Mixing
How can I use the AtTask API to Upload a File using C#
I am using a modified version of the C# API Example to add tasks to an existing Workfront (AtTask) Task. I would also like to upload and download file attachments.
It appears from the documentation that uploading is a two-step process, step 1 upload the file and step 2 attach the uploaded file to the task. I understand somewhat how to do the second step - post a JSON token with the file name, the handle (from the upload), object type (TASK), object ID, and currentVersion. What I don't understand is step 1, the actual uploading of the file.
I am creating a PDF file that needs to be attached to the task. Once the task is completed, a new document will be added that I need to download.
Does anyone have any C# code for performing either the upload or the download?
Here is my code so far:
public JToken DoUpload(string path, string opportunityID, string description, params string parameters)
{
List<string> list = parameters.ToList();
if (!path.StartsWith("/"))
{
path = "/" + path;
}
string fullUrl = url + path + ToQueryString(parameters);
string boundary = "------" + DateTime.Now.Ticks.ToString("x");
WebRequest request = HttpWebRequest.CreateDefault(new Uri(fullUrl));
request.ContentType = "multipart/form-data; boundary=" + boundary;
request.Method = "POST";
using (var requestStream = request.GetRequestStream())
{
using (var writer = new StreamWriter(requestStream))
{
writer.WriteLine(string.Format("Content-Disposition: form-data; name="{0}" filename="{1}"", "uploadedFile", "RFQ" + opportunityID + ".html"));
writer.WriteLine("Content-Type: text/html; charset=UTF-8");
writer.WriteLine();
writer.WriteLine(description);
using (WebResponse response = request.GetResponse())
{
using (Stream responseStream = response.GetResponseStream())
{
return ReadResponse(responseStream);
}
}
}
}
}
c# api upload attask
asked Feb 25 '15 at 19:06
wframsay
11
add a comment |
I am using a modified version of the C# API Example to add tasks to an existing Workfront (AtTask) Task. I would also like to upload and download file attachments.
It appears from the documentation that uploading is a two-step process, step 1 upload the file and step 2 attach the uploaded file to the task. I understand somewhat how to do the second step - post a JSON token with the file name, the handle (from the upload), object type (TASK), object ID, and currentVersion. What I don't understand is step 1, the actual uploading of the file.
I am creating a PDF file that needs to be attached to the task. Once the task is completed, a new document will be added that I need to download.
Does anyone have any C# code for performing either the upload or the download?
Here is my code so far:
public JToken DoUpload(string path, string opportunityID, string description, params string parameters)
{
List<string> list = parameters.ToList();
if (!path.StartsWith("/"))
{
path = "/" + path;
}
string fullUrl = url + path + ToQueryString(parameters);
string boundary = "------" + DateTime.Now.Ticks.ToString("x");
WebRequest request = HttpWebRequest.CreateDefault(new Uri(fullUrl));
request.ContentType = "multipart/form-data; boundary=" + boundary;
request.Method = "POST";
using (var requestStream = request.GetRequestStream())
{
using (var writer = new StreamWriter(requestStream))
{
writer.WriteLine(string.Format("Content-Disposition: form-data; name="{0}" filename="{1}"", "uploadedFile", "RFQ" + opportunityID + ".html"));
writer.WriteLine("Content-Type: text/html; charset=UTF-8");
writer.WriteLine();
writer.WriteLine(description);
using (WebResponse response = request.GetResponse())
{
using (Stream responseStream = response.GetResponseStream())
{
return ReadResponse(responseStream);
}
}
}
}
}
c# api upload attask
asked Feb 25 '15 at 19:06
wframsay
11
add a comment |
I am using a modified version of the C# API Example to add tasks to an existing Workfront (AtTask) Task. I would also like to upload and download file attachments.
It appears from the documentation that uploading is a two-step process, step 1 upload the file and step 2 attach the uploaded file to the task. I understand somewhat how to do the second step - post a JSON token with the file name, the handle (from the upload), object type (TASK), object ID, and currentVersion. What I don't understand is step 1, the actual uploading of the file.
