Mixing
C: Store parameter passed when calling main
-2
I would like to know how to store parameters in C when I compile:
For example: I'd like to store 2 user-input string variables.
The main is called like this:
./main "Hello World!" World
We should store "Hello World!" in string1 and "World" in string2
(supposing we can only use the main function and no head function), without using pointers.
edit: here is my code that still doesn't work:
#include <stdio.h>
#include <err.h>
int
main (int argc, char *argv)
{
if (argc != 2)
{
errx(1, "Error");
}
printf("Number of arguments = %in", argc);
for (int k = 0; k < argc; k += 1)
{
printf("argv[%i] = %sn", i, argv[i]);
}
return 0;
}
c string variables
asked Nov 19 '18 at 15:12
quiasdesamis2
32
|
show 2 more comments
-2
I would like to know how to store parameters in C when I compile:
For example: I'd like to store 2 user-input string variables.
The main is called like this:
./main "Hello World!" World
We should store "Hello World!" in string1 and "World" in string2
(supposing we can only use the main function and no head function), without using pointers.
edit: here is my code that still doesn't work:
#include <stdio.h>
#include <err.h>
int
main (int argc, char *argv)
{
if (argc != 2)
{
errx(1, "Error");
}
printf("Number of arguments = %in", argc);
for (int k = 0; k < argc; k += 1)
{
printf("argv[%i] = %sn", i, argv[i]);
}
return 0;
}
c string variables
asked Nov 19 '18 at 15:12
quiasdesamis2
32
1
Can you post any code that you have tried? Or any error messages you get when you run your code?
– ahota
Nov 19 '18 at 15:17
I cannot test it since I cannot store the variables
– quiasdesamis2
Nov 19 '18 at 15:18
Is it possible to do this without using pointers (at all)
– quiasdesamis2
Nov 19 '18 at 15:19
Mr Bowling I have seen this but didn't understand how the two strings would be stored, how ?
– quiasdesamis2
Nov 19 '18 at 15:20
1
You can't do this in C without using pointers. You'll need them to pass arguments from the command line and for the strings.
– sergiopm
Nov 19 '18 at 15:42
|
show 2 more comments
-2
-2
-2
1
I would like to know how to store parameters in C when I compile:
For example: I'd like to store 2 user-input string variables.
The main is called like this:
./main "Hello World!" World
We should store "Hello World!" in string1 and "World" in string2
(supposing we can only use the main function and no head function), without using pointers.
edit: here is my code that still doesn't work:
#include <stdio.h>
#include <err.h>
int
main (int argc, char *argv)
{
if (argc != 2)
{
errx(1, "Error");
}
printf("Number of arguments = %in", argc);
for (int k = 0; k < argc; k += 1)
{
printf("argv[%i] = %sn", i, argv[i]);
}
return 0;
}
c string variables
asked Nov 19 '18 at 15:12
quiasdesamis2
32
I would like to know how to store parameters in C when I compile:
For example: I'd like to store 2 user-input string variables.
The main is called like this:
./main "Hello World!" World
We should store "Hello World!" in string1 and "World" in string2
(supposing we can only use the main function and no head function), without using pointers.
edit: here is my code that still doesn't work:
#include <stdio.h>
#include <err.h>
int
main (int argc, char *argv)
{
if (argc != 2)
{
errx(1, "Error");
}
printf("Number of arguments = %in", argc);
for (int k = 0; k < argc; k += 1)
{
printf("argv[%i] = %sn", i, argv[i]);
}
return 0;
}
c string variables
c string variables
asked Nov 19 '18 at 15:12
quiasdesamis2
32
asked Nov 19 '18 at 15:12
quiasdesamis2
32
edited Nov 19 '18 at 16:14
asked Nov 19 '18 at 15:12
quiasdesamis2
32
asked Nov 19 '18 at 15:12
quiasdesamis2
32
asked Nov 19 '18 at 15:12
quiasdesamis2
32
32
1
Can you post any code that you have tried? Or any error messages you get when you run your code?
– ahota
Nov 19 '18 at 15:17
I cannot test it since I cannot store the variables
– quiasdesamis2
Nov 19 '18 at 15:18
Is it possible to do this without using pointers (at all)
– quiasdesamis2
Nov 19 '18 at 15:19
Mr Bowling I have seen this but didn't understand how the two strings would be stored, how ?
