Mixing
The while loop is not repeating itself upon throwing garbage values
I am trying to run a while loop using the 'not' keyword but when I am doing so, the loop is accepting garbage values as well(for eg. bjskdjb) which is not the condition set for the while/for loop.
When I am running the for loop instead, it is throwing a syntax error.
What are the mistakes I am doing here(both using for loop and while loop) ?
I have tried doing it with for loop and while loop.
def askplayerchoice():
playerchoice = ''
while playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
else:
return ['O', 'X']
askplayerchoice()
'''
# Using For loop I am getting a syntax error.
def askplayerchoice():
playerchoice = ''
for playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
else:
return ['O', 'X']
askplayerchoice()
'''
I am expecting the code to keep asking the user to enter either 'X' or 'O' until the user enters correct values.
python python-3.x
asked Jan 1 at 5:46
Prashant MishraPrashant Mishra
345
add a comment |
I am trying to run a while loop using the 'not' keyword but when I am doing so, the loop is accepting garbage values as well(for eg. bjskdjb) which is not the condition set for the while/for loop.
When I am running the for loop instead, it is throwing a syntax error.
What are the mistakes I am doing here(both using for loop and while loop) ?
I have tried doing it with for loop and while loop.
def askplayerchoice():
playerchoice = ''
while playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
else:
return ['O', 'X']
askplayerchoice()
'''
# Using For loop I am getting a syntax error.
def askplayerchoice():
playerchoice = ''
for playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
else:
return ['O', 'X']
askplayerchoice()
'''
I am expecting the code to keep asking the user to enter either 'X' or 'O' until the user enters correct values.
python python-3.x
asked Jan 1 at 5:46
Prashant MishraPrashant Mishra
345
add a comment |
I am trying to run a while loop using the 'not' keyword but when I am doing so, the loop is accepting garbage values as well(for eg. bjskdjb) which is not the condition set for the while/for loop.
When I am running the for loop instead, it is throwing a syntax error.
What are the mistakes I am doing here(both using for loop and while loop) ?
I have tried doing it with for loop and while loop.
def askplayerchoice():
playerchoice = ''
while playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
else:
return ['O', 'X']
askplayerchoice()
'''
# Using For loop I am getting a syntax error.
def askplayerchoice():
playerchoice = ''
for playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
else:
return ['O', 'X']
askplayerchoice()
'''
I am expecting the code to keep asking the user to enter either 'X' or 'O' until the user enters correct values.
python python-3.x
asked Jan 1 at 5:46
Prashant MishraPrashant Mishra
345
I am trying to run a while loop using the 'not' keyword but when I am doing so, the loop is accepting garbage values as well(for eg. bjskdjb) which is not the condition set for the while/for loop.
When I am running the for loop instead, it is throwing a syntax error.
What are the mistakes I am doing here(both using for loop and while loop) ?
I have tried doing it with for loop and while loop.
def askplayerchoice():
playerchoice = ''
while playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
else:
return ['O', 'X']
askplayerchoice()
'''
# Using For loop I am getting a syntax error.
def askplayerchoice():
playerchoice = ''
for playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
else:
return ['O', 'X']
askplayerchoice()
'''
I am expecting the code to keep asking the user to enter either 'X' or 'O' until the user enters correct values.
python python-3.x
python python-3.x
asked Jan 1 at 5:46
Prashant MishraPrashant Mishra
345
asked Jan 1 at 5:46
Prashant MishraPrashant Mishra
345
asked Jan 1 at 5:46
Prashant MishraPrashant Mishra
345
asked Jan 1 at 5:46
Prashant MishraPrashant Mishra
345
asked Jan 1 at 5:46
Prashant MishraPrashant Mishra
345
345
add a comment |
add a comment |
5 Answers
5
active
oldest
votes
You are returning from the loop to the function caller in the first pass itself, because you use return inside loop. Hence, whatever is the value other than 'X', ['O', 'X'] is returned.
