Solve the differential equation very tough to solve!!
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Today a classmate of mine had given me and my teacher a differential equation I don't know from where but it became a headache for me and my teacher because we both were unable to solve it at some particular step.
Here is the differential equation:
$$x, frac{dy}{dx} + y ln(x) = x,e^x,x^{(1/2) ln x}.$$
When I and my teacher was solving we compared it by
$dy/dx + Py =Q, $
but when it came to integrate $Q$ (I.F.) it would integrable by me. So please help me in this question. Any guidance will be appreciated.
integration ordinary-differential-equations indefinite-integrals
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add a comment |
$begingroup$
Today a classmate of mine had given me and my teacher a differential equation I don't know from where but it became a headache for me and my teacher because we both were unable to solve it at some particular step.
Here is the differential equation:
$$x, frac{dy}{dx} + y ln(x) = x,e^x,x^{(1/2) ln x}.$$
When I and my teacher was solving we compared it by
$dy/dx + Py =Q, $
but when it came to integrate $Q$ (I.F.) it would integrable by me. So please help me in this question. Any guidance will be appreciated.
integration ordinary-differential-equations indefinite-integrals
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1
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I've taken a stab at typesetting your DE. Please confirm it's correct.
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– Adrian Keister
Jan 7 at 14:29
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Thanks for editing it
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– Ritik
Jan 7 at 14:33
add a comment |
$begingroup$
Today a classmate of mine had given me and my teacher a differential equation I don't know from where but it became a headache for me and my teacher because we both were unable to solve it at some particular step.
Here is the differential equation:
$$x, frac{dy}{dx} + y ln(x) = x,e^x,x^{(1/2) ln x}.$$
When I and my teacher was solving we compared it by
$dy/dx + Py =Q, $
but when it came to integrate $Q$ (I.F.) it would integrable by me. So please help me in this question. Any guidance will be appreciated.
integration ordinary-differential-equations indefinite-integrals
$endgroup$
Today a classmate of mine had given me and my teacher a differential equation I don't know from where but it became a headache for me and my teacher because we both were unable to solve it at some particular step.
Here is the differential equation:
$$x, frac{dy}{dx} + y ln(x) = x,e^x,x^{(1/2) ln x}.$$
When I and my teacher was solving we compared it by
$dy/dx + Py =Q, $
but when it came to integrate $Q$ (I.F.) it would integrable by me. So please help me in this question. Any guidance will be appreciated.
integration ordinary-differential-equations indefinite-integrals
integration ordinary-differential-equations indefinite-integrals
edited Jan 7 at 14:25
Adrian Keister
4,98761933
4,98761933
asked Jan 7 at 14:22
RitikRitik
4710
4710
1
$begingroup$
I've taken a stab at typesetting your DE. Please confirm it's correct.
$endgroup$
– Adrian Keister
Jan 7 at 14:29
$begingroup$
Thanks for editing it
$endgroup$
– Ritik
Jan 7 at 14:33
add a comment |
1
$begingroup$
I've taken a stab at typesetting your DE. Please confirm it's correct.
$endgroup$
– Adrian Keister
Jan 7 at 14:29
$begingroup$
Thanks for editing it
$endgroup$
– Ritik
Jan 7 at 14:33
1
1
$begingroup$
I've taken a stab at typesetting your DE. Please confirm it's correct.
$endgroup$
– Adrian Keister
Jan 7 at 14:29
$begingroup$
I've taken a stab at typesetting your DE. Please confirm it's correct.
$endgroup$
– Adrian Keister
Jan 7 at 14:29
$begingroup$
Thanks for editing it
$endgroup$
– Ritik
Jan 7 at 14:33
$begingroup$
Thanks for editing it
$endgroup$
– Ritik
Jan 7 at 14:33
add a comment |
1 Answer
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There might be a $+/-$ mistake: if either '$+ y ,text{ln}(x)$' is changed to '$- y ,text{ln}(x)$' or $x^{frac{1}{2},text{ln}(x)}$ is changed to $x^{-frac{1}{2},text{ln}(x)}$, the resulting integral is explicitly solvable. As it stands, the integral, which is essentially $int e^{x + text{ln}(x)^2},text{d}x$, is not solvable.
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$begingroup$
Oh that means give ODE is not solvable there might be mistake
$endgroup$
– Ritik
Jan 7 at 14:51
$begingroup$
Please make the appropriate changes and then tell the method to solve he might have given wrong I will suggest him those suggestions given by you guys .
