How to subscribe on the value changed control event of a UISwitch Using Rxswift

I want to use Rxswift and not IBActions to solve my issue below,

I have a UISwitch and I want to subscribe to the value changed event in
it,

I usually subscribe on Buttons using this manner

@IBOutlet weak var myButton: UIButton!





myButton

    .rx

    .tapGesture()

    .when(.recognized)

    .subscribe(onNext : {_ in /*do action here */})

Does anyone know how to subscribe to UISwitch control events?

edited Nov 19 '18 at 20:51

Damon

517317

asked Nov 19 '18 at 19:16

MhmdRizk

436310

Does yourSwitch.rx.value.changed.subscribe(onNext: ...) work?
– Sweeper
Nov 19 '18 at 19:20

I tried it now, and it didnt
– MhmdRizk
Nov 19 '18 at 19:33

add a comment |

I want to use Rxswift and not IBActions to solve my issue below,

I have a UISwitch and I want to subscribe to the value changed event in
it,

I usually subscribe on Buttons using this manner

@IBOutlet weak var myButton: UIButton!





myButton

    .rx

    .tapGesture()

    .when(.recognized)

    .subscribe(onNext : {_ in /*do action here */})

Does anyone know how to subscribe to UISwitch control events?

edited Nov 19 '18 at 20:51

Damon

517317

asked Nov 19 '18 at 19:16

MhmdRizk

436310

Does yourSwitch.rx.value.changed.subscribe(onNext: ...) work?
– Sweeper
Nov 19 '18 at 19:20

I tried it now, and it didnt
– MhmdRizk
Nov 19 '18 at 19:33

add a comment |

I want to use Rxswift and not IBActions to solve my issue below,

I have a UISwitch and I want to subscribe to the value changed event in
it,

I usually subscribe on Buttons using this manner

@IBOutlet weak var myButton: UIButton!





myButton

    .rx

    .tapGesture()

    .when(.recognized)

    .subscribe(onNext : {_ in /*do action here */})

Does anyone know how to subscribe to UISwitch control events?

edited Nov 19 '18 at 20:51

Damon

517317

asked Nov 19 '18 at 19:16

MhmdRizk

436310

I want to use Rxswift and not IBActions to solve my issue below,

I have a UISwitch and I want to subscribe to the value changed event in
it,

I usually subscribe on Buttons using this manner

@IBOutlet weak var myButton: UIButton!





myButton

    .rx

    .tapGesture()

    .when(.recognized)

    .subscribe(onNext : {_ in /*do action here */})

Does anyone know how to subscribe to UISwitch control events?

ios swift rx-swift

edited Nov 19 '18 at 20:51

Damon

517317

asked Nov 19 '18 at 19:16

MhmdRizk

436310

edited Nov 19 '18 at 20:51

Damon

517317

asked Nov 19 '18 at 19:16

MhmdRizk

436310

edited Nov 19 '18 at 20:51

Damon

517317

edited Nov 19 '18 at 20:51

Damon

517317

edited Nov 19 '18 at 20:51

Damon

517317

asked Nov 19 '18 at 19:16

MhmdRizk

436310

asked Nov 19 '18 at 19:16

MhmdRizk

436310

asked Nov 19 '18 at 19:16

MhmdRizk

436310

Does yourSwitch.rx.value.changed.subscribe(onNext: ...) work?
– Sweeper
Nov 19 '18 at 19:20

I tried it now, and it didnt
– MhmdRizk
Nov 19 '18 at 19:33

add a comment |

Does yourSwitch.rx.value.changed.subscribe(onNext: ...) work?
– Sweeper
Nov 19 '18 at 19:20

I tried it now, and it didnt
– MhmdRizk
Nov 19 '18 at 19:33

Does yourSwitch.rx.value.changed.subscribe(onNext: ...) work?
– Sweeper
Nov 19 '18 at 19:20

I tried it now, and it didnt
– MhmdRizk
Nov 19 '18 at 19:33

add a comment |

3 Answers
3

active

oldest

votes

Below are some caveats you would use for UISwitch:



 1. Make sure the event subscribes to unique changes so use distinctUntilChanged

 2. Rigorous switching the switch can cause unexpected behavior so use debounce.



 Example: 



anySwitch.rx

.isOn.changed //when state changed

.debounce(0.8, scheduler: MainScheduler.instance) //handle rigorous user switching

.distinctUntilChanged().asObservable() //take signal if state is different than before. This is optional depends on your use case

