Mixing
Replacing all non-alphanumeric characters with empty strings
I tried using this but didn't work-
return value.replaceAll("/[^A-Za-z0-9 ]/", "");
java regex non-alphanumeric
asked Nov 26 '09 at 20:28
Alex GomesAlex Gomes
900286
add a comment |
I tried using this but didn't work-
return value.replaceAll("/[^A-Za-z0-9 ]/", "");
java regex non-alphanumeric
asked Nov 26 '09 at 20:28
Alex GomesAlex Gomes
900286
27
Guys, you forget there are alphabets other than the Latin one.
– Mateva
Oct 14 '15 at 16:48
add a comment |
I tried using this but didn't work-
return value.replaceAll("/[^A-Za-z0-9 ]/", "");
java regex non-alphanumeric
asked Nov 26 '09 at 20:28
Alex GomesAlex Gomes
900286
I tried using this but didn't work-
return value.replaceAll("/[^A-Za-z0-9 ]/", "");
java regex non-alphanumeric
java regex non-alphanumeric
asked Nov 26 '09 at 20:28
Alex GomesAlex Gomes
900286
asked Nov 26 '09 at 20:28
Alex GomesAlex Gomes
900286
asked Nov 26 '09 at 20:28
Alex GomesAlex Gomes
900286
asked Nov 26 '09 at 20:28
Alex GomesAlex Gomes
900286
asked Nov 26 '09 at 20:28
Alex GomesAlex Gomes
900286
900286
27
Guys, you forget there are alphabets other than the Latin one.
– Mateva
Oct 14 '15 at 16:48
add a comment |
27
Guys, you forget there are alphabets other than the Latin one.
– Mateva
Oct 14 '15 at 16:48
27
27
Guys, you forget there are alphabets other than the Latin one.
– Mateva
Oct 14 '15 at 16:48
Guys, you forget there are alphabets other than the Latin one.
– Mateva
Oct 14 '15 at 16:48
add a comment |
12 Answers
12
active
oldest
votes
Use [^A-Za-z0-9].
Note: removed the space since that is not typically considered alphanumeric.
edited Sep 18 '17 at 17:14
Dave Jarvis
21k30131256
answered Nov 26 '09 at 20:30
Mirek PlutaMirek Pluta
5,94312619
10
Neither should the space at the end of the character class.
– Andrew Duffy
Nov 26 '09 at 20:31
6
He's probably used to programming in PHP.
– William
Nov 26 '09 at 20:31
10
@William -- it's unfortunate that PHP is now getting credit for PCRE
– Thomas Dignan
Feb 11 '13 at 3:10
add a comment |
Try
return value.replaceAll("[^A-Za-z0-9]", "");
or
return value.replaceAll("[\W]|_", "");
answered Nov 26 '09 at 20:33
Andrew DuffyAndrew Duffy
5,49211716
3
With underscores,return value.replaceAll("\W", "");
– erickson
Nov 26 '09 at 20:35
Of course. Compilers are great at spotting that sort of thing.
– Andrew Duffy
Nov 26 '09 at 20:36
1
The second one doesn't answer the question. What about characters like : / etc?
– WW.
Dec 29 '14 at 4:03
add a comment |
return value.replaceAll("[^A-Za-z0-9 ]", "");
This will leave spaces intact. I assume that's what you want. Otherwise, remove the space from the regex.
answered Nov 26 '09 at 20:31
ericksonerickson
222k42331428
add a comment |
You should be aware that [^a-zA-Z] will replace characters not being itself in the character range A-Z/a-z. That means special characters like é, ß etc. or cyrillic characters and such will be removed.
If the replacement of these characters is not wanted use pre-defined character classes instead:
someString.replaceAll("[^\p{IsAlphabetic}^\p{IsDigit}]", "");
PS: p{Alnum} does not achieve this effect, it acts the same as [A-Za-z0-9].
answered Sep 17 '15 at 10:25
Andre SteingressAndre Steingress
3,3872022
6
Thanks a lot for this post - it was very useful to me. Additionally, I believe this is the actual answer to the question. The Latin alphabet isn't the only one in the world!
– Mateva
Oct 15 '15 at 7:15
1
Actually, the stated regex will treat "^" as a valid character, since only the first occurrence of "^" is negating the meaning of the selection.[^\p{IsAlphabetic}\p{IsDigit}]works well.
– Bogdan Klichuk
Jan 19 '18 at 17:22
Only[^\p{Alpha}\p{Digit}]works for me
– Jakub Turcovsky
Apr 17 '18 at 13:47
1
@JakubTurcovsky docs.oracle.com/javase/10/docs/api/java/util/regex/Pattern.html defines IsAlphabetic and IsDigit as binary properties. Alpha and Digit are POSIX character classes (US-ASCII only). Except the docs.oracle.com/javase/10/docs/api/java/util/regex/… flag is specified.
– Andre Steingress
Apr 17 '18 at 14:39
@AndreSteingress Correct, the reason{IsDigit}doesn't work for me and{Digit}does is that I'm trying this on Android. And Android hasUNICODE_CHARACTER_CLASSturned on by default. Thanks for clearance.
– Jakub Turcovsky
Apr 30 '18 at 11:28
|
show 1 more comment
You could also try this simpler regex:
str = str.replaceAll("\P{Alnum}", "");
edited May 20 '14 at 3:14
nhinkle
87911831
answered Aug 6 '13 at 12:17
sauravsaurav
2,6761630
2
Or, preserving whitespace:str.replaceAll("[^\p{Alnum}\s]", "")
– Jonik
Dec 29 '15 at 10:28
Or\p{Alnum}\p{Space}.
– membersound
Dec 15 '16 at 11:22
add a comment |
Java's regular expressions don't require you to put a forward-slash (/) or any other delimiter around the regex, as opposed to other languages like Perl, for example.
answered Nov 26 '09 at 20:39
abyxabyx
43.1k1578109
add a comment |
I made this method for creating filenames:
public static String safeChar(String input)
{
char allowed = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ-_".toCharArray();
char charArray = input.toString().toCharArray();
StringBuilder result = new StringBuilder();
for (char c : charArray)
{
for (char a : allowed)
{
if(c==a) result.append(a);
}
}
return result.toString();
}
answered Nov 27 '09 at 2:08
zneozneo
488310
4
This is pretty brute-force. Regex is the way to go with the OP's situation.
