Mixing
Compare 2 Results by object of selected index of filteredList swift4
I have 2 lists of same custom object i.e. News
class News: Object {
@objc dynamic var title: String?
@objc dynamic var date: Date?
@objc dynamic var contentUrl: String?
}
and 2 lists are
var filteredList: Results<News>! = nil
var newsList: Results<News> {
get {
return realm.objects(News.self).sorted(byKeyPath: "date", ascending:
false)
}
}
I am filtering the list and the filtered data is storing in filteredList.
Now I want to send the IndexPath of newsList to the next VC. When I search in the list, filteredList is appending to the tableView which is absolutely correct. When I selecting row from filteredList it is giving index of filteredList. Now though user selects filteredList's index , it should compare with the object of newList and should return that indexPath /index of newsList
I have done it by my own way
override func tableView(_ tableView: UITableView, didSelectRowAt indexPath:
IndexPath) {
searchController.dismiss(animated: true, completion: nil)
var sendIndex : IndexPath?
let layout = UICollectionViewFlowLayout()
layout.scrollDirection = .horizontal
if !searchBarIsEmpty(){
for (index,news) in newsList.enumerated(){
if news.title == filteredList[indexPath.row].title{
sendIndex = IndexPath(row: index, section: 0)
}
}
}else{
sendIndex = indexPath
}
if let index = sendIndex{
let vc = NewsDetailsVC(collectionViewLayout: layout)
vc.tappedIndex = index
vc.title = "News Details"
vc.isSelectNews = true
self.navigationController?.pushViewController(vc, animated: true)
}
}
but it can be more optimise.. Please suggest some logic of optimisation
arrays swift
edited Jan 2 at 8:48
Rakesha Shastri
7,41621635
asked Jan 2 at 6:17
Kiran S KulkarniKiran S Kulkarni
100211
add a comment |
I have 2 lists of same custom object i.e. News
class News: Object {
@objc dynamic var title: String?
@objc dynamic var date: Date?
@objc dynamic var contentUrl: String?
}
and 2 lists are
var filteredList: Results<News>! = nil
var newsList: Results<News> {
get {
return realm.objects(News.self).sorted(byKeyPath: "date", ascending:
false)
}
}
I am filtering the list and the filtered data is storing in filteredList.
Now I want to send the IndexPath of newsList to the next VC. When I search in the list, filteredList is appending to the tableView which is absolutely correct. When I selecting row from filteredList it is giving index of filteredList. Now though user selects filteredList's index , it should compare with the object of newList and should return that indexPath /index of newsList
I have done it by my own way
override func tableView(_ tableView: UITableView, didSelectRowAt indexPath:
IndexPath) {
searchController.dismiss(animated: true, completion: nil)
var sendIndex : IndexPath?
let layout = UICollectionViewFlowLayout()
layout.scrollDirection = .horizontal
if !searchBarIsEmpty(){
for (index,news) in newsList.enumerated(){
if news.title == filteredList[indexPath.row].title{
sendIndex = IndexPath(row: index, section: 0)
}
}
}else{
sendIndex = indexPath
}
if let index = sendIndex{
let vc = NewsDetailsVC(collectionViewLayout: layout)
vc.tappedIndex = index
vc.title = "News Details"
vc.isSelectNews = true
self.navigationController?.pushViewController(vc, animated: true)
}
}
but it can be more optimise.. Please suggest some logic of optimisation
arrays swift
edited Jan 2 at 8:48
Rakesha Shastri
7,41621635
asked Jan 2 at 6:17
Kiran S KulkarniKiran S Kulkarni
100211
And what is the question?
– matt
Jan 2 at 6:21
When I selecting row from filteredList it is giving index of filteredList. Now though user selects filteredList's index , it should compare with the object of newList and should return that indexPath /index of newsList
– Kiran S Kulkarni
Jan 2 at 6:30
Show us the code which gives you the index from the filtered list.
– Rakesha Shastri
Jan 2 at 6:33
add a comment |
I have 2 lists of same custom object i.e. News
class News: Object {
@objc dynamic var title: String?
@objc dynamic var date: Date?
@objc dynamic var contentUrl: String?
}
and 2 lists are
var filteredList: Results<News>! = nil
var newsList: Results<News> {
get {
return realm.objects(News.self).sorted(byKeyPath: "date", ascending:
false)
}
}
I am filtering the list and the filtered data is storing in filteredList.
