How is the random variable $X=max{x_1,dots,x_n}$ related to the negative binomial distribution












2












$begingroup$


Consider a jar with $N$ indexed balls from $1$ to $N$ and the variable $X=max{x_1,dots,x_n} $ where $n<N$ is the number of balls we took out without replacement.



I found that $P(X=k)=begin{cases} 0 &text{ if } k<n\ frac{{k-1choose n-1}}{Nchoose n-1} &text { if } nle kle N end{cases}$



Is $X$ related to the negative binomial distribution, and how?










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$endgroup$












  • $begingroup$
    What are the $x_i$?
    $endgroup$
    – David M.
    Jan 26 at 20:55










  • $begingroup$
    the balls we took out
    $endgroup$
    – H. Walter
    Jan 27 at 7:20










  • $begingroup$
    Ah okay. I don’t see a connection with negative binomial, as the trials in a negative-binomial-type experiment are independent. The sampling without replacement makes the trials dependent (e.g. if you sample ball $N$ on the first go, $X$ becomes degenerate).
    $endgroup$
    – David M.
    Jan 27 at 14:33










  • $begingroup$
    Since the sampling is without replacement, perhaps you should consider the relation to HyperGeometric distribution.
    $endgroup$
    – Lee David Chung Lin
    Jan 29 at 9:28
















2












$begingroup$


Consider a jar with $N$ indexed balls from $1$ to $N$ and the variable $X=max{x_1,dots,x_n} $ where $n<N$ is the number of balls we took out without replacement.



I found that $P(X=k)=begin{cases} 0 &text{ if } k<n\ frac{{k-1choose n-1}}{Nchoose n-1} &text { if } nle kle N end{cases}$



Is $X$ related to the negative binomial distribution, and how?










share|cite|improve this question









$endgroup$












  • $begingroup$
    What are the $x_i$?
    $endgroup$
    – David M.
    Jan 26 at 20:55










  • $begingroup$
    the balls we took out
    $endgroup$
    – H. Walter
    Jan 27 at 7:20










  • $begingroup$
    Ah okay. I don’t see a connection with negative binomial, as the trials in a negative-binomial-type experiment are independent. The sampling without replacement makes the trials dependent (e.g. if you sample ball $N$ on the first go, $X$ becomes degenerate).
    $endgroup$
    – David M.
    Jan 27 at 14:33










  • $begingroup$
    Since the sampling is without replacement, perhaps you should consider the relation to HyperGeometric distribution.
    $endgroup$
    – Lee David Chung Lin
    Jan 29 at 9:28














2












2








2





$begingroup$


Consider a jar with $N$ indexed balls from $1$ to $N$ and the variable $X=max{x_1,dots,x_n} $ where $n<N$ is the number of balls we took out without replacement.



I found that $P(X=k)=begin{cases} 0 &text{ if } k<n\ frac{{k-1choose n-1}}{Nchoose n-1} &text { if } nle kle N end{cases}$



Is $X$ related to the negative binomial distribution, and how?










share|cite|improve this question









$endgroup$




Consider a jar with $N$ indexed balls from $1$ to $N$ and the variable $X=max{x_1,dots,x_n} $ where $n<N$ is the number of balls we took out without replacement.



I found that $P(X=k)=begin{cases} 0 &text{ if } k<n\ frac{{k-1choose n-1}}{Nchoose n-1} &text { if } nle kle N end{cases}$



Is $X$ related to the negative binomial distribution, and how?







probability negative-binomial






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 26 at 13:33









H. WalterH. Walter

1047




1047












  • $begingroup$
    What are the $x_i$?
    $endgroup$
    – David M.
    Jan 26 at 20:55










  • $begingroup$
    the balls we took out
    $endgroup$
    – H. Walter
    Jan 27 at 7:20










  • $begingroup$
    Ah okay. I don’t see a connection with negative binomial, as the trials in a negative-binomial-type experiment are independent. The sampling without replacement makes the trials dependent (e.g. if you sample ball $N$ on the first go, $X$ becomes degenerate).
    $endgroup$
    – David M.
    Jan 27 at 14:33










  • $begingroup$
    Since the sampling is without replacement, perhaps you should consider the relation to HyperGeometric distribution.
    $endgroup$
    – Lee David Chung Lin
    Jan 29 at 9:28


















  • $begingroup$
    What are the $x_i$?
    $endgroup$
    – David M.
    Jan 26 at 20:55










  • $begingroup$
    the balls we took out
    $endgroup$
    – H. Walter
    Jan 27 at 7:20










  • $begingroup$
    Ah okay. I don’t see a connection with negative binomial, as the trials in a negative-binomial-type experiment are independent. The sampling without replacement makes the trials dependent (e.g. if you sample ball $N$ on the first go, $X$ becomes degenerate).
    $endgroup$
    – David M.
    Jan 27 at 14:33










  • $begingroup$
    Since the sampling is without replacement, perhaps you should consider the relation to HyperGeometric distribution.
    $endgroup$
    – Lee David Chung Lin
    Jan 29 at 9:28
















$begingroup$
What are the $x_i$?
$endgroup$
– David M.
Jan 26 at 20:55




$begingroup$
What are the $x_i$?
$endgroup$
– David M.
Jan 26 at 20:55












$begingroup$
the balls we took out
$endgroup$
– H. Walter
Jan 27 at 7:20




$begingroup$
the balls we took out
$endgroup$
– H. Walter
Jan 27 at 7:20












$begingroup$
Ah okay. I don’t see a connection with negative binomial, as the trials in a negative-binomial-type experiment are independent. The sampling without replacement makes the trials dependent (e.g. if you sample ball $N$ on the first go, $X$ becomes degenerate).
$endgroup$
– David M.
Jan 27 at 14:33




$begingroup$
Ah okay. I don’t see a connection with negative binomial, as the trials in a negative-binomial-type experiment are independent. The sampling without replacement makes the trials dependent (e.g. if you sample ball $N$ on the first go, $X$ becomes degenerate).
$endgroup$
– David M.
Jan 27 at 14:33












$begingroup$
Since the sampling is without replacement, perhaps you should consider the relation to HyperGeometric distribution.
$endgroup$
– Lee David Chung Lin
Jan 29 at 9:28




$begingroup$
Since the sampling is without replacement, perhaps you should consider the relation to HyperGeometric distribution.
$endgroup$
– Lee David Chung Lin
Jan 29 at 9:28










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