Compare 2 Results by object of selected index of filteredList swift4

-1

I have 2 lists of same custom object i.e. News

class News: Object {

    @objc dynamic var title: String?

    @objc dynamic var date: Date?

    @objc dynamic var contentUrl: String?

}

and 2 lists are

var filteredList: Results<News>! = nil

var newsList: Results<News> {

    get {

        return realm.objects(News.self).sorted(byKeyPath: "date", ascending: 

false)

    }

}

I am filtering the list and the filtered data is storing in filteredList.
Now I want to send the IndexPath of newsList to the next VC. When I search in the list, filteredList is appending to the tableView which is absolutely correct. When I selecting row from filteredList it is giving index of filteredList. Now though user selects filteredList's index , it should compare with the object of newList and should return that indexPath /index of newsList

I have done it by my own way

override func tableView(_ tableView: UITableView, didSelectRowAt indexPath: 

IndexPath) {

    searchController.dismiss(animated: true, completion: nil)

    var sendIndex : IndexPath?

    let layout = UICollectionViewFlowLayout()

    layout.scrollDirection = .horizontal

    if !searchBarIsEmpty(){

        for (index,news) in newsList.enumerated(){

            if news.title == filteredList[indexPath.row].title{

                sendIndex = IndexPath(row: index, section: 0)

            }

        }

    }else{

        sendIndex = indexPath

    }

    if let index = sendIndex{

        let vc = NewsDetailsVC(collectionViewLayout: layout)

        vc.tappedIndex = index

        vc.title = "News Details"

        vc.isSelectNews = true

        self.navigationController?.pushViewController(vc, animated: true)

    }



}

but it can be more optimise.. Please suggest some logic of optimisation

edited Jan 2 at 8:48

Rakesha Shastri

7,41621635

asked Jan 2 at 6:17

Kiran S Kulkarni

100211

And what is the question?

– matt
Jan 2 at 6:21

When I selecting row from filteredList it is giving index of filteredList. Now though user selects filteredList's index , it should compare with the object of newList and should return that indexPath /index of newsList

– Kiran S Kulkarni
Jan 2 at 6:30

Show us the code which gives you the index from the filtered list.

– Rakesha Shastri
Jan 2 at 6:33

add a comment |

-1

I have 2 lists of same custom object i.e. News

class News: Object {

    @objc dynamic var title: String?

    @objc dynamic var date: Date?

    @objc dynamic var contentUrl: String?

}

and 2 lists are

var filteredList: Results<News>! = nil

var newsList: Results<News> {

    get {

        return realm.objects(News.self).sorted(byKeyPath: "date", ascending: 

false)

    }

}

I have done it by my own way

override func tableView(_ tableView: UITableView, didSelectRowAt indexPath: 

IndexPath) {

    searchController.dismiss(animated: true, completion: nil)

    var sendIndex : IndexPath?

    let layout = UICollectionViewFlowLayout()

    layout.scrollDirection = .horizontal

    if !searchBarIsEmpty(){

        for (index,news) in newsList.enumerated(){

            if news.title == filteredList[indexPath.row].title{

                sendIndex = IndexPath(row: index, section: 0)

            }

        }

    }else{

        sendIndex = indexPath

    }

    if let index = sendIndex{

        let vc = NewsDetailsVC(collectionViewLayout: layout)

        vc.tappedIndex = index

        vc.title = "News Details"

        vc.isSelectNews = true

        self.navigationController?.pushViewController(vc, animated: true)

    }



}

but it can be more optimise.. Please suggest some logic of optimisation

edited Jan 2 at 8:48

Rakesha Shastri

7,41621635

asked Jan 2 at 6:17

Kiran S Kulkarni

100211

And what is the question?

– matt
Jan 2 at 6:21

When I selecting row from filteredList it is giving index of filteredList. Now though user selects filteredList's index , it should compare with the object of newList and should return that indexPath /index of newsList

– Kiran S Kulkarni
Jan 2 at 6:30

Show us the code which gives you the index from the filtered list.

– Rakesha Shastri
Jan 2 at 6:33

add a comment |

-1

I have 2 lists of same custom object i.e. News

class News: Object {

    @objc dynamic var title: String?

    @objc dynamic var date: Date?

    @objc dynamic var contentUrl: String?

}

and 2 lists are

var filteredList: Results<News>! = nil

var newsList: Results<News> {

    get {

        return realm.objects(News.self).sorted(byKeyPath: "date", ascending: 

false)

    }

}

I have done it by my own way

override func tableView(_ tableView: UITableView, didSelectRowAt indexPath: 

IndexPath) {

    searchController.dismiss(animated: true, completion: nil)

    var sendIndex : IndexPath?

    let layout = UICollectionViewFlowLayout()

    layout.scrollDirection = .horizontal

    if !searchBarIsEmpty(){

        for (index,news) in newsList.enumerated(){

            if news.title == filteredList[indexPath.row].title{

                sendIndex = IndexPath(row: index, section: 0)

            }

        }

    }else{

        sendIndex = indexPath

    }

    if let index = sendIndex{

        let vc = NewsDetailsVC(collectionViewLayout: layout)

        vc.tappedIndex = index

        vc.title = "News Details"

        vc.isSelectNews = true

        self.navigationController?.pushViewController(vc, animated: true)

    }



}

but it can be more optimise.. Please suggest some logic of optimisation

edited Jan 2 at 8:48

Rakesha Shastri

7,41621635

asked Jan 2 at 6:17

Kiran S Kulkarni

100211

I have 2 lists of same custom object i.e. News

class News: Object {

    @objc dynamic var title: String?

    @objc dynamic var date: Date?

    @objc dynamic var contentUrl: String?