I am creating a PDF file that needs to be attached to the task. Once the task is completed, a new document will be added that I need to download.
Does anyone have any C# code for performing either the upload or the download?
Here is my code so far:
public JToken DoUpload(string path, string opportunityID, string description, params string parameters)
{
List<string> list = parameters.ToList();
if (!path.StartsWith("/"))
{
path = "/" + path;
}
string fullUrl = url + path + ToQueryString(parameters);
string boundary = "------" + DateTime.Now.Ticks.ToString("x");
WebRequest request = HttpWebRequest.CreateDefault(new Uri(fullUrl));
request.ContentType = "multipart/form-data; boundary=" + boundary;
request.Method = "POST";
using (var requestStream = request.GetRequestStream())
{
using (var writer = new StreamWriter(requestStream))
{
writer.WriteLine(string.Format("Content-Disposition: form-data; name="{0}" filename="{1}"", "uploadedFile", "RFQ" + opportunityID + ".html"));
writer.WriteLine("Content-Type: text/html; charset=UTF-8");
writer.WriteLine();
writer.WriteLine(description);
using (WebResponse response = request.GetResponse())
{
using (Stream responseStream = response.GetResponseStream())
{
return ReadResponse(responseStream);
}
}
}
}
}
c# api upload attask
asked Feb 25 '15 at 19:06
wframsay
11
I am using a modified version of the C# API Example to add tasks to an existing Workfront (AtTask) Task. I would also like to upload and download file attachments.
It appears from the documentation that uploading is a two-step process, step 1 upload the file and step 2 attach the uploaded file to the task. I understand somewhat how to do the second step - post a JSON token with the file name, the handle (from the upload), object type (TASK), object ID, and currentVersion. What I don't understand is step 1, the actual uploading of the file.
I am creating a PDF file that needs to be attached to the task. Once the task is completed, a new document will be added that I need to download.
Does anyone have any C# code for performing either the upload or the download?
Here is my code so far:
public JToken DoUpload(string path, string opportunityID, string description, params string parameters)
{
List<string> list = parameters.ToList();
if (!path.StartsWith("/"))
{
path = "/" + path;
}
string fullUrl = url + path + ToQueryString(parameters);
string boundary = "------" + DateTime.Now.Ticks.ToString("x");
WebRequest request = HttpWebRequest.CreateDefault(new Uri(fullUrl));
request.ContentType = "multipart/form-data; boundary=" + boundary;
request.Method = "POST";
using (var requestStream = request.GetRequestStream())
{
using (var writer = new StreamWriter(requestStream))
{
writer.WriteLine(string.Format("Content-Disposition: form-data; name="{0}" filename="{1}"", "uploadedFile", "RFQ" + opportunityID + ".html"));
writer.WriteLine("Content-Type: text/html; charset=UTF-8");
writer.WriteLine();
writer.WriteLine(description);
using (WebResponse response = request.GetResponse())
{
using (Stream responseStream = response.GetResponseStream())
{
return ReadResponse(responseStream);
}
}
}
}
}
c# api upload attask
c# api upload attask
asked Feb 25 '15 at 19:06
wframsay
11
asked Feb 25 '15 at 19:06
wframsay
11
edited Mar 3 '15 at 22:41
asked Feb 25 '15 at 19:06
wframsay
11
asked Feb 25 '15 at 19:06
wframsay
11
asked Feb 25 '15 at 19:06
wframsay
11
11
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
The first step is to get a handel, that is done just like any other api call you do to POST /attask/api/upload, this is where you include the file, it will be uploaded to a temp folder at Workfront(AtTask), Workfront will return the handel, then you do a second step to update the task incldue the handel and the file will be posted to it.
For more reference check out https://developers.attask.com/api-docs/ and https://developers.attask.com/api-docs/code-samples/
answered Mar 3 '15 at 21:08
Jim Young
1592
Thanks, Jim. I have read all the documentation, unfortunately the documentation regarding uploading files is very sparse, i.e, "Do a POST/attask/api/upload" - with no details on how to actually perform the upload. I have written some code, but have been successful only in generating 400 errors.