def askplayerchoice():
playerchoice = ''
while playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
elif playerchoice == 'O':
return ['O', 'X']
print(askplayerchoice())
You can also make use of an infinite loop while True: here, like so:
def askplayerchoice():
playerchoice = ''
while True:
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
elif playerchoice == 'O':
return ['O', 'X']
print(askplayerchoice())
answered Jan 1 at 5:50
AustinAustin
11.3k3829
Thanks... Worked for while loop.Can you also tell me why this code is not working with For loop.. def askplayerchoice(): playerchoice = '' for playerchoice not in ('X' , 'O'): playerchoice = input('Enter X or O: ') if playerchoice == 'X': return ['X' , 'O'] else: return ['O', 'X'] askplayerchoice()
– Prashant Mishra
Jan 1 at 6:57
1
@PrashantMishra,fordoes not work likewhile.for x in (..,..)will take values from(.., ..)one item at a time in each iteration. Try printing:for x in (1,2): print(x). What you didfor .. not in (.., ..)is syntactically wrong.
– Austin
Jan 1 at 7:01
yes, you are right.. I got it now !! BIG THANK YOU for clearing the confusion. Happy New year 2019 to you ! :)
– Prashant Mishra
Jan 1 at 7:04
add a comment |
You can add a try catch block and throw an exception when the entered string does not match your desired value. I have updated your code for the same. Below is the snippet :
def askplayerchoice():
playerchoice = ''
while playerchoice.lower() not in ('X' , 'O'):
try:
playerchoice = str(input('Enter X or O: '))
if playerchoice.lower() not in ['x','o']:
raise ValueError('A very specific bad thing happened.')
if playerchoice.lower() == 'x':
return ['X' , 'O']
else:
return ['O', 'X']
except ValueError:
playerchoice = ''
askplayerchoice()
answered Jan 1 at 7:09
Chintan BhattChintan Bhatt
212
add a comment |
Your function is returning a value within the while loop, regardless of what the user input is, and that's causing the loop to end. You need to change your else condition to else if:
if playerchoice == 'X':
return ['X' , 'O']
elif playerchoice == 'O':
return ['O', 'X']
answered Jan 1 at 5:52
kavehkaveh
7331222
Thanks.. What is wrong in this condition: for playerchoice not in ('X' , 'O'): playerchoice = input('Enter X or O: ')
– Prashant Mishra
Jan 1 at 7:02
add a comment |
First you were initializing playerchoice = '' but inside the loop you were only checking for playerchoice == 'X'. But you didn't check for playerchoice == 'O'. therefore it went to the else and got out of the loop.
This should do the work:
def askplayerchoice():
playerchoice = input('Enter X or O: ')
while playerchoice not in('X', 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X', 'O']
elif playerchoice == 'O':
return ['O', 'X']
askplayerchoice()
answered Jan 1 at 5:54
Partho63Partho63
1,8391823
add a comment |
When you use return, the while loop will be stopped.
Try this code, it will keep asking.
def askplayerchoice():
playerchoice = ''
while playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
print('X' , 'O')
else:
print('O', 'X')
return askplayerchoice()
askplayerchoice()
answered Jan 1 at 6:03
WEN WENWEN WEN
9828
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
You are returning from the loop to the function caller in the first pass itself, because you use return inside loop. Hence, whatever is the value other than 'X', ['O', 'X'] is returned.
def askplayerchoice():
playerchoice = ''
while playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
elif playerchoice == 'O':
return ['O', 'X']
print(askplayerchoice())
You can also make use of an infinite loop while True: here, like so:
def askplayerchoice():
playerchoice = ''
while True:
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
elif playerchoice == 'O':
return ['O', 'X']
print(askplayerchoice())
answered Jan 1 at 5:50
AustinAustin
11.3k3829
Thanks... Worked for while loop.Can you also tell me why this code is not working with For loop.. def askplayerchoice(): playerchoice = '' for playerchoice not in ('X' , 'O'): playerchoice = input('Enter X or O: ') if playerchoice == 'X': return ['X' , 'O'] else: return ['O', 'X'] askplayerchoice()
– Prashant Mishra
Jan 1 at 6:57
1
@PrashantMishra,fordoes not work likewhile.for x in (..,..)will take values from(.., ..)one item at a time in each iteration. Try printing:for x in (1,2): print(x). What you didfor .. not in (.., ..)is syntactically wrong.
