Mixing
Diameter of cyclic directed graph as bound for powers of adjacency matrix
Consider a cyclic directed graph $G$, is it true that the power series computation of its adjacency matrix $M$ can stop after $k$ steps, being $k$ the directed diameter of $G$, "converging" to a point in which every node in the graph has been reached with any other?
I try to prove this considering the linear independence of the first $k$ powers of $M$. Am I wrong or this holds for directed cyclic graphs too?
linear-algebra graph-theory power-series adjacency-matrix
asked Nov 21 '18 at 11:20
Nel Son
11
add a comment |
Consider a cyclic directed graph $G$, is it true that the power series computation of its adjacency matrix $M$ can stop after $k$ steps, being $k$ the directed diameter of $G$, "converging" to a point in which every node in the graph has been reached with any other?
I try to prove this considering the linear independence of the first $k$ powers of $M$. Am I wrong or this holds for directed cyclic graphs too?
linear-algebra graph-theory power-series adjacency-matrix
asked Nov 21 '18 at 11:20
Nel Son
11
add a comment |
Consider a cyclic directed graph $G$, is it true that the power series computation of its adjacency matrix $M$ can stop after $k$ steps, being $k$ the directed diameter of $G$, "converging" to a point in which every node in the graph has been reached with any other?
I try to prove this considering the linear independence of the first $k$ powers of $M$. Am I wrong or this holds for directed cyclic graphs too?
linear-algebra graph-theory power-series adjacency-matrix
asked Nov 21 '18 at 11:20
Nel Son
11
Consider a cyclic directed graph $G$, is it true that the power series computation of its adjacency matrix $M$ can stop after $k$ steps, being $k$ the directed diameter of $G$, "converging" to a point in which every node in the graph has been reached with any other?
I try to prove this considering the linear independence of the first $k$ powers of $M$. Am I wrong or this holds for directed cyclic graphs too?
linear-algebra graph-theory power-series adjacency-matrix
linear-algebra graph-theory power-series adjacency-matrix
asked Nov 21 '18 at 11:20
Nel Son
11
asked Nov 21 '18 at 11:20
Nel Son
11
asked Nov 21 '18 at 11:20
Nel Son
11
asked Nov 21 '18 at 11:20
Nel Son
11
asked Nov 21 '18 at 11:20
Nel Son
11
11
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3007585%2fdiameter-of-cyclic-directed-graph-as-bound-for-powers-of-adjacency-matrix%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3007585%2fdiameter-of-cyclic-directed-graph-as-bound-for-powers-of-adjacency-matrix%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