}

and 2 lists are

var filteredList: Results<News>! = nil

var newsList: Results<News> {

    get {

        return realm.objects(News.self).sorted(byKeyPath: "date", ascending: 

false)

    }

}

I have done it by my own way

override func tableView(_ tableView: UITableView, didSelectRowAt indexPath: 

IndexPath) {

    searchController.dismiss(animated: true, completion: nil)

    var sendIndex : IndexPath?

    let layout = UICollectionViewFlowLayout()

    layout.scrollDirection = .horizontal

    if !searchBarIsEmpty(){

        for (index,news) in newsList.enumerated(){

            if news.title == filteredList[indexPath.row].title{

                sendIndex = IndexPath(row: index, section: 0)

            }

        }

    }else{

        sendIndex = indexPath

    }

    if let index = sendIndex{

        let vc = NewsDetailsVC(collectionViewLayout: layout)

        vc.tappedIndex = index

        vc.title = "News Details"

        vc.isSelectNews = true

        self.navigationController?.pushViewController(vc, animated: true)

    }



}

but it can be more optimise.. Please suggest some logic of optimisation

arrays swift

edited Jan 2 at 8:48

Rakesha Shastri

7,41621635

asked Jan 2 at 6:17

Kiran S Kulkarni

100211

edited Jan 2 at 8:48

Rakesha Shastri

7,41621635

asked Jan 2 at 6:17

Kiran S Kulkarni

100211

edited Jan 2 at 8:48

Rakesha Shastri

7,41621635

edited Jan 2 at 8:48

Rakesha Shastri

7,41621635

edited Jan 2 at 8:48

Rakesha Shastri

7,41621635

asked Jan 2 at 6:17

Kiran S Kulkarni

100211

asked Jan 2 at 6:17

Kiran S Kulkarni

100211

asked Jan 2 at 6:17

Kiran S Kulkarni

100211

And what is the question?

– matt
Jan 2 at 6:21

When I selecting row from filteredList it is giving index of filteredList. Now though user selects filteredList's index , it should compare with the object of newList and should return that indexPath /index of newsList

– Kiran S Kulkarni
Jan 2 at 6:30

Show us the code which gives you the index from the filtered list.

– Rakesha Shastri
Jan 2 at 6:33

add a comment |

And what is the question?

– matt
Jan 2 at 6:21

When I selecting row from filteredList it is giving index of filteredList. Now though user selects filteredList's index , it should compare with the object of newList and should return that indexPath /index of newsList

– Kiran S Kulkarni
Jan 2 at 6:30

Show us the code which gives you the index from the filtered list.

– Rakesha Shastri
Jan 2 at 6:33

And what is the question?

– matt
Jan 2 at 6:21

When I selecting row from filteredList it is giving index of filteredList. Now though user selects filteredList's index , it should compare with the object of newList and should return that indexPath /index of newsList

– Kiran S Kulkarni
Jan 2 at 6:30

Show us the code which gives you the index from the filtered list.

– Rakesha Shastri
Jan 2 at 6:33

add a comment |

1 Answer
1

active

oldest

votes

Here's a one-liner for finding the index to be sent.

if !searchBarIsEmpty() {

    sendIndex = IndexPath(row: newsList.firstIndex(where: { $0.title == filteredList[indexPath.row].title }), section: 0)

}

Note: title is assumed to be the primary key. Compare with the appropriate primary key.

answered Jan 2 at 6:43

Rakesha Shastri

7,41621635

great.. its done thanx

– Kiran S Kulkarni
Jan 2 at 8:44

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

Here's a one-liner for finding the index to be sent.

if !searchBarIsEmpty() {

    sendIndex = IndexPath(row: newsList.firstIndex(where: { $0.title == filteredList[indexPath.row].title }), section: 0)

}

Note: title is assumed to be the primary key. Compare with the appropriate primary key.

answered Jan 2 at 6:43

Rakesha Shastri

7,41621635

great.. its done thanx

– Kiran S Kulkarni
Jan 2 at 8:44

add a comment |

Here's a one-liner for finding the index to be sent.

if !searchBarIsEmpty() {

    sendIndex = IndexPath(row: newsList.firstIndex(where: { $0.title == filteredList[indexPath.row].title }), section: 0)

}

Note: title is assumed to be the primary key. Compare with the appropriate primary key.

answered Jan 2 at 6:43

Rakesha Shastri

7,41621635

great.. its done thanx

– Kiran S Kulkarni
Jan 2 at 8:44

add a comment |

Here's a one-liner for finding the index to be sent.

if !searchBarIsEmpty() {

    sendIndex = IndexPath(row: newsList.firstIndex(where: { $0.title == filteredList[indexPath.row].title }), section: 0)

}

Note: title is assumed to be the primary key. Compare with the appropriate primary key.

answered Jan 2 at 6:43

Rakesha Shastri

7,41621635

Here's a one-liner for finding the index to be sent.

if !searchBarIsEmpty() {

    sendIndex = IndexPath(row: newsList.firstIndex(where: { $0.title == filteredList[indexPath.row].title }), section: 0)

}

Note: title is assumed to be the primary key. Compare with the appropriate primary key.

answered Jan 2 at 6:43

Rakesha Shastri

7,41621635

answered Jan 2 at 6:43

Rakesha Shastri

7,41621635

answered Jan 2 at 6:43

Rakesha Shastri

7,41621635

answered Jan 2 at 6:43

Rakesha Shastri

7,41621635

great.. its done thanx

– Kiran S Kulkarni
Jan 2 at 8:44

add a comment |

great.. its done thanx

– Kiran S Kulkarni
Jan 2 at 8:44

great.. its done thanx

– Kiran S Kulkarni
Jan 2 at 8:44

add a comment |

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