– Austin
Jan 1 at 7:01
yes, you are right.. I got it now !! BIG THANK YOU for clearing the confusion. Happy New year 2019 to you ! :)
– Prashant Mishra
Jan 1 at 7:04
add a comment |
You are returning from the loop to the function caller in the first pass itself, because you use return inside loop. Hence, whatever is the value other than 'X', ['O', 'X'] is returned.
def askplayerchoice():
playerchoice = ''
while playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
elif playerchoice == 'O':
return ['O', 'X']
print(askplayerchoice())
You can also make use of an infinite loop while True: here, like so:
def askplayerchoice():
playerchoice = ''
while True:
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
elif playerchoice == 'O':
return ['O', 'X']
print(askplayerchoice())
answered Jan 1 at 5:50
AustinAustin
11.3k3829
Thanks... Worked for while loop.Can you also tell me why this code is not working with For loop.. def askplayerchoice(): playerchoice = '' for playerchoice not in ('X' , 'O'): playerchoice = input('Enter X or O: ') if playerchoice == 'X': return ['X' , 'O'] else: return ['O', 'X'] askplayerchoice()
– Prashant Mishra
Jan 1 at 6:57
1
@PrashantMishra,fordoes not work likewhile.for x in (..,..)will take values from(.., ..)one item at a time in each iteration. Try printing:for x in (1,2): print(x). What you didfor .. not in (.., ..)is syntactically wrong.
– Austin
Jan 1 at 7:01
yes, you are right.. I got it now !! BIG THANK YOU for clearing the confusion. Happy New year 2019 to you ! :)
– Prashant Mishra
Jan 1 at 7:04
add a comment |
You are returning from the loop to the function caller in the first pass itself, because you use return inside loop. Hence, whatever is the value other than 'X', ['O', 'X'] is returned.
def askplayerchoice():
playerchoice = ''
while playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
elif playerchoice == 'O':
return ['O', 'X']
print(askplayerchoice())
You can also make use of an infinite loop while True: here, like so:
def askplayerchoice():
playerchoice = ''
while True:
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
elif playerchoice == 'O':
return ['O', 'X']
print(askplayerchoice())
answered Jan 1 at 5:50
AustinAustin
11.3k3829
You are returning from the loop to the function caller in the first pass itself, because you use return inside loop. Hence, whatever is the value other than 'X', ['O', 'X'] is returned.
def askplayerchoice():
playerchoice = ''
while playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
elif playerchoice == 'O':
return ['O', 'X']
print(askplayerchoice())
You can also make use of an infinite loop while True: here, like so:
def askplayerchoice():
playerchoice = ''
while True:
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X' , 'O']
elif playerchoice == 'O':
return ['O', 'X']
print(askplayerchoice())
answered Jan 1 at 5:50
AustinAustin
11.3k3829
edited Jan 1 at 7:05
answered Jan 1 at 5:50
AustinAustin
11.3k3829
answered Jan 1 at 5:50
AustinAustin
11.3k3829
answered Jan 1 at 5:50
AustinAustin
11.3k3829
11.3k3829
Thanks... Worked for while loop.Can you also tell me why this code is not working with For loop.. def askplayerchoice(): playerchoice = '' for playerchoice not in ('X' , 'O'): playerchoice = input('Enter X or O: ') if playerchoice == 'X': return ['X' , 'O'] else: return ['O', 'X'] askplayerchoice()
– Prashant Mishra
Jan 1 at 6:57
1
@PrashantMishra,fordoes not work likewhile.for x in (..,..)will take values from(.., ..)one item at a time in each iteration. Try printing:for x in (1,2): print(x). What you didfor .. not in (.., ..)is syntactically wrong.
