Mixing
How to fill multidimensional array in javascript?
I tried to get this to work, but the outer loop stops after second iteration, and everything that's after it does not execute(just like it was the end of the script). I want to fill two dimensional array with any character(here i used 'q' as an example)
var A=[,];
for(var i=0;i<12;i++){
for(var j=0;j<81;j++){
A[i][j]='q';
}
}
It didn't work, so i put alert(i+' '+j); to see if it's even executing, and, as i wrote before, it stops after second iteration of outer loop, and then ignores rest of the script.
All I want is to have this array filled with same character in the given range(12 rows, 81 columns in this specific case), so if there's no hope in this method, i'll be glad to see one that works.
javascript arrays loops
edited Jan 1 at 1:13
Jack Bashford
10.7k31643
asked Jan 1 at 0:57
zeregzesiszeregzesis
81
add a comment |
I tried to get this to work, but the outer loop stops after second iteration, and everything that's after it does not execute(just like it was the end of the script). I want to fill two dimensional array with any character(here i used 'q' as an example)
var A=[,];
for(var i=0;i<12;i++){
for(var j=0;j<81;j++){
A[i][j]='q';
}
}
It didn't work, so i put alert(i+' '+j); to see if it's even executing, and, as i wrote before, it stops after second iteration of outer loop, and then ignores rest of the script.
All I want is to have this array filled with same character in the given range(12 rows, 81 columns in this specific case), so if there's no hope in this method, i'll be glad to see one that works.
javascript arrays loops
edited Jan 1 at 1:13
Jack Bashford
10.7k31643
asked Jan 1 at 0:57
zeregzesiszeregzesis
81
You're only initializingAwith 2 items. Always check your console for errors before asking why things aren't working.Uncaught TypeError: Cannot set property '0' of undefinedCreate an array to assign to[i]inside the outer loop.
– CertainPerformance
Jan 1 at 1:00
A neat looking way is something like const A = Array(12).fill(0).map(() => Array(81).fill("q"));
– Countingstuff
Jan 1 at 1:09
Possible duplicate of Efficient way to declare and populate multidimensional array in Javascript
– Heretic Monkey
Jan 1 at 1:25
add a comment |
I tried to get this to work, but the outer loop stops after second iteration, and everything that's after it does not execute(just like it was the end of the script). I want to fill two dimensional array with any character(here i used 'q' as an example)
var A=[,];
for(var i=0;i<12;i++){
for(var j=0;j<81;j++){
A[i][j]='q';
}
}
It didn't work, so i put alert(i+' '+j); to see if it's even executing, and, as i wrote before, it stops after second iteration of outer loop, and then ignores rest of the script.
All I want is to have this array filled with same character in the given range(12 rows, 81 columns in this specific case), so if there's no hope in this method, i'll be glad to see one that works.
javascript arrays loops
edited Jan 1 at 1:13
Jack Bashford
10.7k31643
asked Jan 1 at 0:57
zeregzesiszeregzesis
81
I tried to get this to work, but the outer loop stops after second iteration, and everything that's after it does not execute(just like it was the end of the script). I want to fill two dimensional array with any character(here i used 'q' as an example)
var A=[,];
for(var i=0;i<12;i++){
for(var j=0;j<81;j++){
A[i][j]='q';
}
}
It didn't work, so i put alert(i+' '+j); to see if it's even executing, and, as i wrote before, it stops after second iteration of outer loop, and then ignores rest of the script.
All I want is to have this array filled with same character in the given range(12 rows, 81 columns in this specific case), so if there's no hope in this method, i'll be glad to see one that works.
javascript arrays loops
javascript arrays loops
edited Jan 1 at 1:13
Jack Bashford
10.7k31643
asked Jan 1 at 0:57
zeregzesiszeregzesis
81
edited Jan 1 at 1:13
Jack Bashford
10.7k31643
asked Jan 1 at 0:57
zeregzesiszeregzesis
81
edited Jan 1 at 1:13
Jack Bashford
10.7k31643
edited Jan 1 at 1:13
Jack Bashford
10.7k31643
edited Jan 1 at 1:13
Jack Bashford
10.7k31643
10.7k31643
asked Jan 1 at 0:57
zeregzesiszeregzesis
81
asked Jan 1 at 0:57
zeregzesiszeregzesis
81
asked Jan 1 at 0:57
zeregzesiszeregzesis
81
81
You're only initializingAwith 2 items. Always check your console for errors before asking why things aren't working.Uncaught TypeError: Cannot set property '0' of undefinedCreate an array to assign to[i]inside the outer loop.
