Question on book Numerical recipes, 2nd ed.: allocation/deallocation of memory for vectors












1














The book Numerical recipes, 2nd edition (http://numerical.recipes) uses the following code to allocate/deallocate a memory for a vector v with subscripts [nl..nh]:



#define NR_END 1
#define FREE_ARG char*

float *vector(long nl, long nh)
/* allocate a float vector with subscript range v[nl..nh] */
{
float *v;

v=(float *)malloc((size_t) ((nh-nl+1+NR_END)*sizeof(float)));
if (!v) nrerror("allocation failure in vector()");
return v-nl+NR_END;
}

void free_vector(float *v, long nl, long nh)
/* free a float vector allocated with vector() */
{
free((FREE_ARG) (v+nl-NR_END));
}


Question 1: What is the purpose of adding/subtracting NR_END elements?



Question 2: What is the purpose of converting float * to char * in free_vector?



I understand that +1 in malloc is due to the inclusive right boundary of the array (which is non-inclusive usually in C).










share|improve this question






















  • 1) Numerical Recipes uses first_index=1 indexing ( because it is basically converted FORTRAN code, which used offset=1 indexes) 2) before ANSI /c89 /c90 there was no void* and malloc and free used char pointers.
    – joop
    Nov 19 '18 at 16:32












  • @joop It doesn't use 1 indexing, the function lets you choose the first index.
    – interjay
    Nov 19 '18 at 16:32










  • For nl=0 it returns something different from what malloc returned.
    – joop
    Nov 19 '18 at 16:36










  • stackoverflow.com/q/41489210/2235885 for an example of someone assuming zero-based indexing.
    – joop
    Nov 19 '18 at 17:38










  • @joop, thanks for the explanation of char * in C before the 1989 standard.
    – Dmitry Kabanov
    Nov 19 '18 at 18:53
















1














The book Numerical recipes, 2nd edition (http://numerical.recipes) uses the following code to allocate/deallocate a memory for a vector v with subscripts [nl..nh]:



#define NR_END 1
#define FREE_ARG char*

float *vector(long nl, long nh)
/* allocate a float vector with subscript range v[nl..nh] */
{
float *v;

v=(float *)malloc((size_t) ((nh-nl+1+NR_END)*sizeof(float)));
if (!v) nrerror("allocation failure in vector()");
return v-nl+NR_END;
}

void free_vector(float *v, long nl, long nh)
/* free a float vector allocated with vector() */
{
free((FREE_ARG) (v+nl-NR_END));
}


Question 1: What is the purpose of adding/subtracting NR_END elements?



Question 2: What is the purpose of converting float * to char * in free_vector?



I understand that +1 in malloc is due to the inclusive right boundary of the array (which is non-inclusive usually in C).










share|improve this question






















  • 1) Numerical Recipes uses first_index=1 indexing ( because it is basically converted FORTRAN code, which used offset=1 indexes) 2) before ANSI /c89 /c90 there was no void* and malloc and free used char pointers.
    – joop
    Nov 19 '18 at 16:32












  • @joop It doesn't use 1 indexing, the function lets you choose the first index.
    – interjay
    Nov 19 '18 at 16:32










  • For nl=0 it returns something different from what malloc returned.
    – joop
    Nov 19 '18 at 16:36










  • stackoverflow.com/q/41489210/2235885 for an example of someone assuming zero-based indexing.
    – joop
    Nov 19 '18 at 17:38










  • @joop, thanks for the explanation of char * in C before the 1989 standard.
    – Dmitry Kabanov
    Nov 19 '18 at 18:53














1












1








1







The book Numerical recipes, 2nd edition (http://numerical.recipes) uses the following code to allocate/deallocate a memory for a vector v with subscripts [nl..nh]:



#define NR_END 1
#define FREE_ARG char*

float *vector(long nl, long nh)
/* allocate a float vector with subscript range v[nl..nh] */
{
float *v;

v=(float *)malloc((size_t) ((nh-nl+1+NR_END)*sizeof(float)));
if (!v) nrerror("allocation failure in vector()");
return v-nl+NR_END;
}

void free_vector(float *v, long nl, long nh)
/* free a float vector allocated with vector() */
{
free((FREE_ARG) (v+nl-NR_END));
}


Question 1: What is the purpose of adding/subtracting NR_END elements?