– quiasdesamis2
Nov 19 '18 at 15:20
1
You can't do this in C without using pointers. You'll need them to pass arguments from the command line and for the strings.
– sergiopm
Nov 19 '18 at 15:42
|
show 2 more comments
1
Can you post any code that you have tried? Or any error messages you get when you run your code?
– ahota
Nov 19 '18 at 15:17
I cannot test it since I cannot store the variables
– quiasdesamis2
Nov 19 '18 at 15:18
Is it possible to do this without using pointers (at all)
– quiasdesamis2
Nov 19 '18 at 15:19
Mr Bowling I have seen this but didn't understand how the two strings would be stored, how ?
– quiasdesamis2
Nov 19 '18 at 15:20
1
You can't do this in C without using pointers. You'll need them to pass arguments from the command line and for the strings.
– sergiopm
Nov 19 '18 at 15:42
1
1
Can you post any code that you have tried? Or any error messages you get when you run your code?
– ahota
Nov 19 '18 at 15:17
Can you post any code that you have tried? Or any error messages you get when you run your code?
– ahota
Nov 19 '18 at 15:17
I cannot test it since I cannot store the variables
– quiasdesamis2
Nov 19 '18 at 15:18
I cannot test it since I cannot store the variables
– quiasdesamis2
Nov 19 '18 at 15:18
Is it possible to do this without using pointers (at all)
– quiasdesamis2
Nov 19 '18 at 15:19
Is it possible to do this without using pointers (at all)
– quiasdesamis2
Nov 19 '18 at 15:19
Mr Bowling I have seen this but didn't understand how the two strings would be stored, how ?
– quiasdesamis2
Nov 19 '18 at 15:20
Mr Bowling I have seen this but didn't understand how the two strings would be stored, how ?
– quiasdesamis2
Nov 19 '18 at 15:20
1
1
You can't do this in C without using pointers. You'll need them to pass arguments from the command line and for the strings.
– sergiopm
Nov 19 '18 at 15:42
You can't do this in C without using pointers. You'll need them to pass arguments from the command line and for the strings.
– sergiopm
Nov 19 '18 at 15:42
|
show 2 more comments
1 Answer
1
active
oldest
votes
0
Actually the main declaration is int main(int argc, char **argv); or int main(int argc, char *argv);, where:
argcis the number of arguments passed
**argvor*argvcontains the arguments to pass
So you have to use pointers to pass the arguments (as main is declared), there is no other way. In your example (./main "Hello World!" World), the program will receive:
argcis 3
argv[0]is ./main
argv[1]is Hello World!
argv[2]is World
answered Nov 19 '18 at 15:40
Jose
1,048315
Right, thanks. But somehow I get an error when printing... I do printf("argv[%i] = "%s", i, argv[i]") but it gives me an error
– quiasdesamis2
Nov 19 '18 at 16:00
@quiasdesamis2: Apart from the fact you omitted the newline at the end of the format string, you have stray double quotes all over the place. Consider using single quotes, or use"for each"that you want to appear in the format string. You need more like:printf("argv[%i] = "%s"n", i, argv[i]);— note that this removes the trailing double quote shown in your comment where it says:printf("argv[%i] = "%s", i, argv[i]").
– Jonathan Leffler
Nov 19 '18 at 16:04
Tryprintf("argv[%u] = %sn", i, argv[i]);, being i an unsigned in the range [0-2]
– Jose
Nov 19 '18 at 16:04
it still gives me 2 errors, located at > i and at >argv[i]
– quiasdesamis2
Nov 19 '18 at 16:07
I have edited my question please take a look it doesn't compile
– quiasdesamis2
Nov 19 '18 at 16:14
add a comment |
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0
Actually the main declaration is int main(int argc, char **argv); or int main(int argc, char *argv);, where:
argcis the number of arguments passed
**argvor*argvcontains the arguments to pass
So you have to use pointers to pass the arguments (as main is declared), there is no other way. In your example (./main "Hello World!" World), the program will receive:
argcis 3
argv[0]is ./main
argv[1]is Hello World!
argv[2]is World
answered Nov 19 '18 at 15:40
Jose
1,048315
Right, thanks. But somehow I get an error when printing... I do printf("argv[%i] = "%s", i, argv[i]") but it gives me an error
– quiasdesamis2
Nov 19 '18 at 16:00
@quiasdesamis2: Apart from the fact you omitted the newline at the end of the format string, you have stray double quotes all over the place. Consider using single quotes, or use"for each"that you want to appear in the format string. You need more like:printf("argv[%i] = "%s"n", i, argv[i]);— note that this removes the trailing double quote shown in your comment where it says:printf("argv[%i] = "%s", i, argv[i]").
