How to check if a certain string repeats more than once in a list

In my code, I want to check whether I could check if a certain string e.g

a="."

repeats more than once in a list. e.g

b=[".", ".", "Hello world"]

how would I do that?

asked Nov 22 '18 at 7:03

Coder Cody

408

1

b.count(a) > 1

– sashaaero
Nov 22 '18 at 7:04

add a comment |

In my code, I want to check whether I could check if a certain string e.g

a="."

repeats more than once in a list. e.g

b=[".", ".", "Hello world"]

how would I do that?

asked Nov 22 '18 at 7:03

Coder Cody

408

1

b.count(a) > 1

– sashaaero
Nov 22 '18 at 7:04

add a comment |

In my code, I want to check whether I could check if a certain string e.g

a="."

repeats more than once in a list. e.g

b=[".", ".", "Hello world"]

how would I do that?

asked Nov 22 '18 at 7:03

Coder Cody

408

In my code, I want to check whether I could check if a certain string e.g

a="."

repeats more than once in a list. e.g

b=[".", ".", "Hello world"]

how would I do that?

python python-3.x

asked Nov 22 '18 at 7:03

Coder Cody

408

asked Nov 22 '18 at 7:03

Coder Cody

408

asked Nov 22 '18 at 7:03

Coder Cody

408

asked Nov 22 '18 at 7:03

Coder Cody

408

asked Nov 22 '18 at 7:03

Coder Cody

408

1

b.count(a) > 1

– sashaaero
Nov 22 '18 at 7:04

add a comment |

1

b.count(a) > 1

– sashaaero
Nov 22 '18 at 7:04

b.count(a) > 1

– sashaaero
Nov 22 '18 at 7:04

add a comment |

5 Answers
5

active

oldest

votes

b=[".", ".", "Hello world"]

print(b.count(a))

>>> 2

Use count function.

answered Nov 22 '18 at 7:04

Sandesh34

254113

add a comment |

You can use the built in count method

n_occurences = b.count(a)

answered Nov 22 '18 at 7:04

Sven Harris

2,1881515

add a comment |

Use collections.Counter() or simply list.count()

list.count(x) will return the count of x in list

b=[".", ".", "Hello world"]

# Check for "."

print(b.count(".")

collections.Counter will return a dictionary, which have count information of every item in a list:

from collections import Counter



b=[".", ".", "Hello world"]

# Check for "."

count = b.Counter() 



if count["."] > 1:

   print("More than one occurance")

edited Nov 22 '18 at 7:07

answered Nov 22 '18 at 7:05

enamoria

617621

I think collections.Counter is overkill for this case.

– sashaaero
Nov 22 '18 at 7:05

@sashaaero you are right. I've read OP carelessly and only come with the idea of using Counter. I've made an edit, count() is sufficient for such tasks :D

– enamoria
Nov 22 '18 at 7:09

add a comment |

Use count function.

    a="."

    b=[".", ".", "Hello world"]

    if b.count(a) > 1:

        print("more than 1 time")

answered Nov 22 '18 at 7:09

Usman

800614

add a comment |

Using collections.Counter:

from collections import Counter



a = "."

b=[".", ".", "Hello world"]



print(Counter(b)[a]) # 2

answered Nov 22 '18 at 7:17

b-fg

1,95911522

add a comment |

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5 Answers
5

active

oldest

votes

5 Answers
5

active

oldest

votes

b=[".", ".", "Hello world"]

print(b.count(a))

>>> 2

Use count function.

answered Nov 22 '18 at 7:04

Sandesh34

254113

add a comment |

b=[".", ".", "Hello world"]

print(b.count(a))

>>> 2

Use count function.

answered Nov 22 '18 at 7:04

Sandesh34

254113

add a comment |

b=[".", ".", "Hello world"]

print(b.count(a))

>>> 2

Use count function.

answered Nov 22 '18 at 7:04

Sandesh34

254113

b=[".", ".", "Hello world"]

print(b.count(a))

>>> 2

Use count function.

answered Nov 22 '18 at 7:04

Sandesh34

254113

answered Nov 22 '18 at 7:04

Sandesh34

254113

answered Nov 22 '18 at 7:04

Sandesh34

254113

answered Nov 22 '18 at 7:04

Sandesh34

254113

add a comment |

You can use the built in count method

n_occurences = b.count(a)

answered Nov 22 '18 at 7:04

Sven Harris

2,1881515

add a comment |

You can use the built in count method

n_occurences = b.count(a)

answered Nov 22 '18 at 7:04

Sven Harris

2,1881515

add a comment |

You can use the built in count method

n_occurences = b.count(a)

answered Nov 22 '18 at 7:04

Sven Harris

2,1881515

You can use the built in count method

n_occurences = b.count(a)

answered Nov 22 '18 at 7:04

Sven Harris

2,1881515

answered Nov 22 '18 at 7:04

Sven Harris

2,1881515

answered Nov 22 '18 at 7:04

Sven Harris

2,1881515

answered Nov 22 '18 at 7:04

Sven Harris

2,1881515

add a comment |

Use collections.Counter() or simply list.count()

list.count(x) will return the count of x in list

b=[".", ".", "Hello world"]

# Check for "."

print(b.count(".")

collections.Counter will return a dictionary, which have count information of every item in a list:

from collections import Counter



b=[".", ".", "Hello world"]

# Check for "."

count = b.Counter() 



if count["."] > 1:

   print("More than one occurance")

edited Nov 22 '18 at 7:07

answered Nov 22 '18 at 7:05

enamoria

617621

I think collections.Counter is overkill for this case.