– wframsay
Mar 3 '15 at 22:37
add a comment |
public static string HttpUploadFile(string url, string filename, byte file, string paramName, string contentType, NameValueCollection nvc)
{
string boundary = "---------------------------" + DateTime.Now.Ticks.ToString("x");
byte boundarybytes = System.Text.Encoding.ASCII.GetBytes("rn--" + boundary + "rn");
HttpWebRequest wr = (HttpWebRequest)WebRequest.Create(url);
wr.ContentType = "multipart/form-data; boundary=" + boundary;
wr.Method = "POST";
wr.KeepAlive = true;
wr.Credentials = System.Net.CredentialCache.DefaultCredentials;
Stream rs = wr.GetRequestStream();
string formdataTemplate = "Content-Disposition: form-data; name="{0}"rnrn{1}";
foreach (string key in nvc.Keys)
{
rs.Write(boundarybytes, 0, boundarybytes.Length);
string formitem = string.Format(formdataTemplate, key, nvc[key]);
byte formitembytes = System.Text.Encoding.UTF8.GetBytes(formitem);
rs.Write(formitembytes, 0, formitembytes.Length);
}
rs.Write(boundarybytes, 0, boundarybytes.Length);
string headerTemplate = "Content-Disposition: form-data; name="{0}"; filename="{1}"rnContent-Type: {2}rnrn";
string header = string.Format(headerTemplate, paramName, filename, contentType);
byte headerbytes = System.Text.Encoding.UTF8.GetBytes(header);
rs.Write(headerbytes, 0, headerbytes.Length);
rs.Write(file, 0, file.Length);
byte trailer = System.Text.Encoding.ASCII.GetBytes("rn--" + boundary + "--rn");
rs.Write(trailer, 0, trailer.Length);
rs.Close();
WebResponse wresp = null;
string ret = null;
try
{
wresp = wr.GetResponse();
Stream stream2 = wresp.GetResponseStream();
StreamReader reader2 = new StreamReader(stream2);
ret = reader2.ReadToEnd();
}
catch (Exception ex)
{
if (wresp != null)
{
wresp.Close();
wresp = null;
}
}
finally
{
wr = null;
}
return ret;
}
JToken ret = HttpUploadFile("/upload", file_name, file_bytes, "uploadedFile", "", new NameValueCollection());
edited Nov 19 '18 at 15:16
pushkin
3,949112651
answered Nov 19 '18 at 14:50
Anatoliy Zingerov
1
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The first step is to get a handel, that is done just like any other api call you do to POST /attask/api/upload, this is where you include the file, it will be uploaded to a temp folder at Workfront(AtTask), Workfront will return the handel, then you do a second step to update the task incldue the handel and the file will be posted to it.
For more reference check out https://developers.attask.com/api-docs/ and https://developers.attask.com/api-docs/code-samples/
answered Mar 3 '15 at 21:08
Jim Young
1592
Thanks, Jim. I have read all the documentation, unfortunately the documentation regarding uploading files is very sparse, i.e, "Do a POST/attask/api/upload" - with no details on how to actually perform the upload. I have written some code, but have been successful only in generating 400 errors.
– wframsay
Mar 3 '15 at 22:37
add a comment |
The first step is to get a handel, that is done just like any other api call you do to POST /attask/api/upload, this is where you include the file, it will be uploaded to a temp folder at Workfront(AtTask), Workfront will return the handel, then you do a second step to update the task incldue the handel and the file will be posted to it.
For more reference check out https://developers.attask.com/api-docs/ and https://developers.attask.com/api-docs/code-samples/
answered Mar 3 '15 at 21:08
Jim Young
1592
Thanks, Jim. I have read all the documentation, unfortunately the documentation regarding uploading files is very sparse, i.e, "Do a POST/attask/api/upload" - with no details on how to actually perform the upload. I have written some code, but have been successful only in generating 400 errors.
– wframsay
Mar 3 '15 at 22:37
add a comment |
The first step is to get a handel, that is done just like any other api call you do to POST /attask/api/upload, this is where you include the file, it will be uploaded to a temp folder at Workfront(AtTask), Workfront will return the handel, then you do a second step to update the task incldue the handel and the file will be posted to it.
