Mixing
Embedded Python Block - Get value from work
0
How can I get a value calculated in def work(self, input_items, output_items) and use it in a getter method?
Until now, I defined a self.value but it does not change.
I attached a capture containing my code.how to pass a to getA?
python gnuradio gnuradio-companion
asked Nov 19 '18 at 12:51
Friedrich Maar
13
add a comment |
0
How can I get a value calculated in def work(self, input_items, output_items) and use it in a getter method?
Until now, I defined a self.value but it does not change.
I attached a capture containing my code.how to pass a to getA?
python gnuradio gnuradio-companion
asked Nov 19 '18 at 12:51
Friedrich Maar
13
1
posting the code inside your answer would help others help you
– m1sk
Nov 19 '18 at 12:56
I'm having trouble understanding exactly what you want to do. Could you name each variable and explain what you want to go where?
– m1sk
Nov 19 '18 at 13:23
Sorry if I am unclear. The objective is to access "a" from work() and use it in getA(). I have tried before your answer the method you proposed but the result was 0 not 100. I think work has local effect, not global.
– Friedrich Maar
Nov 19 '18 at 13:32
I think this has something to do with the way gnuradio blocks are run. I'm unfamiliar with them, but I peeked at their documentation. It could be that this sort of thing is impossible in gnuradio. But I don't really know that area, maybe take a step back and think about what you are trying to accomplish, it might be possible by sending more output parameters?
– m1sk
Nov 19 '18 at 13:40
I thought about that, but I will search a little bit. Thank you!
– Friedrich Maar
Nov 19 '18 at 13:47
add a comment |
0
0
0
How can I get a value calculated in def work(self, input_items, output_items) and use it in a getter method?
Until now, I defined a self.value but it does not change.
I attached a capture containing my code.how to pass a to getA?
python gnuradio gnuradio-companion
asked Nov 19 '18 at 12:51
Friedrich Maar
13
How can I get a value calculated in def work(self, input_items, output_items) and use it in a getter method?
Until now, I defined a self.value but it does not change.
I attached a capture containing my code.how to pass a to getA?
python gnuradio gnuradio-companion
python gnuradio gnuradio-companion
asked Nov 19 '18 at 12:51
Friedrich Maar
13
asked Nov 19 '18 at 12:51
Friedrich Maar
13
asked Nov 19 '18 at 12:51
Friedrich Maar
13
asked Nov 19 '18 at 12:51
Friedrich Maar
13
asked Nov 19 '18 at 12:51
Friedrich Maar
13
13
1
posting the code inside your answer would help others help you
– m1sk
Nov 19 '18 at 12:56
I'm having trouble understanding exactly what you want to do. Could you name each variable and explain what you want to go where?
– m1sk
Nov 19 '18 at 13:23
Sorry if I am unclear. The objective is to access "a" from work() and use it in getA(). I have tried before your answer the method you proposed but the result was 0 not 100. I think work has local effect, not global.
– Friedrich Maar
Nov 19 '18 at 13:32
I think this has something to do with the way gnuradio blocks are run. I'm unfamiliar with them, but I peeked at their documentation. It could be that this sort of thing is impossible in gnuradio. But I don't really know that area, maybe take a step back and think about what you are trying to accomplish, it might be possible by sending more output parameters?
– m1sk
Nov 19 '18 at 13:40
I thought about that, but I will search a little bit. Thank you!
– Friedrich Maar
Nov 19 '18 at 13:47
add a comment |
1
posting the code inside your answer would help others help you
– m1sk
Nov 19 '18 at 12:56
I'm having trouble understanding exactly what you want to do. Could you name each variable and explain what you want to go where?
– m1sk
Nov 19 '18 at 13:23
Sorry if I am unclear. The objective is to access "a" from work() and use it in getA(). I have tried before your answer the method you proposed but the result was 0 not 100. I think work has local effect, not global.
– Friedrich Maar
Nov 19 '18 at 13:32
I think this has something to do with the way gnuradio blocks are run. I'm unfamiliar with them, but I peeked at their documentation. It could be that this sort of thing is impossible in gnuradio. But I don't really know that area, maybe take a step back and think about what you are trying to accomplish, it might be possible by sending more output parameters?
– m1sk
Nov 19 '18 at 13:40
I thought about that, but I will search a little bit. Thank you!
– Friedrich Maar
Nov 19 '18 at 13:47
1
1
posting the code inside your answer would help others help you
– m1sk
Nov 19 '18 at 12:56
posting the code inside your answer would help others help you
– m1sk
Nov 19 '18 at 12:56
I'm having trouble understanding exactly what you want to do. Could you name each variable and explain what you want to go where?
– m1sk
Nov 19 '18 at 13:23
I'm having trouble understanding exactly what you want to do. Could you name each variable and explain what you want to go where?
– m1sk
Nov 19 '18 at 13:23
Sorry if I am unclear. The objective is to access "a" from work() and use it in getA(). I have tried before your answer the method you proposed but the result was 0 not 100. I think work has local effect, not global.
– Friedrich Maar
Nov 19 '18 at 13:32
Sorry if I am unclear. The objective is to access "a" from work() and use it in getA(). I have tried before your answer the method you proposed but the result was 0 not 100. I think work has local effect, not global.
– Friedrich Maar
Nov 19 '18 at 13:32
I think this has something to do with the way gnuradio blocks are run. I'm unfamiliar with them, but I peeked at their documentation. It could be that this sort of thing is impossible in gnuradio. But I don't really know that area, maybe take a step back and think about what you are trying to accomplish, it might be possible by sending more output parameters?