– CertainPerformance
Jan 1 at 1:00
A neat looking way is something like const A = Array(12).fill(0).map(() => Array(81).fill("q"));
– Countingstuff
Jan 1 at 1:09
Possible duplicate of Efficient way to declare and populate multidimensional array in Javascript
– Heretic Monkey
Jan 1 at 1:25
add a comment |
You're only initializingAwith 2 items. Always check your console for errors before asking why things aren't working.Uncaught TypeError: Cannot set property '0' of undefinedCreate an array to assign to[i]inside the outer loop.
– CertainPerformance
Jan 1 at 1:00
A neat looking way is something like const A = Array(12).fill(0).map(() => Array(81).fill("q"));
– Countingstuff
Jan 1 at 1:09
Possible duplicate of Efficient way to declare and populate multidimensional array in Javascript
– Heretic Monkey
Jan 1 at 1:25
You're only initializing
A with 2 items. Always check your console for errors before asking why things aren't working. Uncaught TypeError: Cannot set property '0' of undefined Create an array to assign to [i] inside the outer loop.– CertainPerformance
Jan 1 at 1:00
You're only initializing
A with 2 items. Always check your console for errors before asking why things aren't working. Uncaught TypeError: Cannot set property '0' of undefined Create an array to assign to [i] inside the outer loop.– CertainPerformance
Jan 1 at 1:00
A neat looking way is something like const A = Array(12).fill(0).map(() => Array(81).fill("q"));
– Countingstuff
Jan 1 at 1:09
A neat looking way is something like const A = Array(12).fill(0).map(() => Array(81).fill("q"));
– Countingstuff
Jan 1 at 1:09
Possible duplicate of Efficient way to declare and populate multidimensional array in Javascript
– Heretic Monkey
Jan 1 at 1:25
Possible duplicate of Efficient way to declare and populate multidimensional array in Javascript
– Heretic Monkey
Jan 1 at 1:25
add a comment |
3 Answers
3
active
oldest
votes
var A=[, ];
^ This line declares a two dimensional array of size 1x2. Try this instead:
var A = ;
for (var i = 0; i < 12; i++) {
A[i] = ;
for (var j = 0; j < 81; j++) {
A[i][j] = 'q';
}
}
answered Jan 1 at 1:05
johnheroyjohnheroy
32615
@MarkMeyer I forgotA[i] = ;on the third line when I reformatted the code to make the stack overflow form validation for multiline code happy :) Nice catch!
– johnheroy
Jan 1 at 1:11
add a comment |
You need to initialise a new array for i each time the first loop runs, and you don't need to set the layout of the array before you create it (Remove the , inside the declaration of A). Try this:
var A = ;
for (var i = 0; i < 12; i++) {
A[i] = ;
for (var j = 0; j < 81; j++) {
A[i][j] = 'q';
}
}
console.log(A);.as-console-wrapper {
max-height: 100% !important;
top: 0;
}answered Jan 1 at 1:12
Jack BashfordJack Bashford
10.7k31643
add a comment |
const range = (start, stop, step) => Array.from({ length: (stop - start) / step }, () => 'q');
let twoDArray =
for(i=0; i<12; i++){
twoDArray.push(range(0,81,1))
}
console.log(twoDArray)Alternative
function genrateTwoDArray({
rows,
columns,
defaultValue
}){ return Array.from({ length:rows}, () => (
Array.from({length: columns}, ()=> defaultValue )
))
}
console.log(genrateTwoDArray({rows:3, columns:9, defaultValue: 'q'}))answered Jan 1 at 6:42
Mohammed AshfaqMohammed Ashfaq
1,7192612
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
var A=[, ];
^ This line declares a two dimensional array of size 1x2. Try this instead:
var A = ;
for (var i = 0; i < 12; i++) {
A[i] = ;
for (var j = 0; j < 81; j++) {
A[i][j] = 'q';
}
}
answered Jan 1 at 1:05
johnheroyjohnheroy
32615
@MarkMeyer I forgotA[i] = ;on the third line when I reformatted the code to make the stack overflow form validation for multiline code happy :) Nice catch!
– johnheroy
Jan 1 at 1:11
add a comment |
var A=[, ];
^ This line declares a two dimensional array of size 1x2. Try this instead:
var A = ;
for (var i = 0; i < 12; i++) {
A[i] = ;
for (var j = 0; j < 81; j++) {
A[i][j] = 'q';
}
}
answered Jan 1 at 1:05
johnheroyjohnheroy
32615
@MarkMeyer I forgotA[i] = ;on the third line when I reformatted the code to make the stack overflow form validation for multiline code happy :) Nice catch!
