philipp

2,10972853

add a comment |

2 Answers
2

active

oldest

votes

You can use:

» str = char(Color.RED)

str =

RED

» class(str)

ans =

char

You can even override the default behaviour:

classdef(Enumeration) Color < int32

 enumeration

  RED(0)

  GREEN(1)

  BLUE(2)

 end



 methods

  function s = char(obj)

   s = ['Color ' num2str(obj)];

   %# or use a switch statement..

  end



  function disp(obj)

   disp( char(obj) )

  end

 end

end

and now:

» char(Color.BLUE)

ans =

Color 2

edited Feb 22 '10 at 19:59

answered Feb 22 '10 at 18:42

Amro

116k19210393

note: since I dont have simulink, I tested the above using the definition: classdef(Enumeration) Color < int32

– Amro
Feb 22 '10 at 18:46

Did you test what str actually was? I can't test it right now, but I think this might just convert the integer representation of the enumerated type to a char (i.e. char(0)).

– gnovice
Feb 22 '10 at 19:41

1

@gnovice: it is returning "RED" as expected

– Amro
Feb 22 '10 at 19:59

Ah, good. Just checking. ;)

– gnovice
Feb 22 '10 at 21:38

add a comment |

A different approach, generic, in your calling entitiy:

strtrim(matlab.unittest.diagnostics.ConstraintDiagnostic.getDisplayableString(Color.BLUE))

This way you can save the class specific implementation of disp() and/or char().

edited Jan 3 at 9:28

answered Jan 3 at 9:07

braggPeaks

591516

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

You can use:

» str = char(Color.RED)

str =

RED

» class(str)

ans =

char

You can even override the default behaviour:

classdef(Enumeration) Color < int32

 enumeration

  RED(0)

  GREEN(1)

  BLUE(2)

 end



 methods

  function s = char(obj)

   s = ['Color ' num2str(obj)];

   %# or use a switch statement..

  end



  function disp(obj)

   disp( char(obj) )

  end

 end

end

and now:

» char(Color.BLUE)

ans =

Color 2

edited Feb 22 '10 at 19:59

answered Feb 22 '10 at 18:42

Amro

116k19210393

note: since I dont have simulink, I tested the above using the definition: classdef(Enumeration) Color < int32

– Amro
Feb 22 '10 at 18:46

Did you test what str actually was? I can't test it right now, but I think this might just convert the integer representation of the enumerated type to a char (i.e. char(0)).

– gnovice
Feb 22 '10 at 19:41

1

@gnovice: it is returning "RED" as expected

– Amro
Feb 22 '10 at 19:59

Ah, good. Just checking. ;)

– gnovice
Feb 22 '10 at 21:38

add a comment |

You can use:

» str = char(Color.RED)

str =

RED

» class(str)

ans =

char

You can even override the default behaviour:

classdef(Enumeration) Color < int32

 enumeration

  RED(0)

  GREEN(1)

  BLUE(2)

 end



 methods

  function s = char(obj)

   s = ['Color ' num2str(obj)];

   %# or use a switch statement..

  end



  function disp(obj)

   disp( char(obj) )

  end

 end

end

and now:

» char(Color.BLUE)

ans =

Color 2

edited Feb 22 '10 at 19:59

answered Feb 22 '10 at 18:42

Amro

116k19210393

note: since I dont have simulink, I tested the above using the definition: classdef(Enumeration) Color < int32

– Amro
Feb 22 '10 at 18:46

Did you test what str actually was? I can't test it right now, but I think this might just convert the integer representation of the enumerated type to a char (i.e. char(0)).

– gnovice
Feb 22 '10 at 19:41

1

@gnovice: it is returning "RED" as expected

– Amro
Feb 22 '10 at 19:59

Ah, good. Just checking. ;)

– gnovice
Feb 22 '10 at 21:38

add a comment |

You can use:

» str = char(Color.RED)

str =

RED

» class(str)

ans =

char

You can even override the default behaviour:

classdef(Enumeration) Color < int32

 enumeration

  RED(0)

  GREEN(1)

  BLUE(2)

 end



 methods

  function s = char(obj)

   s = ['Color ' num2str(obj)];

   %# or use a switch statement..