$endgroup$
– Ritik
Jan 7 at 14:53
add a comment |
Your Answer
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1 Answer
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1 Answer
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active
oldest
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$begingroup$
There might be a $+/-$ mistake: if either '$+ y ,text{ln}(x)$' is changed to '$- y ,text{ln}(x)$' or $x^{frac{1}{2},text{ln}(x)}$ is changed to $x^{-frac{1}{2},text{ln}(x)}$, the resulting integral is explicitly solvable. As it stands, the integral, which is essentially $int e^{x + text{ln}(x)^2},text{d}x$, is not solvable.
$endgroup$
$begingroup$
Oh that means give ODE is not solvable there might be mistake
$endgroup$
– Ritik
Jan 7 at 14:51
$begingroup$
Please make the appropriate changes and then tell the method to solve he might have given wrong I will suggest him those suggestions given by you guys .
$endgroup$
– Ritik
Jan 7 at 14:53
add a comment |
$begingroup$
There might be a $+/-$ mistake: if either '$+ y ,text{ln}(x)$' is changed to '$- y ,text{ln}(x)$' or $x^{frac{1}{2},text{ln}(x)}$ is changed to $x^{-frac{1}{2},text{ln}(x)}$, the resulting integral is explicitly solvable. As it stands, the integral, which is essentially $int e^{x + text{ln}(x)^2},text{d}x$, is not solvable.
$endgroup$
$begingroup$
Oh that means give ODE is not solvable there might be mistake
$endgroup$
– Ritik
Jan 7 at 14:51
$begingroup$
Please make the appropriate changes and then tell the method to solve he might have given wrong I will suggest him those suggestions given by you guys .
$endgroup$
– Ritik
Jan 7 at 14:53
add a comment |
$begingroup$
There might be a $+/-$ mistake: if either '$+ y ,text{ln}(x)$' is changed to '$- y ,text{ln}(x)$' or $x^{frac{1}{2},text{ln}(x)}$ is changed to $x^{-frac{1}{2},text{ln}(x)}$, the resulting integral is explicitly solvable. As it stands, the integral, which is essentially $int e^{x + text{ln}(x)^2},text{d}x$, is not solvable.
$endgroup$
There might be a $+/-$ mistake: if either '$+ y ,text{ln}(x)$' is changed to '$- y ,text{ln}(x)$' or $x^{frac{1}{2},text{ln}(x)}$ is changed to $x^{-frac{1}{2},text{ln}(x)}$, the resulting integral is explicitly solvable. As it stands, the integral, which is essentially $int e^{x + text{ln}(x)^2},text{d}x$, is not solvable.
answered Jan 7 at 14:47
Frits VeermanFrits Veerman
6,5362920
6,5362920
$begingroup$
Oh that means give ODE is not solvable there might be mistake
$endgroup$
– Ritik
Jan 7 at 14:51
$begingroup$
Please make the appropriate changes and then tell the method to solve he might have given wrong I will suggest him those suggestions given by you guys .
$endgroup$
– Ritik
Jan 7 at 14:53
add a comment |
$begingroup$
Oh that means give ODE is not solvable there might be mistake
$endgroup$
– Ritik
Jan 7 at 14:51
$begingroup$
Please make the appropriate changes and then tell the method to solve he might have given wrong I will suggest him those suggestions given by you guys .
$endgroup$
– Ritik
Jan 7 at 14:53
$begingroup$
Oh that means give ODE is not solvable there might be mistake
$endgroup$
– Ritik
Jan 7 at 14:51
$begingroup$
Oh that means give ODE is not solvable there might be mistake
$endgroup$
– Ritik
Jan 7 at 14:51
$begingroup$
Please make the appropriate changes and then tell the method to solve he might have given wrong I will suggest him those suggestions given by you guys .
$endgroup$
– Ritik
Jan 7 at 14:53
$begingroup$
Please make the appropriate changes and then tell the method to solve he might have given wrong I will suggest him those suggestions given by you guys .
$endgroup$
– Ritik
Jan 7 at 14:53
add a comment |
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$begingroup$
I've taken a stab at typesetting your DE. Please confirm it's correct.
$endgroup$
– Adrian Keister
Jan 7 at 14:29
$begingroup$
Thanks for editing it
$endgroup$
– Ritik
Jan 7 at 14:33