– Austin
Jan 1 at 7:01
yes, you are right.. I got it now !! BIG THANK YOU for clearing the confusion. Happy New year 2019 to you ! :)
– Prashant Mishra
Jan 1 at 7:04
add a comment |
Thanks... Worked for while loop.Can you also tell me why this code is not working with For loop.. def askplayerchoice(): playerchoice = '' for playerchoice not in ('X' , 'O'): playerchoice = input('Enter X or O: ') if playerchoice == 'X': return ['X' , 'O'] else: return ['O', 'X'] askplayerchoice()
– Prashant Mishra
Jan 1 at 6:57
1
@PrashantMishra,fordoes not work likewhile.for x in (..,..)will take values from(.., ..)one item at a time in each iteration. Try printing:for x in (1,2): print(x). What you didfor .. not in (.., ..)is syntactically wrong.
– Austin
Jan 1 at 7:01
yes, you are right.. I got it now !! BIG THANK YOU for clearing the confusion. Happy New year 2019 to you ! :)
– Prashant Mishra
Jan 1 at 7:04
Thanks... Worked for while loop.Can you also tell me why this code is not working with For loop.. def askplayerchoice(): playerchoice = '' for playerchoice not in ('X' , 'O'): playerchoice = input('Enter X or O: ') if playerchoice == 'X': return ['X' , 'O'] else: return ['O', 'X'] askplayerchoice()
– Prashant Mishra
Jan 1 at 6:57
Thanks... Worked for while loop.Can you also tell me why this code is not working with For loop.. def askplayerchoice(): playerchoice = '' for playerchoice not in ('X' , 'O'): playerchoice = input('Enter X or O: ') if playerchoice == 'X': return ['X' , 'O'] else: return ['O', 'X'] askplayerchoice()
– Prashant Mishra
Jan 1 at 6:57
1
1
@PrashantMishra,
for does not work like while. for x in (..,..) will take values from (.., ..) one item at a time in each iteration. Try printing: for x in (1,2): print(x). What you did for .. not in (.., ..) is syntactically wrong.– Austin
Jan 1 at 7:01
@PrashantMishra,
for does not work like while. for x in (..,..) will take values from (.., ..) one item at a time in each iteration. Try printing: for x in (1,2): print(x). What you did for .. not in (.., ..) is syntactically wrong.– Austin
Jan 1 at 7:01
yes, you are right.. I got it now !! BIG THANK YOU for clearing the confusion. Happy New year 2019 to you ! :)
– Prashant Mishra
Jan 1 at 7:04
yes, you are right.. I got it now !! BIG THANK YOU for clearing the confusion. Happy New year 2019 to you ! :)
– Prashant Mishra
Jan 1 at 7:04
add a comment |
You can add a try catch block and throw an exception when the entered string does not match your desired value. I have updated your code for the same. Below is the snippet :
def askplayerchoice():
playerchoice = ''
while playerchoice.lower() not in ('X' , 'O'):
try:
playerchoice = str(input('Enter X or O: '))
if playerchoice.lower() not in ['x','o']:
raise ValueError('A very specific bad thing happened.')
if playerchoice.lower() == 'x':
return ['X' , 'O']
else:
return ['O', 'X']
except ValueError:
playerchoice = ''
askplayerchoice()
answered Jan 1 at 7:09
Chintan BhattChintan Bhatt
212
add a comment |
You can add a try catch block and throw an exception when the entered string does not match your desired value. I have updated your code for the same. Below is the snippet :
def askplayerchoice():
playerchoice = ''
while playerchoice.lower() not in ('X' , 'O'):
try:
playerchoice = str(input('Enter X or O: '))
if playerchoice.lower() not in ['x','o']:
raise ValueError('A very specific bad thing happened.')