– Michael Peterson
Mar 20 '12 at 0:28
1
You're right, regex is better. But at the time, regex and me I didn't come along well.
– zneo
Apr 12 '12 at 19:10
Hah, does anyone really get along that well with regex? ;)
– Michael Peterson
Apr 12 '12 at 22:46
You're so right! After it's written, it sort of turn into machine language..
– zneo
Apr 14 '12 at 18:04
add a comment |
Simple method:
public boolean isBlank(String value) {
return (value == null || value.equals("") || value.equals("null") || value.trim().equals(""));
}
public String normalizeOnlyLettersNumbers(String str) {
if (!isBlank(str)) {
return str.replaceAll("[^\p{L}\p{Nd}]+", "");
} else {
return "";
}
}
answered Nov 1 '16 at 19:36
Alberto CerqueiraAlberto Cerqueira
639912
add a comment |
public static void main(String args) {
String value = " Chlamydia_spp. IgG, IgM & IgA Abs (8006) ";
System.out.println(value.replaceAll("[^A-Za-z0-9]", ""));
}
output: ChlamydiasppIgGIgMIgAAbs8006
Github: https://github.com/AlbinViju/Learning/blob/master/StripNonAlphaNumericFromString.java
edited Aug 23 '17 at 15:46
Jason Roman
6,304102530
answered Aug 23 '17 at 15:21
AlbinAlbin
114
add a comment |
If you want to also allow alphanumeric characters which don't belong to the ascii characters set, like for instance german umlaut's, you can consider using the following solution:
String value = "your value";
// this could be placed as a static final constant, so the compiling is only done once
Pattern pattern = Pattern.compile("[^\w]", Pattern.UNICODE_CHARACTER_CLASS);
value = pattern.matcher(value).replaceAll("");
Please note that the usage of the UNICODE_CHARACTER_CLASS flag could have an impose on performance penalty (see javadoc of this flag)
answered May 24 '18 at 10:18
snapsnap
6411711
add a comment |
Solution:
value.replaceAll("[^A-Za-z0-9]", "")
Explanation:
[^abc]
When a caret^appears as the first character inside square brackets, it negates the pattern. This pattern matches any character except a or b or c.
Looking at the keyword as two function:
[(Pattern)] = match(Pattern)
[^(Pattern)] = notMatch(Pattern)
Moreover regarding a pattern:
A-Z = all characters included from A to Za-z = all characters included from a to z0=0 = all characters included from 0 to 9
Therefore it will substitute all the char NOT included in the pattern
answered Nov 21 '18 at 12:07
GalloCedroneGalloCedrone
2,5752928
add a comment |
Using Guava you can easily combine different type of criteria. For your specific solution you can use:
value = CharMatcher.inRange('0', '9')
.or(CharMatcher.inRange('a', 'z')
.or(CharMatcher.inRange('A', 'Z'))).retainFrom(value)
answered Oct 4 '18 at 7:45
Debmalya BiswasDebmalya Biswas
2,0041726
add a comment |
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12 Answers
12
active
oldest
votes
12 Answers
12
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use [^A-Za-z0-9].
Note: removed the space since that is not typically considered alphanumeric.
edited Sep 18 '17 at 17:14
Dave Jarvis
21k30131256
answered Nov 26 '09 at 20:30
Mirek PlutaMirek Pluta
5,94312619
10
Neither should the space at the end of the character class.
– Andrew Duffy
Nov 26 '09 at 20:31
6
He's probably used to programming in PHP.
– William
Nov 26 '09 at 20:31
10
@William -- it's unfortunate that PHP is now getting credit for PCRE
– Thomas Dignan
Feb 11 '13 at 3:10
add a comment |
Use [^A-Za-z0-9].
Note: removed the space since that is not typically considered alphanumeric.
edited Sep 18 '17 at 17:14
Dave Jarvis
21k30131256
answered Nov 26 '09 at 20:30
Mirek PlutaMirek Pluta
5,94312619
10
Neither should the space at the end of the character class.
– Andrew Duffy
Nov 26 '09 at 20:31
6
He's probably used to programming in PHP.
– William
Nov 26 '09 at 20:31
10
@William -- it's unfortunate that PHP is now getting credit for PCRE
– Thomas Dignan
Feb 11 '13 at 3:10
add a comment |
Use [^A-Za-z0-9].
Note: removed the space since that is not typically considered alphanumeric.
edited Sep 18 '17 at 17:14
Dave Jarvis
21k30131256
answered Nov 26 '09 at 20:30
Mirek PlutaMirek Pluta
5,94312619
Use [^A-Za-z0-9].
Note: removed the space since that is not typically considered alphanumeric.
edited Sep 18 '17 at 17:14
Dave Jarvis
21k30131256
answered Nov 26 '09 at 20:30
Mirek PlutaMirek Pluta
5,94312619
edited Sep 18 '17 at 17:14
Dave Jarvis
21k30131256
edited Sep 18 '17 at 17:14
Dave Jarvis
21k30131256
edited Sep 18 '17 at 17:14
Dave Jarvis
21k30131256
21k30131256
answered Nov 26 '09 at 20:30
Mirek PlutaMirek Pluta
5,94312619
answered Nov 26 '09 at 20:30
Mirek PlutaMirek Pluta
5,94312619
answered Nov 26 '09 at 20:30
Mirek PlutaMirek Pluta
5,94312619
5,94312619
10
Neither should the space at the end of the character class.
– Andrew Duffy
Nov 26 '09 at 20:31
6
He's probably used to programming in PHP.
– William
Nov 26 '09 at 20:31
10
@William -- it's unfortunate that PHP is now getting credit for PCRE
– Thomas Dignan
Feb 11 '13 at 3:10
add a comment |
10
Neither should the space at the end of the character class.
