Mixing
Add items into Tuples within a List
0
I have a list that looks as such:
final_list = (1, "Baseline")
final_list2 = (1, "Baseline")
final = [final_list, final_list2]*7
values = [1.0, None, False, True, 1, 100, 'ovr', 1, 'l2', None, 'liblinear', 0.0001, 0, False]
I would like to insert each element from values into the corresponding element tuple in final. The final result would look like this:
[(1, 'Baseline', 1.0), (1, 'Baseline', None), (1, 'Baseline', False), (1, 'Baseline', True), (1, 'Baseline', 1), (1, 'Baseline', 100), (1, 'Baseline', 'ovr'), (1, 'Baseline', 1), (1, 'Baseline', l2), (1, 'Baseline', None), (1, 'Baseline', 'liblinear'), (1, 'Baseline', 0.0001), (1, 'Baseline',0), (1, 'Baseline', False)]
How can I do this?
python python-3.x
asked Nov 19 '18 at 16:38
Workhorse
439510
add a comment |
0
I have a list that looks as such:
final_list = (1, "Baseline")
final_list2 = (1, "Baseline")
final = [final_list, final_list2]*7
values = [1.0, None, False, True, 1, 100, 'ovr', 1, 'l2', None, 'liblinear', 0.0001, 0, False]
I would like to insert each element from values into the corresponding element tuple in final. The final result would look like this:
[(1, 'Baseline', 1.0), (1, 'Baseline', None), (1, 'Baseline', False), (1, 'Baseline', True), (1, 'Baseline', 1), (1, 'Baseline', 100), (1, 'Baseline', 'ovr'), (1, 'Baseline', 1), (1, 'Baseline', l2), (1, 'Baseline', None), (1, 'Baseline', 'liblinear'), (1, 'Baseline', 0.0001), (1, 'Baseline',0), (1, 'Baseline', False)]
How can I do this?
python python-3.x
asked Nov 19 '18 at 16:38
Workhorse
439510
2
What have you tried so far?
– natn2323
Nov 19 '18 at 16:38
3
Tuples are immutable. You cannot insert a value into an existing tuple; you need to create new tuples.
– chepner
Nov 19 '18 at 16:40
add a comment |
0
0
0
I have a list that looks as such:
final_list = (1, "Baseline")
final_list2 = (1, "Baseline")
final = [final_list, final_list2]*7
values = [1.0, None, False, True, 1, 100, 'ovr', 1, 'l2', None, 'liblinear', 0.0001, 0, False]
I would like to insert each element from values into the corresponding element tuple in final. The final result would look like this:
[(1, 'Baseline', 1.0), (1, 'Baseline', None), (1, 'Baseline', False), (1, 'Baseline', True), (1, 'Baseline', 1), (1, 'Baseline', 100), (1, 'Baseline', 'ovr'), (1, 'Baseline', 1), (1, 'Baseline', l2), (1, 'Baseline', None), (1, 'Baseline', 'liblinear'), (1, 'Baseline', 0.0001), (1, 'Baseline',0), (1, 'Baseline', False)]
How can I do this?
python python-3.x
asked Nov 19 '18 at 16:38
Workhorse
439510
I have a list that looks as such:
final_list = (1, "Baseline")
final_list2 = (1, "Baseline")
final = [final_list, final_list2]*7
values = [1.0, None, False, True, 1, 100, 'ovr', 1, 'l2', None, 'liblinear', 0.0001, 0, False]
I would like to insert each element from values into the corresponding element tuple in final. The final result would look like this:
[(1, 'Baseline', 1.0), (1, 'Baseline', None), (1, 'Baseline', False), (1, 'Baseline', True), (1, 'Baseline', 1), (1, 'Baseline', 100), (1, 'Baseline', 'ovr'), (1, 'Baseline', 1), (1, 'Baseline', l2), (1, 'Baseline', None), (1, 'Baseline', 'liblinear'), (1, 'Baseline', 0.0001), (1, 'Baseline',0), (1, 'Baseline', False)]
How can I do this?
python python-3.x
python python-3.x
asked Nov 19 '18 at 16:38
Workhorse
439510
asked Nov 19 '18 at 16:38
Workhorse
439510
asked Nov 19 '18 at 16:38
Workhorse
439510
asked Nov 19 '18 at 16:38
Workhorse
439510
asked Nov 19 '18 at 16:38
Workhorse
439510
439510
2
What have you tried so far?