.subscribe(onNext:{[weak self] value in

            //your code

}).disposed(by: disposeBag)

edited Nov 20 '18 at 0:20

answered Nov 20 '18 at 0:13

prekshya basnet

466110

add a comment |

I found the answer Im looking for, in order to subscribe on and control event we should do the below :

@IBOutlet weak var mySwitch : UISwitch!



       mySwitch 

            .rx

            .controlEvent(.valueChanged)

            .withLatestFrom(mySwitch.rx.value)

            .subscribe(onNext : { bool in

                // this is the value of mySwitch

            })

            .disposed(by: disposeBag)

answered Nov 20 '18 at 7:18

MhmdRizk

436310

Looks good. Congrats. :)
– Glenn
Nov 20 '18 at 9:11

add a comment |

There are couple of ways to do that. But this one is how I usually do it:
Try this out.

self.mySwitch.rx.isOn.subscribe { isOn in

            print(isOn)

        }.disposed(by: self.disposeBag)

I hope this helps.

EDIT:

Another would be subscribing to the value rx property of the UISwitch, like so:

mySwitch.rx.value.subscribe { (isOn) in

            print(isOn)

        }.disposed(by: self.disposeBag)

Now, as for your comment:

this worked for me thanks , but I preferred subscribing on the control
event it self, not the value.

We could do this below, I'm not sure though if there's a better way than this. Since UISwitch is a UIControl object, you can subscribe to its .valueChanged event, like so:

    mySwitch.rx.controlEvent([.valueChanged]).subscribe { _ in

        print("isOn? : (mySwitch.isOn)")

        }.disposed(by: self.disposeBag)

More info: https://developer.apple.com/documentation/uikit/uiswitch

edited Nov 20 '18 at 8:55

answered Nov 19 '18 at 19:42

Glenn

4,86421740

this worked for me thanks , but I preferred subscribing on the control event it self, not the value
– MhmdRizk
Nov 20 '18 at 7:19

See my updated answer. :)
– Glenn
Nov 20 '18 at 8:55

thanks for the effort bro, but I posted the solution and it worked by subscribe on the value changed event, check my answer
– MhmdRizk
Nov 20 '18 at 9:03

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

Below are some caveats you would use for UISwitch:



 1. Make sure the event subscribes to unique changes so use distinctUntilChanged

 2. Rigorous switching the switch can cause unexpected behavior so use debounce.



 Example: 



anySwitch.rx

.isOn.changed //when state changed

.debounce(0.8, scheduler: MainScheduler.instance) //handle rigorous user switching

.distinctUntilChanged().asObservable() //take signal if state is different than before. This is optional depends on your use case

.subscribe(onNext:{[weak self] value in

            //your code

}).disposed(by: disposeBag)

edited Nov 20 '18 at 0:20

answered Nov 20 '18 at 0:13

prekshya basnet

466110

add a comment |

Below are some caveats you would use for UISwitch:



 1. Make sure the event subscribes to unique changes so use distinctUntilChanged

 2. Rigorous switching the switch can cause unexpected behavior so use debounce.



 Example: 



anySwitch.rx

.isOn.changed //when state changed

.debounce(0.8, scheduler: MainScheduler.instance) //handle rigorous user switching

.distinctUntilChanged().asObservable() //take signal if state is different than before. This is optional depends on your use case

.subscribe(onNext:{[weak self] value in

            //your code

}).disposed(by: disposeBag)

edited Nov 20 '18 at 0:20

answered Nov 20 '18 at 0:13

prekshya basnet

466110

add a comment |

Below are some caveats you would use for UISwitch:



 1. Make sure the event subscribes to unique changes so use distinctUntilChanged

 2. Rigorous switching the switch can cause unexpected behavior so use debounce.



 Example: 



anySwitch.rx

.isOn.changed //when state changed

.debounce(0.8, scheduler: MainScheduler.instance) //handle rigorous user switching

.distinctUntilChanged().asObservable() //take signal if state is different than before. This is optional depends on your use case

.subscribe(onNext:{[weak self] value in

            //your code

}).disposed(by: disposeBag)

edited Nov 20 '18 at 0:20

answered Nov 20 '18 at 0:13

prekshya basnet

466110

Below are some caveats you would use for UISwitch:



 1. Make sure the event subscribes to unique changes so use distinctUntilChanged

 2. Rigorous switching the switch can cause unexpected behavior so use debounce.



 Example: 



anySwitch.rx

.isOn.changed //when state changed

.debounce(0.8, scheduler: MainScheduler.instance) //handle rigorous user switching

.distinctUntilChanged().asObservable() //take signal if state is different than before. This is optional depends on your use case