– Andrew Duffy
Nov 26 '09 at 20:31
6
He's probably used to programming in PHP.
– William
Nov 26 '09 at 20:31
10
@William -- it's unfortunate that PHP is now getting credit for PCRE
– Thomas Dignan
Feb 11 '13 at 3:10
10
10
Neither should the space at the end of the character class.
– Andrew Duffy
Nov 26 '09 at 20:31
Neither should the space at the end of the character class.
– Andrew Duffy
Nov 26 '09 at 20:31
6
6
He's probably used to programming in PHP.
– William
Nov 26 '09 at 20:31
He's probably used to programming in PHP.
– William
Nov 26 '09 at 20:31
10
10
@William -- it's unfortunate that PHP is now getting credit for PCRE
– Thomas Dignan
Feb 11 '13 at 3:10
@William -- it's unfortunate that PHP is now getting credit for PCRE
– Thomas Dignan
Feb 11 '13 at 3:10
add a comment |
Try
return value.replaceAll("[^A-Za-z0-9]", "");
or
return value.replaceAll("[\W]|_", "");
answered Nov 26 '09 at 20:33
Andrew DuffyAndrew Duffy
5,49211716
3
With underscores,return value.replaceAll("\W", "");
– erickson
Nov 26 '09 at 20:35
Of course. Compilers are great at spotting that sort of thing.
– Andrew Duffy
Nov 26 '09 at 20:36
1
The second one doesn't answer the question. What about characters like : / etc?
– WW.
Dec 29 '14 at 4:03
add a comment |
Try
return value.replaceAll("[^A-Za-z0-9]", "");
or
return value.replaceAll("[\W]|_", "");
answered Nov 26 '09 at 20:33
Andrew DuffyAndrew Duffy
5,49211716
3
With underscores,return value.replaceAll("\W", "");
– erickson
Nov 26 '09 at 20:35
Of course. Compilers are great at spotting that sort of thing.
– Andrew Duffy
Nov 26 '09 at 20:36
1
The second one doesn't answer the question. What about characters like : / etc?
– WW.
Dec 29 '14 at 4:03
add a comment |
Try
return value.replaceAll("[^A-Za-z0-9]", "");
or
return value.replaceAll("[\W]|_", "");
answered Nov 26 '09 at 20:33
Andrew DuffyAndrew Duffy
5,49211716
Try
return value.replaceAll("[^A-Za-z0-9]", "");
or
return value.replaceAll("[\W]|_", "");
answered Nov 26 '09 at 20:33
Andrew DuffyAndrew Duffy
5,49211716
answered Nov 26 '09 at 20:33
Andrew DuffyAndrew Duffy
5,49211716
answered Nov 26 '09 at 20:33
Andrew DuffyAndrew Duffy
5,49211716
answered Nov 26 '09 at 20:33
Andrew DuffyAndrew Duffy
5,49211716
5,49211716
3
With underscores,return value.replaceAll("\W", "");
– erickson
Nov 26 '09 at 20:35
Of course. Compilers are great at spotting that sort of thing.
– Andrew Duffy
Nov 26 '09 at 20:36
1
The second one doesn't answer the question. What about characters like : / etc?
– WW.
Dec 29 '14 at 4:03
add a comment |
3
With underscores,return value.replaceAll("\W", "");
– erickson
Nov 26 '09 at 20:35
Of course. Compilers are great at spotting that sort of thing.
– Andrew Duffy
Nov 26 '09 at 20:36
1
The second one doesn't answer the question. What about characters like : / etc?
– WW.
Dec 29 '14 at 4:03
3
3
With underscores,
return value.replaceAll("\W", "");– erickson
Nov 26 '09 at 20:35
With underscores,
return value.replaceAll("\W", "");– erickson
Nov 26 '09 at 20:35
Of course. Compilers are great at spotting that sort of thing.
– Andrew Duffy
Nov 26 '09 at 20:36
Of course. Compilers are great at spotting that sort of thing.
– Andrew Duffy
Nov 26 '09 at 20:36
1
1
The second one doesn't answer the question. What about characters like : / etc?
– WW.
Dec 29 '14 at 4:03
The second one doesn't answer the question. What about characters like : / etc?
– WW.
Dec 29 '14 at 4:03
add a comment |
return value.replaceAll("[^A-Za-z0-9 ]", "");
This will leave spaces intact. I assume that's what you want. Otherwise, remove the space from the regex.
answered Nov 26 '09 at 20:31
ericksonerickson
222k42331428
add a comment |
return value.replaceAll("[^A-Za-z0-9 ]", "");
This will leave spaces intact. I assume that's what you want. Otherwise, remove the space from the regex.
answered Nov 26 '09 at 20:31
ericksonerickson
222k42331428
add a comment |
return value.replaceAll("[^A-Za-z0-9 ]", "");
This will leave spaces intact. I assume that's what you want. Otherwise, remove the space from the regex.
answered Nov 26 '09 at 20:31
ericksonerickson
222k42331428
return value.replaceAll("[^A-Za-z0-9 ]", "");
This will leave spaces intact. I assume that's what you want. Otherwise, remove the space from the regex.
answered Nov 26 '09 at 20:31
ericksonerickson
222k42331428
answered Nov 26 '09 at 20:31
ericksonerickson
222k42331428
answered Nov 26 '09 at 20:31
ericksonerickson
222k42331428
answered Nov 26 '09 at 20:31
ericksonerickson
222k42331428
222k42331428
add a comment |
add a comment |
You should be aware that [^a-zA-Z] will replace characters not being itself in the character range A-Z/a-z. That means special characters like é, ß etc. or cyrillic characters and such will be removed.
If the replacement of these characters is not wanted use pre-defined character classes instead:
someString.replaceAll("[^\p{IsAlphabetic}^\p{IsDigit}]", "");
PS: p{Alnum} does not achieve this effect, it acts the same as [A-Za-z0-9].
answered Sep 17 '15 at 10:25
Andre SteingressAndre Steingress
3,3872022
6
Thanks a lot for this post - it was very useful to me. Additionally, I believe this is the actual answer to the question. The Latin alphabet isn't the only one in the world!
