Mixing
Are quotients of topological categories also topological categories?
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I am considering quotients of categories as in MacLane's Categories for the working mathematician, as described in the next paragraph.
Let $C$ be a (small) category and $R$ an equivalence relation on (the arrows of) $C$ such that the domain and range maps are invariant on $R$-equivalence classes (i.e., if two arrows are equivalent then they have same domain and range). Assume further that $R$ is a congruence: $f_1Rg_1$ and $f_2Rg_2$ implies $f_1f_2Rg_1g_2$ whenever that makes sense. Then $C/R$ is a category (with same object space $Ob(C/R)=Ob(C)$ as $C$).
Assume further that $C$ is a topological category: $C$ and $Ob(C)$ are endowed with topologies making all structural maps continuous. Endow $C/R$ with the quotient topology.
Is $C/R$ a topological category?
It is quite clear that the domain, range, and unit maps are continuous, however the composition is not clear because $C/Rtimes C/R$ does not necessarily have the quotient topology of $Ctimes C$ (under the obvious map). See "Products of quotient topology same as quotient of product topology".
Ronnie Brown and J. P. L. Hardy have proven that the category of topological categories has quotients in the categorical sense (satisfying the universal property) in this article, but the underlying category of this quotient is not necessarily $C/R$ as defined above.
general-topology category-theory
asked Nov 30 '18 at 21:58
QuestionerQuestioner
549321
$endgroup$
add a comment |
$begingroup$
I am considering quotients of categories as in MacLane's Categories for the working mathematician, as described in the next paragraph.
Let $C$ be a (small) category and $R$ an equivalence relation on (the arrows of) $C$ such that the domain and range maps are invariant on $R$-equivalence classes (i.e., if two arrows are equivalent then they have same domain and range). Assume further that $R$ is a congruence: $f_1Rg_1$ and $f_2Rg_2$ implies $f_1f_2Rg_1g_2$ whenever that makes sense. Then $C/R$ is a category (with same object space $Ob(C/R)=Ob(C)$ as $C$).
Assume further that $C$ is a topological category: $C$ and $Ob(C)$ are endowed with topologies making all structural maps continuous. Endow $C/R$ with the quotient topology.
Is $C/R$ a topological category?
It is quite clear that the domain, range, and unit maps are continuous, however the composition is not clear because $C/Rtimes C/R$ does not necessarily have the quotient topology of $Ctimes C$ (under the obvious map). See "Products of quotient topology same as quotient of product topology".
Ronnie Brown and J. P. L. Hardy have proven that the category of topological categories has quotients in the categorical sense (satisfying the universal property) in this article, but the underlying category of this quotient is not necessarily $C/R$ as defined above.
general-topology category-theory
asked Nov 30 '18 at 21:58
QuestionerQuestioner
549321
$endgroup$
$begingroup$
So is a topological category a subcategory of the category of all topological spaces and all continuous maps?
$endgroup$
– Paul Frost
Nov 30 '18 at 23:41
2
$begingroup$
@PaulFrost Not at all. There is no natural topology on the set of all topological spaces. A topological category is a category internal to topological spaces, not a subcategory thereof.
$endgroup$
– Kevin Carlson
Dec 1 '18 at 7:30
add a comment |
$begingroup$
I am considering quotients of categories as in MacLane's Categories for the working mathematician, as described in the next paragraph.
Let $C$ be a (small) category and $R$ an equivalence relation on (the arrows of) $C$ such that the domain and range maps are invariant on $R$-equivalence classes (i.e., if two arrows are equivalent then they have same domain and range). Assume further that $R$ is a congruence: $f_1Rg_1$ and $f_2Rg_2$ implies $f_1f_2Rg_1g_2$ whenever that makes sense. Then $C/R$ is a category (with same object space $Ob(C/R)=Ob(C)$ as $C$).
Assume further that $C$ is a topological category: $C$ and $Ob(C)$ are endowed with topologies making all structural maps continuous. Endow $C/R$ with the quotient topology.
Is $C/R$ a topological category?
It is quite clear that the domain, range, and unit maps are continuous, however the composition is not clear because $C/Rtimes C/R$ does not necessarily have the quotient topology of $Ctimes C$ (under the obvious map). See "Products of quotient topology same as quotient of product topology".