– johnheroy
Jan 1 at 1:11
add a comment |
var A=[, ];
^ This line declares a two dimensional array of size 1x2. Try this instead:
var A = ;
for (var i = 0; i < 12; i++) {
A[i] = ;
for (var j = 0; j < 81; j++) {
A[i][j] = 'q';
}
}
answered Jan 1 at 1:05
johnheroyjohnheroy
32615
var A=[, ];
^ This line declares a two dimensional array of size 1x2. Try this instead:
var A = ;
for (var i = 0; i < 12; i++) {
A[i] = ;
for (var j = 0; j < 81; j++) {
A[i][j] = 'q';
}
}
answered Jan 1 at 1:05
johnheroyjohnheroy
32615
edited Jan 1 at 1:10
answered Jan 1 at 1:05
johnheroyjohnheroy
32615
answered Jan 1 at 1:05
johnheroyjohnheroy
32615
answered Jan 1 at 1:05
johnheroyjohnheroy
32615
32615
@MarkMeyer I forgotA[i] = ;on the third line when I reformatted the code to make the stack overflow form validation for multiline code happy :) Nice catch!
– johnheroy
Jan 1 at 1:11
add a comment |
@MarkMeyer I forgotA[i] = ;on the third line when I reformatted the code to make the stack overflow form validation for multiline code happy :) Nice catch!
– johnheroy
Jan 1 at 1:11
@MarkMeyer I forgot
A[i] = ; on the third line when I reformatted the code to make the stack overflow form validation for multiline code happy :) Nice catch!– johnheroy
Jan 1 at 1:11
@MarkMeyer I forgot
A[i] = ; on the third line when I reformatted the code to make the stack overflow form validation for multiline code happy :) Nice catch!– johnheroy
Jan 1 at 1:11
add a comment |
You need to initialise a new array for i each time the first loop runs, and you don't need to set the layout of the array before you create it (Remove the , inside the declaration of A). Try this:
var A = ;
for (var i = 0; i < 12; i++) {
A[i] = ;
for (var j = 0; j < 81; j++) {
A[i][j] = 'q';
}
}
console.log(A);.as-console-wrapper {
max-height: 100% !important;
top: 0;
}answered Jan 1 at 1:12
Jack BashfordJack Bashford
10.7k31643
add a comment |
You need to initialise a new array for i each time the first loop runs, and you don't need to set the layout of the array before you create it (Remove the , inside the declaration of A). Try this:
var A = ;
for (var i = 0; i < 12; i++) {
A[i] = ;
for (var j = 0; j < 81; j++) {
A[i][j] = 'q';
}
}
console.log(A);.as-console-wrapper {
max-height: 100% !important;
top: 0;
}answered Jan 1 at 1:12
Jack BashfordJack Bashford
10.7k31643
add a comment |
You need to initialise a new array for i each time the first loop runs, and you don't need to set the layout of the array before you create it (Remove the , inside the declaration of A). Try this:
var A = ;
for (var i = 0; i < 12; i++) {
A[i] = ;
for (var j = 0; j < 81; j++) {
A[i][j] = 'q';
}
}
console.log(A);.as-console-wrapper {
max-height: 100% !important;
top: 0;
}answered Jan 1 at 1:12
Jack BashfordJack Bashford
10.7k31643
You need to initialise a new array for i each time the first loop runs, and you don't need to set the layout of the array before you create it (Remove the , inside the declaration of A). Try this:
var A = ;
for (var i = 0; i < 12; i++) {
A[i] = ;
for (var j = 0; j < 81; j++) {
A[i][j] = 'q';
}
}
console.log(A);.as-console-wrapper {
max-height: 100% !important;
top: 0;
}var A = ;
for (var i = 0; i < 12; i++) {
A[i] = ;
for (var j = 0; j < 81; j++) {
A[i][j] = 'q';
}
}
console.log(A);.as-console-wrapper {
max-height: 100% !important;
top: 0;
}var A = ;
for (var i = 0; i < 12; i++) {
A[i] = ;
for (var j = 0; j < 81; j++) {
A[i][j] = 'q';
}
}
console.log(A);.as-console-wrapper {
max-height: 100% !important;
top: 0;
}answered Jan 1 at 1:12
Jack BashfordJack Bashford
10.7k31643
edited Jan 1 at 1:20
answered Jan 1 at 1:12
Jack BashfordJack Bashford
10.7k31643
answered Jan 1 at 1:12
Jack BashfordJack Bashford
10.7k31643
answered Jan 1 at 1:12
