Mixing
Program to replace each string with an integer value in a given list of strings
Write a program to replace each string with an integer value in a given list of strings. The replacement integer value should be a sum of Ascci values of each character of the corresponding string.
list_rivers =["Ganges", "Godavari", "Brahmaputra", "Narmada","Yamuna", "Mahanadi", "Kaveri", "Tapti"]
I tried the following which is correct but I want to optimize the code.
list_rivers =["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
river = // empty list
for i in list_rivers:
num=0
for j in i:
num = num + ord(j)
river.append(num) // [597, 813, 1143, 692, 619, 787, 610, 514]
Can anyone help how to optimize the above code?
Thanks in advance.
python python-3.x python-2.7
edited Nov 20 '18 at 17:39
Brian Minton
2,04712232
asked Nov 20 '18 at 17:23
user_not_defineuser_not_define
186
add a comment |
Write a program to replace each string with an integer value in a given list of strings. The replacement integer value should be a sum of Ascci values of each character of the corresponding string.
list_rivers =["Ganges", "Godavari", "Brahmaputra", "Narmada","Yamuna", "Mahanadi", "Kaveri", "Tapti"]
I tried the following which is correct but I want to optimize the code.
list_rivers =["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
river = // empty list
for i in list_rivers:
num=0
for j in i:
num = num + ord(j)
river.append(num) // [597, 813, 1143, 692, 619, 787, 610, 514]
Can anyone help how to optimize the above code?
Thanks in advance.
python python-3.x python-2.7
edited Nov 20 '18 at 17:39
Brian Minton
2,04712232
asked Nov 20 '18 at 17:23
user_not_defineuser_not_define
186
add a comment |
Write a program to replace each string with an integer value in a given list of strings. The replacement integer value should be a sum of Ascci values of each character of the corresponding string.
list_rivers =["Ganges", "Godavari", "Brahmaputra", "Narmada","Yamuna", "Mahanadi", "Kaveri", "Tapti"]
I tried the following which is correct but I want to optimize the code.
list_rivers =["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
river = // empty list
for i in list_rivers:
num=0
for j in i:
num = num + ord(j)
river.append(num) // [597, 813, 1143, 692, 619, 787, 610, 514]
Can anyone help how to optimize the above code?
Thanks in advance.
python python-3.x python-2.7
edited Nov 20 '18 at 17:39
Brian Minton
2,04712232
asked Nov 20 '18 at 17:23
user_not_defineuser_not_define
186
Write a program to replace each string with an integer value in a given list of strings. The replacement integer value should be a sum of Ascci values of each character of the corresponding string.
list_rivers =["Ganges", "Godavari", "Brahmaputra", "Narmada","Yamuna", "Mahanadi", "Kaveri", "Tapti"]
I tried the following which is correct but I want to optimize the code.
list_rivers =["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
river = // empty list
for i in list_rivers:
num=0
for j in i:
num = num + ord(j)
river.append(num) // [597, 813, 1143, 692, 619, 787, 610, 514]
Can anyone help how to optimize the above code?
Thanks in advance.
python python-3.x python-2.7
python python-3.x python-2.7
edited Nov 20 '18 at 17:39
Brian Minton
2,04712232
asked Nov 20 '18 at 17:23
user_not_defineuser_not_define
186
edited Nov 20 '18 at 17:39
Brian Minton
2,04712232
asked Nov 20 '18 at 17:23
user_not_defineuser_not_define
186
edited Nov 20 '18 at 17:39
Brian Minton
2,04712232
edited Nov 20 '18 at 17:39
Brian Minton
2,04712232
edited Nov 20 '18 at 17:39
Brian Minton
2,04712232
2,04712232
asked Nov 20 '18 at 17:23
user_not_defineuser_not_define
186
asked Nov 20 '18 at 17:23
user_not_defineuser_not_define
186
asked Nov 20 '18 at 17:23
user_not_defineuser_not_define
186
186
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
You can use list compréhension :
[sum([ord(i) for i in word]) for word in list_rivers]
it's equivalent to do
tmp_1 =
for word in list_rivers:
tmp_2 =
for i in word:
tmp_2.append(ord(i))
tmp_1.append(sum(tmp_2))
answered Nov 20 '18 at 17:30
iEldeniElden
650417
add a comment |
As iElden mentions, you may use list comprehension here. Note that in this case, doing so does not necessarily optimize your code for efficiency.