Question 2: What is the purpose of converting float * to char * in free_vector?



I understand that +1 in malloc is due to the inclusive right boundary of the array (which is non-inclusive usually in C).










share|improve this question













The book Numerical recipes, 2nd edition (http://numerical.recipes) uses the following code to allocate/deallocate a memory for a vector v with subscripts [nl..nh]:



#define NR_END 1
#define FREE_ARG char*

float *vector(long nl, long nh)
/* allocate a float vector with subscript range v[nl..nh] */
{
float *v;

v=(float *)malloc((size_t) ((nh-nl+1+NR_END)*sizeof(float)));
if (!v) nrerror("allocation failure in vector()");
return v-nl+NR_END;
}

void free_vector(float *v, long nl, long nh)
/* free a float vector allocated with vector() */
{
free((FREE_ARG) (v+nl-NR_END));
}


Question 1: What is the purpose of adding/subtracting NR_END elements?



Question 2: What is the purpose of converting float * to char * in free_vector?



I understand that +1 in malloc is due to the inclusive right boundary of the array (which is non-inclusive usually in C).







c numerical-recipes






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 19 '18 at 16:25









Dmitry Kabanov

136110




136110












  • 1) Numerical Recipes uses first_index=1 indexing ( because it is basically converted FORTRAN code, which used offset=1 indexes) 2) before ANSI /c89 /c90 there was no void* and malloc and free used char pointers.
    – joop
    Nov 19 '18 at 16:32












  • @joop It doesn't use 1 indexing, the function lets you choose the first index.
    – interjay
    Nov 19 '18 at 16:32










  • For nl=0 it returns something different from what malloc returned.
    – joop
    Nov 19 '18 at 16:36










  • stackoverflow.com/q/41489210/2235885 for an example of someone assuming zero-based indexing.
    – joop
    Nov 19 '18 at 17:38










  • @joop, thanks for the explanation of char * in C before the 1989 standard.
    – Dmitry Kabanov
    Nov 19 '18 at 18:53


















  • 1) Numerical Recipes uses first_index=1 indexing ( because it is basically converted FORTRAN code, which used offset=1 indexes) 2) before ANSI /c89 /c90 there was no void* and malloc and free used char pointers.
    – joop
    Nov 19 '18 at 16:32












  • @joop It doesn't use 1 indexing, the function lets you choose the first index.
    – interjay
    Nov 19 '18 at 16:32










  • For nl=0 it returns something different from what malloc returned.
    – joop
    Nov 19 '18 at 16:36










  • stackoverflow.com/q/41489210/2235885 for an example of someone assuming zero-based indexing.
    – joop
    Nov 19 '18 at 17:38










  • @joop, thanks for the explanation of char * in C before the 1989 standard.
    – Dmitry Kabanov
    Nov 19 '18 at 18:53
















1) Numerical Recipes uses first_index=1 indexing ( because it is basically converted FORTRAN code, which used offset=1 indexes) 2) before ANSI /c89 /c90 there was no void* and malloc and free used char pointers.
– joop
Nov 19 '18 at 16:32






1) Numerical Recipes uses first_index=1 indexing ( because it is basically converted FORTRAN code, which used offset=1 indexes) 2) before ANSI /c89 /c90 there was no void* and malloc and free used char pointers.
– joop
Nov 19 '18 at 16:32














@joop It doesn't use 1 indexing, the function lets you choose the first index.
– interjay
Nov 19 '18 at 16:32




@joop It doesn't use 1 indexing, the function lets you choose the first index.
– interjay
Nov 19 '18 at 16:32












For nl=0 it returns something different from what malloc returned.
– joop
Nov 19 '18 at 16:36




For nl=0 it returns something different from what malloc returned.
– joop
Nov 19 '18 at 16:36












stackoverflow.com/q/41489210/2235885 for an example of someone assuming zero-based indexing.
– joop
Nov 19 '18 at 17:38




stackoverflow.com/q/41489210/2235885 for an example of someone assuming zero-based indexing.
– joop
Nov 19 '18 at 17:38












