MYsql - Get average time between a start and stop time across many rows












0















I have the following SQL and PHP that doesnt seem to be giving me the right numbers. (VERY high numbers)



I have a lot of rows with a start time and an end timestamp.
Im looking to get the average time between those two times.



Ie: 2 hours, 3 minutes, 46 seconds.



This is what I have.



SELECT AVG(tmp.dd) AS timetook
FROM
( SELECT TIME_TO_SEC(TIMEDIFF(timeclosed, timeanswered)) AS dd
FROM logs
WHERE timeclosed > DATE_SUB(NOW(), INTERVAL 1 DAY)
) tmp;


Am I going about this the completely wrong way? Anything obviously wrong here?



while($row = $result->fetch_assoc()) {
$timetoclose = $row['timetook'];
$hours = floor($timetoclose / 3600);
$mins = floor($timetoclose / 60 % 60);
$secs = floor($timetoclose % 60);
$timetoclose = sprintf('%02d Hour(s), %02d Minute(s), %02d Second(s)', $hours, $mins, $secs);
}


Cheers
G










share|improve this question

























  • See: Why should I provide an MCVE for what seems to me to be a very simple SQL query?

    – Strawberry
    Jan 2 at 12:02











  • I see nothing obviously wrong in your query. Is the average of "2 hours" is THAT high? Over 24 hours, it doesnt look incorrect to me. Keep in my mind that with AVG, if you have a few rows with a high number, it increase everything. Maybe you should use MEDIAN instead, not available in MySQL but can mimick it

    – Thomas G
    Jan 2 at 12:32
















0















I have the following SQL and PHP that doesnt seem to be giving me the right numbers. (VERY high numbers)



I have a lot of rows with a start time and an end timestamp.
Im looking to get the average time between those two times.



Ie: 2 hours, 3 minutes, 46 seconds.



This is what I have.



SELECT AVG(tmp.dd) AS timetook
FROM
( SELECT TIME_TO_SEC(TIMEDIFF(timeclosed, timeanswered)) AS dd
FROM logs
WHERE timeclosed > DATE_SUB(NOW(), INTERVAL 1 DAY)
) tmp;


Am I going about this the completely wrong way? Anything obviously wrong here?



while($row = $result->fetch_assoc()) {
$timetoclose = $row['timetook'];
$hours = floor($timetoclose / 3600);
$mins = floor($timetoclose / 60 % 60);
$secs = floor($timetoclose % 60);
$timetoclose = sprintf('%02d Hour(s), %02d Minute(s), %02d Second(s)', $hours, $mins, $secs);
}


Cheers
G










share|improve this question

























  • See: Why should I provide an MCVE for what seems to me to be a very simple SQL query?

    – Strawberry
    Jan 2 at 12:02











  • I see nothing obviously wrong in your query. Is the average of "2 hours" is THAT high? Over 24 hours, it doesnt look incorrect to me. Keep in my mind that with AVG, if you have a few rows with a high number, it increase everything. Maybe you should use MEDIAN instead, not available in MySQL but can mimick it

    – Thomas G
    Jan 2 at 12:32














0












0








0








I have the following SQL and PHP that doesnt seem to be giving me the right numbers. (VERY high numbers)



I have a lot of rows with a start time and an end timestamp.
Im looking to get the average time between those two times.



Ie: 2 hours, 3 minutes, 46 seconds.



This is what I have.



SELECT AVG(tmp.dd) AS timetook
FROM
( SELECT TIME_TO_SEC(TIMEDIFF(timeclosed, timeanswered)) AS dd
FROM logs
WHERE timeclosed > DATE_SUB(NOW(), INTERVAL 1 DAY)
) tmp;


Am I going about this the completely wrong way? Anything obviously wrong here?



while($row = $result->fetch_assoc()) {
$timetoclose = $row['timetook'];
$hours = floor($timetoclose / 3600);
$mins = floor($timetoclose / 60 % 60);
$secs = floor($timetoclose % 60);
$timetoclose = sprintf('%02d Hour(s), %02d Minute(s), %02d Second(s)', $hours, $mins, $secs);
}


Cheers
G










share|improve this question
















I have the following SQL and PHP that doesnt seem to be giving me the right numbers. (VERY high numbers)



I have a lot of rows with a start time and an end timestamp.
Im looking to get the average time between those two times.