if playerchoice.lower() == 'x':
return ['X' , 'O']
else:
return ['O', 'X']
except ValueError:
playerchoice = ''
askplayerchoice()
answered Jan 1 at 7:09
Chintan BhattChintan Bhatt
212
add a comment |
You can add a try catch block and throw an exception when the entered string does not match your desired value. I have updated your code for the same. Below is the snippet :
def askplayerchoice():
playerchoice = ''
while playerchoice.lower() not in ('X' , 'O'):
try:
playerchoice = str(input('Enter X or O: '))
if playerchoice.lower() not in ['x','o']:
raise ValueError('A very specific bad thing happened.')
if playerchoice.lower() == 'x':
return ['X' , 'O']
else:
return ['O', 'X']
except ValueError:
playerchoice = ''
askplayerchoice()
answered Jan 1 at 7:09
Chintan BhattChintan Bhatt
212
You can add a try catch block and throw an exception when the entered string does not match your desired value. I have updated your code for the same. Below is the snippet :
def askplayerchoice():
playerchoice = ''
while playerchoice.lower() not in ('X' , 'O'):
try:
playerchoice = str(input('Enter X or O: '))
if playerchoice.lower() not in ['x','o']:
raise ValueError('A very specific bad thing happened.')
if playerchoice.lower() == 'x':
return ['X' , 'O']
else:
return ['O', 'X']
except ValueError:
playerchoice = ''
askplayerchoice()
answered Jan 1 at 7:09
Chintan BhattChintan Bhatt
212
answered Jan 1 at 7:09
Chintan BhattChintan Bhatt
212
answered Jan 1 at 7:09
Chintan BhattChintan Bhatt
212
answered Jan 1 at 7:09
Chintan BhattChintan Bhatt
212
212
add a comment |
add a comment |
Your function is returning a value within the while loop, regardless of what the user input is, and that's causing the loop to end. You need to change your else condition to else if:
if playerchoice == 'X':
return ['X' , 'O']
elif playerchoice == 'O':
return ['O', 'X']
answered Jan 1 at 5:52
kavehkaveh
7331222
Thanks.. What is wrong in this condition: for playerchoice not in ('X' , 'O'): playerchoice = input('Enter X or O: ')
– Prashant Mishra
Jan 1 at 7:02
add a comment |
Your function is returning a value within the while loop, regardless of what the user input is, and that's causing the loop to end. You need to change your else condition to else if:
if playerchoice == 'X':
return ['X' , 'O']
elif playerchoice == 'O':
return ['O', 'X']
answered Jan 1 at 5:52
kavehkaveh
7331222
Thanks.. What is wrong in this condition: for playerchoice not in ('X' , 'O'): playerchoice = input('Enter X or O: ')
– Prashant Mishra
Jan 1 at 7:02
add a comment |
Your function is returning a value within the while loop, regardless of what the user input is, and that's causing the loop to end. You need to change your else condition to else if:
if playerchoice == 'X':
return ['X' , 'O']
elif playerchoice == 'O':
return ['O', 'X']
answered Jan 1 at 5:52
kavehkaveh
7331222
Your function is returning a value within the while loop, regardless of what the user input is, and that's causing the loop to end. You need to change your else condition to else if:
if playerchoice == 'X':
return ['X' , 'O']
elif playerchoice == 'O':
return ['O', 'X']
answered Jan 1 at 5:52
kavehkaveh
7331222
answered Jan 1 at 5:52
kavehkaveh
7331222
answered Jan 1 at 5:52
kavehkaveh
7331222
answered Jan 1 at 5:52
kavehkaveh
7331222
7331222
Thanks.. What is wrong in this condition: for playerchoice not in ('X' , 'O'): playerchoice = input('Enter X or O: ')
– Prashant Mishra
Jan 1 at 7:02
add a comment |
Thanks.. What is wrong in this condition: for playerchoice not in ('X' , 'O'): playerchoice = input('Enter X or O: ')
– Prashant Mishra
Jan 1 at 7:02
Thanks.. What is wrong in this condition: for playerchoice not in ('X' , 'O'): playerchoice = input('Enter X or O: ')
– Prashant Mishra
Jan 1 at 7:02
Thanks.. What is wrong in this condition: for playerchoice not in ('X' , 'O'): playerchoice = input('Enter X or O: ')
– Prashant Mishra
Jan 1 at 7:02
add a comment |
First you were initializing playerchoice = '' but inside the loop you were only checking for playerchoice == 'X'. But you didn't check for playerchoice == 'O'. therefore it went to the else and got out of the loop.