– Jonathan Leffler
Nov 19 '18 at 16:04
Tryprintf("argv[%u] = %sn", i, argv[i]);, being i an unsigned in the range [0-2]
– Jose
Nov 19 '18 at 16:04
it still gives me 2 errors, located at > i and at >argv[i]
– quiasdesamis2
Nov 19 '18 at 16:07
I have edited my question please take a look it doesn't compile
– quiasdesamis2
Nov 19 '18 at 16:14
add a comment |
0
Actually the main declaration is int main(int argc, char **argv); or int main(int argc, char *argv);, where:
argcis the number of arguments passed
**argvor*argvcontains the arguments to pass
So you have to use pointers to pass the arguments (as main is declared), there is no other way. In your example (./main "Hello World!" World), the program will receive:
argcis 3
argv[0]is ./main
argv[1]is Hello World!
argv[2]is World
answered Nov 19 '18 at 15:40
Jose
1,048315
Right, thanks. But somehow I get an error when printing... I do printf("argv[%i] = "%s", i, argv[i]") but it gives me an error
– quiasdesamis2
Nov 19 '18 at 16:00
@quiasdesamis2: Apart from the fact you omitted the newline at the end of the format string, you have stray double quotes all over the place. Consider using single quotes, or use"for each"that you want to appear in the format string. You need more like:printf("argv[%i] = "%s"n", i, argv[i]);— note that this removes the trailing double quote shown in your comment where it says:printf("argv[%i] = "%s", i, argv[i]").
– Jonathan Leffler
Nov 19 '18 at 16:04
Tryprintf("argv[%u] = %sn", i, argv[i]);, being i an unsigned in the range [0-2]
– Jose
Nov 19 '18 at 16:04
it still gives me 2 errors, located at > i and at >argv[i]
– quiasdesamis2
Nov 19 '18 at 16:07
I have edited my question please take a look it doesn't compile
– quiasdesamis2
Nov 19 '18 at 16:14
add a comment |
0
0
0
Actually the main declaration is int main(int argc, char **argv); or int main(int argc, char *argv);, where:
argcis the number of arguments passed
**argvor*argvcontains the arguments to pass
So you have to use pointers to pass the arguments (as main is declared), there is no other way. In your example (./main "Hello World!" World), the program will receive:
argcis 3
argv[0]is ./main
argv[1]is Hello World!
argv[2]is World
answered Nov 19 '18 at 15:40
Jose
1,048315
Actually the main declaration is int main(int argc, char **argv); or int main(int argc, char *argv);, where:
argcis the number of arguments passed
**argvor*argvcontains the arguments to pass
So you have to use pointers to pass the arguments (as main is declared), there is no other way. In your example (./main "Hello World!" World), the program will receive:
argcis 3
argv[0]is ./main
argv[1]is Hello World!
argv[2]is World
answered Nov 19 '18 at 15:40
Jose
1,048315
answered Nov 19 '18 at 15:40
Jose
1,048315
answered Nov 19 '18 at 15:40
Jose
1,048315
answered Nov 19 '18 at 15:40
Jose
1,048315
1,048315
Right, thanks. But somehow I get an error when printing... I do printf("argv[%i] = "%s", i, argv[i]") but it gives me an error
– quiasdesamis2
Nov 19 '18 at 16:00
@quiasdesamis2: Apart from the fact you omitted the newline at the end of the format string, you have stray double quotes all over the place. Consider using single quotes, or use"for each"that you want to appear in the format string. You need more like:printf("argv[%i] = "%s"n", i, argv[i]);— note that this removes the trailing double quote shown in your comment where it says:printf("argv[%i] = "%s", i, argv[i]").
