Mixing
Sort objects in array by multiple property (possibility does not exist)
0
I am trying to sort this array:
[
{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
]
As you can see, there are object who doesn't have parentId. I need to keep this one on the top and the rest will be sorted by id.
Here's my code:
input.sort(function (a, b) {
if (typeof a.parentId === 'undefined'))
return -1;
else
return a.id - b.id;
});
It doesn't work though. Is it possible to do this?
Expected result:
[
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
},
{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
}
]
Thanks in advance
javascript
asked Jan 2 at 5:19
wowhcumoswowhcumos
32
add a comment |
0
I am trying to sort this array:
[
{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
]
As you can see, there are object who doesn't have parentId. I need to keep this one on the top and the rest will be sorted by id.
Here's my code:
input.sort(function (a, b) {
if (typeof a.parentId === 'undefined'))
return -1;
else
return a.id - b.id;
});
It doesn't work though. Is it possible to do this?
Expected result:
[
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
},
{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
}
]
Thanks in advance
javascript
asked Jan 2 at 5:19
wowhcumoswowhcumos
32
if sorting in descending order then in expected resultparentId877234003 will come first thenparentId877234003. pls edit your question.
– Shiv Kumar Baghel
Jan 2 at 5:32
add a comment |
0
0
0
I am trying to sort this array:
[
{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
]
As you can see, there are object who doesn't have parentId. I need to keep this one on the top and the rest will be sorted by id.
Here's my code:
input.sort(function (a, b) {
if (typeof a.parentId === 'undefined'))
return -1;
else
return a.id - b.id;
});
It doesn't work though. Is it possible to do this?
Expected result:
[
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
},
{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
}
]
Thanks in advance
javascript
asked Jan 2 at 5:19
wowhcumoswowhcumos
32
I am trying to sort this array:
[
{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
]
As you can see, there are object who doesn't have parentId. I need to keep this one on the top and the rest will be sorted by id.
Here's my code:
input.sort(function (a, b) {
if (typeof a.parentId === 'undefined'))
return -1;
else
return a.id - b.id;
});
It doesn't work though. Is it possible to do this?
Expected result:
[
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
},
{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
}
]
Thanks in advance
javascript
javascript
asked Jan 2 at 5:19
wowhcumoswowhcumos
32
asked Jan 2 at 5:19
wowhcumoswowhcumos
32
asked Jan 2 at 5:19
wowhcumoswowhcumos
32
asked Jan 2 at 5:19
wowhcumoswowhcumos
32
asked Jan 2 at 5:19
wowhcumoswowhcumos
32
32
if sorting in descending order then in expected resultparentId877234003 will come first thenparentId877234003. pls edit your question.
– Shiv Kumar Baghel
Jan 2 at 5:32
add a comment |
if sorting in descending order then in expected resultparentId877234003 will come first thenparentId877234003. pls edit your question.
– Shiv Kumar Baghel
Jan 2 at 5:32
if sorting in descending order then in expected result
parentId 877234003 will come first then parentId 877234003. pls edit your question.– Shiv Kumar Baghel
Jan 2 at 5:32
if sorting in descending order then in expected result
parentId 877234003 will come first then parentId 877234003. pls edit your question.– Shiv Kumar Baghel
Jan 2 at 5:32
add a comment |
2 Answers
2
active
oldest
votes
1
Need to test A and B and invert. if A is missing the prop use -1 if B use +1
let arr = [{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
];
const sortPredicate = (a,b) => {
if (a.hasOwnProperty('parentId') === false) {
return -1;
} else if(b.hasOwnProperty('parentId') === false) {
return 1;
} else {
return a.id - b.id;
}
};
console.log(arr.sort(sortPredicate));answered Jan 2 at 5:32
BibbertyBibberty
1,9431315
beautiful, thanks master!
– wowhcumos
Jan 2 at 5:41
An possible optimization would be to return the difference between eachhasOwnPropertycheck.
– CertainPerformance
Jan 2 at 9:29
add a comment |
2
i would suggest to use lodash js library
var arr = [
{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
];
var sortedArr = _.orderBy(arr, 'parentId', 'desc');
console.log(sortedArr);<script src="https://cdn.jsdelivr.net/npm/lodash@4.17.11/lodash.min.js"></script>answered Jan 2 at 5:28
Shiv Kumar BaghelShiv Kumar Baghel
1,4263921
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Need to test A and B and invert. if A is missing the prop use -1 if B use +1
let arr = [{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
];
const sortPredicate = (a,b) => {
if (a.hasOwnProperty('parentId') === false) {
return -1;
} else if(b.hasOwnProperty('parentId') === false) {
return 1;
} else {
return a.id - b.id;
}
};
console.log(arr.sort(sortPredicate));answered Jan 2 at 5:32
BibbertyBibberty
1,9431315
beautiful, thanks master!
– wowhcumos
Jan 2 at 5:41
An possible optimization would be to return the difference between eachhasOwnPropertycheck.
– CertainPerformance
Jan 2 at 9:29
add a comment |
1
Need to test A and B and invert. if A is missing the prop use -1 if B use +1
let arr = [{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
];
const sortPredicate = (a,b) => {
if (a.hasOwnProperty('parentId') === false) {
return -1;
} else if(b.hasOwnProperty('parentId') === false) {
return 1;
} else {
return a.id - b.id;
}
};
console.log(arr.sort(sortPredicate));answered Jan 2 at 5:32
BibbertyBibberty
1,9431315
beautiful, thanks master!
– wowhcumos
Jan 2 at 5:41
An possible optimization would be to return the difference between eachhasOwnPropertycheck.