Your method:
%%timeit
river =
for i in list_rivers:
num=0
for j in i:
num = num + ord(j)
river.append(num)
# 100000 loops, best of 3: 6.57 µs per loop
List comprehension:
%%timeit
result = [sum([ord(i) for i in word]) for word in list_rivers]
# 100000 loops, best of 3: 9.37 µs per loop
(Even slower) using map:
%%timeit
result = map(lambda x: sum([ord(letter) for letter in x]), list_rivers)
# 100000 loops, best of 3: 10.3 µs per loop
answered Nov 20 '18 at 17:36
Wes DoyleWes Doyle
1,0692719
add a comment |
It says write a program to do it, so here's a program to do so. Example output: [597, 813, 1143, 692, 619, 787, 610, 514]
def string_to_int(string):
retval = 0
for c in string:
retval += ord(c)
return retval
def main(data):
retval =
for item in data:
retval.append(string_to_int(item))
return retval
if __name__ == "__main__":
list_rivers = ["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
results = main(list_rivers)
print results
answered Nov 20 '18 at 20:04
13aal13aal
8531135
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use list compréhension :
[sum([ord(i) for i in word]) for word in list_rivers]
it's equivalent to do
tmp_1 =
for word in list_rivers:
tmp_2 =
for i in word:
tmp_2.append(ord(i))
tmp_1.append(sum(tmp_2))
answered Nov 20 '18 at 17:30
iEldeniElden
650417
add a comment |
You can use list compréhension :
[sum([ord(i) for i in word]) for word in list_rivers]
it's equivalent to do
tmp_1 =
for word in list_rivers:
tmp_2 =
for i in word:
tmp_2.append(ord(i))
tmp_1.append(sum(tmp_2))
answered Nov 20 '18 at 17:30
iEldeniElden
650417
add a comment |
You can use list compréhension :
[sum([ord(i) for i in word]) for word in list_rivers]
it's equivalent to do
tmp_1 =
for word in list_rivers:
tmp_2 =
for i in word:
tmp_2.append(ord(i))
tmp_1.append(sum(tmp_2))
answered Nov 20 '18 at 17:30
iEldeniElden
650417
You can use list compréhension :
[sum([ord(i) for i in word]) for word in list_rivers]
it's equivalent to do
tmp_1 =
for word in list_rivers:
tmp_2 =
for i in word:
tmp_2.append(ord(i))
tmp_1.append(sum(tmp_2))
answered Nov 20 '18 at 17:30
iEldeniElden
650417
answered Nov 20 '18 at 17:30
iEldeniElden
650417
answered Nov 20 '18 at 17:30
iEldeniElden
650417
answered Nov 20 '18 at 17:30
iEldeniElden
650417
650417
add a comment |
add a comment |
As iElden mentions, you may use list comprehension here. Note that in this case, doing so does not necessarily optimize your code for efficiency.
Your method:
%%timeit
river =
for i in list_rivers:
num=0
for j in i:
num = num + ord(j)
river.append(num)
# 100000 loops, best of 3: 6.57 µs per loop
List comprehension:
%%timeit
result = [sum([ord(i) for i in word]) for word in list_rivers]
# 100000 loops, best of 3: 9.37 µs per loop
(Even slower) using map:
%%timeit
result = map(lambda x: sum([ord(letter) for letter in x]), list_rivers)
# 100000 loops, best of 3: 10.3 µs per loop
answered Nov 20 '18 at 17:36
Wes DoyleWes Doyle
1,0692719
add a comment |
As iElden mentions, you may use list comprehension here. Note that in this case, doing so does not necessarily optimize your code for efficiency.
Your method:
%%timeit
river =
for i in list_rivers:
num=0
for j in i:
num = num + ord(j)
river.append(num)
# 100000 loops, best of 3: 6.57 µs per loop
List comprehension:
%%timeit
result = [sum([ord(i) for i in word]) for word in list_rivers]
# 100000 loops, best of 3: 9.37 µs per loop
(Even slower) using map:
%%timeit
result = map(lambda x: sum([ord(letter) for letter in x]), list_rivers)
# 100000 loops, best of 3: 10.3 µs per loop
answered Nov 20 '18 at 17:36
Wes DoyleWes Doyle
1,0692719
add a comment |
As iElden mentions, you may use list comprehension here. Note that in this case, doing so does not necessarily optimize your code for efficiency.