– Mateva
Oct 15 '15 at 7:15
1
Actually, the stated regex will treat "^" as a valid character, since only the first occurrence of "^" is negating the meaning of the selection.[^\p{IsAlphabetic}\p{IsDigit}]works well.
– Bogdan Klichuk
Jan 19 '18 at 17:22
Only[^\p{Alpha}\p{Digit}]works for me
– Jakub Turcovsky
Apr 17 '18 at 13:47
1
@JakubTurcovsky docs.oracle.com/javase/10/docs/api/java/util/regex/Pattern.html defines IsAlphabetic and IsDigit as binary properties. Alpha and Digit are POSIX character classes (US-ASCII only). Except the docs.oracle.com/javase/10/docs/api/java/util/regex/… flag is specified.
– Andre Steingress
Apr 17 '18 at 14:39
@AndreSteingress Correct, the reason{IsDigit}doesn't work for me and{Digit}does is that I'm trying this on Android. And Android hasUNICODE_CHARACTER_CLASSturned on by default. Thanks for clearance.
– Jakub Turcovsky
Apr 30 '18 at 11:28
|
show 1 more comment
You should be aware that [^a-zA-Z] will replace characters not being itself in the character range A-Z/a-z. That means special characters like é, ß etc. or cyrillic characters and such will be removed.
If the replacement of these characters is not wanted use pre-defined character classes instead:
someString.replaceAll("[^\p{IsAlphabetic}^\p{IsDigit}]", "");
PS: p{Alnum} does not achieve this effect, it acts the same as [A-Za-z0-9].
answered Sep 17 '15 at 10:25
Andre SteingressAndre Steingress
3,3872022
6
Thanks a lot for this post - it was very useful to me. Additionally, I believe this is the actual answer to the question. The Latin alphabet isn't the only one in the world!
– Mateva
Oct 15 '15 at 7:15
1
Actually, the stated regex will treat "^" as a valid character, since only the first occurrence of "^" is negating the meaning of the selection.[^\p{IsAlphabetic}\p{IsDigit}]works well.
– Bogdan Klichuk
Jan 19 '18 at 17:22
Only[^\p{Alpha}\p{Digit}]works for me
– Jakub Turcovsky
Apr 17 '18 at 13:47
1
@JakubTurcovsky docs.oracle.com/javase/10/docs/api/java/util/regex/Pattern.html defines IsAlphabetic and IsDigit as binary properties. Alpha and Digit are POSIX character classes (US-ASCII only). Except the docs.oracle.com/javase/10/docs/api/java/util/regex/… flag is specified.
– Andre Steingress
Apr 17 '18 at 14:39
@AndreSteingress Correct, the reason{IsDigit}doesn't work for me and{Digit}does is that I'm trying this on Android. And Android hasUNICODE_CHARACTER_CLASSturned on by default. Thanks for clearance.
– Jakub Turcovsky
Apr 30 '18 at 11:28
|
show 1 more comment
You should be aware that [^a-zA-Z] will replace characters not being itself in the character range A-Z/a-z. That means special characters like é, ß etc. or cyrillic characters and such will be removed.
If the replacement of these characters is not wanted use pre-defined character classes instead:
someString.replaceAll("[^\p{IsAlphabetic}^\p{IsDigit}]", "");
PS: p{Alnum} does not achieve this effect, it acts the same as [A-Za-z0-9].
answered Sep 17 '15 at 10:25
Andre SteingressAndre Steingress
3,3872022
You should be aware that [^a-zA-Z] will replace characters not being itself in the character range A-Z/a-z. That means special characters like é, ß etc. or cyrillic characters and such will be removed.
If the replacement of these characters is not wanted use pre-defined character classes instead:
someString.replaceAll("[^\p{IsAlphabetic}^\p{IsDigit}]", "");
PS: p{Alnum} does not achieve this effect, it acts the same as [A-Za-z0-9].
answered Sep 17 '15 at 10:25
Andre SteingressAndre Steingress
3,3872022
edited Sep 18 '17 at 10:26
answered Sep 17 '15 at 10:25
Andre SteingressAndre Steingress
3,3872022
answered Sep 17 '15 at 10:25
Andre SteingressAndre Steingress
3,3872022
answered Sep 17 '15 at 10:25
Andre SteingressAndre Steingress
3,3872022
3,3872022
6
Thanks a lot for this post - it was very useful to me. Additionally, I believe this is the actual answer to the question. The Latin alphabet isn't the only one in the world!
– Mateva
Oct 15 '15 at 7:15
1
Actually, the stated regex will treat "^" as a valid character, since only the first occurrence of "^" is negating the meaning of the selection.[^\p{IsAlphabetic}\p{IsDigit}]works well.
– Bogdan Klichuk
Jan 19 '18 at 17:22
Only[^\p{Alpha}\p{Digit}]works for me
– Jakub Turcovsky
Apr 17 '18 at 13:47
1
@JakubTurcovsky docs.oracle.com/javase/10/docs/api/java/util/regex/Pattern.html defines IsAlphabetic and IsDigit as binary properties. Alpha and Digit are POSIX character classes (US-ASCII only). Except the docs.oracle.com/javase/10/docs/api/java/util/regex/… flag is specified.
– Andre Steingress
Apr 17 '18 at 14:39
@AndreSteingress Correct, the reason{IsDigit}doesn't work for me and{Digit}does is that I'm trying this on Android. And Android hasUNICODE_CHARACTER_CLASSturned on by default. Thanks for clearance.
– Jakub Turcovsky
Apr 30 '18 at 11:28
|
show 1 more comment
6
Thanks a lot for this post - it was very useful to me. Additionally, I believe this is the actual answer to the question. The Latin alphabet isn't the only one in the world!
– Mateva
Oct 15 '15 at 7:15
1
Actually, the stated regex will treat "^" as a valid character, since only the first occurrence of "^" is negating the meaning of the selection.[^\p{IsAlphabetic}\p{IsDigit}]works well.