.subscribe(onNext:{[weak self] value in

            //your code

}).disposed(by: disposeBag)

edited Nov 20 '18 at 0:20

answered Nov 20 '18 at 0:13

prekshya basnet

466110

edited Nov 20 '18 at 0:20

answered Nov 20 '18 at 0:13

prekshya basnet

466110

answered Nov 20 '18 at 0:13

prekshya basnet

466110

answered Nov 20 '18 at 0:13

prekshya basnet

466110

add a comment |

I found the answer Im looking for, in order to subscribe on and control event we should do the below :

@IBOutlet weak var mySwitch : UISwitch!



       mySwitch 

            .rx

            .controlEvent(.valueChanged)

            .withLatestFrom(mySwitch.rx.value)

            .subscribe(onNext : { bool in

                // this is the value of mySwitch

            })

            .disposed(by: disposeBag)

answered Nov 20 '18 at 7:18

MhmdRizk

436310

Looks good. Congrats. :)
– Glenn
Nov 20 '18 at 9:11

add a comment |

I found the answer Im looking for, in order to subscribe on and control event we should do the below :

@IBOutlet weak var mySwitch : UISwitch!



       mySwitch 

            .rx

            .controlEvent(.valueChanged)

            .withLatestFrom(mySwitch.rx.value)

            .subscribe(onNext : { bool in

                // this is the value of mySwitch

            })

            .disposed(by: disposeBag)

answered Nov 20 '18 at 7:18

MhmdRizk

436310

Looks good. Congrats. :)
– Glenn
Nov 20 '18 at 9:11

add a comment |

I found the answer Im looking for, in order to subscribe on and control event we should do the below :

@IBOutlet weak var mySwitch : UISwitch!



       mySwitch 

            .rx

            .controlEvent(.valueChanged)

            .withLatestFrom(mySwitch.rx.value)

            .subscribe(onNext : { bool in

                // this is the value of mySwitch

            })

            .disposed(by: disposeBag)

answered Nov 20 '18 at 7:18

MhmdRizk

436310

I found the answer Im looking for, in order to subscribe on and control event we should do the below :

@IBOutlet weak var mySwitch : UISwitch!



       mySwitch 

            .rx

            .controlEvent(.valueChanged)

            .withLatestFrom(mySwitch.rx.value)

            .subscribe(onNext : { bool in

                // this is the value of mySwitch

            })

            .disposed(by: disposeBag)

answered Nov 20 '18 at 7:18

MhmdRizk

436310

answered Nov 20 '18 at 7:18

MhmdRizk

436310

answered Nov 20 '18 at 7:18

MhmdRizk

436310

answered Nov 20 '18 at 7:18

MhmdRizk

436310

Looks good. Congrats. :)
– Glenn
Nov 20 '18 at 9:11

add a comment |

Looks good. Congrats. :)
– Glenn
Nov 20 '18 at 9:11

Looks good. Congrats. :)
– Glenn
Nov 20 '18 at 9:11

add a comment |

There are couple of ways to do that. But this one is how I usually do it:
Try this out.

self.mySwitch.rx.isOn.subscribe { isOn in

            print(isOn)

        }.disposed(by: self.disposeBag)

I hope this helps.

EDIT:

Another would be subscribing to the value rx property of the UISwitch, like so:

mySwitch.rx.value.subscribe { (isOn) in

            print(isOn)

        }.disposed(by: self.disposeBag)

Now, as for your comment:

this worked for me thanks , but I preferred subscribing on the control
event it self, not the value.

We could do this below, I'm not sure though if there's a better way than this. Since UISwitch is a UIControl object, you can subscribe to its .valueChanged event, like so:

    mySwitch.rx.controlEvent([.valueChanged]).subscribe { _ in

        print("isOn? : (mySwitch.isOn)")

        }.disposed(by: self.disposeBag)

More info: https://developer.apple.com/documentation/uikit/uiswitch

edited Nov 20 '18 at 8:55

answered Nov 19 '18 at 19:42

Glenn

4,86421740

this worked for me thanks , but I preferred subscribing on the control event it self, not the value
– MhmdRizk
Nov 20 '18 at 7:19

See my updated answer. :)
– Glenn
Nov 20 '18 at 8:55

thanks for the effort bro, but I posted the solution and it worked by subscribe on the value changed event, check my answer
– MhmdRizk
Nov 20 '18 at 9:03

add a comment |

There are couple of ways to do that. But this one is how I usually do it:
Try this out.

self.mySwitch.rx.isOn.subscribe { isOn in

            print(isOn)

        }.disposed(by: self.disposeBag)

I hope this helps.