– sashaaero
Nov 22 '18 at 7:05

@sashaaero you are right. I've read OP carelessly and only come with the idea of using Counter. I've made an edit, count() is sufficient for such tasks :D

– enamoria
Nov 22 '18 at 7:09

add a comment |

Use collections.Counter() or simply list.count()

list.count(x) will return the count of x in list

b=[".", ".", "Hello world"]

# Check for "."

print(b.count(".")

collections.Counter will return a dictionary, which have count information of every item in a list:

from collections import Counter



b=[".", ".", "Hello world"]

# Check for "."

count = b.Counter() 



if count["."] > 1:

   print("More than one occurance")

edited Nov 22 '18 at 7:07

answered Nov 22 '18 at 7:05

enamoria

617621

I think collections.Counter is overkill for this case.

– sashaaero
Nov 22 '18 at 7:05

@sashaaero you are right. I've read OP carelessly and only come with the idea of using Counter. I've made an edit, count() is sufficient for such tasks :D

– enamoria
Nov 22 '18 at 7:09

add a comment |

Use collections.Counter() or simply list.count()

list.count(x) will return the count of x in list

b=[".", ".", "Hello world"]

# Check for "."

print(b.count(".")

collections.Counter will return a dictionary, which have count information of every item in a list:

from collections import Counter



b=[".", ".", "Hello world"]

# Check for "."

count = b.Counter() 



if count["."] > 1:

   print("More than one occurance")

edited Nov 22 '18 at 7:07

answered Nov 22 '18 at 7:05

enamoria

617621

Use collections.Counter() or simply list.count()

list.count(x) will return the count of x in list

b=[".", ".", "Hello world"]

# Check for "."

print(b.count(".")

collections.Counter will return a dictionary, which have count information of every item in a list:

from collections import Counter



b=[".", ".", "Hello world"]

# Check for "."

count = b.Counter() 



if count["."] > 1:

   print("More than one occurance")

edited Nov 22 '18 at 7:07

answered Nov 22 '18 at 7:05

enamoria

617621

edited Nov 22 '18 at 7:07

answered Nov 22 '18 at 7:05

enamoria

617621

answered Nov 22 '18 at 7:05

enamoria

617621

answered Nov 22 '18 at 7:05

enamoria

617621

I think collections.Counter is overkill for this case.

– sashaaero
Nov 22 '18 at 7:05

@sashaaero you are right. I've read OP carelessly and only come with the idea of using Counter. I've made an edit, count() is sufficient for such tasks :D

– enamoria
Nov 22 '18 at 7:09

add a comment |

I think collections.Counter is overkill for this case.

– sashaaero
Nov 22 '18 at 7:05

@sashaaero you are right. I've read OP carelessly and only come with the idea of using Counter. I've made an edit, count() is sufficient for such tasks :D

– enamoria
Nov 22 '18 at 7:09

I think collections.Counter is overkill for this case.

– sashaaero
Nov 22 '18 at 7:05

@sashaaero you are right. I've read OP carelessly and only come with the idea of using Counter. I've made an edit, count() is sufficient for such tasks :D

– enamoria
Nov 22 '18 at 7:09

add a comment |

Use count function.

    a="."

    b=[".", ".", "Hello world"]

    if b.count(a) > 1:

        print("more than 1 time")

answered Nov 22 '18 at 7:09

Usman

800614

add a comment |

Use count function.

    a="."

    b=[".", ".", "Hello world"]

    if b.count(a) > 1:

        print("more than 1 time")

answered Nov 22 '18 at 7:09

Usman

800614

add a comment |

Use count function.

    a="."

    b=[".", ".", "Hello world"]

    if b.count(a) > 1:

        print("more than 1 time")

answered Nov 22 '18 at 7:09

Usman

800614

Use count function.

    a="."

    b=[".", ".", "Hello world"]

    if b.count(a) > 1:

        print("more than 1 time")

answered Nov 22 '18 at 7:09

Usman

800614

answered Nov 22 '18 at 7:09

Usman

800614

answered Nov 22 '18 at 7:09

Usman

800614

answered Nov 22 '18 at 7:09

Usman

800614

add a comment |

Using collections.Counter:

from collections import Counter



a = "."

b=[".", ".", "Hello world"]



print(Counter(b)[a]) # 2

answered Nov 22 '18 at 7:17

b-fg

1,95911522

add a comment |

Using collections.Counter:

from collections import Counter



a = "."

b=[".", ".", "Hello world"]



print(Counter(b)[a]) # 2

answered Nov 22 '18 at 7:17

b-fg

1,95911522

add a comment |

Using collections.Counter:

from collections import Counter



a = "."

b=[".", ".", "Hello world"]



print(Counter(b)[a]) # 2

answered Nov 22 '18 at 7:17

b-fg

1,95911522

Using collections.Counter:

from collections import Counter



a = "."

b=[".", ".", "Hello world"]



print(Counter(b)[a]) # 2

answered Nov 22 '18 at 7:17

b-fg

1,95911522

answered Nov 22 '18 at 7:17

b-fg

1,95911522

answered Nov 22 '18 at 7:17

b-fg

1,95911522

answered Nov 22 '18 at 7:17

b-fg

1,95911522

add a comment |

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