This should do the work:
def askplayerchoice():
playerchoice = input('Enter X or O: ')
while playerchoice not in('X', 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X', 'O']
elif playerchoice == 'O':
return ['O', 'X']
askplayerchoice()
answered Jan 1 at 5:54
Partho63Partho63
1,8391823
add a comment |
First you were initializing playerchoice = '' but inside the loop you were only checking for playerchoice == 'X'. But you didn't check for playerchoice == 'O'. therefore it went to the else and got out of the loop.
This should do the work:
def askplayerchoice():
playerchoice = input('Enter X or O: ')
while playerchoice not in('X', 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X', 'O']
elif playerchoice == 'O':
return ['O', 'X']
askplayerchoice()
answered Jan 1 at 5:54
Partho63Partho63
1,8391823
add a comment |
First you were initializing playerchoice = '' but inside the loop you were only checking for playerchoice == 'X'. But you didn't check for playerchoice == 'O'. therefore it went to the else and got out of the loop.
This should do the work:
def askplayerchoice():
playerchoice = input('Enter X or O: ')
while playerchoice not in('X', 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X', 'O']
elif playerchoice == 'O':
return ['O', 'X']
askplayerchoice()
answered Jan 1 at 5:54
Partho63Partho63
1,8391823
First you were initializing playerchoice = '' but inside the loop you were only checking for playerchoice == 'X'. But you didn't check for playerchoice == 'O'. therefore it went to the else and got out of the loop.
This should do the work:
def askplayerchoice():
playerchoice = input('Enter X or O: ')
while playerchoice not in('X', 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
return ['X', 'O']
elif playerchoice == 'O':
return ['O', 'X']
askplayerchoice()
answered Jan 1 at 5:54
Partho63Partho63
1,8391823
edited Jan 1 at 6:01
answered Jan 1 at 5:54
Partho63Partho63
1,8391823
answered Jan 1 at 5:54
Partho63Partho63
1,8391823
answered Jan 1 at 5:54
Partho63Partho63
1,8391823
1,8391823
add a comment |
add a comment |
When you use return, the while loop will be stopped.
Try this code, it will keep asking.
def askplayerchoice():
playerchoice = ''
while playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
print('X' , 'O')
else:
print('O', 'X')
return askplayerchoice()
askplayerchoice()
answered Jan 1 at 6:03
WEN WENWEN WEN
9828
add a comment |
When you use return, the while loop will be stopped.
Try this code, it will keep asking.
def askplayerchoice():
playerchoice = ''
while playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
print('X' , 'O')
else:
print('O', 'X')
return askplayerchoice()
askplayerchoice()
answered Jan 1 at 6:03
WEN WENWEN WEN
9828
add a comment |
When you use return, the while loop will be stopped.
Try this code, it will keep asking.
def askplayerchoice():
playerchoice = ''
while playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
print('X' , 'O')
else:
print('O', 'X')
return askplayerchoice()
askplayerchoice()
answered Jan 1 at 6:03
WEN WENWEN WEN
9828
When you use return, the while loop will be stopped.
Try this code, it will keep asking.
def askplayerchoice():
playerchoice = ''
while playerchoice not in ('X' , 'O'):
playerchoice = input('Enter X or O: ')
if playerchoice == 'X':
print('X' , 'O')
else:
print('O', 'X')
return askplayerchoice()
askplayerchoice()
answered Jan 1 at 6:03
WEN WENWEN WEN
9828
answered Jan 1 at 6:03
WEN WENWEN WEN
9828
answered Jan 1 at 6:03
WEN WENWEN WEN
9828
answered Jan 1 at 6:03
WEN WENWEN WEN
9828
9828
add a comment |
add a comment |
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