For more reference check out https://developers.attask.com/api-docs/ and https://developers.attask.com/api-docs/code-samples/
answered Mar 3 '15 at 21:08
Jim Young
1592
The first step is to get a handel, that is done just like any other api call you do to POST /attask/api/upload, this is where you include the file, it will be uploaded to a temp folder at Workfront(AtTask), Workfront will return the handel, then you do a second step to update the task incldue the handel and the file will be posted to it.
For more reference check out https://developers.attask.com/api-docs/ and https://developers.attask.com/api-docs/code-samples/
answered Mar 3 '15 at 21:08
Jim Young
1592
answered Mar 3 '15 at 21:08
Jim Young
1592
answered Mar 3 '15 at 21:08
Jim Young
1592
answered Mar 3 '15 at 21:08
Jim Young
1592
1592
Thanks, Jim. I have read all the documentation, unfortunately the documentation regarding uploading files is very sparse, i.e, "Do a POST/attask/api/upload" - with no details on how to actually perform the upload. I have written some code, but have been successful only in generating 400 errors.
– wframsay
Mar 3 '15 at 22:37
add a comment |
Thanks, Jim. I have read all the documentation, unfortunately the documentation regarding uploading files is very sparse, i.e, "Do a POST/attask/api/upload" - with no details on how to actually perform the upload. I have written some code, but have been successful only in generating 400 errors.
– wframsay
Mar 3 '15 at 22:37
Thanks, Jim. I have read all the documentation, unfortunately the documentation regarding uploading files is very sparse, i.e, "Do a POST/attask/api/upload" - with no details on how to actually perform the upload. I have written some code, but have been successful only in generating 400 errors.
– wframsay
Mar 3 '15 at 22:37
Thanks, Jim. I have read all the documentation, unfortunately the documentation regarding uploading files is very sparse, i.e, "Do a POST/attask/api/upload" - with no details on how to actually perform the upload. I have written some code, but have been successful only in generating 400 errors.
– wframsay
Mar 3 '15 at 22:37
add a comment |
public static string HttpUploadFile(string url, string filename, byte file, string paramName, string contentType, NameValueCollection nvc)
{
string boundary = "---------------------------" + DateTime.Now.Ticks.ToString("x");
byte boundarybytes = System.Text.Encoding.ASCII.GetBytes("rn--" + boundary + "rn");
HttpWebRequest wr = (HttpWebRequest)WebRequest.Create(url);
wr.ContentType = "multipart/form-data; boundary=" + boundary;
wr.Method = "POST";
wr.KeepAlive = true;
wr.Credentials = System.Net.CredentialCache.DefaultCredentials;
Stream rs = wr.GetRequestStream();
string formdataTemplate = "Content-Disposition: form-data; name="{0}"rnrn{1}";
foreach (string key in nvc.Keys)
{
rs.Write(boundarybytes, 0, boundarybytes.Length);
string formitem = string.Format(formdataTemplate, key, nvc[key]);
byte formitembytes = System.Text.Encoding.UTF8.GetBytes(formitem);
rs.Write(formitembytes, 0, formitembytes.Length);
}
rs.Write(boundarybytes, 0, boundarybytes.Length);
string headerTemplate = "Content-Disposition: form-data; name="{0}"; filename="{1}"rnContent-Type: {2}rnrn";
string header = string.Format(headerTemplate, paramName, filename, contentType);
byte headerbytes = System.Text.Encoding.UTF8.GetBytes(header);
rs.Write(headerbytes, 0, headerbytes.Length);
rs.Write(file, 0, file.Length);