– m1sk
Nov 19 '18 at 13:40
I think this has something to do with the way gnuradio blocks are run. I'm unfamiliar with them, but I peeked at their documentation. It could be that this sort of thing is impossible in gnuradio. But I don't really know that area, maybe take a step back and think about what you are trying to accomplish, it might be possible by sending more output parameters?
– m1sk
Nov 19 '18 at 13:40
I thought about that, but I will search a little bit. Thank you!
– Friedrich Maar
Nov 19 '18 at 13:47
I thought about that, but I will search a little bit. Thank you!
– Friedrich Maar
Nov 19 '18 at 13:47
add a comment |
1 Answer
1
active
oldest
votes
2
You are storing the value of a in self.b.
So you can just return that value:
def getA(self):
return self.b
answered Nov 19 '18 at 12:59
m1sk
17310
It will not be OK. self.b does not change in work(). I need something to do this change.
– Friedrich Maar
Nov 19 '18 at 13:11
1
@FriedrichMaar GNU Radio maintainer here. It does change. If it doesn't, something else is wrong. In this case, you're returning somea(which you didn't define anywhere in that scope, so you should be getting an exception); you should be, as m1sk recommends, returningself.b.
– Marcus Müller
Nov 20 '18 at 0:30
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
You are storing the value of a in self.b.
So you can just return that value:
def getA(self):
return self.b
answered Nov 19 '18 at 12:59
m1sk
17310
It will not be OK. self.b does not change in work(). I need something to do this change.
– Friedrich Maar
Nov 19 '18 at 13:11
1
@FriedrichMaar GNU Radio maintainer here. It does change. If it doesn't, something else is wrong. In this case, you're returning somea(which you didn't define anywhere in that scope, so you should be getting an exception); you should be, as m1sk recommends, returningself.b.
– Marcus Müller
Nov 20 '18 at 0:30
add a comment |
2
You are storing the value of a in self.b.
So you can just return that value:
def getA(self):
return self.b
answered Nov 19 '18 at 12:59
m1sk
17310
It will not be OK. self.b does not change in work(). I need something to do this change.
– Friedrich Maar
Nov 19 '18 at 13:11
1
@FriedrichMaar GNU Radio maintainer here. It does change. If it doesn't, something else is wrong. In this case, you're returning somea(which you didn't define anywhere in that scope, so you should be getting an exception); you should be, as m1sk recommends, returningself.b.
– Marcus Müller
Nov 20 '18 at 0:30
add a comment |
2
2
2
You are storing the value of a in self.b.
So you can just return that value:
def getA(self):
return self.b
answered Nov 19 '18 at 12:59
m1sk
17310
You are storing the value of a in self.b.
So you can just return that value:
def getA(self):
return self.b
answered Nov 19 '18 at 12:59
m1sk
17310
answered Nov 19 '18 at 12:59
m1sk
17310
answered Nov 19 '18 at 12:59
m1sk
17310
answered Nov 19 '18 at 12:59
m1sk
17310
17310
It will not be OK. self.b does not change in work(). I need something to do this change.
– Friedrich Maar
Nov 19 '18 at 13:11
1
@FriedrichMaar GNU Radio maintainer here. It does change. If it doesn't, something else is wrong. In this case, you're returning somea(which you didn't define anywhere in that scope, so you should be getting an exception); you should be, as m1sk recommends, returningself.b.
– Marcus Müller
Nov 20 '18 at 0:30
add a comment |
It will not be OK. self.b does not change in work(). I need something to do this change.
– Friedrich Maar
Nov 19 '18 at 13:11
1
@FriedrichMaar GNU Radio maintainer here. It does change. If it doesn't, something else is wrong. In this case, you're returning somea(which you didn't define anywhere in that scope, so you should be getting an exception); you should be, as m1sk recommends, returningself.b.
– Marcus Müller
Nov 20 '18 at 0:30
It will not be OK. self.b does not change in work(). I need something to do this change.
– Friedrich Maar
Nov 19 '18 at 13:11
It will not be OK. self.b does not change in work(). I need something to do this change.
– Friedrich Maar
Nov 19 '18 at 13:11
1
1
@FriedrichMaar GNU Radio maintainer here. It does change. If it doesn't, something else is wrong. In this case, you're returning some
a (which you didn't define anywhere in that scope, so you should be getting an exception); you should be, as m1sk recommends, returning self.b.– Marcus Müller
Nov 20 '18 at 0:30
@FriedrichMaar GNU Radio maintainer here. It does change. If it doesn't, something else is wrong. In this case, you're returning some
a (which you didn't define anywhere in that scope, so you should be getting an exception); you should be, as m1sk recommends, returning self.b.– Marcus Müller
Nov 20 '18 at 0:30
add a comment |
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1
posting the code inside your answer would help others help you
– m1sk
Nov 19 '18 at 12:56
I'm having trouble understanding exactly what you want to do. Could you name each variable and explain what you want to go where?
– m1sk
Nov 19 '18 at 13:23
Sorry if I am unclear. The objective is to access "a" from work() and use it in getA(). I have tried before your answer the method you proposed but the result was 0 not 100. I think work has local effect, not global.
– Friedrich Maar
Nov 19 '18 at 13:32
I think this has something to do with the way gnuradio blocks are run. I'm unfamiliar with them, but I peeked at their documentation. It could be that this sort of thing is impossible in gnuradio. But I don't really know that area, maybe take a step back and think about what you are trying to accomplish, it might be possible by sending more output parameters?
– m1sk
Nov 19 '18 at 13:40
I thought about that, but I will search a little bit. Thank you!
– Friedrich Maar
Nov 19 '18 at 13:47