– Bogdan Klichuk
Jan 19 '18 at 17:22
Only[^\p{Alpha}\p{Digit}]works for me
– Jakub Turcovsky
Apr 17 '18 at 13:47
1
@JakubTurcovsky docs.oracle.com/javase/10/docs/api/java/util/regex/Pattern.html defines IsAlphabetic and IsDigit as binary properties. Alpha and Digit are POSIX character classes (US-ASCII only). Except the docs.oracle.com/javase/10/docs/api/java/util/regex/… flag is specified.
– Andre Steingress
Apr 17 '18 at 14:39
@AndreSteingress Correct, the reason{IsDigit}doesn't work for me and{Digit}does is that I'm trying this on Android. And Android hasUNICODE_CHARACTER_CLASSturned on by default. Thanks for clearance.
– Jakub Turcovsky
Apr 30 '18 at 11:28
6
6
Thanks a lot for this post - it was very useful to me. Additionally, I believe this is the actual answer to the question. The Latin alphabet isn't the only one in the world!
– Mateva
Oct 15 '15 at 7:15
Thanks a lot for this post - it was very useful to me. Additionally, I believe this is the actual answer to the question. The Latin alphabet isn't the only one in the world!
– Mateva
Oct 15 '15 at 7:15
1
1
Actually, the stated regex will treat "^" as a valid character, since only the first occurrence of "^" is negating the meaning of the selection.
[^\p{IsAlphabetic}\p{IsDigit}] works well.– Bogdan Klichuk
Jan 19 '18 at 17:22
Actually, the stated regex will treat "^" as a valid character, since only the first occurrence of "^" is negating the meaning of the selection.
[^\p{IsAlphabetic}\p{IsDigit}] works well.– Bogdan Klichuk
Jan 19 '18 at 17:22
Only
[^\p{Alpha}\p{Digit}] works for me– Jakub Turcovsky
Apr 17 '18 at 13:47
Only
[^\p{Alpha}\p{Digit}] works for me– Jakub Turcovsky
Apr 17 '18 at 13:47
1
1
@JakubTurcovsky docs.oracle.com/javase/10/docs/api/java/util/regex/Pattern.html defines IsAlphabetic and IsDigit as binary properties. Alpha and Digit are POSIX character classes (US-ASCII only). Except the docs.oracle.com/javase/10/docs/api/java/util/regex/… flag is specified.
– Andre Steingress
Apr 17 '18 at 14:39
@JakubTurcovsky docs.oracle.com/javase/10/docs/api/java/util/regex/Pattern.html defines IsAlphabetic and IsDigit as binary properties. Alpha and Digit are POSIX character classes (US-ASCII only). Except the docs.oracle.com/javase/10/docs/api/java/util/regex/… flag is specified.
– Andre Steingress
Apr 17 '18 at 14:39
@AndreSteingress Correct, the reason
{IsDigit} doesn't work for me and {Digit} does is that I'm trying this on Android. And Android has UNICODE_CHARACTER_CLASS turned on by default. Thanks for clearance.– Jakub Turcovsky
Apr 30 '18 at 11:28
@AndreSteingress Correct, the reason
{IsDigit} doesn't work for me and {Digit} does is that I'm trying this on Android. And Android has UNICODE_CHARACTER_CLASS turned on by default. Thanks for clearance.– Jakub Turcovsky
Apr 30 '18 at 11:28
|
show 1 more comment
You could also try this simpler regex:
str = str.replaceAll("\P{Alnum}", "");
edited May 20 '14 at 3:14
nhinkle
87911831
answered Aug 6 '13 at 12:17
sauravsaurav
2,6761630
2
Or, preserving whitespace:str.replaceAll("[^\p{Alnum}\s]", "")
– Jonik
Dec 29 '15 at 10:28
Or\p{Alnum}\p{Space}.
– membersound
Dec 15 '16 at 11:22
add a comment |
You could also try this simpler regex:
str = str.replaceAll("\P{Alnum}", "");
edited May 20 '14 at 3:14
nhinkle
87911831
answered Aug 6 '13 at 12:17
sauravsaurav
2,6761630
2
Or, preserving whitespace:str.replaceAll("[^\p{Alnum}\s]", "")
– Jonik
Dec 29 '15 at 10:28
Or\p{Alnum}\p{Space}.
– membersound
Dec 15 '16 at 11:22
add a comment |
You could also try this simpler regex:
str = str.replaceAll("\P{Alnum}", "");
edited May 20 '14 at 3:14
nhinkle
87911831
answered Aug 6 '13 at 12:17
sauravsaurav
2,6761630
You could also try this simpler regex:
str = str.replaceAll("\P{Alnum}", "");
edited May 20 '14 at 3:14
nhinkle
87911831
answered Aug 6 '13 at 12:17
sauravsaurav
2,6761630
edited May 20 '14 at 3:14
nhinkle
87911831
edited May 20 '14 at 3:14
nhinkle
87911831
edited May 20 '14 at 3:14
nhinkle
87911831
87911831
answered Aug 6 '13 at 12:17
sauravsaurav
2,6761630
answered Aug 6 '13 at 12:17
sauravsaurav
2,6761630
answered Aug 6 '13 at 12:17
sauravsaurav
2,6761630
2,6761630
2
Or, preserving whitespace:str.replaceAll("[^\p{Alnum}\s]", "")
– Jonik
Dec 29 '15 at 10:28
Or\p{Alnum}\p{Space}.
– membersound
Dec 15 '16 at 11:22
add a comment |
2
Or, preserving whitespace:str.replaceAll("[^\p{Alnum}\s]", "")
– Jonik
Dec 29 '15 at 10:28
Or\p{Alnum}\p{Space}.