  end



  function disp(obj)

   disp( char(obj) )

  end

 end

end

and now:

» char(Color.BLUE)

ans =

Color 2

edited Feb 22 '10 at 19:59

answered Feb 22 '10 at 18:42

Amro

116k19210393

You can use:

» str = char(Color.RED)

str =

RED

» class(str)

ans =

char

You can even override the default behaviour:

classdef(Enumeration) Color < int32

 enumeration

  RED(0)

  GREEN(1)

  BLUE(2)

 end



 methods

  function s = char(obj)

   s = ['Color ' num2str(obj)];

   %# or use a switch statement..

  end



  function disp(obj)

   disp( char(obj) )

  end

 end

end

and now:

» char(Color.BLUE)

ans =

Color 2

edited Feb 22 '10 at 19:59

answered Feb 22 '10 at 18:42

Amro

116k19210393

edited Feb 22 '10 at 19:59

answered Feb 22 '10 at 18:42

Amro

116k19210393

answered Feb 22 '10 at 18:42

Amro

116k19210393

answered Feb 22 '10 at 18:42

Amro

116k19210393

note: since I dont have simulink, I tested the above using the definition: classdef(Enumeration) Color < int32

– Amro
Feb 22 '10 at 18:46

Did you test what str actually was? I can't test it right now, but I think this might just convert the integer representation of the enumerated type to a char (i.e. char(0)).

– gnovice
Feb 22 '10 at 19:41

1

@gnovice: it is returning "RED" as expected

– Amro
Feb 22 '10 at 19:59

Ah, good. Just checking. ;)

– gnovice
Feb 22 '10 at 21:38

add a comment |

note: since I dont have simulink, I tested the above using the definition: classdef(Enumeration) Color < int32

– Amro
Feb 22 '10 at 18:46

Did you test what str actually was? I can't test it right now, but I think this might just convert the integer representation of the enumerated type to a char (i.e. char(0)).

– gnovice
Feb 22 '10 at 19:41

1

@gnovice: it is returning "RED" as expected

– Amro
Feb 22 '10 at 19:59

Ah, good. Just checking. ;)

– gnovice
Feb 22 '10 at 21:38

note: since I dont have simulink, I tested the above using the definition: classdef(Enumeration) Color < int32

– Amro
Feb 22 '10 at 18:46

Did you test what str actually was? I can't test it right now, but I think this might just convert the integer representation of the enumerated type to a char (i.e. char(0)).

– gnovice
Feb 22 '10 at 19:41

@gnovice: it is returning "RED" as expected

– Amro
Feb 22 '10 at 19:59

Ah, good. Just checking. ;)

– gnovice
Feb 22 '10 at 21:38

add a comment |

A different approach, generic, in your calling entitiy:

strtrim(matlab.unittest.diagnostics.ConstraintDiagnostic.getDisplayableString(Color.BLUE))

This way you can save the class specific implementation of disp() and/or char().

edited Jan 3 at 9:28

answered Jan 3 at 9:07

braggPeaks

591516

add a comment |

A different approach, generic, in your calling entitiy:

strtrim(matlab.unittest.diagnostics.ConstraintDiagnostic.getDisplayableString(Color.BLUE))

This way you can save the class specific implementation of disp() and/or char().

edited Jan 3 at 9:28

answered Jan 3 at 9:07

braggPeaks

591516

add a comment |

A different approach, generic, in your calling entitiy:

strtrim(matlab.unittest.diagnostics.ConstraintDiagnostic.getDisplayableString(Color.BLUE))

This way you can save the class specific implementation of disp() and/or char().

edited Jan 3 at 9:28

answered Jan 3 at 9:07

braggPeaks

591516

A different approach, generic, in your calling entitiy:

strtrim(matlab.unittest.diagnostics.ConstraintDiagnostic.getDisplayableString(Color.BLUE))

This way you can save the class specific implementation of disp() and/or char().

edited Jan 3 at 9:28

answered Jan 3 at 9:07

braggPeaks

591516

edited Jan 3 at 9:28

answered Jan 3 at 9:07

braggPeaks

591516

answered Jan 3 at 9:07

braggPeaks

591516

answered Jan 3 at 9:07

braggPeaks

591516

add a comment |

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