Ie: 2 hours, 3 minutes, 46 seconds.



This is what I have.



SELECT AVG(tmp.dd) AS timetook
FROM
( SELECT TIME_TO_SEC(TIMEDIFF(timeclosed, timeanswered)) AS dd
FROM logs
WHERE timeclosed > DATE_SUB(NOW(), INTERVAL 1 DAY)
) tmp;


Am I going about this the completely wrong way? Anything obviously wrong here?



while($row = $result->fetch_assoc()) {
$timetoclose = $row['timetook'];
$hours = floor($timetoclose / 3600);
$mins = floor($timetoclose / 60 % 60);
$secs = floor($timetoclose % 60);
$timetoclose = sprintf('%02d Hour(s), %02d Minute(s), %02d Second(s)', $hours, $mins, $secs);
}


Cheers
G







mysql average






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edited Jan 2 at 12:02









Strawberry

26.8k83250




26.8k83250










asked Jan 2 at 11:53









Graham SmartGraham Smart

115




115













  • See: Why should I provide an MCVE for what seems to me to be a very simple SQL query?

    – Strawberry
    Jan 2 at 12:02











  • I see nothing obviously wrong in your query. Is the average of "2 hours" is THAT high? Over 24 hours, it doesnt look incorrect to me. Keep in my mind that with AVG, if you have a few rows with a high number, it increase everything. Maybe you should use MEDIAN instead, not available in MySQL but can mimick it

    – Thomas G
    Jan 2 at 12:32



















  • See: Why should I provide an MCVE for what seems to me to be a very simple SQL query?

    – Strawberry
    Jan 2 at 12:02











  • I see nothing obviously wrong in your query. Is the average of "2 hours" is THAT high? Over 24 hours, it doesnt look incorrect to me. Keep in my mind that with AVG, if you have a few rows with a high number, it increase everything. Maybe you should use MEDIAN instead, not available in MySQL but can mimick it

    – Thomas G
    Jan 2 at 12:32

















See: Why should I provide an MCVE for what seems to me to be a very simple SQL query?

– Strawberry
Jan 2 at 12:02





See: Why should I provide an MCVE for what seems to me to be a very simple SQL query?

– Strawberry
Jan 2 at 12:02













I see nothing obviously wrong in your query. Is the average of "2 hours" is THAT high? Over 24 hours, it doesnt look incorrect to me. Keep in my mind that with AVG, if you have a few rows with a high number, it increase everything. Maybe you should use MEDIAN instead, not available in MySQL but can mimick it

– Thomas G
Jan 2 at 12:32





I see nothing obviously wrong in your query. Is the average of "2 hours" is THAT high? Over 24 hours, it doesnt look incorrect to me. Keep in my mind that with AVG, if you have a few rows with a high number, it increase everything. Maybe you should use MEDIAN instead, not available in MySQL but can mimick it

– Thomas G
Jan 2 at 12:32












1 Answer
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SELECT SUM(TIMESTAMPDIFF(minute, start_time, end_time)) / COUNT(*) AS avg_minutes
FROM your_table


try this query.






share|improve this answer

























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    SELECT SUM(TIMESTAMPDIFF(minute, start_time, end_time)) / COUNT(*) AS avg_minutes
    FROM your_table


    try this query.






    share|improve this answer






























      0














      SELECT SUM(TIMESTAMPDIFF(minute, start_time, end_time)) / COUNT(*) AS avg_minutes
      FROM your_table


      try this query.






      share|improve this answer




























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        0








        0







        SELECT SUM(TIMESTAMPDIFF(minute, start_time, end_time)) / COUNT(*) AS avg_minutes
        FROM your_table


        try this query.






        share|improve this answer















        SELECT SUM(TIMESTAMPDIFF(minute, start_time, end_time)) / COUNT(*) AS avg_minutes
        FROM your_table


        try this query.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Jan 2 at 13:23









        JochenJung

        5,708105398




        5,708105398










        answered Jan 2 at 12:19









        Mukitul IslamMukitul Islam

        11




        11
































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