– natn2323
Nov 19 '18 at 16:38
3
Tuples are immutable. You cannot insert a value into an existing tuple; you need to create new tuples.
– chepner
Nov 19 '18 at 16:40
add a comment |
2
What have you tried so far?
– natn2323
Nov 19 '18 at 16:38
3
Tuples are immutable. You cannot insert a value into an existing tuple; you need to create new tuples.
– chepner
Nov 19 '18 at 16:40
2
2
What have you tried so far?
– natn2323
Nov 19 '18 at 16:38
What have you tried so far?
– natn2323
Nov 19 '18 at 16:38
3
3
Tuples are immutable. You cannot insert a value into an existing tuple; you need to create new tuples.
– chepner
Nov 19 '18 at 16:40
Tuples are immutable. You cannot insert a value into an existing tuple; you need to create new tuples.
– chepner
Nov 19 '18 at 16:40
add a comment |
1 Answer
1
active
oldest
votes
3
You could do a list-comprehension which iterates through values appending final_list at the beginning:
final_list = (1, "Baseline")
values = [1.0, None, False, True, 1, 100, 'ovr', 1, 'l2', None, 'liblinear', 0.0001, 0, False]
print([final_list + (x, ) for x in values])
# [(1, 'Baseline', 1.0),
# (1, 'Baseline', None),
# (1, 'Baseline', False),
# (1, 'Baseline', True),
# (1, 'Baseline', 1),
# (1, 'Baseline', 100),
# (1, 'Baseline', 'ovr'),
# (1, 'Baseline', 1),
# (1, 'Baseline', 'l2'),
# (1, 'Baseline', None),
# (1, 'Baseline', 'liblinear'),
# (1, 'Baseline', 0.0001),
# (1, 'Baseline', 0),
# (1, 'Baseline', False)]
answered Nov 19 '18 at 16:41
Austin
9,5823828
1
Or, if there is indeed a difference betweenfinal_listandfinal_list2, then[fl+(v,) for fl, v in zip(final, values)]or[fl+(v,) for fl, v in zip(itertools.cycle([final_list, final_list2]), values)]
– tobias_k
Nov 19 '18 at 16:53
There is no difference. I wanted to create a nested list and figured tuples would be the way to go.
– Workhorse
Nov 19 '18 at 18:39
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
You could do a list-comprehension which iterates through values appending final_list at the beginning:
final_list = (1, "Baseline")
values = [1.0, None, False, True, 1, 100, 'ovr', 1, 'l2', None, 'liblinear', 0.0001, 0, False]
print([final_list + (x, ) for x in values])
# [(1, 'Baseline', 1.0),
# (1, 'Baseline', None),
# (1, 'Baseline', False),
# (1, 'Baseline', True),
# (1, 'Baseline', 1),
# (1, 'Baseline', 100),
# (1, 'Baseline', 'ovr'),
# (1, 'Baseline', 1),
# (1, 'Baseline', 'l2'),
# (1, 'Baseline', None),
# (1, 'Baseline', 'liblinear'),
# (1, 'Baseline', 0.0001),
# (1, 'Baseline', 0),
# (1, 'Baseline', False)]
answered Nov 19 '18 at 16:41
Austin
9,5823828
1
Or, if there is indeed a difference betweenfinal_listandfinal_list2, then[fl+(v,) for fl, v in zip(final, values)]or[fl+(v,) for fl, v in zip(itertools.cycle([final_list, final_list2]), values)]
– tobias_k
Nov 19 '18 at 16:53
There is no difference. I wanted to create a nested list and figured tuples would be the way to go.
– Workhorse
Nov 19 '18 at 18:39
add a comment |
3
You could do a list-comprehension which iterates through values appending final_list at the beginning:
final_list = (1, "Baseline")
values = [1.0, None, False, True, 1, 100, 'ovr', 1, 'l2', None, 'liblinear', 0.0001, 0, False]
print([final_list + (x, ) for x in values])
# [(1, 'Baseline', 1.0),
# (1, 'Baseline', None),
# (1, 'Baseline', False),
# (1, 'Baseline', True),
# (1, 'Baseline', 1),
# (1, 'Baseline', 100),
# (1, 'Baseline', 'ovr'),
# (1, 'Baseline', 1),
# (1, 'Baseline', 'l2'),
# (1, 'Baseline', None),
# (1, 'Baseline', 'liblinear'),
# (1, 'Baseline', 0.0001),
# (1, 'Baseline', 0),
# (1, 'Baseline', False)]
answered Nov 19 '18 at 16:41
Austin
9,5823828
1
Or, if there is indeed a difference betweenfinal_listandfinal_list2, then[fl+(v,) for fl, v in zip(final, values)]or[fl+(v,) for fl, v in zip(itertools.cycle([final_list, final_list2]), values)]
– tobias_k
Nov 19 '18 at 16:53
There is no difference. I wanted to create a nested list and figured tuples would be the way to go.
