Private method in Typescript definitions(React)












1















This is just a general question which has been bothering me for sometime.



I have a React component that has some methods both private and public.
Lets assume I have a component:



import React from 'react';
import { CRComponent } from '../CRComponent';

export interface Props {
className?: string;
type?: string;
}

class AlertItem extends CRComponent<Props> {
public render() {
return (
///// Some render
);
}

private getClassNames() {
///some logic
}

private mapAlertTypeIcon() {
///Some logic
}
}

export default AlertItem;


When I generate a typescript definition file the following file gets generated:



import { CRComponent } from '../CRComponent';
interface Props {
className?: string;
}
declare class AlertItem extends CRComponent<Props> {
private getClassNames;
private mapAlertTypeIcon;
public render(): JSX.Element;
}
export default AlertItem;


I purposefully removed the prop type from the .d.ts file so that the user cannot use it as it is internal.



Now when I publish this .d.ts file all the member methods are published in .d.ts file including private. For this class the methods are relatively less. Suppose I have a big component then the number of private methods might be huge.



Now a component library will have lots of such component.



When I publish these a major size of the package is because of these files. So my question is that whether it is necessary to keep private members in the .d.ts files or can I just ignore them as the user will not have access to them anyway?



I tried finding answers but could not find one. So a help would be appreciated.










share|improve this question



























    1















    This is just a general question which has been bothering me for sometime.



    I have a React component that has some methods both private and public.
    Lets assume I have a component:



    import React from 'react';
    import { CRComponent } from '../CRComponent';

    export interface Props {
    className?: string;
    type?: string;
    }

    class AlertItem extends CRComponent<Props> {
    public render() {
    return (
    ///// Some render
    );
    }

    private getClassNames() {
    ///some logic
    }

    private mapAlertTypeIcon() {
    ///Some logic
    }
    }

    export default AlertItem;


    When I generate a typescript definition file the following file gets generated:



    import { CRComponent } from '../CRComponent';
    interface Props {
    className?: string;
    }
    declare class AlertItem extends CRComponent<Props> {
    private getClassNames;
    private mapAlertTypeIcon;
    public render(): JSX.Element;
    }
    export default AlertItem;


    I purposefully removed the prop type from the .d.ts file so that the user cannot use it as it is internal.



    Now when I publish this .d.ts file all the member methods are published in .d.ts file including private. For this class the methods are relatively less. Suppose I have a big component then the number of private methods might be huge.



    Now a component library will have lots of such component.



    When I publish these a major size of the package is because of these files. So my question is that whether it is necessary to keep private members in the .d.ts files or can I just ignore them as the user will not have access to them anyway?



    I tried finding answers but could not find one. So a help would be appreciated.










    share|improve this question

























      1












      1








      1








      This is just a general question which has been bothering me for sometime.



      I have a React component that has some methods both private and public.
      Lets assume I have a component:



      import React from 'react';
      import { CRComponent } from '../CRComponent';

      export interface Props {
      className?: string;
      type?: string;
      }

      class AlertItem extends CRComponent<Props> {
      public render() {
      return (
      ///// Some render
      );
      }

      private getClassNames() {
      ///some logic
      }

      private mapAlertTypeIcon() {
      ///Some logic
      }
      }

      export default AlertItem;


      When I generate a typescript definition file the following file gets generated:



      import { CRComponent } from '../CRComponent';
      interface Props {
      className?: string;
      }
      declare class AlertItem extends CRComponent<Props> {
      private getClassNames;
      private mapAlertTypeIcon;
      public render(): JSX.Element;
      }
      export default AlertItem;


      I purposefully removed the prop type from the .d.ts file so that the user cannot use it as it is internal.



      Now when I publish this .d.ts file all the member methods are published in .d.ts file including private. For this class the methods are relatively less. Suppose I have a big component then the number of private methods might be huge.



      Now a component library will have lots of such component.



      When I publish these a major size of the package is because of these files. So my question is that whether it is necessary to keep private members in the .d.ts files or can I just ignore them as the user will not have access to them anyway?



      I tried finding answers but could not find one. So a help would be appreciated.










      share|improve this question














      This is just a general question which has been bothering me for sometime.



      I have a React component that has some methods both private and public.
      Lets assume I have a component:



      import React from 'react';
      import { CRComponent } from '../CRComponent';

      export interface Props {
      className?: string;
      type?: string;
      }

      class AlertItem extends CRComponent<Props> {
      public render() {
      return (
      ///// Some render
      );
      }

      private getClassNames() {
      ///some logic
      }

      private mapAlertTypeIcon() {
      ///Some logic
      }
      }

      export default AlertItem;


      When I generate a typescript definition file the following file gets generated:



      import { CRComponent } from '../CRComponent';
      interface Props {
      className?: string;
      }
      declare class AlertItem extends CRComponent<Props> {
      private getClassNames;
      private mapAlertTypeIcon;
      public render(): JSX.Element;
      }
      export default AlertItem;


      I purposefully removed the prop type from the .d.ts file so that the user cannot use it as it is internal.



      Now when I publish this .d.ts file all the member methods are published in .d.ts file including private. For this class the methods are relatively less. Suppose I have a big component then the number of private methods might be huge.



