Mixing
Find the inverse laplace (if there is one)
$begingroup$
I need to find if F(s) can be a laplace transform of a continuous exponential function:
F(s)=s^3/(s^3+2s^2+s+1)
any ideas?
laplace-transform
asked Jan 13 at 1:46
eceece
12
$endgroup$
add a comment |
$begingroup$
I need to find if F(s) can be a laplace transform of a continuous exponential function:
F(s)=s^3/(s^3+2s^2+s+1)
any ideas?
laplace-transform
asked Jan 13 at 1:46
eceece
12
$endgroup$
$begingroup$
Well the fact that it doesn't vanish at infinity already means there's some kind of Dirac delta going on, are you prepared for that? If not then you've probably written the problem wrong. The fact that the roots of the cubic in the denominator are really nasty also suggests you may have written the problem wrong.
$endgroup$
– Ian
Jan 13 at 1:48
add a comment |
$begingroup$
I need to find if F(s) can be a laplace transform of a continuous exponential function:
F(s)=s^3/(s^3+2s^2+s+1)
any ideas?
laplace-transform
asked Jan 13 at 1:46
eceece
12
$endgroup$
I need to find if F(s) can be a laplace transform of a continuous exponential function:
F(s)=s^3/(s^3+2s^2+s+1)
any ideas?
laplace-transform
laplace-transform
asked Jan 13 at 1:46
eceece
12
asked Jan 13 at 1:46
eceece
12
edited Jan 13 at 1:54
ece
asked Jan 13 at 1:46
eceece
12
asked Jan 13 at 1:46
eceece
12
asked Jan 13 at 1:46
eceece
12
12
$begingroup$
Well the fact that it doesn't vanish at infinity already means there's some kind of Dirac delta going on, are you prepared for that? If not then you've probably written the problem wrong. The fact that the roots of the cubic in the denominator are really nasty also suggests you may have written the problem wrong.
$endgroup$
– Ian
Jan 13 at 1:48
add a comment |
$begingroup$
Well the fact that it doesn't vanish at infinity already means there's some kind of Dirac delta going on, are you prepared for that? If not then you've probably written the problem wrong. The fact that the roots of the cubic in the denominator are really nasty also suggests you may have written the problem wrong.
$endgroup$
– Ian
Jan 13 at 1:48
$begingroup$
Well the fact that it doesn't vanish at infinity already means there's some kind of Dirac delta going on, are you prepared for that? If not then you've probably written the problem wrong. The fact that the roots of the cubic in the denominator are really nasty also suggests you may have written the problem wrong.
$endgroup$
– Ian
Jan 13 at 1:48
$begingroup$
Well the fact that it doesn't vanish at infinity already means there's some kind of Dirac delta going on, are you prepared for that? If not then you've probably written the problem wrong. The fact that the roots of the cubic in the denominator are really nasty also suggests you may have written the problem wrong.
$endgroup$
– Ian
Jan 13 at 1:48
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
As Ian suggests, because of the equal polynomial orders in the numerator and the denominator, the inverse implicates the Dirac delta function. So the answer is no, F(s) is not a transform of a continuous exponential function.
answered Jan 15 at 17:53
SotirisSotiris
814
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3071618%2ffind-the-inverse-laplace-if-there-is-one%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
As Ian suggests, because of the equal polynomial orders in the numerator and the denominator, the inverse implicates the Dirac delta function. So the answer is no, F(s) is not a transform of a continuous exponential function.
answered Jan 15 at 17:53
SotirisSotiris
814
$endgroup$
add a comment |
$begingroup$
As Ian suggests, because of the equal polynomial orders in the numerator and the denominator, the inverse implicates the Dirac delta function. So the answer is no, F(s) is not a transform of a continuous exponential function.
answered Jan 15 at 17:53
SotirisSotiris
814
$endgroup$
add a comment |
$begingroup$
As Ian suggests, because of the equal polynomial orders in the numerator and the denominator, the inverse implicates the Dirac delta function. So the answer is no, F(s) is not a transform of a continuous exponential function.
answered Jan 15 at 17:53
SotirisSotiris
814
$endgroup$
As Ian suggests, because of the equal polynomial orders in the numerator and the denominator, the inverse implicates the Dirac delta function. So the answer is no, F(s) is not a transform of a continuous exponential function.
answered Jan 15 at 17:53
SotirisSotiris
814
answered Jan 15 at 17:53
SotirisSotiris
814
answered Jan 15 at 17:53
SotirisSotiris
814
answered Jan 15 at 17:53
SotirisSotiris
814
814
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3071618%2ffind-the-inverse-laplace-if-there-is-one%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
Well the fact that it doesn't vanish at infinity already means there's some kind of Dirac delta going on, are you prepared for that? If not then you've probably written the problem wrong. The fact that the roots of the cubic in the denominator are really nasty also suggests you may have written the problem wrong.
$endgroup$
– Ian
Jan 13 at 1:48