Jack BashfordJack Bashford
10.7k31643
10.7k31643
add a comment |
add a comment |
const range = (start, stop, step) => Array.from({ length: (stop - start) / step }, () => 'q');
let twoDArray =
for(i=0; i<12; i++){
twoDArray.push(range(0,81,1))
}
console.log(twoDArray)Alternative
function genrateTwoDArray({
rows,
columns,
defaultValue
}){ return Array.from({ length:rows}, () => (
Array.from({length: columns}, ()=> defaultValue )
))
}
console.log(genrateTwoDArray({rows:3, columns:9, defaultValue: 'q'}))answered Jan 1 at 6:42
Mohammed AshfaqMohammed Ashfaq
1,7192612
add a comment |
const range = (start, stop, step) => Array.from({ length: (stop - start) / step }, () => 'q');
let twoDArray =
for(i=0; i<12; i++){
twoDArray.push(range(0,81,1))
}
console.log(twoDArray)Alternative
function genrateTwoDArray({
rows,
columns,
defaultValue
}){ return Array.from({ length:rows}, () => (
Array.from({length: columns}, ()=> defaultValue )
))
}
console.log(genrateTwoDArray({rows:3, columns:9, defaultValue: 'q'}))answered Jan 1 at 6:42
Mohammed AshfaqMohammed Ashfaq
1,7192612
add a comment |
const range = (start, stop, step) => Array.from({ length: (stop - start) / step }, () => 'q');
let twoDArray =
for(i=0; i<12; i++){
twoDArray.push(range(0,81,1))
}
console.log(twoDArray)Alternative
function genrateTwoDArray({
rows,
columns,
defaultValue
}){ return Array.from({ length:rows}, () => (
Array.from({length: columns}, ()=> defaultValue )
))
}
console.log(genrateTwoDArray({rows:3, columns:9, defaultValue: 'q'}))answered Jan 1 at 6:42
Mohammed AshfaqMohammed Ashfaq
1,7192612
const range = (start, stop, step) => Array.from({ length: (stop - start) / step }, () => 'q');
let twoDArray =
for(i=0; i<12; i++){
twoDArray.push(range(0,81,1))
}
console.log(twoDArray)Alternative
function genrateTwoDArray({
rows,
columns,
defaultValue
}){ return Array.from({ length:rows}, () => (
Array.from({length: columns}, ()=> defaultValue )
))
}
console.log(genrateTwoDArray({rows:3, columns:9, defaultValue: 'q'}))const range = (start, stop, step) => Array.from({ length: (stop - start) / step }, () => 'q');
let twoDArray =
for(i=0; i<12; i++){
twoDArray.push(range(0,81,1))
}
console.log(twoDArray)const range = (start, stop, step) => Array.from({ length: (stop - start) / step }, () => 'q');
let twoDArray =
for(i=0; i<12; i++){
twoDArray.push(range(0,81,1))
}
console.log(twoDArray)function genrateTwoDArray({
rows,
columns,
defaultValue
}){ return Array.from({ length:rows}, () => (
Array.from({length: columns}, ()=> defaultValue )
))
}
console.log(genrateTwoDArray({rows:3, columns:9, defaultValue: 'q'}))function genrateTwoDArray({
rows,
columns,
defaultValue
}){ return Array.from({ length:rows}, () => (
Array.from({length: columns}, ()=> defaultValue )
))
}
console.log(genrateTwoDArray({rows:3, columns:9, defaultValue: 'q'}))answered Jan 1 at 6:42
Mohammed AshfaqMohammed Ashfaq
1,7192612
edited Jan 1 at 6:59
answered Jan 1 at 6:42
Mohammed AshfaqMohammed Ashfaq
1,7192612
answered Jan 1 at 6:42
Mohammed AshfaqMohammed Ashfaq
1,7192612
answered Jan 1 at 6:42
Mohammed AshfaqMohammed Ashfaq
1,7192612
1,7192612
add a comment |
add a comment |
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You're only initializing
Awith 2 items. Always check your console for errors before asking why things aren't working.Uncaught TypeError: Cannot set property '0' of undefinedCreate an array to assign to[i]inside the outer loop.– CertainPerformance
Jan 1 at 1:00
A neat looking way is something like const A = Array(12).fill(0).map(() => Array(81).fill("q"));
– Countingstuff
Jan 1 at 1:09
Possible duplicate of Efficient way to declare and populate multidimensional array in Javascript
– Heretic Monkey
Jan 1 at 1:25