@joop, thanks for the explanation of char * in C before the 1989 standard.
– Dmitry Kabanov
Nov 19 '18 at 18:53




@joop, thanks for the explanation of char * in C before the 1989 standard.
– Dmitry Kabanov
Nov 19 '18 at 18:53












1 Answer
1






active

oldest

votes


















1
















  1. Suppose you had nl=1 and NR_END=0. Then the returned pointer would be out of bounds (it points before the allocated block). This is undefined behavior and can lead to incorrect results, although it is unlikely to cause problems on major compilers because the pointer would be incremented back before it is dereferenced.



    To avoid this undefined behavior, you can set NR_END to the maximum expected value of nl (which is 1 in the book). This guarantees that the returned pointer is valid. However, the implementation given in the question is still incorrect, because v-nl+NR_END decrements by nl before incrementing by NR_END. A correct implementation would be v+NR_END-nl.



    Note that if nl only ever has non-negative values, a much simpler implementation would be to simply allocate nh+1 values, and then you don't need any pointer arithmetic after malloc or before free.



    Here you can see a quote from the book explaining this, from pages 940-941 of the second edition. Some quotes:




    it might
    happen in rare cases (and probably only on a segmented machine) that the expression b-1
    has no representation at all. If this occurs, then there is no guarantee that the relation
    b=(b-1)+1 is satisfied.




    [....]




    the parameter NR_END is used as a number of extra storage
    locations allocated at the beginning of every vector or matrix block, simply for the purpose
    of making offset pointer references guaranteed-representable.




  2. The cast to char* is not needed in any standardized version of C. It may have been needed in ancient versions. Casting the return value of malloc is also not needed.







share|improve this answer



















  • 1




    I'm not buying your explanation of NR_END. What you say is true, but if indeed values of nl different from 0 and 1 are not supported then it is sufficient to add NR_END to the size of the allocation, as indeed is done. vector() could then simply return the value from malloc() without doing any arithmetic on it, and vector_free() would not need to account for the same.
    – John Bollinger
    Nov 19 '18 at 17:29












  • @JohnBollinger It isn't my explanation, it is the book's explanation, See here. I did say in my answer that it would be much simpler to not perform any pointer arithmetic. It is in general quite bad code.
    – interjay
    Nov 19 '18 at 17:30










  • @interjay, thanks for the explanation! I wish I were more patient and looked at the book more carefully before asking my question here :-) I accept your answer.
    – Dmitry Kabanov
    Nov 19 '18 at 19:19










  • @interjay, regarding your third paragraph (starting with 'Note that if nl only ever has non-negative values'). Are you sure what you say is correct? I think, it is applicable only if you whant array to be indexed by 0, 1, ..., nh (inclusive). This routine expects the caller to index an array by nl, nl+1, ..., nh (inclusive).
    – Dmitry Kabanov
    Nov 19 '18 at 19:20






  • 1




    Thanks for the assumption of bad faith
    – Tim Randall
    Nov 19 '18 at 21:39











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  1. Suppose you had nl=1 and NR_END=0. Then the returned pointer would be out of bounds (it points before the allocated block). This is undefined behavior and can lead to incorrect results, although it is unlikely to cause problems on major compilers because the pointer would be incremented back before it is dereferenced.



    To avoid this undefined behavior, you can set NR_END to the maximum expected value of nl (which is 1 in the book). This guarantees that the returned pointer is valid. However, the implementation given in the question is still incorrect, because v-nl+NR_END decrements by nl before incrementing by NR_END. A correct implementation would be v+NR_END-nl.



    Note that if nl only ever has non-negative values, a much simpler implementation would be to simply allocate nh+1 values, and then you don't need any pointer arithmetic after malloc or before free.



    Here you can see a quote from the book explaining this, from pages 940-941 of the second edition. Some quotes:




    it might
    happen in rare cases (and probably only on a segmented machine) that the expression b-1
    has no representation at all. If this occurs, then there is no guarantee that the relation
    b=(b-1)+1 is satisfied.