EDIT:

Another would be subscribing to the value rx property of the UISwitch, like so:

mySwitch.rx.value.subscribe { (isOn) in

            print(isOn)

        }.disposed(by: self.disposeBag)

Now, as for your comment:

this worked for me thanks , but I preferred subscribing on the control
event it self, not the value.

We could do this below, I'm not sure though if there's a better way than this. Since UISwitch is a UIControl object, you can subscribe to its .valueChanged event, like so:

    mySwitch.rx.controlEvent([.valueChanged]).subscribe { _ in

        print("isOn? : (mySwitch.isOn)")

        }.disposed(by: self.disposeBag)

More info: https://developer.apple.com/documentation/uikit/uiswitch

edited Nov 20 '18 at 8:55

answered Nov 19 '18 at 19:42

Glenn

4,86421740

this worked for me thanks , but I preferred subscribing on the control event it self, not the value
– MhmdRizk
Nov 20 '18 at 7:19

See my updated answer. :)
– Glenn
Nov 20 '18 at 8:55

thanks for the effort bro, but I posted the solution and it worked by subscribe on the value changed event, check my answer
– MhmdRizk
Nov 20 '18 at 9:03

add a comment |

There are couple of ways to do that. But this one is how I usually do it:
Try this out.

self.mySwitch.rx.isOn.subscribe { isOn in

            print(isOn)

        }.disposed(by: self.disposeBag)

I hope this helps.

EDIT:

Another would be subscribing to the value rx property of the UISwitch, like so:

mySwitch.rx.value.subscribe { (isOn) in

            print(isOn)

        }.disposed(by: self.disposeBag)

Now, as for your comment:

this worked for me thanks , but I preferred subscribing on the control
event it self, not the value.

We could do this below, I'm not sure though if there's a better way than this. Since UISwitch is a UIControl object, you can subscribe to its .valueChanged event, like so:

    mySwitch.rx.controlEvent([.valueChanged]).subscribe { _ in

        print("isOn? : (mySwitch.isOn)")

        }.disposed(by: self.disposeBag)

More info: https://developer.apple.com/documentation/uikit/uiswitch

edited Nov 20 '18 at 8:55

answered Nov 19 '18 at 19:42

Glenn

4,86421740

There are couple of ways to do that. But this one is how I usually do it:
Try this out.

self.mySwitch.rx.isOn.subscribe { isOn in

            print(isOn)

        }.disposed(by: self.disposeBag)

I hope this helps.

EDIT:

Another would be subscribing to the value rx property of the UISwitch, like so:

mySwitch.rx.value.subscribe { (isOn) in

            print(isOn)

        }.disposed(by: self.disposeBag)

Now, as for your comment:

this worked for me thanks , but I preferred subscribing on the control
event it self, not the value.

We could do this below, I'm not sure though if there's a better way than this. Since UISwitch is a UIControl object, you can subscribe to its .valueChanged event, like so:

    mySwitch.rx.controlEvent([.valueChanged]).subscribe { _ in

        print("isOn? : (mySwitch.isOn)")

        }.disposed(by: self.disposeBag)

More info: https://developer.apple.com/documentation/uikit/uiswitch

edited Nov 20 '18 at 8:55

answered Nov 19 '18 at 19:42

Glenn

4,86421740

edited Nov 20 '18 at 8:55

answered Nov 19 '18 at 19:42

Glenn

4,86421740

answered Nov 19 '18 at 19:42

Glenn

4,86421740

answered Nov 19 '18 at 19:42

Glenn

4,86421740

this worked for me thanks , but I preferred subscribing on the control event it self, not the value
– MhmdRizk
Nov 20 '18 at 7:19

See my updated answer. :)
– Glenn
Nov 20 '18 at 8:55

thanks for the effort bro, but I posted the solution and it worked by subscribe on the value changed event, check my answer
– MhmdRizk
Nov 20 '18 at 9:03

add a comment |

this worked for me thanks , but I preferred subscribing on the control event it self, not the value
– MhmdRizk
Nov 20 '18 at 7:19

See my updated answer. :)
– Glenn
Nov 20 '18 at 8:55

thanks for the effort bro, but I posted the solution and it worked by subscribe on the value changed event, check my answer
– MhmdRizk
Nov 20 '18 at 9:03

this worked for me thanks , but I preferred subscribing on the control event it self, not the value
– MhmdRizk
Nov 20 '18 at 7:19

See my updated answer. :)
– Glenn
Nov 20 '18 at 8:55

thanks for the effort bro, but I posted the solution and it worked by subscribe on the value changed event, check my answer
– MhmdRizk
Nov 20 '18 at 9:03

add a comment |

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