Mixing
Trying to populate the datatable with php ajax mysql
-1
I am trying to populate my datatable from mysql database. Everything works fine but when I try to see my table it says:
DataTables warning: table id=manageProductTable - Invalid JSON response.
For more information about this error, please see http://datatables.net/tn/1
I've already checked console and I can see my list there as:
connection success {
"data": [
["tulum","rtert","6","12.30","dfsdfsdf"],
["body","bd56","8","56,30","dfsdfsdf"],
["dfdsf","dsfdsf","8","56,32","dsfdsfsd"],
["","saf","8","25.90","dsfdsfsd"],
["tulum","FWNWP","","","dsfdsfsd"],
["bluz","dd56","6","78","dsfdsfsd"],
["dsfdsf","sdfsdf","9","23","chicco"],
["atlet","ATL30","30","23,30","chicco"],
["BODY","56FG","6","56,30","dsfdsfsd"]
]
}
So what am I doing wrong here?
JS
$('#manageProductTable').DataTable({
ajax: {
'url': 'php_action/fetchProduct.php',
'dataSrc': 'features'},
'columns': [
{"data":"Name"},
{"data":"Code"},
{"data":"Brand"},
{"data":"Quantity"},
{"data":"Price"},
]
});
PHP
$sql = "SELECT product.product_id, product.product_name,
product.product_code, product.brand_id,
product.quantity, product.price, brand.brand_name
FROM product
INNER JOIN brand ON product.brand_id = brand.brand_id";
$result = $connect->query($sql);
$output = array('data' => array());
if($result->num_rows > 0) {
$active = "";
while($row = $result->fetch_array()) {
$brandName = $row[6];
$output['data']= array(
$row[1],
$row[2],
$row[4],
$row[5],
$brandName,
);
}
}
$connect->close();
echo json_encode($output);
I have one more php file but it's just to build web page.
php mysql
edited Jan 1 at 18:45
trincot
127k1688123
asked Jan 1 at 17:32
workingonitworkingonit
134
add a comment |
-1
I am trying to populate my datatable from mysql database. Everything works fine but when I try to see my table it says:
DataTables warning: table id=manageProductTable - Invalid JSON response.
For more information about this error, please see http://datatables.net/tn/1
I've already checked console and I can see my list there as:
connection success {
"data": [
["tulum","rtert","6","12.30","dfsdfsdf"],
["body","bd56","8","56,30","dfsdfsdf"],
["dfdsf","dsfdsf","8","56,32","dsfdsfsd"],
["","saf","8","25.90","dsfdsfsd"],
["tulum","FWNWP","","","dsfdsfsd"],
["bluz","dd56","6","78","dsfdsfsd"],
["dsfdsf","sdfsdf","9","23","chicco"],
["atlet","ATL30","30","23,30","chicco"],
["BODY","56FG","6","56,30","dsfdsfsd"]
]
}
So what am I doing wrong here?
JS
$('#manageProductTable').DataTable({
ajax: {
'url': 'php_action/fetchProduct.php',
'dataSrc': 'features'},
'columns': [
{"data":"Name"},
{"data":"Code"},
{"data":"Brand"},
{"data":"Quantity"},
{"data":"Price"},
]
});
PHP
$sql = "SELECT product.product_id, product.product_name,
product.product_code, product.brand_id,
product.quantity, product.price, brand.brand_name
FROM product
INNER JOIN brand ON product.brand_id = brand.brand_id";
$result = $connect->query($sql);
$output = array('data' => array());
if($result->num_rows > 0) {
$active = "";
while($row = $result->fetch_array()) {
$brandName = $row[6];
$output['data']= array(
$row[1],
$row[2],
$row[4],
$row[5],
$brandName,
);
}
}
$connect->close();
echo json_encode($output);
I have one more php file but it's just to build web page.
php mysql
edited Jan 1 at 18:45
trincot
127k1688123
asked Jan 1 at 17:32
workingonitworkingonit
134
add a comment |
-1
-1
-1
I am trying to populate my datatable from mysql database. Everything works fine but when I try to see my table it says:
DataTables warning: table id=manageProductTable - Invalid JSON response.
For more information about this error, please see http://datatables.net/tn/1
I've already checked console and I can see my list there as:
connection success {
"data": [
["tulum","rtert","6","12.30","dfsdfsdf"],
["body","bd56","8","56,30","dfsdfsdf"],
["dfdsf","dsfdsf","8","56,32","dsfdsfsd"],
["","saf","8","25.90","dsfdsfsd"],
["tulum","FWNWP","","","dsfdsfsd"],
["bluz","dd56","6","78","dsfdsfsd"],
["dsfdsf","sdfsdf","9","23","chicco"],
["atlet","ATL30","30","23,30","chicco"],
["BODY","56FG","6","56,30","dsfdsfsd"]
]
}
So what am I doing wrong here?