byte trailer = System.Text.Encoding.ASCII.GetBytes("rn--" + boundary + "--rn");
rs.Write(trailer, 0, trailer.Length);
rs.Close();
WebResponse wresp = null;
string ret = null;
try
{
wresp = wr.GetResponse();
Stream stream2 = wresp.GetResponseStream();
StreamReader reader2 = new StreamReader(stream2);
ret = reader2.ReadToEnd();
}
catch (Exception ex)
{
if (wresp != null)
{
wresp.Close();
wresp = null;
}
}
finally
{
wr = null;
}
return ret;
}
JToken ret = HttpUploadFile("/upload", file_name, file_bytes, "uploadedFile", "", new NameValueCollection());
edited Nov 19 '18 at 15:16
pushkin
3,949112651
answered Nov 19 '18 at 14:50
Anatoliy Zingerov
1
add a comment |
public static string HttpUploadFile(string url, string filename, byte file, string paramName, string contentType, NameValueCollection nvc)
{
string boundary = "---------------------------" + DateTime.Now.Ticks.ToString("x");
byte boundarybytes = System.Text.Encoding.ASCII.GetBytes("rn--" + boundary + "rn");
HttpWebRequest wr = (HttpWebRequest)WebRequest.Create(url);
wr.ContentType = "multipart/form-data; boundary=" + boundary;
wr.Method = "POST";
wr.KeepAlive = true;
wr.Credentials = System.Net.CredentialCache.DefaultCredentials;
Stream rs = wr.GetRequestStream();
string formdataTemplate = "Content-Disposition: form-data; name="{0}"rnrn{1}";
foreach (string key in nvc.Keys)
{
rs.Write(boundarybytes, 0, boundarybytes.Length);
string formitem = string.Format(formdataTemplate, key, nvc[key]);
byte formitembytes = System.Text.Encoding.UTF8.GetBytes(formitem);
rs.Write(formitembytes, 0, formitembytes.Length);
}
rs.Write(boundarybytes, 0, boundarybytes.Length);
string headerTemplate = "Content-Disposition: form-data; name="{0}"; filename="{1}"rnContent-Type: {2}rnrn";
string header = string.Format(headerTemplate, paramName, filename, contentType);
byte headerbytes = System.Text.Encoding.UTF8.GetBytes(header);
rs.Write(headerbytes, 0, headerbytes.Length);
rs.Write(file, 0, file.Length);
byte trailer = System.Text.Encoding.ASCII.GetBytes("rn--" + boundary + "--rn");
rs.Write(trailer, 0, trailer.Length);
rs.Close();
WebResponse wresp = null;
string ret = null;
try
{
wresp = wr.GetResponse();
Stream stream2 = wresp.GetResponseStream();
StreamReader reader2 = new StreamReader(stream2);
ret = reader2.ReadToEnd();
}
catch (Exception ex)
{
if (wresp != null)
{
wresp.Close();
wresp = null;
}
}
finally
{
wr = null;
}
return ret;
}
JToken ret = HttpUploadFile("/upload", file_name, file_bytes, "uploadedFile", "", new NameValueCollection());
edited Nov 19 '18 at 15:16
pushkin
3,949112651
answered Nov 19 '18 at 14:50
Anatoliy Zingerov
1
add a comment |
public static string HttpUploadFile(string url, string filename, byte file, string paramName, string contentType, NameValueCollection nvc)
{
string boundary = "---------------------------" + DateTime.Now.Ticks.ToString("x");
byte boundarybytes = System.Text.Encoding.ASCII.GetBytes("rn--" + boundary + "rn");
HttpWebRequest wr = (HttpWebRequest)WebRequest.Create(url);
wr.ContentType = "multipart/form-data; boundary=" + boundary;
wr.Method = "POST";
wr.KeepAlive = true;
wr.Credentials = System.Net.CredentialCache.DefaultCredentials;
Stream rs = wr.GetRequestStream();
string formdataTemplate = "Content-Disposition: form-data; name="{0}"rnrn{1}";
foreach (string key in nvc.Keys)
{
rs.Write(boundarybytes, 0, boundarybytes.Length);
string formitem = string.Format(formdataTemplate, key, nvc[key]);
