$bigcup_{xin K}B'(x,r)=left {xin X |d(x,K)leq rright }$ for $K$ compact












1












$begingroup$


Let $(X,d)$ be a metric space and let $K$ be a compact subset of $X$



Let $r>0$ be given



Prove, $bigcup_{xin K}B'(x,r)=left {xin X |d(x,K)leq rright }$ where $d(x,K)=inf_{yin K}d(x,y)$ (B' is closed ball)



Any hints ?










share|cite|improve this question











$endgroup$

















    1












    $begingroup$


    Let $(X,d)$ be a metric space and let $K$ be a compact subset of $X$



    Let $r>0$ be given



    Prove, $bigcup_{xin K}B'(x,r)=left {xin X |d(x,K)leq rright }$ where $d(x,K)=inf_{yin K}d(x,y)$ (B' is closed ball)



    Any hints ?










    share|cite|improve this question











    $endgroup$















      1












      1








      1





      $begingroup$


      Let $(X,d)$ be a metric space and let $K$ be a compact subset of $X$



      Let $r>0$ be given



      Prove, $bigcup_{xin K}B'(x,r)=left {xin X |d(x,K)leq rright }$ where $d(x,K)=inf_{yin K}d(x,y)$ (B' is closed ball)



      Any hints ?










      share|cite|improve this question











      $endgroup$




      Let $(X,d)$ be a metric space and let $K$ be a compact subset of $X$



      Let $r>0$ be given



      Prove, $bigcup_{xin K}B'(x,r)=left {xin X |d(x,K)leq rright }$ where $d(x,K)=inf_{yin K}d(x,y)$ (B' is closed ball)



      Any hints ?







      general-topology






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Jan 21 at 10:34









      Mariah

      1,5561718




      1,5561718










      asked Jan 20 at 22:53









      Pedro AlvarèsPedro Alvarès

      636




      636






















          1 Answer
          1






          active

          oldest

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          1












          $begingroup$

          Hints:



          $1). $ If $yin bigcup_{xin K}B'(x,r),$ then $yin B'(x,r)$ for some ball $B'$. Then, $d(x,y)le r.$



          $2). $ If $yin left {xin X |d(x,K)leq rright }, $ then fix this $y$ and note that the function $d(y,cdot ):Xto mathbb R$ is continuous, so it attains its minimum on the compact set $K$.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            I'm done with 1) , I found my way with the first inclusion,but I'm stuck with 2)
            $endgroup$
            – Pedro Alvarès
            Jan 20 at 23:47










          • $begingroup$
            The key phrase is: " it attains its minimum on the compact set K."
            $endgroup$
            – Matematleta
            Jan 20 at 23:51










          • $begingroup$
            You mean inf(d(y,K))=<d(y,K) ?
            $endgroup$
            – Pedro Alvarès
            Jan 21 at 0:00










          • $begingroup$
            I mean the inf is reached. So now that means that there is a ___ in ___ such that ___.
            $endgroup$
            – Matematleta
            Jan 21 at 0:01












          • $begingroup$
            There is a sequence in K that converges ??
            $endgroup$
            – Pedro Alvarès
            Jan 21 at 0:08











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          1 Answer
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          oldest

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          active

          oldest

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          active

          oldest

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          1












          $begingroup$

          Hints:



          $1). $ If $yin bigcup_{xin K}B'(x,r),$ then $yin B'(x,r)$ for some ball $B'$. Then, $d(x,y)le r.$



          $2). $ If $yin left {xin X |d(x,K)leq rright }, $ then fix this $y$ and note that the function $d(y,cdot ):Xto mathbb R$ is continuous, so it attains its minimum on the compact set $K$.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            I'm done with 1) , I found my way with the first inclusion,but I'm stuck with 2)
            $endgroup$
            – Pedro Alvarès
            Jan 20 at 23:47










          • $begingroup$
            The key phrase is: " it attains its minimum on the compact set K."
            $endgroup$
            – Matematleta
            Jan 20 at 23:51










          • $begingroup$
            You mean inf(d(y,K))=<d(y,K) ?
            $endgroup$
            – Pedro Alvarès
            Jan 21 at 0:00










          • $begingroup$
            I mean the inf is reached. So now that means that there is a ___ in ___ such that ___.
            $endgroup$
            – Matematleta
            Jan 21 at 0:01












          • $begingroup$
            There is a sequence in K that converges ??
            $endgroup$
            – Pedro Alvarès
            Jan 21 at 0:08
















          1












          $begingroup$

          Hints:



          $1). $ If $yin bigcup_{xin K}B'(x,r),$ then $yin B'(x,r)$ for some ball $B'$. Then, $d(x,y)le r.$



          $2). $ If $yin left {xin X |d(x,K)leq rright }, $ then fix this $y$ and note that the function $d(y,cdot ):Xto mathbb R$ is continuous, so it attains its minimum on the compact set $K$.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            I'm done with 1) , I found my way with the first inclusion,but I'm stuck with 2)
            $endgroup$
            – Pedro Alvarès
            Jan 20 at 23:47










