In how many ways n seat can be placed with people from Group A and Group B and no two people from Group B...












0












$begingroup$


It is given that there are n seats for some event.



It is not know how many people attend from Group A or Group B.



But no two people from Group B should not sit together.



Like if there is 2 seats in event.



Valid combinations:
AA
AB
BA



Invalid combinations:
BB



What will be the number of valid combinations?










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$endgroup$

















    0












    $begingroup$


    It is given that there are n seats for some event.



    It is not know how many people attend from Group A or Group B.



    But no two people from Group B should not sit together.



    Like if there is 2 seats in event.



    Valid combinations:
    AA
    AB
    BA



    Invalid combinations:
    BB



    What will be the number of valid combinations?










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      It is given that there are n seats for some event.



      It is not know how many people attend from Group A or Group B.



      But no two people from Group B should not sit together.



      Like if there is 2 seats in event.



      Valid combinations:
      AA
      AB
      BA



      Invalid combinations:
      BB



      What will be the number of valid combinations?










      share|cite|improve this question









      $endgroup$




      It is given that there are n seats for some event.



      It is not know how many people attend from Group A or Group B.



      But no two people from Group B should not sit together.



      Like if there is 2 seats in event.



      Valid combinations:
      AA
      AB
      BA



      Invalid combinations:
      BB



      What will be the number of valid combinations?







      combinatorics combinations






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      share|cite|improve this question











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      share|cite|improve this question










      asked Jan 26 at 15:39









      Kawin MKawin M

      1012




      1012






















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          $begingroup$

          Denote the number of valid combinations by $a_n$. The first (i.e., leftmost) of the $ngeq3$ seats can be an A-seat or a B-seat. If it is an A-seat the remaining $n-1$ seats can be filled in an arbitrary admissible way. If the first seat is a B-seat the next seat has to be an A-seat, and the remaining $n-2$ seats can again be filled in an arbitrary admissible way. This leads to a recursive formula of the form
          $$a_n=ldotsquad,$$
          whereby the RHS has to be filled with the appropriate terms. In addition think about $a_1$ and $a_2$, and you will arrive at a familiar sequence $ldots$






          share|cite|improve this answer









          $endgroup$













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            1 Answer
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            $begingroup$

            Denote the number of valid combinations by $a_n$. The first (i.e., leftmost) of the $ngeq3$ seats can be an A-seat or a B-seat. If it is an A-seat the remaining $n-1$ seats can be filled in an arbitrary admissible way. If the first seat is a B-seat the next seat has to be an A-seat, and the remaining $n-2$ seats can again be filled in an arbitrary admissible way. This leads to a recursive formula of the form
            $$a_n=ldotsquad,$$
            whereby the RHS has to be filled with the appropriate terms. In addition think about $a_1$ and $a_2$, and you will arrive at a familiar sequence $ldots$






            share|cite|improve this answer









            $endgroup$


















              1












              $begingroup$

              Denote the number of valid combinations by $a_n$. The first (i.e., leftmost) of the $ngeq3$ seats can be an A-seat or a B-seat. If it is an A-seat the remaining $n-1$ seats can be filled in an arbitrary admissible way. If the first seat is a B-seat the next seat has to be an A-seat, and the remaining $n-2$ seats can again be filled in an arbitrary admissible way. This leads to a recursive formula of the form
              $$a_n=ldotsquad,$$
              whereby the RHS has to be filled with the appropriate terms. In addition think about $a_1$ and $a_2$, and you will arrive at a familiar sequence $ldots$






              share|cite|improve this answer









              $endgroup$
















                1












                1








                1





                $begingroup$

                Denote the number of valid combinations by $a_n$. The first (i.e., leftmost) of the $ngeq3$ seats can be an A-seat or a B-seat. If it is an A-seat the remaining $n-1$ seats can be filled in an arbitrary admissible way. If the first seat is a B-seat the next seat has to be an A-seat, and the remaining $n-2$ seats can again be filled in an arbitrary admissible way. This leads to a recursive formula of the form
                $$a_n=ldotsquad,$$
                whereby the RHS has to be filled with the appropriate terms. In addition think about $a_1$ and $a_2$, and you will arrive at a familiar sequence $ldots$






                share|cite|improve this answer









                $endgroup$



                Denote the number of valid combinations by $a_n$. The first (i.e., leftmost) of the $ngeq3$ seats can be an A-seat or a B-seat. If it is an A-seat the remaining $n-1$ seats can be filled in an arbitrary admissible way. If the first seat is a B-seat the next seat has to be an A-seat, and the remaining $n-2$ seats can again be filled in an arbitrary admissible way. This leads to a recursive formula of the form
                $$a_n=ldotsquad,$$
                whereby the RHS has to be filled with the appropriate terms. In addition think about $a_1$ and $a_2$, and you will arrive at a familiar sequence $ldots$







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Jan 26 at 16:18









                Christian BlatterChristian Blatter

                175k8115327




                175k8115327






























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