– membersound
Dec 15 '16 at 11:22
2
2
Or, preserving whitespace:
str.replaceAll("[^\p{Alnum}\s]", "")– Jonik
Dec 29 '15 at 10:28
Or, preserving whitespace:
str.replaceAll("[^\p{Alnum}\s]", "")– Jonik
Dec 29 '15 at 10:28
Or
\p{Alnum}\p{Space}.– membersound
Dec 15 '16 at 11:22
Or
\p{Alnum}\p{Space}.– membersound
Dec 15 '16 at 11:22
add a comment |
Java's regular expressions don't require you to put a forward-slash (/) or any other delimiter around the regex, as opposed to other languages like Perl, for example.
answered Nov 26 '09 at 20:39
abyxabyx
43.1k1578109
add a comment |
Java's regular expressions don't require you to put a forward-slash (/) or any other delimiter around the regex, as opposed to other languages like Perl, for example.
answered Nov 26 '09 at 20:39
abyxabyx
43.1k1578109
add a comment |
Java's regular expressions don't require you to put a forward-slash (/) or any other delimiter around the regex, as opposed to other languages like Perl, for example.
answered Nov 26 '09 at 20:39
abyxabyx
43.1k1578109
Java's regular expressions don't require you to put a forward-slash (/) or any other delimiter around the regex, as opposed to other languages like Perl, for example.
answered Nov 26 '09 at 20:39
abyxabyx
43.1k1578109
answered Nov 26 '09 at 20:39
abyxabyx
43.1k1578109
answered Nov 26 '09 at 20:39
abyxabyx
43.1k1578109
answered Nov 26 '09 at 20:39
abyxabyx
43.1k1578109
43.1k1578109
add a comment |
add a comment |
I made this method for creating filenames:
public static String safeChar(String input)
{
char allowed = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ-_".toCharArray();
char charArray = input.toString().toCharArray();
StringBuilder result = new StringBuilder();
for (char c : charArray)
{
for (char a : allowed)
{
if(c==a) result.append(a);
}
}
return result.toString();
}
answered Nov 27 '09 at 2:08
zneozneo
488310
4
This is pretty brute-force. Regex is the way to go with the OP's situation.
– Michael Peterson
Mar 20 '12 at 0:28
1
You're right, regex is better. But at the time, regex and me I didn't come along well.
– zneo
Apr 12 '12 at 19:10
Hah, does anyone really get along that well with regex? ;)
– Michael Peterson
Apr 12 '12 at 22:46
You're so right! After it's written, it sort of turn into machine language..
– zneo
Apr 14 '12 at 18:04
add a comment |
I made this method for creating filenames:
public static String safeChar(String input)
{
char allowed = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ-_".toCharArray();
char charArray = input.toString().toCharArray();
StringBuilder result = new StringBuilder();
for (char c : charArray)
{
for (char a : allowed)
{
if(c==a) result.append(a);
}
}
return result.toString();
}
answered Nov 27 '09 at 2:08
zneozneo
488310
4
This is pretty brute-force. Regex is the way to go with the OP's situation.
– Michael Peterson
Mar 20 '12 at 0:28
1
You're right, regex is better. But at the time, regex and me I didn't come along well.
– zneo
Apr 12 '12 at 19:10
Hah, does anyone really get along that well with regex? ;)
– Michael Peterson
Apr 12 '12 at 22:46
You're so right! After it's written, it sort of turn into machine language..
– zneo
Apr 14 '12 at 18:04
add a comment |
I made this method for creating filenames:
public static String safeChar(String input)
{
char allowed = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ-_".toCharArray();
char charArray = input.toString().toCharArray();
StringBuilder result = new StringBuilder();
for (char c : charArray)
{
for (char a : allowed)
{
if(c==a) result.append(a);
}
}
return result.toString();
}
answered Nov 27 '09 at 2:08
zneozneo
488310
I made this method for creating filenames:
public static String safeChar(String input)
{
char allowed = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ-_".toCharArray();
char charArray = input.toString().toCharArray();
StringBuilder result = new StringBuilder();
for (char c : charArray)
{
for (char a : allowed)
{
if(c==a) result.append(a);
}
}
return result.toString();
}
answered Nov 27 '09 at 2:08
zneozneo
488310
answered Nov 27 '09 at 2:08
zneozneo
488310
answered Nov 27 '09 at 2:08
zneozneo
488310
answered Nov 27 '09 at 2:08
zneozneo
488310
488310
4
This is pretty brute-force. Regex is the way to go with the OP's situation.
– Michael Peterson
Mar 20 '12 at 0:28
1
You're right, regex is better. But at the time, regex and me I didn't come along well.
– zneo
Apr 12 '12 at 19:10
Hah, does anyone really get along that well with regex? ;)
– Michael Peterson
Apr 12 '12 at 22:46
You're so right! After it's written, it sort of turn into machine language..
– zneo
Apr 14 '12 at 18:04
add a comment |
4
This is pretty brute-force. Regex is the way to go with the OP's situation.
– Michael Peterson
Mar 20 '12 at 0:28
1
You're right, regex is better. But at the time, regex and me I didn't come along well.
– zneo
Apr 12 '12 at 19:10
Hah, does anyone really get along that well with regex? ;)
– Michael Peterson
Apr 12 '12 at 22:46
You're so right! After it's written, it sort of turn into machine language..
– zneo
Apr 14 '12 at 18:04
4
4
This is pretty brute-force. Regex is the way to go with the OP's situation.
– Michael Peterson
Mar 20 '12 at 0:28
This is pretty brute-force. Regex is the way to go with the OP's situation.
– Michael Peterson
Mar 20 '12 at 0:28
1
1
You're right, regex is better. But at the time, regex and me I didn't come along well.
– zneo
Apr 12 '12 at 19:10
You're right, regex is better. But at the time, regex and me I didn't come along well.
– zneo
Apr 12 '12 at 19:10
Hah, does anyone really get along that well with regex? ;)
– Michael Peterson
Apr 12 '12 at 22:46
Hah, does anyone really get along that well with regex? ;)
– Michael Peterson
Apr 12 '12 at 22:46
You're so right! After it's written, it sort of turn into machine language..
– zneo
Apr 14 '12 at 18:04
You're so right! After it's written, it sort of turn into machine language..
