Mixing
How Process can Share array2(the oracle array) in Spectre Attack?
In spectre paper, the PoC place Victim and Attacker code in same process.
The code is like this:
if (x < array1_size)
y = array2[ array1[x] * 256 ];
So Attacker and victim can use the same array2(because they are in same code, process).
But in real world, Attacker and Victim is separated(they are different process), so they can't share array2.
So here is my question, in this case, How can Attacker measure access time to array2?
How can Attacker know array2's address?
I have no idea how to attacker access to array2. What is misunderstood here?
security spectre side-channel-attacks
asked Jan 2 at 9:55
Kyuwon ChoKyuwon Cho
11
add a comment |
In spectre paper, the PoC place Victim and Attacker code in same process.
The code is like this:
if (x < array1_size)
y = array2[ array1[x] * 256 ];
So Attacker and victim can use the same array2(because they are in same code, process).
But in real world, Attacker and Victim is separated(they are different process), so they can't share array2.
So here is my question, in this case, How can Attacker measure access time to array2?
How can Attacker know array2's address?
I have no idea how to attacker access to array2. What is misunderstood here?
security spectre side-channel-attacks
asked Jan 2 at 9:55
Kyuwon ChoKyuwon Cho
11
add a comment |
In spectre paper, the PoC place Victim and Attacker code in same process.
The code is like this:
if (x < array1_size)
y = array2[ array1[x] * 256 ];
So Attacker and victim can use the same array2(because they are in same code, process).
But in real world, Attacker and Victim is separated(they are different process), so they can't share array2.
So here is my question, in this case, How can Attacker measure access time to array2?
How can Attacker know array2's address?
I have no idea how to attacker access to array2. What is misunderstood here?
security spectre side-channel-attacks
asked Jan 2 at 9:55
Kyuwon ChoKyuwon Cho
11
In spectre paper, the PoC place Victim and Attacker code in same process.
The code is like this:
if (x < array1_size)
y = array2[ array1[x] * 256 ];
So Attacker and victim can use the same array2(because they are in same code, process).
But in real world, Attacker and Victim is separated(they are different process), so they can't share array2.
So here is my question, in this case, How can Attacker measure access time to array2?
How can Attacker know array2's address?
I have no idea how to attacker access to array2. What is misunderstood here?
security spectre side-channel-attacks
security spectre side-channel-attacks
asked Jan 2 at 9:55
Kyuwon ChoKyuwon Cho
11
asked Jan 2 at 9:55
Kyuwon ChoKyuwon Cho
11
asked Jan 2 at 9:55
Kyuwon ChoKyuwon Cho
11
asked Jan 2 at 9:55
Kyuwon ChoKyuwon Cho
11
asked Jan 2 at 9:55
Kyuwon ChoKyuwon Cho
11
11
add a comment |
add a comment |
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