Now I want to send the IndexPath of newsList to the next VC. When I search in the list, filteredList is appending to the tableView which is absolutely correct. When I selecting row from filteredList it is giving index of filteredList. Now though user selects filteredList's index , it should compare with the object of newList and should return that indexPath /index of newsList
I have done it by my own way
override func tableView(_ tableView: UITableView, didSelectRowAt indexPath:
IndexPath) {
searchController.dismiss(animated: true, completion: nil)
var sendIndex : IndexPath?
let layout = UICollectionViewFlowLayout()
layout.scrollDirection = .horizontal
if !searchBarIsEmpty(){
for (index,news) in newsList.enumerated(){
if news.title == filteredList[indexPath.row].title{
sendIndex = IndexPath(row: index, section: 0)
}
}
}else{
sendIndex = indexPath
}
if let index = sendIndex{
let vc = NewsDetailsVC(collectionViewLayout: layout)
vc.tappedIndex = index
vc.title = "News Details"
vc.isSelectNews = true
self.navigationController?.pushViewController(vc, animated: true)
}
}
but it can be more optimise.. Please suggest some logic of optimisation
arrays swift
edited Jan 2 at 8:48
Rakesha Shastri
7,41621635
asked Jan 2 at 6:17
Kiran S KulkarniKiran S Kulkarni
100211
I have 2 lists of same custom object i.e. News
class News: Object {
@objc dynamic var title: String?
@objc dynamic var date: Date?
@objc dynamic var contentUrl: String?
}
and 2 lists are
var filteredList: Results<News>! = nil
var newsList: Results<News> {
get {
return realm.objects(News.self).sorted(byKeyPath: "date", ascending:
false)
}
}
I am filtering the list and the filtered data is storing in filteredList.
Now I want to send the IndexPath of newsList to the next VC. When I search in the list, filteredList is appending to the tableView which is absolutely correct. When I selecting row from filteredList it is giving index of filteredList. Now though user selects filteredList's index , it should compare with the object of newList and should return that indexPath /index of newsList
I have done it by my own way
override func tableView(_ tableView: UITableView, didSelectRowAt indexPath:
IndexPath) {
searchController.dismiss(animated: true, completion: nil)
var sendIndex : IndexPath?
let layout = UICollectionViewFlowLayout()
layout.scrollDirection = .horizontal
if !searchBarIsEmpty(){
for (index,news) in newsList.enumerated(){
if news.title == filteredList[indexPath.row].title{
sendIndex = IndexPath(row: index, section: 0)
}
}
}else{
sendIndex = indexPath
}
if let index = sendIndex{
let vc = NewsDetailsVC(collectionViewLayout: layout)
vc.tappedIndex = index
vc.title = "News Details"
vc.isSelectNews = true
self.navigationController?.pushViewController(vc, animated: true)
}
}
but it can be more optimise.. Please suggest some logic of optimisation
arrays swift
arrays swift
edited Jan 2 at 8:48
Rakesha Shastri
7,41621635
asked Jan 2 at 6:17
Kiran S KulkarniKiran S Kulkarni
100211
edited Jan 2 at 8:48
Rakesha Shastri
7,41621635
asked Jan 2 at 6:17
Kiran S KulkarniKiran S Kulkarni
100211
edited Jan 2 at 8:48
Rakesha Shastri
7,41621635
edited Jan 2 at 8:48
Rakesha Shastri
7,41621635
edited Jan 2 at 8:48
Rakesha Shastri
7,41621635
7,41621635
asked Jan 2 at 6:17
Kiran S KulkarniKiran S Kulkarni
100211
asked Jan 2 at 6:17
Kiran S KulkarniKiran S Kulkarni
100211
asked Jan 2 at 6:17
Kiran S KulkarniKiran S Kulkarni
100211
100211
And what is the question?
– matt
Jan 2 at 6:21
When I selecting row from filteredList it is giving index of filteredList. Now though user selects filteredList's index , it should compare with the object of newList and should return that indexPath /index of newsList
– Kiran S Kulkarni
Jan 2 at 6:30
Show us the code which gives you the index from the filtered list.
– Rakesha Shastri
Jan 2 at 6:33
add a comment |
And what is the question?