Ronnie Brown and J. P. L. Hardy have proven that the category of topological categories has quotients in the categorical sense (satisfying the universal property) in this article, but the underlying category of this quotient is not necessarily $C/R$ as defined above.
general-topology category-theory
asked Nov 30 '18 at 21:58
QuestionerQuestioner
549321
$endgroup$
I am considering quotients of categories as in MacLane's Categories for the working mathematician, as described in the next paragraph.
Let $C$ be a (small) category and $R$ an equivalence relation on (the arrows of) $C$ such that the domain and range maps are invariant on $R$-equivalence classes (i.e., if two arrows are equivalent then they have same domain and range). Assume further that $R$ is a congruence: $f_1Rg_1$ and $f_2Rg_2$ implies $f_1f_2Rg_1g_2$ whenever that makes sense. Then $C/R$ is a category (with same object space $Ob(C/R)=Ob(C)$ as $C$).
Assume further that $C$ is a topological category: $C$ and $Ob(C)$ are endowed with topologies making all structural maps continuous. Endow $C/R$ with the quotient topology.
Is $C/R$ a topological category?
It is quite clear that the domain, range, and unit maps are continuous, however the composition is not clear because $C/Rtimes C/R$ does not necessarily have the quotient topology of $Ctimes C$ (under the obvious map). See "Products of quotient topology same as quotient of product topology".
Ronnie Brown and J. P. L. Hardy have proven that the category of topological categories has quotients in the categorical sense (satisfying the universal property) in this article, but the underlying category of this quotient is not necessarily $C/R$ as defined above.
general-topology category-theory
general-topology category-theory
asked Nov 30 '18 at 21:58
QuestionerQuestioner
549321
asked Nov 30 '18 at 21:58
QuestionerQuestioner
549321
edited Jan 7 at 8:18
Questioner
asked Nov 30 '18 at 21:58
QuestionerQuestioner
549321
asked Nov 30 '18 at 21:58
QuestionerQuestioner
549321
asked Nov 30 '18 at 21:58
QuestionerQuestioner
549321
549321
$begingroup$
So is a topological category a subcategory of the category of all topological spaces and all continuous maps?
$endgroup$
– Paul Frost
Nov 30 '18 at 23:41
2
$begingroup$
@PaulFrost Not at all. There is no natural topology on the set of all topological spaces. A topological category is a category internal to topological spaces, not a subcategory thereof.
$endgroup$
– Kevin Carlson
Dec 1 '18 at 7:30
add a comment |
$begingroup$
So is a topological category a subcategory of the category of all topological spaces and all continuous maps?
$endgroup$
– Paul Frost
Nov 30 '18 at 23:41
2
$begingroup$
@PaulFrost Not at all. There is no natural topology on the set of all topological spaces. A topological category is a category internal to topological spaces, not a subcategory thereof.
$endgroup$
– Kevin Carlson
Dec 1 '18 at 7:30
$begingroup$
So is a topological category a subcategory of the category of all topological spaces and all continuous maps?
$endgroup$
– Paul Frost
Nov 30 '18 at 23:41
$begingroup$
So is a topological category a subcategory of the category of all topological spaces and all continuous maps?
$endgroup$
– Paul Frost
Nov 30 '18 at 23:41
2
2
$begingroup$
@PaulFrost Not at all. There is no natural topology on the set of all topological spaces. A topological category is a category internal to topological spaces, not a subcategory thereof.
$endgroup$
– Kevin Carlson
Dec 1 '18 at 7:30
$begingroup$
@PaulFrost Not at all. There is no natural topology on the set of all topological spaces. A topological category is a category internal to topological spaces, not a subcategory thereof.
$endgroup$
– Kevin Carlson
Dec 1 '18 at 7:30
add a comment |
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$begingroup$
So is a topological category a subcategory of the category of all topological spaces and all continuous maps?
$endgroup$
– Paul Frost
Nov 30 '18 at 23:41
2
$begingroup$
@PaulFrost Not at all. There is no natural topology on the set of all topological spaces. A topological category is a category internal to topological spaces, not a subcategory thereof.
$endgroup$
– Kevin Carlson
Dec 1 '18 at 7:30