      Now a component library will have lots of such component.



      When I publish these a major size of the package is because of these files. So my question is that whether it is necessary to keep private members in the .d.ts files or can I just ignore them as the user will not have access to them anyway?



      I tried finding answers but could not find one. So a help would be appreciated.







      reactjs typescript






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 20 '18 at 9:07









      Varun SharmaVarun Sharma

      628




      628
























          1 Answer
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          A private method changes whether you can create a substitutable type, for example the declaration of Example prevents a type match with our concrete class (whether or not we add a private identity member!)



          declare class Example {
          private identity: string;
          public doSomething(): string;
          }

          class ConcreteExample {
          private identity: string = 'id';

          doSomething() {
          return 'done';
          }
          }

          function passMeExample(input: Example) {

          }

          // ConcreteExample is not allowable!
          passMeExample(new ConcreteExample());


          If you remove the private members, it changes the behaviour of the type checking:



          declare class Example {
          public doSomething(): string;
          }

          class ConcreteExample {
          private identity: string = 'id';

          doSomething() {
          return 'done';
          }
          }

          function passMeExample(input: Example) {

          }

          // OK!
          passMeExample(new ConcreteExample());


          So it is important to bear in mind that there is a difference in behaviour if you remove those private members. The classes will not act as they would if they were included.






          share|improve this answer























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            1 Answer
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            active

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            2














            A private method changes whether you can create a substitutable type, for example the declaration of Example prevents a type match with our concrete class (whether or not we add a private identity member!)



            declare class Example {
            private identity: string;
            public doSomething(): string;
            }

            class ConcreteExample {
            private identity: string = 'id';

            doSomething() {
            return 'done';
            }
            }

            function passMeExample(input: Example) {

            }

            // ConcreteExample is not allowable!
            passMeExample(new ConcreteExample());


            If you remove the private members, it changes the behaviour of the type checking:



            declare class Example {
            public doSomething(): string;
            }

            class ConcreteExample {
            private identity: string = 'id';

            doSomething() {
            return 'done';
            }
            }

            function passMeExample(input: Example) {

            }

            // OK!
            passMeExample(new ConcreteExample());


            So it is important to bear in mind that there is a difference in behaviour if you remove those private members. The classes will not act as they would if they were included.






            share|improve this answer




























              2














              A private method changes whether you can create a substitutable type, for example the declaration of Example prevents a type match with our concrete class (whether or not we add a private identity member!)



              declare class Example {
              private identity: string;
              public doSomething(): string;
              }

              class ConcreteExample {
              private identity: string = 'id';

              doSomething() {
              return 'done';
              }
              }

              function passMeExample(input: Example) {

              }

              // ConcreteExample is not allowable!
              passMeExample(new ConcreteExample());


              If you remove the private members, it changes the behaviour of the type checking:



              declare class Example {
              public doSomething(): string;
              }

              class ConcreteExample {
              private identity: string = 'id';

              doSomething() {
              return 'done';
              }
              }

              function passMeExample(input: Example) {

              }

              // OK!
              passMeExample(new ConcreteExample());


              So it is important to bear in mind that there is a difference in behaviour if you remove those private members. The classes will not act as they would if they were included.






              share|improve this answer


























                2












                2








                2







                A private method changes whether you can create a substitutable type, for example the declaration of Example prevents a type match with our concrete class (whether or not we add a private identity member!)



                declare class Example {
                private identity: string;
                public doSomething(): string;
                }

                class ConcreteExample {
                private identity: string = 'id';

                doSomething() {
                return 'done';
                }
                }

                function passMeExample(input: Example) {

                }

                // ConcreteExample is not allowable!
                passMeExample(new ConcreteExample());


                If you remove the private members, it changes the behaviour of the type checking:



                declare class Example {
                public doSomething(): string;
                }

                class ConcreteExample {
                private identity: string = 'id';

                doSomething() {
                return 'done';
                }
                }

                function passMeExample(input: Example) {

                }

                // OK!
                passMeExample(new ConcreteExample());


                So it is important to bear in mind that there is a difference in behaviour if you remove those private members. The classes will not act as they would if they were included.






                share|improve this answer













                A private method changes whether you can create a substitutable type, for example the declaration of Example prevents a type match with our concrete class (whether or not we add a private identity member!)



                declare class Example {
                private identity: string;
                public doSomething(): string;
                }

                class ConcreteExample {
                private identity: string = 'id';

                doSomething() {
                return 'done';
                }
                }

                function passMeExample(input: Example) {

                }

                // ConcreteExample is not allowable!
                passMeExample(new ConcreteExample());


                If you remove the private members, it changes the behaviour of the type checking:



                declare class Example {
                public doSomething(): string;
                }

                class ConcreteExample {
                private identity: string = 'id';

                doSomething() {
                return 'done';
                }
                }

                function passMeExample(input: Example) {

                }

                // OK!
                passMeExample(new ConcreteExample());


                So it is important to bear in mind that there is a difference in behaviour if you remove those private members. The classes will not act as they would if they were included.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 20 '18 at 9:25









                FentonFenton

                152k42287311




                152k42287311






























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