          • $begingroup$
            The key phrase is: " it attains its minimum on the compact set K."
            $endgroup$
            – Matematleta
            Jan 20 at 23:51










          • $begingroup$
            You mean inf(d(y,K))=<d(y,K) ?
            $endgroup$
            – Pedro Alvarès
            Jan 21 at 0:00










          • $begingroup$
            I mean the inf is reached. So now that means that there is a ___ in ___ such that ___.
            $endgroup$
            – Matematleta
            Jan 21 at 0:01












          • $begingroup$
            There is a sequence in K that converges ??
            $endgroup$
            – Pedro Alvarès
            Jan 21 at 0:08














          1












          1








          1





          $begingroup$

          Hints:



          $1). $ If $yin bigcup_{xin K}B'(x,r),$ then $yin B'(x,r)$ for some ball $B'$. Then, $d(x,y)le r.$



          $2). $ If $yin left {xin X |d(x,K)leq rright }, $ then fix this $y$ and note that the function $d(y,cdot ):Xto mathbb R$ is continuous, so it attains its minimum on the compact set $K$.






          share|cite|improve this answer









          $endgroup$



          Hints:



          $1). $ If $yin bigcup_{xin K}B'(x,r),$ then $yin B'(x,r)$ for some ball $B'$. Then, $d(x,y)le r.$



          $2). $ If $yin left {xin X |d(x,K)leq rright }, $ then fix this $y$ and note that the function $d(y,cdot ):Xto mathbb R$ is continuous, so it attains its minimum on the compact set $K$.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Jan 20 at 23:36









          MatematletaMatematleta

          11.5k2920




          11.5k2920












          • $begingroup$
            I'm done with 1) , I found my way with the first inclusion,but I'm stuck with 2)
            $endgroup$
            – Pedro Alvarès
            Jan 20 at 23:47










          • $begingroup$
            The key phrase is: " it attains its minimum on the compact set K."
            $endgroup$
            – Matematleta
            Jan 20 at 23:51










          • $begingroup$
            You mean inf(d(y,K))=<d(y,K) ?
            $endgroup$
            – Pedro Alvarès
            Jan 21 at 0:00










          • $begingroup$
            I mean the inf is reached. So now that means that there is a ___ in ___ such that ___.
            $endgroup$
            – Matematleta
            Jan 21 at 0:01












          • $begingroup$
            There is a sequence in K that converges ??
            $endgroup$
            – Pedro Alvarès
            Jan 21 at 0:08


















          • $begingroup$
            I'm done with 1) , I found my way with the first inclusion,but I'm stuck with 2)
            $endgroup$
            – Pedro Alvarès
            Jan 20 at 23:47










          • $begingroup$
            The key phrase is: " it attains its minimum on the compact set K."
            $endgroup$
            – Matematleta
            Jan 20 at 23:51










          • $begingroup$
            You mean inf(d(y,K))=<d(y,K) ?
            $endgroup$
            – Pedro Alvarès
            Jan 21 at 0:00










          • $begingroup$
            I mean the inf is reached. So now that means that there is a ___ in ___ such that ___.
            $endgroup$
            – Matematleta
            Jan 21 at 0:01












          • $begingroup$
            There is a sequence in K that converges ??
            $endgroup$
            – Pedro Alvarès
            Jan 21 at 0:08
















          $begingroup$
          I'm done with 1) , I found my way with the first inclusion,but I'm stuck with 2)
          $endgroup$
          – Pedro Alvarès
          Jan 20 at 23:47




          $begingroup$
          I'm done with 1) , I found my way with the first inclusion,but I'm stuck with 2)
          $endgroup$
          – Pedro Alvarès
          Jan 20 at 23:47












          $begingroup$
          The key phrase is: " it attains its minimum on the compact set K."
          $endgroup$
          – Matematleta
          Jan 20 at 23:51




          $begingroup$
          The key phrase is: " it attains its minimum on the compact set K."
          $endgroup$
          – Matematleta
          Jan 20 at 23:51












          $begingroup$
          You mean inf(d(y,K))=<d(y,K) ?
          $endgroup$
          – Pedro Alvarès
          Jan 21 at 0:00




          $begingroup$
          You mean inf(d(y,K))=<d(y,K) ?
          $endgroup$
          – Pedro Alvarès
          Jan 21 at 0:00












          $begingroup$
          I mean the inf is reached. So now that means that there is a ___ in ___ such that ___.
          $endgroup$
          – Matematleta
          Jan 21 at 0:01






          $begingroup$
          I mean the inf is reached. So now that means that there is a ___ in ___ such that ___.
          $endgroup$
          – Matematleta
          Jan 21 at 0:01














          $begingroup$
          There is a sequence in K that converges ??
          $endgroup$
          – Pedro Alvarès
          Jan 21 at 0:08




          $begingroup$
          There is a sequence in K that converges ??
          $endgroup$
          – Pedro Alvarès
          Jan 21 at 0:08


















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