    [....]




    the parameter NR_END is used as a number of extra storage
    locations allocated at the beginning of every vector or matrix block, simply for the purpose
    of making offset pointer references guaranteed-representable.




  2. The cast to char* is not needed in any standardized version of C. It may have been needed in ancient versions. Casting the return value of malloc is also not needed.







share|improve this answer



















  • 1




    I'm not buying your explanation of NR_END. What you say is true, but if indeed values of nl different from 0 and 1 are not supported then it is sufficient to add NR_END to the size of the allocation, as indeed is done. vector() could then simply return the value from malloc() without doing any arithmetic on it, and vector_free() would not need to account for the same.
    – John Bollinger
    Nov 19 '18 at 17:29












  • @JohnBollinger It isn't my explanation, it is the book's explanation, See here. I did say in my answer that it would be much simpler to not perform any pointer arithmetic. It is in general quite bad code.
    – interjay
    Nov 19 '18 at 17:30










  • @interjay, thanks for the explanation! I wish I were more patient and looked at the book more carefully before asking my question here :-) I accept your answer.
    – Dmitry Kabanov
    Nov 19 '18 at 19:19










  • @interjay, regarding your third paragraph (starting with 'Note that if nl only ever has non-negative values'). Are you sure what you say is correct? I think, it is applicable only if you whant array to be indexed by 0, 1, ..., nh (inclusive). This routine expects the caller to index an array by nl, nl+1, ..., nh (inclusive).
    – Dmitry Kabanov
    Nov 19 '18 at 19:20






  • 1




    Thanks for the assumption of bad faith
    – Tim Randall
    Nov 19 '18 at 21:39
















1
















  1. Suppose you had nl=1 and NR_END=0. Then the returned pointer would be out of bounds (it points before the allocated block). This is undefined behavior and can lead to incorrect results, although it is unlikely to cause problems on major compilers because the pointer would be incremented back before it is dereferenced.



    To avoid this undefined behavior, you can set NR_END to the maximum expected value of nl (which is 1 in the book). This guarantees that the returned pointer is valid. However, the implementation given in the question is still incorrect, because v-nl+NR_END decrements by nl before incrementing by NR_END. A correct implementation would be v+NR_END-nl.



    Note that if nl only ever has non-negative values, a much simpler implementation would be to simply allocate nh+1 values, and then you don't need any pointer arithmetic after malloc or before free.



    Here you can see a quote from the book explaining this, from pages 940-941 of the second edition. Some quotes:




    it might
    happen in rare cases (and probably only on a segmented machine) that the expression b-1
    has no representation at all. If this occurs, then there is no guarantee that the relation
    b=(b-1)+1 is satisfied.




    [....]




    the parameter NR_END is used as a number of extra storage
    locations allocated at the beginning of every vector or matrix block, simply for the purpose
    of making offset pointer references guaranteed-representable.




  2. The cast to char* is not needed in any standardized version of C. It may have been needed in ancient versions. Casting the return value of malloc is also not needed.







share|improve this answer



















  • 1




    I'm not buying your explanation of NR_END. What you say is true, but if indeed values of nl different from 0 and 1 are not supported then it is sufficient to add NR_END to the size of the allocation, as indeed is done. vector() could then simply return the value from malloc() without doing any arithmetic on it, and vector_free() would not need to account for the same.
    – John Bollinger
    Nov 19 '18 at 17:29












  • @JohnBollinger It isn't my explanation, it is the book's explanation, See here. I did say in my answer that it would be much simpler to not perform any pointer arithmetic. It is in general quite bad code.
    – interjay
    Nov 19 '18 at 17:30










  • @interjay, thanks for the explanation! I wish I were more patient and looked at the book more carefully before asking my question here :-) I accept your answer.
    – Dmitry Kabanov
    Nov 19 '18 at 19:19










  • @interjay, regarding your third paragraph (starting with 'Note that if nl only ever has non-negative values'). Are you sure what you say is correct? I think, it is applicable only if you whant array to be indexed by 0, 1, ..., nh (inclusive). This routine expects the caller to index an array by nl, nl+1, ..., nh (inclusive).
    – Dmitry Kabanov
    Nov 19 '18 at 19:20






  • 1




    Thanks for the assumption of bad faith
    – Tim Randall
    Nov 19 '18 at 21:39














1












1








1








  1. Suppose you had nl=1 and NR_END=0. Then the returned pointer would be out of bounds (it points before the allocated block). This is undefined behavior and can lead to incorrect results, although it is unlikely to cause problems on major compilers because the pointer would be incremented back before it is dereferenced.