– zneo
Apr 14 '12 at 18:04
add a comment |
Simple method:
public boolean isBlank(String value) {
return (value == null || value.equals("") || value.equals("null") || value.trim().equals(""));
}
public String normalizeOnlyLettersNumbers(String str) {
if (!isBlank(str)) {
return str.replaceAll("[^\p{L}\p{Nd}]+", "");
} else {
return "";
}
}
answered Nov 1 '16 at 19:36
Alberto CerqueiraAlberto Cerqueira
639912
add a comment |
Simple method:
public boolean isBlank(String value) {
return (value == null || value.equals("") || value.equals("null") || value.trim().equals(""));
}
public String normalizeOnlyLettersNumbers(String str) {
if (!isBlank(str)) {
return str.replaceAll("[^\p{L}\p{Nd}]+", "");
} else {
return "";
}
}
answered Nov 1 '16 at 19:36
Alberto CerqueiraAlberto Cerqueira
639912
add a comment |
Simple method:
public boolean isBlank(String value) {
return (value == null || value.equals("") || value.equals("null") || value.trim().equals(""));
}
public String normalizeOnlyLettersNumbers(String str) {
if (!isBlank(str)) {
return str.replaceAll("[^\p{L}\p{Nd}]+", "");
} else {
return "";
}
}
answered Nov 1 '16 at 19:36
Alberto CerqueiraAlberto Cerqueira
639912
Simple method:
public boolean isBlank(String value) {
return (value == null || value.equals("") || value.equals("null") || value.trim().equals(""));
}
public String normalizeOnlyLettersNumbers(String str) {
if (!isBlank(str)) {
return str.replaceAll("[^\p{L}\p{Nd}]+", "");
} else {
return "";
}
}
answered Nov 1 '16 at 19:36
Alberto CerqueiraAlberto Cerqueira
639912
answered Nov 1 '16 at 19:36
Alberto CerqueiraAlberto Cerqueira
639912
answered Nov 1 '16 at 19:36
Alberto CerqueiraAlberto Cerqueira
639912
answered Nov 1 '16 at 19:36
Alberto CerqueiraAlberto Cerqueira
639912
639912
add a comment |
add a comment |
public static void main(String args) {
String value = " Chlamydia_spp. IgG, IgM & IgA Abs (8006) ";
System.out.println(value.replaceAll("[^A-Za-z0-9]", ""));
}
output: ChlamydiasppIgGIgMIgAAbs8006
Github: https://github.com/AlbinViju/Learning/blob/master/StripNonAlphaNumericFromString.java
edited Aug 23 '17 at 15:46
Jason Roman
6,304102530
answered Aug 23 '17 at 15:21
AlbinAlbin
114
add a comment |
public static void main(String args) {
String value = " Chlamydia_spp. IgG, IgM & IgA Abs (8006) ";
System.out.println(value.replaceAll("[^A-Za-z0-9]", ""));
}
output: ChlamydiasppIgGIgMIgAAbs8006
Github: https://github.com/AlbinViju/Learning/blob/master/StripNonAlphaNumericFromString.java
edited Aug 23 '17 at 15:46
Jason Roman
6,304102530
answered Aug 23 '17 at 15:21
AlbinAlbin
114
add a comment |
public static void main(String args) {
String value = " Chlamydia_spp. IgG, IgM & IgA Abs (8006) ";
System.out.println(value.replaceAll("[^A-Za-z0-9]", ""));
}
output: ChlamydiasppIgGIgMIgAAbs8006
Github: https://github.com/AlbinViju/Learning/blob/master/StripNonAlphaNumericFromString.java
edited Aug 23 '17 at 15:46
Jason Roman
6,304102530
answered Aug 23 '17 at 15:21
AlbinAlbin
114
public static void main(String args) {
String value = " Chlamydia_spp. IgG, IgM & IgA Abs (8006) ";
System.out.println(value.replaceAll("[^A-Za-z0-9]", ""));
}
output: ChlamydiasppIgGIgMIgAAbs8006
Github: https://github.com/AlbinViju/Learning/blob/master/StripNonAlphaNumericFromString.java
edited Aug 23 '17 at 15:46
Jason Roman
6,304102530
answered Aug 23 '17 at 15:21
AlbinAlbin
114
edited Aug 23 '17 at 15:46
Jason Roman
6,304102530
edited Aug 23 '17 at 15:46
Jason Roman
6,304102530
edited Aug 23 '17 at 15:46
Jason Roman
6,304102530
6,304102530
answered Aug 23 '17 at 15:21
AlbinAlbin
114
answered Aug 23 '17 at 15:21
AlbinAlbin
114
answered Aug 23 '17 at 15:21
AlbinAlbin
114
114
add a comment |
add a comment |
If you want to also allow alphanumeric characters which don't belong to the ascii characters set, like for instance german umlaut's, you can consider using the following solution:
String value = "your value";
// this could be placed as a static final constant, so the compiling is only done once
Pattern pattern = Pattern.compile("[^\w]", Pattern.UNICODE_CHARACTER_CLASS);
value = pattern.matcher(value).replaceAll("");
Please note that the usage of the UNICODE_CHARACTER_CLASS flag could have an impose on performance penalty (see javadoc of this flag)
answered May 24 '18 at 10:18
snapsnap
6411711
add a comment |
If you want to also allow alphanumeric characters which don't belong to the ascii characters set, like for instance german umlaut's, you can consider using the following solution:
String value = "your value";
// this could be placed as a static final constant, so the compiling is only done once
Pattern pattern = Pattern.compile("[^\w]", Pattern.UNICODE_CHARACTER_CLASS);
value = pattern.matcher(value).replaceAll("");
Please note that the usage of the UNICODE_CHARACTER_CLASS flag could have an impose on performance penalty (see javadoc of this flag)
answered May 24 '18 at 10:18
snapsnap
6411711
add a comment |
If you want to also allow alphanumeric characters which don't belong to the ascii characters set, like for instance german umlaut's, you can consider using the following solution:
String value = "your value";
// this could be placed as a static final constant, so the compiling is only done once
Pattern pattern = Pattern.compile("[^\w]", Pattern.UNICODE_CHARACTER_CLASS);
value = pattern.matcher(value).replaceAll("");
Please note that the usage of the UNICODE_CHARACTER_CLASS flag could have an impose on performance penalty (see javadoc of this flag)
answered May 24 '18 at 10:18
snapsnap
6411711
If you want to also allow alphanumeric characters which don't belong to the ascii characters set, like for instance german umlaut's, you can consider using the following solution:
String value = "your value";
// this could be placed as a static final constant, so the compiling is only done once
Pattern pattern = Pattern.compile("[^\w]", Pattern.UNICODE_CHARACTER_CLASS);
value = pattern.matcher(value).replaceAll("");
Please note that the usage of the UNICODE_CHARACTER_CLASS flag could have an impose on performance penalty (see javadoc of this flag)
answered May 24 '18 at 10:18
snapsnap
6411711
answered May 24 '18 at 10:18
snapsnap
6411711
answered May 24 '18 at 10:18
snapsnap
6411711
answered May 24 '18 at 10:18
snapsnap
6411711
6411711
add a comment |
add a comment |
Solution:
value.replaceAll("[^A-Za-z0-9]", "")
Explanation:
[^abc]
When a caret^appears as the first character inside square brackets, it negates the pattern. This pattern matches any character except a or b or c.