Your method:
%%timeit
river =
for i in list_rivers:
num=0
for j in i:
num = num + ord(j)
river.append(num)
# 100000 loops, best of 3: 6.57 µs per loop
List comprehension:
%%timeit
result = [sum([ord(i) for i in word]) for word in list_rivers]
# 100000 loops, best of 3: 9.37 µs per loop
(Even slower) using map:
%%timeit
result = map(lambda x: sum([ord(letter) for letter in x]), list_rivers)
# 100000 loops, best of 3: 10.3 µs per loop
answered Nov 20 '18 at 17:36
Wes DoyleWes Doyle
1,0692719
As iElden mentions, you may use list comprehension here. Note that in this case, doing so does not necessarily optimize your code for efficiency.
Your method:
%%timeit
river =
for i in list_rivers:
num=0
for j in i:
num = num + ord(j)
river.append(num)
# 100000 loops, best of 3: 6.57 µs per loop
List comprehension:
%%timeit
result = [sum([ord(i) for i in word]) for word in list_rivers]
# 100000 loops, best of 3: 9.37 µs per loop
(Even slower) using map:
%%timeit
result = map(lambda x: sum([ord(letter) for letter in x]), list_rivers)
# 100000 loops, best of 3: 10.3 µs per loop
answered Nov 20 '18 at 17:36
Wes DoyleWes Doyle
1,0692719
edited Nov 20 '18 at 17:42
answered Nov 20 '18 at 17:36
Wes DoyleWes Doyle
1,0692719
answered Nov 20 '18 at 17:36
Wes DoyleWes Doyle
1,0692719
answered Nov 20 '18 at 17:36
Wes DoyleWes Doyle
1,0692719
1,0692719
add a comment |
add a comment |
It says write a program to do it, so here's a program to do so. Example output: [597, 813, 1143, 692, 619, 787, 610, 514]
def string_to_int(string):
retval = 0
for c in string:
retval += ord(c)
return retval
def main(data):
retval =
for item in data:
retval.append(string_to_int(item))
return retval
if __name__ == "__main__":
list_rivers = ["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
results = main(list_rivers)
print results
answered Nov 20 '18 at 20:04
13aal13aal
8531135
add a comment |
It says write a program to do it, so here's a program to do so. Example output: [597, 813, 1143, 692, 619, 787, 610, 514]
def string_to_int(string):
retval = 0
for c in string:
retval += ord(c)
return retval
def main(data):
retval =
for item in data:
retval.append(string_to_int(item))
return retval
if __name__ == "__main__":
list_rivers = ["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
results = main(list_rivers)
print results
answered Nov 20 '18 at 20:04
13aal13aal
8531135
add a comment |
It says write a program to do it, so here's a program to do so. Example output: [597, 813, 1143, 692, 619, 787, 610, 514]
def string_to_int(string):
retval = 0
for c in string:
retval += ord(c)
return retval
def main(data):
retval =
for item in data:
retval.append(string_to_int(item))
return retval
if __name__ == "__main__":
list_rivers = ["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
results = main(list_rivers)
print results
answered Nov 20 '18 at 20:04
13aal13aal
8531135
It says write a program to do it, so here's a program to do so. Example output: [597, 813, 1143, 692, 619, 787, 610, 514]
def string_to_int(string):
retval = 0
for c in string:
retval += ord(c)
return retval
def main(data):
retval =
for item in data:
retval.append(string_to_int(item))
return retval
if __name__ == "__main__":
list_rivers = ["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
results = main(list_rivers)
print results
answered Nov 20 '18 at 20:04
13aal13aal
8531135
answered Nov 20 '18 at 20:04
13aal13aal
8531135
answered Nov 20 '18 at 20:04
13aal13aal
8531135
answered Nov 20 '18 at 20:04
13aal13aal
8531135
8531135
add a comment |
add a comment |
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