– matt
Jan 2 at 6:21
When I selecting row from filteredList it is giving index of filteredList. Now though user selects filteredList's index , it should compare with the object of newList and should return that indexPath /index of newsList
– Kiran S Kulkarni
Jan 2 at 6:30
Show us the code which gives you the index from the filtered list.
– Rakesha Shastri
Jan 2 at 6:33
And what is the question?
– matt
Jan 2 at 6:21
And what is the question?
– matt
Jan 2 at 6:21
When I selecting row from filteredList it is giving index of filteredList. Now though user selects filteredList's index , it should compare with the object of newList and should return that indexPath /index of newsList
– Kiran S Kulkarni
Jan 2 at 6:30
When I selecting row from filteredList it is giving index of filteredList. Now though user selects filteredList's index , it should compare with the object of newList and should return that indexPath /index of newsList
– Kiran S Kulkarni
Jan 2 at 6:30
Show us the code which gives you the index from the filtered list.
– Rakesha Shastri
Jan 2 at 6:33
Show us the code which gives you the index from the filtered list.
– Rakesha Shastri
Jan 2 at 6:33
add a comment |
1 Answer
1
active
oldest
votes
Here's a one-liner for finding the index to be sent.
if !searchBarIsEmpty() {
sendIndex = IndexPath(row: newsList.firstIndex(where: { $0.title == filteredList[indexPath.row].title }), section: 0)
}
Note: title is assumed to be the primary key. Compare with the appropriate primary key.
answered Jan 2 at 6:43
Rakesha ShastriRakesha Shastri
7,41621635
great.. its done thanx
– Kiran S Kulkarni
Jan 2 at 8:44
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Here's a one-liner for finding the index to be sent.
if !searchBarIsEmpty() {
sendIndex = IndexPath(row: newsList.firstIndex(where: { $0.title == filteredList[indexPath.row].title }), section: 0)
}
Note: title is assumed to be the primary key. Compare with the appropriate primary key.
answered Jan 2 at 6:43
Rakesha ShastriRakesha Shastri
7,41621635
great.. its done thanx
– Kiran S Kulkarni
Jan 2 at 8:44
add a comment |
Here's a one-liner for finding the index to be sent.
if !searchBarIsEmpty() {
sendIndex = IndexPath(row: newsList.firstIndex(where: { $0.title == filteredList[indexPath.row].title }), section: 0)
}
Note: title is assumed to be the primary key. Compare with the appropriate primary key.
answered Jan 2 at 6:43
Rakesha ShastriRakesha Shastri
7,41621635
great.. its done thanx
– Kiran S Kulkarni
Jan 2 at 8:44
add a comment |
Here's a one-liner for finding the index to be sent.
if !searchBarIsEmpty() {
sendIndex = IndexPath(row: newsList.firstIndex(where: { $0.title == filteredList[indexPath.row].title }), section: 0)
}
Note: title is assumed to be the primary key. Compare with the appropriate primary key.
answered Jan 2 at 6:43
Rakesha ShastriRakesha Shastri
7,41621635
Here's a one-liner for finding the index to be sent.
if !searchBarIsEmpty() {
sendIndex = IndexPath(row: newsList.firstIndex(where: { $0.title == filteredList[indexPath.row].title }), section: 0)
}
Note: title is assumed to be the primary key. Compare with the appropriate primary key.
answered Jan 2 at 6:43
Rakesha ShastriRakesha Shastri
7,41621635
answered Jan 2 at 6:43
Rakesha ShastriRakesha Shastri
7,41621635
answered Jan 2 at 6:43
Rakesha ShastriRakesha Shastri
7,41621635
answered Jan 2 at 6:43
Rakesha ShastriRakesha Shastri
7,41621635
7,41621635
great.. its done thanx
– Kiran S Kulkarni
Jan 2 at 8:44
add a comment |
great.. its done thanx
– Kiran S Kulkarni
Jan 2 at 8:44
great.. its done thanx
– Kiran S Kulkarni
Jan 2 at 8:44
great.. its done thanx
– Kiran S Kulkarni
Jan 2 at 8:44
add a comment |
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And what is the question?
– matt
Jan 2 at 6:21
When I selecting row from filteredList it is giving index of filteredList. Now though user selects filteredList's index , it should compare with the object of newList and should return that indexPath /index of newsList
– Kiran S Kulkarni
Jan 2 at 6:30
Show us the code which gives you the index from the filtered list.
– Rakesha Shastri
Jan 2 at 6:33