Mixing
How to obtain Printed Output in R?
I have a function called filter_output in R which, when evaluated, gives the following output:
Smoothed values of states and standard errors at time n = 392:
Estimate Std. Error
Kappa 0.000000003006008509 0.000001266168236651
Phi -0.000000005332550866 0.000001592969577779
custom1 0.007754099549102765 0.001189674872696318
custom2 0.000000000029421272 0.000614394025071959
The problem however is that there's no way for me to store these values in a separate matrix - for example, I can't use filter_output$... or filter_output[1] etc. to obtain the estimates or standard error since they don't appear to be a part of any call of the function (it's not in a list either).
I've tried using the function capture.output in order to obtain these individual values but this function appears to extract them as strings, which seems to be computationally inefficient since I have to split up the string and then convert it to a numeric value. Is there a quick and efficient way for me to store values when they're outputted?
r
asked Jan 2 at 5:05
ThePlowKingThePlowKing
109112
add a comment |
I have a function called filter_output in R which, when evaluated, gives the following output:
Smoothed values of states and standard errors at time n = 392:
Estimate Std. Error
Kappa 0.000000003006008509 0.000001266168236651
Phi -0.000000005332550866 0.000001592969577779
custom1 0.007754099549102765 0.001189674872696318
custom2 0.000000000029421272 0.000614394025071959
The problem however is that there's no way for me to store these values in a separate matrix - for example, I can't use filter_output$... or filter_output[1] etc. to obtain the estimates or standard error since they don't appear to be a part of any call of the function (it's not in a list either).
I've tried using the function capture.output in order to obtain these individual values but this function appears to extract them as strings, which seems to be computationally inefficient since I have to split up the string and then convert it to a numeric value. Is there a quick and efficient way for me to store values when they're outputted?
r
asked Jan 2 at 5:05
ThePlowKingThePlowKing
109112
add a comment |
I have a function called filter_output in R which, when evaluated, gives the following output:
Smoothed values of states and standard errors at time n = 392:
Estimate Std. Error
Kappa 0.000000003006008509 0.000001266168236651
Phi -0.000000005332550866 0.000001592969577779
custom1 0.007754099549102765 0.001189674872696318
custom2 0.000000000029421272 0.000614394025071959
The problem however is that there's no way for me to store these values in a separate matrix - for example, I can't use filter_output$... or filter_output[1] etc. to obtain the estimates or standard error since they don't appear to be a part of any call of the function (it's not in a list either).
I've tried using the function capture.output in order to obtain these individual values but this function appears to extract them as strings, which seems to be computationally inefficient since I have to split up the string and then convert it to a numeric value. Is there a quick and efficient way for me to store values when they're outputted?
r
asked Jan 2 at 5:05
ThePlowKingThePlowKing
109112
I have a function called filter_output in R which, when evaluated, gives the following output:
Smoothed values of states and standard errors at time n = 392:
Estimate Std. Error
Kappa 0.000000003006008509 0.000001266168236651
Phi -0.000000005332550866 0.000001592969577779
custom1 0.007754099549102765 0.001189674872696318
custom2 0.000000000029421272 0.000614394025071959
The problem however is that there's no way for me to store these values in a separate matrix - for example, I can't use filter_output$... or filter_output[1] etc. to obtain the estimates or standard error since they don't appear to be a part of any call of the function (it's not in a list either).
I've tried using the function capture.output in order to obtain these individual values but this function appears to extract them as strings, which seems to be computationally inefficient since I have to split up the string and then convert it to a numeric value. Is there a quick and efficient way for me to store values when they're outputted?
r
r
asked Jan 2 at 5:05
ThePlowKingThePlowKing
109112
asked Jan 2 at 5:05
ThePlowKingThePlowKing
109112
asked Jan 2 at 5:05
ThePlowKingThePlowKing
109112
asked Jan 2 at 5:05
ThePlowKingThePlowKing
109112
asked Jan 2 at 5:05
ThePlowKingThePlowKing
109112
109112
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Just type the name of the opbject you have saved it as
filter_output1 <- filter_output %>% select(Estimate, Std. Error)
#print
filter_output1
edited Jan 2 at 5:49
RAB
1,412418
answered Jan 2 at 5:17
Farah NazifaFarah Nazifa
587512
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Just type the name of the opbject you have saved it as
filter_output1 <- filter_output %>% select(Estimate, Std. Error)
#print
filter_output1
edited Jan 2 at 5:49
RAB
1,412418
answered Jan 2 at 5:17
Farah NazifaFarah Nazifa
587512
add a comment |
Just type the name of the opbject you have saved it as
filter_output1 <- filter_output %>% select(Estimate, Std. Error)
#print
filter_output1
edited Jan 2 at 5:49
RAB
1,412418
answered Jan 2 at 5:17
Farah NazifaFarah Nazifa
587512
add a comment |
Just type the name of the opbject you have saved it as
filter_output1 <- filter_output %>% select(Estimate, Std. Error)
#print
filter_output1
edited Jan 2 at 5:49
RAB
1,412418
answered Jan 2 at 5:17
Farah NazifaFarah Nazifa
587512
Just type the name of the opbject you have saved it as
filter_output1 <- filter_output %>% select(Estimate, Std. Error)
#print
filter_output1
edited Jan 2 at 5:49
RAB
1,412418
answered Jan 2 at 5:17
Farah NazifaFarah Nazifa
587512
edited Jan 2 at 5:49
RAB
1,412418
edited Jan 2 at 5:49
RAB
1,412418
edited Jan 2 at 5:49
RAB
1,412418
1,412418
answered Jan 2 at 5:17
Farah NazifaFarah Nazifa
587512
answered Jan 2 at 5:17
Farah NazifaFarah Nazifa
587512
answered Jan 2 at 5:17
Farah NazifaFarah Nazifa
587512
587512
add a comment |
add a comment |
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