byte formitembytes = System.Text.Encoding.UTF8.GetBytes(formitem);
rs.Write(formitembytes, 0, formitembytes.Length);
}
rs.Write(boundarybytes, 0, boundarybytes.Length);
string headerTemplate = "Content-Disposition: form-data; name="{0}"; filename="{1}"rnContent-Type: {2}rnrn";
string header = string.Format(headerTemplate, paramName, filename, contentType);
byte headerbytes = System.Text.Encoding.UTF8.GetBytes(header);
rs.Write(headerbytes, 0, headerbytes.Length);
rs.Write(file, 0, file.Length);
byte trailer = System.Text.Encoding.ASCII.GetBytes("rn--" + boundary + "--rn");
rs.Write(trailer, 0, trailer.Length);
rs.Close();
WebResponse wresp = null;
string ret = null;
try
{
wresp = wr.GetResponse();
Stream stream2 = wresp.GetResponseStream();
StreamReader reader2 = new StreamReader(stream2);
ret = reader2.ReadToEnd();
}
catch (Exception ex)
{
if (wresp != null)
{
wresp.Close();
wresp = null;
}
}
finally
{
wr = null;
}
return ret;
}
JToken ret = HttpUploadFile("/upload", file_name, file_bytes, "uploadedFile", "", new NameValueCollection());
edited Nov 19 '18 at 15:16
pushkin
3,949112651
answered Nov 19 '18 at 14:50
Anatoliy Zingerov
1
public static string HttpUploadFile(string url, string filename, byte file, string paramName, string contentType, NameValueCollection nvc)
{
string boundary = "---------------------------" + DateTime.Now.Ticks.ToString("x");
byte boundarybytes = System.Text.Encoding.ASCII.GetBytes("rn--" + boundary + "rn");
HttpWebRequest wr = (HttpWebRequest)WebRequest.Create(url);
wr.ContentType = "multipart/form-data; boundary=" + boundary;
wr.Method = "POST";
wr.KeepAlive = true;
wr.Credentials = System.Net.CredentialCache.DefaultCredentials;
Stream rs = wr.GetRequestStream();
string formdataTemplate = "Content-Disposition: form-data; name="{0}"rnrn{1}";
foreach (string key in nvc.Keys)
{
rs.Write(boundarybytes, 0, boundarybytes.Length);
string formitem = string.Format(formdataTemplate, key, nvc[key]);
byte formitembytes = System.Text.Encoding.UTF8.GetBytes(formitem);
rs.Write(formitembytes, 0, formitembytes.Length);
}
rs.Write(boundarybytes, 0, boundarybytes.Length);
string headerTemplate = "Content-Disposition: form-data; name="{0}"; filename="{1}"rnContent-Type: {2}rnrn";
string header = string.Format(headerTemplate, paramName, filename, contentType);
byte headerbytes = System.Text.Encoding.UTF8.GetBytes(header);
rs.Write(headerbytes, 0, headerbytes.Length);
rs.Write(file, 0, file.Length);
byte trailer = System.Text.Encoding.ASCII.GetBytes("rn--" + boundary + "--rn");
rs.Write(trailer, 0, trailer.Length);
rs.Close();
WebResponse wresp = null;
string ret = null;
try
{
wresp = wr.GetResponse();
Stream stream2 = wresp.GetResponseStream();
StreamReader reader2 = new StreamReader(stream2);
ret = reader2.ReadToEnd();
}
catch (Exception ex)
{
if (wresp != null)
{
wresp.Close();
wresp = null;
}
}
finally
{
wr = null;
}
return ret;
}
JToken ret = HttpUploadFile("/upload", file_name, file_bytes, "uploadedFile", "", new NameValueCollection());
edited Nov 19 '18 at 15:16
pushkin
3,949112651
answered Nov 19 '18 at 14:50
Anatoliy Zingerov
1
edited Nov 19 '18 at 15:16
pushkin
3,949112651
edited Nov 19 '18 at 15:16
pushkin
3,949112651
edited Nov 19 '18 at 15:16
pushkin
3,949112651
3,949112651
answered Nov 19 '18 at 14:50
Anatoliy Zingerov
1
answered Nov 19 '18 at 14:50
Anatoliy Zingerov
1
answered Nov 19 '18 at 14:50
Anatoliy Zingerov
1
1
add a comment |
add a comment |
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