JS
$('#manageProductTable').DataTable({
ajax: {
'url': 'php_action/fetchProduct.php',
'dataSrc': 'features'},
'columns': [
{"data":"Name"},
{"data":"Code"},
{"data":"Brand"},
{"data":"Quantity"},
{"data":"Price"},
]
});
PHP
$sql = "SELECT product.product_id, product.product_name,
product.product_code, product.brand_id,
product.quantity, product.price, brand.brand_name
FROM product
INNER JOIN brand ON product.brand_id = brand.brand_id";
$result = $connect->query($sql);
$output = array('data' => array());
if($result->num_rows > 0) {
$active = "";
while($row = $result->fetch_array()) {
$brandName = $row[6];
$output['data']= array(
$row[1],
$row[2],
$row[4],
$row[5],
$brandName,
);
}
}
$connect->close();
echo json_encode($output);
I have one more php file but it's just to build web page.
php mysql
edited Jan 1 at 18:45
trincot
127k1688123
asked Jan 1 at 17:32
workingonitworkingonit
134
I am trying to populate my datatable from mysql database. Everything works fine but when I try to see my table it says:
DataTables warning: table id=manageProductTable - Invalid JSON response.
For more information about this error, please see http://datatables.net/tn/1
I've already checked console and I can see my list there as:
connection success {
"data": [
["tulum","rtert","6","12.30","dfsdfsdf"],
["body","bd56","8","56,30","dfsdfsdf"],
["dfdsf","dsfdsf","8","56,32","dsfdsfsd"],
["","saf","8","25.90","dsfdsfsd"],
["tulum","FWNWP","","","dsfdsfsd"],
["bluz","dd56","6","78","dsfdsfsd"],
["dsfdsf","sdfsdf","9","23","chicco"],
["atlet","ATL30","30","23,30","chicco"],
["BODY","56FG","6","56,30","dsfdsfsd"]
]
}
So what am I doing wrong here?
JS
$('#manageProductTable').DataTable({
ajax: {
'url': 'php_action/fetchProduct.php',
'dataSrc': 'features'},
'columns': [
{"data":"Name"},
{"data":"Code"},
{"data":"Brand"},
{"data":"Quantity"},
{"data":"Price"},
]
});
PHP
$sql = "SELECT product.product_id, product.product_name,
product.product_code, product.brand_id,
product.quantity, product.price, brand.brand_name
FROM product
INNER JOIN brand ON product.brand_id = brand.brand_id";
$result = $connect->query($sql);
$output = array('data' => array());
if($result->num_rows > 0) {
$active = "";
while($row = $result->fetch_array()) {
$brandName = $row[6];
$output['data']= array(
$row[1],
$row[2],
$row[4],
$row[5],
$brandName,
);
}
}
$connect->close();
echo json_encode($output);
I have one more php file but it's just to build web page.
php mysql
php mysql
edited Jan 1 at 18:45
trincot
127k1688123
asked Jan 1 at 17:32
workingonitworkingonit
134
edited Jan 1 at 18:45
trincot
127k1688123
asked Jan 1 at 17:32
workingonitworkingonit
134
edited Jan 1 at 18:45
trincot
127k1688123
edited Jan 1 at 18:45
trincot
127k1688123
edited Jan 1 at 18:45
trincot
127k1688123
127k1688123
asked Jan 1 at 17:32
workingonitworkingonit
134
asked Jan 1 at 17:32
workingonitworkingonit
134
asked Jan 1 at 17:32
workingonitworkingonit
134
134
add a comment |
add a comment |
1 Answer
1
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votes
0
what is doing "connection success" there?
That is altering your response.
answered Jan 1 at 17:39
Răducanu IonuţRăducanu Ionuţ
403211
that was my database connection control. Thanks!
– workingonit
Jan 1 at 17:43
you are welcome
– Răducanu Ionuţ
Jan 1 at 17:47
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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active
oldest
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active
oldest
votes
0
what is doing "connection success" there?
That is altering your response.
answered Jan 1 at 17:39
Răducanu IonuţRăducanu Ionuţ
403211
that was my database connection control. Thanks!
– workingonit
Jan 1 at 17:43
you are welcome
– Răducanu Ionuţ
Jan 1 at 17:47
add a comment |
0
what is doing "connection success" there?
That is altering your response.
answered Jan 1 at 17:39
Răducanu IonuţRăducanu Ionuţ
403211
that was my database connection control. Thanks!
– workingonit
Jan 1 at 17:43
you are welcome
– Răducanu Ionuţ
Jan 1 at 17:47
add a comment |
0
0
0
what is doing "connection success" there?
That is altering your response.
answered Jan 1 at 17:39
Răducanu IonuţRăducanu Ionuţ
403211
what is doing "connection success" there?
That is altering your response.
answered Jan 1 at 17:39
Răducanu IonuţRăducanu Ionuţ
403211
answered Jan 1 at 17:39
Răducanu IonuţRăducanu Ionuţ
403211
answered Jan 1 at 17:39
Răducanu IonuţRăducanu Ionuţ
403211
answered Jan 1 at 17:39
Răducanu IonuţRăducanu Ionuţ
403211
403211
that was my database connection control. Thanks!
– workingonit
Jan 1 at 17:43
you are welcome
– Răducanu Ionuţ
Jan 1 at 17:47
add a comment |
that was my database connection control. Thanks!
– workingonit
Jan 1 at 17:43
you are welcome
– Răducanu Ionuţ
Jan 1 at 17:47
that was my database connection control. Thanks!
– workingonit
Jan 1 at 17:43
that was my database connection control. Thanks!
– workingonit
Jan 1 at 17:43
you are welcome
– Răducanu Ionuţ
Jan 1 at 17:47
you are welcome
– Răducanu Ionuţ
Jan 1 at 17:47
add a comment |
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