– CertainPerformance
Jan 2 at 9:29
add a comment |
1
1
1
Need to test A and B and invert. if A is missing the prop use -1 if B use +1
let arr = [{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
];
const sortPredicate = (a,b) => {
if (a.hasOwnProperty('parentId') === false) {
return -1;
} else if(b.hasOwnProperty('parentId') === false) {
return 1;
} else {
return a.id - b.id;
}
};
console.log(arr.sort(sortPredicate));answered Jan 2 at 5:32
BibbertyBibberty
1,9431315
Need to test A and B and invert. if A is missing the prop use -1 if B use +1
let arr = [{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
];
const sortPredicate = (a,b) => {
if (a.hasOwnProperty('parentId') === false) {
return -1;
} else if(b.hasOwnProperty('parentId') === false) {
return 1;
} else {
return a.id - b.id;
}
};
console.log(arr.sort(sortPredicate));let arr = [{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
];
const sortPredicate = (a,b) => {
if (a.hasOwnProperty('parentId') === false) {
return -1;
} else if(b.hasOwnProperty('parentId') === false) {
return 1;
} else {
return a.id - b.id;
}
};
console.log(arr.sort(sortPredicate));let arr = [{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
];
const sortPredicate = (a,b) => {
if (a.hasOwnProperty('parentId') === false) {
return -1;
} else if(b.hasOwnProperty('parentId') === false) {
return 1;
} else {
return a.id - b.id;
}
};
console.log(arr.sort(sortPredicate));answered Jan 2 at 5:32
BibbertyBibberty
1,9431315
answered Jan 2 at 5:32
BibbertyBibberty
1,9431315
answered Jan 2 at 5:32
BibbertyBibberty
1,9431315
answered Jan 2 at 5:32
BibbertyBibberty
1,9431315
1,9431315
beautiful, thanks master!
– wowhcumos
Jan 2 at 5:41
An possible optimization would be to return the difference between eachhasOwnPropertycheck.
– CertainPerformance
Jan 2 at 9:29
add a comment |
beautiful, thanks master!
– wowhcumos
Jan 2 at 5:41
An possible optimization would be to return the difference between eachhasOwnPropertycheck.
– CertainPerformance
Jan 2 at 9:29
beautiful, thanks master!
– wowhcumos
Jan 2 at 5:41
beautiful, thanks master!
– wowhcumos
Jan 2 at 5:41
An possible optimization would be to return the difference between each
hasOwnProperty check.– CertainPerformance
Jan 2 at 9:29
An possible optimization would be to return the difference between each
hasOwnProperty check.– CertainPerformance
Jan 2 at 9:29
add a comment |
2
i would suggest to use lodash js library
var arr = [
{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
];
var sortedArr = _.orderBy(arr, 'parentId', 'desc');
console.log(sortedArr);<script src="https://cdn.jsdelivr.net/npm/lodash@4.17.11/lodash.min.js"></script>answered Jan 2 at 5:28
Shiv Kumar BaghelShiv Kumar Baghel
1,4263921
add a comment |
2
i would suggest to use lodash js library
var arr = [
{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
];
var sortedArr = _.orderBy(arr, 'parentId', 'desc');
console.log(sortedArr);<script src="https://cdn.jsdelivr.net/npm/lodash@4.17.11/lodash.min.js"></script>answered Jan 2 at 5:28
Shiv Kumar BaghelShiv Kumar Baghel
1,4263921
add a comment |
2
2
2
i would suggest to use lodash js library
var arr = [
{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
];
var sortedArr = _.orderBy(arr, 'parentId', 'desc');
console.log(sortedArr);<script src="https://cdn.jsdelivr.net/npm/lodash@4.17.11/lodash.min.js"></script>answered Jan 2 at 5:28
Shiv Kumar BaghelShiv Kumar Baghel
1,4263921
i would suggest to use lodash js library
var arr = [
{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
];
var sortedArr = _.orderBy(arr, 'parentId', 'desc');
console.log(sortedArr);<script src="https://cdn.jsdelivr.net/npm/lodash@4.17.11/lodash.min.js"></script>var arr = [
{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
];
var sortedArr = _.orderBy(arr, 'parentId', 'desc');
console.log(sortedArr);<script src="https://cdn.jsdelivr.net/npm/lodash@4.17.11/lodash.min.js"></script>var arr = [
{
"id": 877234004,
"name": "app.js",
"type": "FILE",
"parentId": 877234003
},
{
"id": 877234010,
"name": "project",
"type": "DIRECTORY"
},
{
"id": 877234002,
"name": "src",
"type": "DIRECTORY",
"parentId": 877234010
},
{
"id": 877234003,
"name": "app",
"type": "DIRECTORY",
"parentId": 877234002
}
];
var sortedArr = _.orderBy(arr, 'parentId', 'desc');
console.log(sortedArr);<script src="https://cdn.jsdelivr.net/npm/lodash@4.17.11/lodash.min.js"></script>answered Jan 2 at 5:28
Shiv Kumar BaghelShiv Kumar Baghel
1,4263921
edited Jan 2 at 5:33
answered Jan 2 at 5:28
Shiv Kumar BaghelShiv Kumar Baghel
1,4263921
answered Jan 2 at 5:28
Shiv Kumar BaghelShiv Kumar Baghel
1,4263921
answered Jan 2 at 5:28
Shiv Kumar BaghelShiv Kumar Baghel
1,4263921
1,4263921
add a comment |
add a comment |
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if sorting in descending order then in expected result
parentId877234003 will come first thenparentId877234003. pls edit your question.– Shiv Kumar Baghel
Jan 2 at 5:32