Looking at the keyword as two function:
[(Pattern)] = match(Pattern)
[^(Pattern)] = notMatch(Pattern)
Moreover regarding a pattern:
A-Z = all characters included from A to Za-z = all characters included from a to z0=0 = all characters included from 0 to 9
Therefore it will substitute all the char NOT included in the pattern
answered Nov 21 '18 at 12:07
GalloCedroneGalloCedrone
2,5752928
add a comment |
Solution:
value.replaceAll("[^A-Za-z0-9]", "")
Explanation:
[^abc]
When a caret^appears as the first character inside square brackets, it negates the pattern. This pattern matches any character except a or b or c.
Looking at the keyword as two function:
[(Pattern)] = match(Pattern)
[^(Pattern)] = notMatch(Pattern)
Moreover regarding a pattern:
A-Z = all characters included from A to Za-z = all characters included from a to z0=0 = all characters included from 0 to 9
Therefore it will substitute all the char NOT included in the pattern
answered Nov 21 '18 at 12:07
GalloCedroneGalloCedrone
2,5752928
add a comment |
Solution:
value.replaceAll("[^A-Za-z0-9]", "")
Explanation:
[^abc]
When a caret^appears as the first character inside square brackets, it negates the pattern. This pattern matches any character except a or b or c.
Looking at the keyword as two function:
[(Pattern)] = match(Pattern)
[^(Pattern)] = notMatch(Pattern)
Moreover regarding a pattern:
A-Z = all characters included from A to Za-z = all characters included from a to z0=0 = all characters included from 0 to 9
Therefore it will substitute all the char NOT included in the pattern
answered Nov 21 '18 at 12:07
GalloCedroneGalloCedrone
2,5752928
Solution:
value.replaceAll("[^A-Za-z0-9]", "")
Explanation:
[^abc]
When a caret^appears as the first character inside square brackets, it negates the pattern. This pattern matches any character except a or b or c.
Looking at the keyword as two function:
[(Pattern)] = match(Pattern)
[^(Pattern)] = notMatch(Pattern)
Moreover regarding a pattern:
A-Z = all characters included from A to Za-z = all characters included from a to z0=0 = all characters included from 0 to 9
Therefore it will substitute all the char NOT included in the pattern
answered Nov 21 '18 at 12:07
GalloCedroneGalloCedrone
2,5752928
answered Nov 21 '18 at 12:07
GalloCedroneGalloCedrone
2,5752928
answered Nov 21 '18 at 12:07
GalloCedroneGalloCedrone
2,5752928
answered Nov 21 '18 at 12:07
GalloCedroneGalloCedrone
2,5752928
2,5752928
add a comment |
add a comment |
Using Guava you can easily combine different type of criteria. For your specific solution you can use:
value = CharMatcher.inRange('0', '9')
.or(CharMatcher.inRange('a', 'z')
.or(CharMatcher.inRange('A', 'Z'))).retainFrom(value)
answered Oct 4 '18 at 7:45
Debmalya BiswasDebmalya Biswas
2,0041726
add a comment |
Using Guava you can easily combine different type of criteria. For your specific solution you can use:
value = CharMatcher.inRange('0', '9')
.or(CharMatcher.inRange('a', 'z')
.or(CharMatcher.inRange('A', 'Z'))).retainFrom(value)
answered Oct 4 '18 at 7:45
Debmalya BiswasDebmalya Biswas
2,0041726
add a comment |
Using Guava you can easily combine different type of criteria. For your specific solution you can use:
value = CharMatcher.inRange('0', '9')
.or(CharMatcher.inRange('a', 'z')
.or(CharMatcher.inRange('A', 'Z'))).retainFrom(value)
answered Oct 4 '18 at 7:45
Debmalya BiswasDebmalya Biswas
2,0041726
Using Guava you can easily combine different type of criteria. For your specific solution you can use:
value = CharMatcher.inRange('0', '9')
.or(CharMatcher.inRange('a', 'z')
.or(CharMatcher.inRange('A', 'Z'))).retainFrom(value)
answered Oct 4 '18 at 7:45
Debmalya BiswasDebmalya Biswas
2,0041726
edited Oct 4 '18 at 8:40
answered Oct 4 '18 at 7:45
Debmalya BiswasDebmalya Biswas
2,0041726
answered Oct 4 '18 at 7:45
Debmalya BiswasDebmalya Biswas
2,0041726
answered Oct 4 '18 at 7:45
Debmalya BiswasDebmalya Biswas
2,0041726
2,0041726
add a comment |
add a comment |
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27
Guys, you forget there are alphabets other than the Latin one.
– Mateva
Oct 14 '15 at 16:48