    To avoid this undefined behavior, you can set NR_END to the maximum expected value of nl (which is 1 in the book). This guarantees that the returned pointer is valid. However, the implementation given in the question is still incorrect, because v-nl+NR_END decrements by nl before incrementing by NR_END. A correct implementation would be v+NR_END-nl.



    Note that if nl only ever has non-negative values, a much simpler implementation would be to simply allocate nh+1 values, and then you don't need any pointer arithmetic after malloc or before free.



    Here you can see a quote from the book explaining this, from pages 940-941 of the second edition. Some quotes:




    it might
    happen in rare cases (and probably only on a segmented machine) that the expression b-1
    has no representation at all. If this occurs, then there is no guarantee that the relation
    b=(b-1)+1 is satisfied.




    [....]




    the parameter NR_END is used as a number of extra storage
    locations allocated at the beginning of every vector or matrix block, simply for the purpose
    of making offset pointer references guaranteed-representable.




  2. The cast to char* is not needed in any standardized version of C. It may have been needed in ancient versions. Casting the return value of malloc is also not needed.







share|improve this answer
















  1. Suppose you had nl=1 and NR_END=0. Then the returned pointer would be out of bounds (it points before the allocated block). This is undefined behavior and can lead to incorrect results, although it is unlikely to cause problems on major compilers because the pointer would be incremented back before it is dereferenced.



    To avoid this undefined behavior, you can set NR_END to the maximum expected value of nl (which is 1 in the book). This guarantees that the returned pointer is valid. However, the implementation given in the question is still incorrect, because v-nl+NR_END decrements by nl before incrementing by NR_END. A correct implementation would be v+NR_END-nl.



    Note that if nl only ever has non-negative values, a much simpler implementation would be to simply allocate nh+1 values, and then you don't need any pointer arithmetic after malloc or before free.



    Here you can see a quote from the book explaining this, from pages 940-941 of the second edition. Some quotes:




    it might
    happen in rare cases (and probably only on a segmented machine) that the expression b-1
    has no representation at all. If this occurs, then there is no guarantee that the relation
    b=(b-1)+1 is satisfied.




    [....]




    the parameter NR_END is used as a number of extra storage
    locations allocated at the beginning of every vector or matrix block, simply for the purpose
    of making offset pointer references guaranteed-representable.




  2. The cast to char* is not needed in any standardized version of C. It may have been needed in ancient versions. Casting the return value of malloc is also not needed.








share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 19 '18 at 17:39

























answered Nov 19 '18 at 17:09









interjay

83.6k16202210




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  • 1




    I'm not buying your explanation of NR_END. What you say is true, but if indeed values of nl different from 0 and 1 are not supported then it is sufficient to add NR_END to the size of the allocation, as indeed is done. vector() could then simply return the value from malloc() without doing any arithmetic on it, and vector_free() would not need to account for the same.
    – John Bollinger
    Nov 19 '18 at 17:29












  • @JohnBollinger It isn't my explanation, it is the book's explanation, See here. I did say in my answer that it would be much simpler to not perform any pointer arithmetic. It is in general quite bad code.
    – interjay
    Nov 19 '18 at 17:30










  • @interjay, thanks for the explanation! I wish I were more patient and looked at the book more carefully before asking my question here :-) I accept your answer.
    – Dmitry Kabanov
    Nov 19 '18 at 19:19