– Workhorse
Nov 19 '18 at 18:39
add a comment |
3
3
3
You could do a list-comprehension which iterates through values appending final_list at the beginning:
final_list = (1, "Baseline")
values = [1.0, None, False, True, 1, 100, 'ovr', 1, 'l2', None, 'liblinear', 0.0001, 0, False]
print([final_list + (x, ) for x in values])
# [(1, 'Baseline', 1.0),
# (1, 'Baseline', None),
# (1, 'Baseline', False),
# (1, 'Baseline', True),
# (1, 'Baseline', 1),
# (1, 'Baseline', 100),
# (1, 'Baseline', 'ovr'),
# (1, 'Baseline', 1),
# (1, 'Baseline', 'l2'),
# (1, 'Baseline', None),
# (1, 'Baseline', 'liblinear'),
# (1, 'Baseline', 0.0001),
# (1, 'Baseline', 0),
# (1, 'Baseline', False)]
answered Nov 19 '18 at 16:41
Austin
9,5823828
You could do a list-comprehension which iterates through values appending final_list at the beginning:
final_list = (1, "Baseline")
values = [1.0, None, False, True, 1, 100, 'ovr', 1, 'l2', None, 'liblinear', 0.0001, 0, False]
print([final_list + (x, ) for x in values])
# [(1, 'Baseline', 1.0),
# (1, 'Baseline', None),
# (1, 'Baseline', False),
# (1, 'Baseline', True),
# (1, 'Baseline', 1),
# (1, 'Baseline', 100),
# (1, 'Baseline', 'ovr'),
# (1, 'Baseline', 1),
# (1, 'Baseline', 'l2'),
# (1, 'Baseline', None),
# (1, 'Baseline', 'liblinear'),
# (1, 'Baseline', 0.0001),
# (1, 'Baseline', 0),
# (1, 'Baseline', False)]
answered Nov 19 '18 at 16:41
Austin
9,5823828
answered Nov 19 '18 at 16:41
Austin
9,5823828
answered Nov 19 '18 at 16:41
Austin
9,5823828
answered Nov 19 '18 at 16:41
Austin
9,5823828
9,5823828
1
Or, if there is indeed a difference betweenfinal_listandfinal_list2, then[fl+(v,) for fl, v in zip(final, values)]or[fl+(v,) for fl, v in zip(itertools.cycle([final_list, final_list2]), values)]
– tobias_k
Nov 19 '18 at 16:53
There is no difference. I wanted to create a nested list and figured tuples would be the way to go.
– Workhorse
Nov 19 '18 at 18:39
add a comment |
1
Or, if there is indeed a difference betweenfinal_listandfinal_list2, then[fl+(v,) for fl, v in zip(final, values)]or[fl+(v,) for fl, v in zip(itertools.cycle([final_list, final_list2]), values)]
– tobias_k
Nov 19 '18 at 16:53
There is no difference. I wanted to create a nested list and figured tuples would be the way to go.
– Workhorse
Nov 19 '18 at 18:39
1
1
Or, if there is indeed a difference between
final_list and final_list2, then [fl+(v,) for fl, v in zip(final, values)] or [fl+(v,) for fl, v in zip(itertools.cycle([final_list, final_list2]), values)]– tobias_k
Nov 19 '18 at 16:53
Or, if there is indeed a difference between
final_list and final_list2, then [fl+(v,) for fl, v in zip(final, values)] or [fl+(v,) for fl, v in zip(itertools.cycle([final_list, final_list2]), values)]– tobias_k
Nov 19 '18 at 16:53
There is no difference. I wanted to create a nested list and figured tuples would be the way to go.
– Workhorse
Nov 19 '18 at 18:39
There is no difference. I wanted to create a nested list and figured tuples would be the way to go.
– Workhorse
Nov 19 '18 at 18:39
add a comment |
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2
What have you tried so far?
– natn2323
Nov 19 '18 at 16:38
3
Tuples are immutable. You cannot insert a value into an existing tuple; you need to create new tuples.
– chepner
Nov 19 '18 at 16:40