– Jonathan Leffler
Nov 19 '18 at 16:04
Tryprintf("argv[%u] = %sn", i, argv[i]);, being i an unsigned in the range [0-2]
– Jose
Nov 19 '18 at 16:04
it still gives me 2 errors, located at > i and at >argv[i]
– quiasdesamis2
Nov 19 '18 at 16:07
I have edited my question please take a look it doesn't compile
– quiasdesamis2
Nov 19 '18 at 16:14
add a comment |
Right, thanks. But somehow I get an error when printing... I do printf("argv[%i] = "%s", i, argv[i]") but it gives me an error
– quiasdesamis2
Nov 19 '18 at 16:00
@quiasdesamis2: Apart from the fact you omitted the newline at the end of the format string, you have stray double quotes all over the place. Consider using single quotes, or use"for each"that you want to appear in the format string. You need more like:printf("argv[%i] = "%s"n", i, argv[i]);— note that this removes the trailing double quote shown in your comment where it says:printf("argv[%i] = "%s", i, argv[i]").
– Jonathan Leffler
Nov 19 '18 at 16:04
Tryprintf("argv[%u] = %sn", i, argv[i]);, being i an unsigned in the range [0-2]
– Jose
Nov 19 '18 at 16:04
it still gives me 2 errors, located at > i and at >argv[i]
– quiasdesamis2
Nov 19 '18 at 16:07
I have edited my question please take a look it doesn't compile
– quiasdesamis2
Nov 19 '18 at 16:14
Right, thanks. But somehow I get an error when printing... I do printf("argv[%i] = "%s", i, argv[i]") but it gives me an error
– quiasdesamis2
Nov 19 '18 at 16:00
Right, thanks. But somehow I get an error when printing... I do printf("argv[%i] = "%s", i, argv[i]") but it gives me an error
– quiasdesamis2
Nov 19 '18 at 16:00
@quiasdesamis2: Apart from the fact you omitted the newline at the end of the format string, you have stray double quotes all over the place. Consider using single quotes, or use
" for each " that you want to appear in the format string. You need more like: printf("argv[%i] = "%s"n", i, argv[i]); — note that this removes the trailing double quote shown in your comment where it says: printf("argv[%i] = "%s", i, argv[i]").– Jonathan Leffler
Nov 19 '18 at 16:04
@quiasdesamis2: Apart from the fact you omitted the newline at the end of the format string, you have stray double quotes all over the place. Consider using single quotes, or use
" for each " that you want to appear in the format string. You need more like: printf("argv[%i] = "%s"n", i, argv[i]); — note that this removes the trailing double quote shown in your comment where it says: printf("argv[%i] = "%s", i, argv[i]").– Jonathan Leffler
Nov 19 '18 at 16:04
Try
printf("argv[%u] = %sn", i, argv[i]);, being i an unsigned in the range [0-2]– Jose
Nov 19 '18 at 16:04
Try
printf("argv[%u] = %sn", i, argv[i]);, being i an unsigned in the range [0-2]– Jose
Nov 19 '18 at 16:04
it still gives me 2 errors, located at > i and at >argv[i]
– quiasdesamis2
Nov 19 '18 at 16:07
it still gives me 2 errors, located at > i and at >argv[i]
– quiasdesamis2
Nov 19 '18 at 16:07
I have edited my question please take a look it doesn't compile
– quiasdesamis2
Nov 19 '18 at 16:14
I have edited my question please take a look it doesn't compile
– quiasdesamis2
Nov 19 '18 at 16:14
add a comment |
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1
Can you post any code that you have tried? Or any error messages you get when you run your code?
– ahota
Nov 19 '18 at 15:17
I cannot test it since I cannot store the variables
– quiasdesamis2
Nov 19 '18 at 15:18
Is it possible to do this without using pointers (at all)
– quiasdesamis2
Nov 19 '18 at 15:19
Mr Bowling I have seen this but didn't understand how the two strings would be stored, how ?
– quiasdesamis2
Nov 19 '18 at 15:20
1
You can't do this in C without using pointers. You'll need them to pass arguments from the command line and for the strings.
– sergiopm
Nov 19 '18 at 15:42