  • @interjay, regarding your third paragraph (starting with 'Note that if nl only ever has non-negative values'). Are you sure what you say is correct? I think, it is applicable only if you whant array to be indexed by 0, 1, ..., nh (inclusive). This routine expects the caller to index an array by nl, nl+1, ..., nh (inclusive).
    – Dmitry Kabanov
    Nov 19 '18 at 19:20






  • 1




    Thanks for the assumption of bad faith
    – Tim Randall
    Nov 19 '18 at 21:39














  • 1




    I'm not buying your explanation of NR_END. What you say is true, but if indeed values of nl different from 0 and 1 are not supported then it is sufficient to add NR_END to the size of the allocation, as indeed is done. vector() could then simply return the value from malloc() without doing any arithmetic on it, and vector_free() would not need to account for the same.
    – John Bollinger
    Nov 19 '18 at 17:29












  • @JohnBollinger It isn't my explanation, it is the book's explanation, See here. I did say in my answer that it would be much simpler to not perform any pointer arithmetic. It is in general quite bad code.
    – interjay
    Nov 19 '18 at 17:30










  • @interjay, thanks for the explanation! I wish I were more patient and looked at the book more carefully before asking my question here :-) I accept your answer.
    – Dmitry Kabanov
    Nov 19 '18 at 19:19










  • @interjay, regarding your third paragraph (starting with 'Note that if nl only ever has non-negative values'). Are you sure what you say is correct? I think, it is applicable only if you whant array to be indexed by 0, 1, ..., nh (inclusive). This routine expects the caller to index an array by nl, nl+1, ..., nh (inclusive).
    – Dmitry Kabanov
    Nov 19 '18 at 19:20






  • 1




    Thanks for the assumption of bad faith
    – Tim Randall
    Nov 19 '18 at 21:39








1




1




I'm not buying your explanation of NR_END. What you say is true, but if indeed values of nl different from 0 and 1 are not supported then it is sufficient to add NR_END to the size of the allocation, as indeed is done. vector() could then simply return the value from malloc() without doing any arithmetic on it, and vector_free() would not need to account for the same.
– John Bollinger
Nov 19 '18 at 17:29






I'm not buying your explanation of NR_END. What you say is true, but if indeed values of nl different from 0 and 1 are not supported then it is sufficient to add NR_END to the size of the allocation, as indeed is done. vector() could then simply return the value from malloc() without doing any arithmetic on it, and vector_free() would not need to account for the same.
– John Bollinger
Nov 19 '18 at 17:29














@JohnBollinger It isn't my explanation, it is the book's explanation, See here. I did say in my answer that it would be much simpler to not perform any pointer arithmetic. It is in general quite bad code.
– interjay
Nov 19 '18 at 17:30




@JohnBollinger It isn't my explanation, it is the book's explanation, See here. I did say in my answer that it would be much simpler to not perform any pointer arithmetic. It is in general quite bad code.
– interjay
Nov 19 '18 at 17:30












@interjay, thanks for the explanation! I wish I were more patient and looked at the book more carefully before asking my question here :-) I accept your answer.
– Dmitry Kabanov
Nov 19 '18 at 19:19




@interjay, thanks for the explanation! I wish I were more patient and looked at the book more carefully before asking my question here :-) I accept your answer.
– Dmitry Kabanov
Nov 19 '18 at 19:19












@interjay, regarding your third paragraph (starting with 'Note that if nl only ever has non-negative values'). Are you sure what you say is correct? I think, it is applicable only if you whant array to be indexed by 0, 1, ..., nh (inclusive). This routine expects the caller to index an array by nl, nl+1, ..., nh (inclusive).
– Dmitry Kabanov
Nov 19 '18 at 19:20




@interjay, regarding your third paragraph (starting with 'Note that if nl only ever has non-negative values'). Are you sure what you say is correct? I think, it is applicable only if you whant array to be indexed by 0, 1, ..., nh (inclusive). This routine expects the caller to index an array by nl, nl+1, ..., nh (inclusive).
– Dmitry Kabanov
Nov 19 '18 at 19:20




1




1




Thanks for the assumption of bad faith
– Tim Randall
Nov 19 '18 at 21:39




Thanks for the assumption of bad faith
– Tim Randall
Nov 19 '18 at 21:39


















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